I am trying to create a query that allows me to select the data like shown below
organizing by the role 45 and showing its win rate in order of DESC.
For example champ_1 = 45 and champ_2 = 36 but some time its can be champ_1 = 36 and champ_2 = 45. When like this how would i make the query so that is orders the win rate for champion 45 depending on if its champ1 or champ2 and then organizing it desc.
id Role Champ_1 Champ_2 Champ_1_winrate Champ_2_winrate
---|------------|------------|-----------|-----------------|---------------
1 | 1 | 45 | 17 | 0.54 | 0.46
2 | 1 | 67 | 45 | 0.52 | 0.48
5 | 1 | 45 | 27 | 0.59 | 0.41
3 | 1 | 45 | 35 | 0.29 | 0.71
4 | 1 | 45 | 23 | 0.094 | 0.916
6 | 1 | 80 | 45 | 0.38 | 0.62
7 | 1 | 45 | 47 | 0.544 | 0.456
8 | 1 | 32 | 45 | 0.78 | 0.22
It should show the data:
id Role Champ_1 Champ_2 winrate
---|------------|------------|-----------|-----------------|
6 | 1 | 80 | 45 | 0.62 |
5 | 1 | 45 | 27 | 0.59 |
7 | 1 | 45 | 47 | 0.544 |
1 | 1 | 45 | 17 | 0.54 |
2 | 1 | 67 | 45 | 0.48 |
3 | 1 | 45 | 35 | 0.29 |
8 | 1 | 32 | 45 | 0.22 |
4 | 1 | 45 | 23 | 0.094 |
I have tried the following code and its the closest I have came for over 3 hours now, so could someone help please.
SELECT *
FROM Bronze_Matchups a
WHERE (Champ_2 = 24 AND Role = 'JUNGLE')
OR (Champ_1 = 24 AND Role = 'JUNGLE')
ORDER BY Champ_2_winrate desc, Champ_1_winrate asc
You can use UNION and ORDER BY (add desc or asc in ORDER BY clause as you need)
SELECT a.id, a.Role, a.Champ_1, a.Champ_2, a.Champ_2_winrate as winrate
FROM Bronze_Matchups a
WHERE a.Champ_2 = 24
AND a.Role = 'JUNGLE'
UNION
SELECT a.id, a.Role, a.Champ_1, a.Champ_2, a.Champ_1_winrate as winrate
FROM Bronze_Matchups a
WHERE a.Champ_1 = 24
AND a.Role = 'JUNGLE'
ORDER BY winrate
Use a case-statement in your order-by
SELECT *
FROM Bronze_Matchups a
WHERE
(Champ_2 = 24 AND Role = 'JUNGLE')
OR (Champ_1 = 24 AND Role = 'JUNGLE')
ORDER BY
CASE
WHEN Champ_2 = 24 THEN Champ_2_winrate
ELSE Champ_1_winrate
END
Related
This is very conflict for me let me explain to the best that I could please. This is like a 2 layers to compute. The first layer is I need to get the total A, and total B, and total C, and total D . But, to get the total A is i need to compute some columns, as well as total B, C and D . The second layer is to display and get the sum of the total A ,B, C, D. This is a bunch of tables.
For the first table.
tbl_criteria
------------------------
crit_id | criteria_name
16 | sports
17 | formal
18 | talent
19 | nothing
The tbl_criteria has a sub criteria
tbl_sub_criteria
----------------------
sub_crit_id | crit_id | sub_crit_name
22 | 16 | originality
23 | 16 | audience Impact
24 | 18 | Appeal
25 | 18 | Stage Presence
Third table the judges.
tbl_judges
------------------------
judge_id | judge_name
61 | first
62 | second
63 | third
Table of contestant lets say 2 contestant
tbl_cotestant
-----------------------------------------------
con_id | contestant_number | contestant_name |
1 | 1 | john |
2 | 2 | sy |
Last table, This is the constructed table
tbl_score
--------------------------------------------------
score_id | crit_id | sub_crit_id | judge_id | con_id | contestant_number | score
1 | 16 | 22 | 61 | 1 | 1 | 25
2 | 16 | 22 | 61 | 2 | 2 | 25
3 | 16 | 22 | 62 | 1 | 1 | 25
4 | 16 | 22 | 62 | 2 | 2 | 73
5 | 16 | 22 | 63 | 1 | 1 | 70
6 | 16 | 22 | 63 | 2 | 2 | 80
7 | 16 | 23 | 61 | 1 | 1 | 25
8 | 16 | 23 | 61 | 2 | 2 | 25
9 | 16 | 23 | 62 | 1 | 1 | 25
10 | 16 | 23 | 62 | 2 | 2 | 73
11 | 18 | 23 | 63 | 1 | 1 | 70
12 | 16 | 23 | 63 | 2 | 2 | 80
13 | 18 | 24 | 61 | 1 | 1 | 25
14 | 18 | 24 | 61 | 2 | 2 | 25
15 | 18 | 24 | 62 | 1 | 1 | 25
16 | 18 | 24 | 62 | 2 | 2 | 73
17 | 18 | 24 | 63 | 1 | 1 | 70
18 | 18 | 24 | 63 | 2 | 2 | 80
19 | 18 | 25 | 61 | 1 | 1 | 25
20 | 18 | 25 | 61 | 2 | 2 | 25
21 | 18 | 25 | 62 | 1 | 1 | 25
22 | 18 | 25 | 62 | 2 | 2 | 73
23 | 18 | 25 | 63 | 1 | 1 | 70
24 | 18 | 25 | 63 | 2 | 2 | 80
25 | 17 | null | 61 | 1 | 1 | 25
26 | 17 | null | 61 | 2 | 2 | 25
27 | 17 | null | 62 | 1 | 1 | 25
28 | 17 | null | 62 | 2 | 2 | 73
29 | 17 | null | 63 | 1 | 1 | 70
30 | 17 | null | 63 | 2 | 2 | 80
31 | 19 | null | 61 | 1 | 1 | 25
32 | 19 | null | 61 | 2 | 2 | 25
33 | 19 | null | 62 | 1 | 1 | 25
34 | 19 | null | 62 | 2 | 2 | 73
35 | 19 | null | 63 | 1 | 1 | 70
36 | 19 | null | 63 | 2 | 2 | 80
The first layer output are something like this, getting the total A, B, C ,D.
Total are should be display like
(criteria 16 has two sub-criterias 22, 23 , that means it will be x2)
con_num | contestant_name | 16_judge_61 | 16_judge_62 | 16_judge_63 | total a
1 | john | 50 | 25 | 140 | 215
2 | sy | 50 | 146 | 160 | 365
Table right above, John has got a total of 215 in Criteria number 16 (crit_id 16). As well as sy has got a total of 365 in criteria number 16.
So, i have 4 criteria in my table 16,17,18,19. This is my problem, that means i need to do query one by one to get each total output and that would be like
con_num | contestant_name | 17_judge_61 | 17_judge_62 | 17_judge_63 | total b
1 | john | 25 | 25 | 70 | 120
2 | sy | 25 | 73 | 80 | 178
(criteria 18 has a sub criteria 24,25 that means it will x2)
con_num | contestant_name | 18_judge_61 | 18_judge_62 | 18_judge_63 | total c
1 | john | 50 | 50 | 140 | 240
2 | sy | 50 | 146 | 160 | 356
con_num | contestant_name | 19_judge_61 | 19_judge_62 | 19_judge_63 | total d
1 | john | 25 | 25 | 70 | 120
2 | sy | 25 | 73 | 80 | 178
I need to do that in one query, I can do only if one by one getting total A, B C. But i need a one query that execute this kind of output. How can i achieve this output?
The total_a, b , c, d are equivalent to crit_id 16, 17, 18, 19
con_num | contestant_name | 16total_a | 17total_b | 18total_c | 19total_d | Grand_total
1 | john | 215 | 120 | 240 | 120 | 695
2 | jy | 365 | 178 | 356 | 178 | 1077
This query, I'm still learning about the logic
SELECT DISTINCT(a.contestant_number) as con_num, a.contestant_name,
//Getting first the sum of total a, Notice criteria 16 has a sub criteria 22, 23
SUM(CASE WHEN s.crit_id='16' AND s.sub_crit_id = 22 AND s.judge_id='61' THEN s.score END) as 16_judge_61,
SUM(CASE WHEN s.crit_id='16' AND s.sub_crit_id = 22 AND s.judge_id='62' THEN s.score END) as 16_judge_62,
SUM(CASE WHEN s.crit_id='16' AND s.sub_crit_id = 22 AND s.judge_id='63' THEN s.score END) as 16_judge_63,
SUM(CASE WHEN s.crit_id='16' AND s.sub_crit_id = 23 AND s.judge_id='61' THEN s.score END) as 16_judge_61,
SUM(CASE WHEN s.crit_id='16' AND s.sub_crit_id = 23 AND s.judge_id='62' THEN s.score END) as 16_judge_62,
SUM(CASE WHEN s.crit_id='16' AND s.sub_crit_id = 23 AND s.judge_id='63' THEN s.score END) as 16_judge_63,
SUM(CASE WHEN s.crit_id='16' AND s.judge_id in (61, 62, 63) THEN s.score END) as 'total a'
//Criteria 17 has no sub criteria
SUM(CASE WHEN s.crit_id='17' AND s.judge_id='61' THEN s.score END) as 16_judge_61,
SUM(CASE WHEN s.crit_id='17' AND s.judge_id='62' THEN s.score END) as 16_judge_62,
SUM(CASE WHEN s.crit_id='17' AND s.judge_id='63' THEN s.score END) as 16_judge_63,
SUM(CASE WHEN s.crit_id='17' AND s.judge_id in (61, 62, 63) THEN s.score END) as 'total b'
//And iterate again for the 2 more criteria
//
FROM tbl_score s
INNER JOIN tbl_contestant a ON s.contestant_number = a.contestant_number
INNER JOIN tbl_judges j ON j.judge_id = s.judge_id
WHERE c.gender = 'male' and c.con_id = s.con_id
GROUP BY s.contestant_number
ORDER By `Grand toal' DESC";
http://sqlfiddle.com/#!9/cfe90/1
Getting the sum of only one total
http://sqlfiddle.com/#!9/9efa5/1
Put your query in a subquery, and then add together the columns to get the grand total.
SELECT x.*, `total a` + `total b` + `total c` AS `Grand Total`
FROM (put your query here) AS x
Currently I am developing a system to support a competition. In this competition there are 11 judges that give a grade to the participant. This grade is stored in a table per judge. With the following Select statement I retrieve the total score from the MySQL database (and also some inner joins to select other information from other tables).
Now I want to have ranking in this system, where also ex aequo is taken into account. I have tried several mysql solutions from this forum. But somehow the statement is always incorrect. Hopefully, someone can help me.
SELECT optreden.id, optreden.wedstrijd, optreden.jaartal,
liedje.titel, club.volledige_clubnaam,
(SELECT SUM(score.score_lied) FROM score WHERE score.optreden=optreden.id) AS score
FROM optreden
INNER JOIN liedje ON optreden.liedje=liedje.id
INNER JOIN club ON liedje.uitvoerende_club=club.id
WHERE optreden.wedstrijd="voorselectie" AND optreden.jaartal=2014
GROUP BY optreden.id
ORDER BY score_lied DESC
With this query, I get the following result:
+----+--------------+------+----------+--------------+------+
| id | Competition | Year | Title | Artist (club)| Score|
+----+--------------+------+----------+--------------+------+
| 12 | voorselectie | 2014 | Song 1 | Club 1 | 792 |
| 16 | voorselectie | 2014 | Song 2 | Club 2 | 600 |
| 10 | voorselectie | 2014 | Song 3 | Club 3 | 600 |
| 11 | voorselectie | 2014 | Song 3 | Club 3 | 500 |
| 12 | voorselectie | 2014 | Song 3 | Club 3 | 400 |
The query fetches information from the following tables:
Score: in this table the scores given by the 11 judges is stored as
line-items (result is given below);
Optreden: in this table the information from the club and the song is linked;
Club: information from the club,
such as name;
Liedje: information about the song, performed by the
club.
All the tables are linked by id's. In the result, there should come a column, with the ranking of the club.
The result from the table score is as follows:
+----+----+--------+----+
| ID | Pid| Userid | 85 |
+----+----+--------+----+
| 1 | 12 | 444 | 85 |
| 12 | 12 | 454 | 92 |
| 13 | 12 | 445 | 87 |
| 14 | 12 | 446 | 56 |
| 15 | 12 | 447 | 81 |
| 16 | 12 | 448 | 78 |
| 17 | 12 | 449 | 55 |
| 18 | 12 | 450 | 69 |
| 19 | 12 | 451 | 88 |
| 20 | 12 | 452 | 69 |
| 21 | 12 | 453 | 32 |
+----+----+--------+----+
Where the columns represent the following:
- ID: the id of the score in the table;
- Pid: the id of the performance (with this performing club and song are linked);
- Userid: the userid of the 11 judges;
- Score: the score given by each judge.
The end result should be as follows:
+----+--------------+------+----------+--------------+------+------+
| id | Competition | Year | Title | Artist (club)| Score| Rank |
+----+--------------+------+----------+--------------+------+------+
| 12 | voorselectie | 2014 | Song 1 | Club 1 | 792 | 1 |
| 16 | voorselectie | 2014 | Song 2 | Club 2 | 600 | 2 |
| 10 | voorselectie | 2014 | Song 3 | Club 3 | 600 | 2 |
| 11 | voorselectie | 2014 | Song 3 | Club 3 | 500 | 4 |
| 12 | voorselectie | 2014 | Song 3 | Club 3 | 400 | 5 |
I have tried the solution from Neville before and now again. I have rewritten the SQL statement as follows:
SELECT optreden.id, optreden.wedstrijd, optreden.jaartal,
liedje.titel, club.volledige_clubnaam,
(SELECT SUM(score.score_lied) FROM score WHERE score.optreden=optreden.id) AS score, CASE
WHEN #prev_value = score THEN #rank_count
WHEN #prev_value := score THEN #rank_count := #rank_count + 1
END AS rank,
FROM optreden
INNER JOIN liedje ON optreden.liedje=liedje.id
INNER JOIN club ON liedje.uitvoerende_club=club.id
WHERE optreden.wedstrijd="voorselectie" AND optreden.jaartal=2014
GROUP BY optreden.id
ORDER BY score_lied DESC
Here I get the error: Unknown column 'score' in 'field list'..
It seems that you are getting this error simply because there is no field score... I have extracted your inner SELECT into a JOIN so the real field can be used directly. (Not tested though, sorry)
SELECT optreden.id, optreden.wedstrijd, optreden.jaartal,
liedje.titel, club.volledige_clubnaam,
SUM(score.score_lied) AS score, CASE
WHEN #prev_value = SUM(score.score_lied) THEN #rank_count
WHEN #prev_value := SUM(score.score_lied) THEN #rank_count := #rank_count + 1
END AS rank,
FROM optreden
INNER JOIN liedje ON optreden.liedje=liedje.id
INNER JOIN club ON liedje.uitvoerende_club=club.id
LEFT JOIN score ON score.optreden=optreden.id
WHERE optreden.wedstrijd="voorselectie" AND optreden.jaartal=2014
GROUP BY optreden.id
ORDER BY score_lied DESC
Please note that you might face another little problem with this kind of ranking: Normally, when two entities end up on the same rank, the next rank is not given to the next person. Here's what I mean with an example, with two persons ranking in 3:
1, 2, 3, 3, 5
But in your code, it will give:
1, 2, 3, 3, 4
I hope this helps.
I have tried several things. However, I had forgotten to tell you one important feature I was gonna use. The ranking of the clubs should be presented through a presentation on a big screen. Therefor the MySQL code changed a little.
I have added a support table to my database. In this support table the sum of the scores is recorded with a INSERT INTO...SELECT statement.
When this insert is done. An update script is launched which makes the ranking in the table and also makes a correct calculation for ex aequo.
Here's the update statement:
SET #rank=0, #last_score = null, #tie_build_up = 0;
UPDATE ranking_voorselectie_lied
SET rank= #rank:= if(#last_score = totaal_score_lied, #rank, #rank+#tie_build_up+1),
tie_build_up= #tie_build_up:= if(#last_score = totaal_score_lied, #tie_build_up+1, 0),
last_score= #last_score:= totaal_score_lied
WHERE wedstrijd="voorselectie" AND jaar=2014
ORDER BY totaal_score_lied DESC;
This gives me the following result:
+--------------+------+----------+-------------------+------+-----+------------+
| Wedstrijd | Jaar | Optreden | totaal_score_lied | Rank | Tie | last_score |
+--------------+------+----------+-------------------+------+-----+------------+
| voorselectie | 2014 | 12 | 792 | 1 | 0 | 792 |
| voorselectie | 2014 | 16 | 82 | 2 | 0 | 82 |
| voorselectie | 2014 | 10 | 73 | 3 | 0 | 73 |
| voorselectie | 2014 | 15 | 51 | 4 | 0 | 51 |
| voorselectie | 2014 | 3 | 50 | 5 | 0 | 50 |
| voorselectie | 2014 | 11 | 42 | 6 | 0 | 42 |
| voorselectie | 2014 | 13 | 38 | 7 | 0 | 38 |
| voorselectie | 2014 | 8 | 38 | 7 | 1 | 38 |
| voorselectie | 2014 | 14 | 37 | 9 | 0 | 37 |
| voorselectie | 2014 | 5 | 35 | 10 | 0 | 35 |
| voorselectie | 2014 | 4 | 33 | 11 | 0 | 33 |
| voorselectie | 2014 | 7 | 25 | 12 | 0 | 25 |
| voorselectie | 2014 | 9 | 23 | 13 | 0 | 23 |
+--------------+------+----------+-------------------+------+-----+------------+
---------------------------------------------------------------------
id | stid | Subject | Total_cumulative | Year |
----------------------------------------------------------------------
1 | 23 | English | 40 | 2014/2015
2 | 1 | English | 29 | 2014/2015
3 | 13 | Maths | 40 | 2014/2015
4 | 4 | Physics | 60 | 2014/2015
5 | 13 | Commerce | 40 | 2014/2015
6 | 1 | Biology | 89 | 2014/2015
7 | 13 | English | 29 | 2014/2015
8 | 13 | Agric | 60 | 2014/2015
Now I have a query that gets all of a particular students results as follow
SELECT * FROM results where stid='13' AND year='2014/2015'
ORDER BY subject ASC LIMIT 20
and I have the following result
---------------------------------------------------------------------
id | stid | Subject | Total_cumulative | Year |
----------------------------------------------------------------------
3 | 13 | Maths | 40 | 2014/2015
5 | 13 | Commerce | 40 | 2014/2015
7 | 13 | English | 89 | 2014/2015
8 | 13 | Agric | 60 | 2014/2015
But my aim is to get the particular students rank in each subject and I have a sub query inside my the while loop of my first sql statement as follow
SELECT rank_number, id, name, total_cumulative
FROM ( SELECT id, name, total_cumulative, #rank:=#rank+1 AS rank_number FROM
(SELECT pl.id, pl.name,SUM(en.total_cumulative) AS total_cumulative
FROM students pl JOIN results en ON pl.id = en.stid
WHERE en.subject = '$subject' AND en.year='$year'
GROUP BY pl.id ORDER BY total_cumulative DESC ) AS rankings,
(SELECT #rank:=0) AS r ) AS overall_rankings
WHERE id = '13'
LIMIT 0, 1";
after that I have the following result
----------------------------------------------------------------------------
id | stid | Subject | Total_cumulative | Year | Rank
----------------------------------------------------------------------------
3 | 13 | Maths | 40 | 2014/2015 | 1
5 | 13 | Commerce | 40 | 2014/2015 | 2
7 | 13 | English | 29 | 2014/2015 | 3
8 | 13 | Agric | 60 | 2014/2015 | 1
but I want the query to check for ties and give the results in the following order
----------------------------------------------------------------------------
id | stid | Subject | Total_cumulative | Year | Rank
----------------------------------------------------------------------------
3 | 13 | Maths | 40 | 2014/2015 | 1
5 | 13 | Commerce | 40 | 2014/2015 | 2
7 | 13 | English | 29 | 2014/2015 | 2
8 | 13 | Agric | 60 | 2014/2015 | 1
Please help me I am a newbies in mysql programming
I am using the query to find the rank of a user in a given test id, and this gives me rank for just one test at a time and I have to use foreach to get the test rank of all the test.
SELECT * , t.UserRank
FROM (
SELECT * , (
#rownum := #rownum +1
)UserRank
FROM User_Date_Table, (
SELECT #rownum :=0
)t
WHERE my_test_id = '$test_id'
ORDER BY test_score DESC
)t
WHERE user_id = '$my_user_id'
Can a query be generated which can give me user rank for all the test taken by user in single query as this will reduced the db hitting multiple times.
I have to find the all the ranks of user with Test_Type_Id = $my_test_type_id(say), joining a.id with b.my_test_id for a user with user_id = $my_user_id(say)
TABLE STRUCTURE
My_Test_Table (a)
id | name | Test_Type_Id
----------------------------------------------
1 | name_1 | 1
2 | name_2 | 1
3 | name_3 | 2
4 | name_4 | 1
5 | name_5 | 1
6 | name_6 | 2
7 | name_7 | 1
8 | name_8 | 2
9 | name_9 | 1
User_Date_Table (b)
id | my_test_id | user_id | test_score
---------------------------------------------------------
1 | 1 | 32 | 34
2 | 1 | 2 | 345
3 | 2 | 4 | 654
4 | 1 | 76 | 87
5 | 3 | 23 | 453
6 | 2 | 5 | 45
7 | 1 | 43 | 22
8 | 2 | 7 | 987
9 | 2 | 32 | 45
10 | 1 | 1 | 12
11 | 1 | 9 | 35
12 | 3 | 67 | 765
13 | 1 | 88 | 23
14 | 2 | 34 | 76
15 | 3 | 1 | 765
16 | 2 | 54 | 45
17 | 1 | 10 | 87
18 | 1 | 23 | 3
19 | 3 | 44 | 345
20 | 1 | 55 | 232
21 | 2 | 28 | 234
22 | 3 | 32 | 231
Simplest is probably to just remove the user variable for ranking and just do it using a subquery;
SELECT *, (SELECT COUNT(*)+1
FROM User_Date_Table b
WHERE a.my_test_id = b.my_test_id
AND a.test_score < b.test_score) userrank
FROM User_Date_Table a
WHERE user_id = '1';
An SQLfiddle to test with.
SELECT * , t.UserRank
FROM (
SELECT * , #rownum :=if(#user!=user_id,0, #rownum +1),#user:=user_id UserRank
FROM User_Date_Table , (SELECT #rownum :=0,#user :=-1) t
ORDER BY my_test_id ,test_score DESC
)t
WHERE user_id = '$my_user_id'
We introducean additional variable #user to reset #rownum on user_id change
I have 3 Tables:
user_subscriptions
ID | SUB_ID | TYPE | Type 1 = scripts | Type 2 = packages
1 | 1 | 1 |
2 | 2 | 1 |
3 | 3 | 1 |
4 | 4 | 1 |
5 | 1 | 2 |
6 | 2 | 2 |
7 | 3 | 2 |
8 | 4 | 2 |
9 | 5 | 1 |
10 | 6 | 2 |
11 | 7 | 1 |
12 | 8 | 1 |
13 | 9 | 2 |
scripts
ID | AUTHOR_ID |
1 | 58 |
2 | 58 |
3 | 58 |
4 | 58 |
5 | 52 |
6 | 53 |
7 | 58 |
8 | 55 |
9 | 58 |
10 | 56 |
packages
ID | AUTHOR_ID |
1 | 58 |
2 | 58 |
3 | 58 |
4 | 58 |
5 | 56 |
6 | 57 |
7 | 58 |
8 | 58 |
9 | 56 |
10 | 58 |
In the 'user_subscriptions' table, the 'SUB_ID' column corresponds with a script ID or package ID, depending on the type that is set for that subscription.
My goal is to query for the total number of subscriptions to scripts & packages created by a particular author. Author 58 has created 6 Scripts and 7 Packages (total 13) but there are only 9 user subscriptions that are related to author_id 58.
I am having trouble writing a query that will return the user_subscriptions pertaining to author_id 58.
Any and all assistance is greatly appreciated. I am making this query from PHP and will likely use mysqli_num_rows in order to get the count that I need. Thanks again!
SELECT author_id
, COUNT(*) total
FROM
( SELECT id, author_id FROM scripts
UNION ALL
SELECT id, author_id FROM packages
) x
GROUP
BY author_id;
Note that this solution has fewer words in it than webnoobs comment above ;-)