Combine separate HTML and PHP MYSQL form into one file - php

Question

The reasons behind my needing this are complicated but I have a currently working HTML form that inserts a row into my MYSQL database. However... I need to combine the two separate processes into one HTML file but after many attempts at arranging the code cannot come to a working solution. Hopefully someone can point me in the right direction.
Here is the HTML file:
<form method="post" action="process.php">
<input type="text" name="id" placeholder="Enter ID" /><br />
<input type="hidden" name="user_text" id="hiddenField" value="x" /><br />
<input type="submit" value="Submit" />
</form>
Here is the related process.php file:
<?php
if ($_SERVER["REQUEST_METHOD"] == "POST") {
//mysql credentials
$mysql_host = "localhost";
$mysql_username = "*";
$mysql_password = "*";
$mysql_database = "*";
$u_name = $_POST["id"];
$u_text = $_POST["user_text"];
if (empty($u_name)){
die("Please enter your id");
}
//Open a new connection to the MySQL server
$mysqli = new mysqli($mysql_host, $mysql_username, $mysql_password, $mysql_database);
//Output any connection error
if ($mysqli->connect_error) {
die('Error : ('. $mysqli->connect_errno .') '. $mysqli->connect_error);
}
$statement = $mysqli->prepare("INSERT INTO users_data (contractor_id, status) VALUES(?, ?)"); //prepare sql insert query
$statement->bind_param('ss', $u_name, $u_text); //bind values and execute insert query
}
?>
I know this isn't the right way to do things but it isn't for a public site, more a personal logging project. Thank you in advanced!

Answer 1

You can simply have a file like this:
<?php
if ($_SERVER["REQUEST_METHOD"] == "POST") {
process();
}
else {
show_form();
}
function show_form () {
?>
<form method="post">
<input type="text" name="id" placeholder="Enter ID" /><br />
<input type="hidden" name="user_text" id="hiddenField" value="x" /><br />
<input type="submit" value="Submit" />
</form>
<?php
}
function process () {
//mysql credentials
$mysql_host = "localhost";
$mysql_username = "*";
$mysql_password = "*";
$mysql_database = "*";
$u_name = $_POST["id"];
$u_text = $_POST["user_text"];
if (empty($u_name)){
die("Please enter your id");
}
//Open a new connection to the MySQL server
$mysqli = new mysqli($mysql_host, $mysql_username, $mysql_password, $mysql_database);
//Output any connection error
if ($mysqli->connect_error) {
die('Error : ('. $mysqli->connect_errno .') '. $mysqli->connect_error);
}
$statement = $mysqli->prepare("INSERT INTO users_data (contractor_id, status) VALUES(?, ?)"); //prepare sql insert query
$statement->bind_param('ss', $u_name, $u_text); //bind values and execute insert query
}
If you do not set theaction for form, by default, it submits to itself