Image is always NULL on upload form - php

I'm trying to upload image on user registration via ajax. This is how it's look like the form + some fields for name, password and email which are working good.
<form method="post" class="registerForm" enctype="multipart/form-data" id="login-form">
<div class="form-group">
<label><b>Profile Image <span class="required">*</span></b></label>
<input accept="image/*" type="file" id="picture" name="picture" required>
</div>
<div class="clearfix">
<button type="submit" id="login" class="signupbtn">Sign Up</button>
</div>
</form>
I have found on another thread here on SO that I need to put this on my ajax script
var data = $("#login-form").serialize();
var form = new FormData(document.getElementById('picture'));
//append files
var file = document.getElementById('picture').files[0];
if (file) {
form.append('picture', file);
}
And this is whole ajax
function submitForm()
{
var data = $("#login-form").serialize();
var form = new FormData(document.getElementById('picture'));
//append files
var file = document.getElementById('picture').files[0];
if (file) {
form.append('picture', file);
}
$.ajax({
type : 'POST',
url : 'registration.php',
data : data,
beforeSend: function()
{
$("#error").fadeOut();
$("#login").html('<span class="glyphicon glyphicon-transfer"></span> sending ...');
},
success : function(data)
{
if(data=="registered")
{
}
}
});
return false;
}
And the server side for the picture part and the query
if(!empty($_FILES['picture']) && $_FILES['picture']['size'] >0 ){
$profilePic = $randomString. basename($_FILES['picture']['name']);
$uploadfile = $uploaddir .$randomString. basename($_FILES['picture']['name']);
if (move_uploaded_file($_FILES['picture']['tmp_name'], $uploadfile)) {
} else {
$error = "error\n";
}
}else{
$error ='Please add your Picture!';
}
var_dump($_FILES['picture']);
try
{
$stmt = $db_con->prepare("SELECT * FROM users WHERE email=:email");
$stmt->execute(array(":email"=>$email));
$count = $stmt->rowCount();
if($count==0){
$stmt = $db_con->prepare("INSERT INTO users (picture) VALUES (:picture)");
$stmt->bindParam(":picture",$profilePic);
if($stmt->execute()) {
echo "registered";
}
else { echo "Query could not execute !"; }
}
else{ echo "1"; }
}
catch(PDOException $e){
echo $e->getMessage();
}
I've removed other fields in order keep the code simple as much as possible. All fields got inserted and saved in database except the image name.
What can be the problem? No errors at all. I've got registered on the console and NULL for var_dump($_FILES['picture'])

jQuery processes the data as a string if you don't use proccessData: false. Bellow code will work just fine. Also included some comments in code
$(document).ready(function (e){
$("#login-form").on('submit',(function(e){
e.preventDefault();
$.ajax({
url: "registration.php",
type: "POST",
data: new FormData(this), // Data sent to server
contentType: false, // The content type used when sending data to the server.
cache: false, // To unable request pages to be cached
processData:false, // To send DOMDocument or non processed data file it is set to false
success: function(data){
if(data=="registered"){}
},
error: function(){}
});
}));
});

You must set the contentType option to false, so jQuery won't add a Content-Type heade also set processData flag set to false otherwise jQuery will try to convert your FormData into a string, which will fail.
So ajax code will look like
$(".signupbtn").click(function(e){
e.preventDefault();
var form = new FormData(document.getElementById('picture'));
//append files
var file = document.getElementById('picture').files[0];
if (file) {
form.append('picture', file);
}
$.ajax({
type : 'POST',
url : 'registration.php',
data : form,
contentType: false,
processData: false,
success : function(data){}
});
});

Related

cakephp 2.0 upload file using jQuery Ajax with parameters - still can't get any answer

I am still can't get any answer of this question. Could any one help me out this issue.
I am trying to send an email with attachment to select person. So, I have filtered the data from database and send email with attachment to selected users.
I have gone through the below answer:
How can I upload files asynchronously?
I have tried the below code of JQuery, Ajax, Controller Action:
<script type="text/javascript">
function SendEmail(){
var checked=0;
jQuery("#action_row").val('delete');
var filename = jQuery("#UserPdf").val();
var audits = '';
$('.checkboxes:checked').each(function(){
checked=1;
audits += this.value+',';
});
var auditsval = audits.slice(0, -1);
//alert(auditsval);
if(checked==1){
var con = confirm('Are you sure you want to send email?');
if(con){
jQuery.ajax({
type: "POST",
url: CommanPath.basePath+'admin/users/send_email',
enctype: 'multipart/form-data',
data: {
file: filename,
ids: auditsval,
},
success: function (data) {
alert("Email sent to selected users ");
}
});
}
}else{
alert("Please select atleast one to send email");
}
}
</script>
UsersCOntroller.php
public function admin_send_email($id = null){
//echo 'here'; die;
$this->layout = 'ajax';
echo '<pre>'; print_r($_FILES); die;
if(isset($this->params['data']['file']) && $this->params['data']['file']){
$filename = time().$this->params['data']['file'];
move_uploaded_file($_FILES['data']['tmp_name']['file']['name'], WWW_ROOT.'uploads/sellingtools/' . $filename);
}
$userids = explode(",", $this->params['data']['ids']);
echo '<pre>'; print_r($userids); die;
}
When I am trying to get uploaded file name, I am getting only file name not getting the tmp_name.
Anyone can let me know how I can get the tmp_name and move file to exact path.
Please help.
You need to use Form and FormData as below
HTML:
<form id="myForm" method="post" enctype="multipart/form-data">
<input type="file" name="file">
</form>
JQUERY:
function SendEmail(){
var checked=0;
jQuery("#action_row").val('delete');
var filename = jQuery("#UserPdf").val();
var audits = '';
$('.checkboxes:checked').each(function(){
checked=1;
audits += this.value+',';
});
var auditsval = audits.slice(0, -1);
//alert(auditsval);
var formdata = new FormData($('#myForm')[0]); /////formdata object
formdata.append('ids',auditsval); /// add additional fields
if(checked==1){
var con = confirm('Are you sure you want to send email?');
if(con){
jQuery.ajax({
type: "POST",
url: CommanPath.basePath+'admin/users/send_email',
processData: false, ///required to upload file
contentType: false, /// required
data: formdata, /// send form data
success: function (data) {
alert("Email sent to selected users ");
}
});
}
}else{
alert("Please select atleast one to send email");
}
}

PHP: Unable to insert a doc file into mysql database [duplicate]

Can I use the following jQuery code to perform file upload using POST method of an ajax request ?
$.ajax({
type: "POST",
timeout: 50000,
url: url,
data: dataString,
success: function (data) {
alert('success');
return false;
}
});
If it is possible, do I need to fill data part? Is it the correct way? I only POST the file to the server side.
I have been googling around, but what I found was a plugin while in my plan I do not want to use it. At least for the moment.
File upload is not possible through AJAX.
You can upload file, without refreshing page by using IFrame.
You can check further details here.
UPDATE
With XHR2, File upload through AJAX is supported. E.g. through FormData object, but unfortunately it is not supported by all/old browsers.
FormData support starts from following desktop browsers versions.
IE 10+
Firefox 4.0+
Chrome 7+
Safari 5+
Opera 12+
For more detail, see MDN link.
Iframes is no longer needed for uploading files through ajax. I've recently done it by myself. Check out these pages:
Using HTML5 file uploads with AJAX and jQuery
http://dev.w3.org/2006/webapi/FileAPI/#FileReader-interface
Updated the answer and cleaned it up. Use the getSize function to check size or use getType function to check types.
Added progressbar html and css code.
var Upload = function (file) {
this.file = file;
};
Upload.prototype.getType = function() {
return this.file.type;
};
Upload.prototype.getSize = function() {
return this.file.size;
};
Upload.prototype.getName = function() {
return this.file.name;
};
Upload.prototype.doUpload = function () {
var that = this;
var formData = new FormData();
// add assoc key values, this will be posts values
formData.append("file", this.file, this.getName());
formData.append("upload_file", true);
$.ajax({
type: "POST",
url: "script",
xhr: function () {
var myXhr = $.ajaxSettings.xhr();
if (myXhr.upload) {
myXhr.upload.addEventListener('progress', that.progressHandling, false);
}
return myXhr;
},
success: function (data) {
// your callback here
},
error: function (error) {
// handle error
},
async: true,
data: formData,
cache: false,
contentType: false,
processData: false,
timeout: 60000
});
};
Upload.prototype.progressHandling = function (event) {
var percent = 0;
var position = event.loaded || event.position;
var total = event.total;
var progress_bar_id = "#progress-wrp";
if (event.lengthComputable) {
percent = Math.ceil(position / total * 100);
}
// update progressbars classes so it fits your code
$(progress_bar_id + " .progress-bar").css("width", +percent + "%");
$(progress_bar_id + " .status").text(percent + "%");
};
How to use the Upload class
//Change id to your id
$("#ingredient_file").on("change", function (e) {
var file = $(this)[0].files[0];
var upload = new Upload(file);
// maby check size or type here with upload.getSize() and upload.getType()
// execute upload
upload.doUpload();
});
Progressbar html code
<div id="progress-wrp">
<div class="progress-bar"></div>
<div class="status">0%</div>
</div>
Progressbar css code
#progress-wrp {
border: 1px solid #0099CC;
padding: 1px;
position: relative;
height: 30px;
border-radius: 3px;
margin: 10px;
text-align: left;
background: #fff;
box-shadow: inset 1px 3px 6px rgba(0, 0, 0, 0.12);
}
#progress-wrp .progress-bar {
height: 100%;
border-radius: 3px;
background-color: #f39ac7;
width: 0;
box-shadow: inset 1px 1px 10px rgba(0, 0, 0, 0.11);
}
#progress-wrp .status {
top: 3px;
left: 50%;
position: absolute;
display: inline-block;
color: #000000;
}
Ajax post and upload file is possible. I'm using jQuery $.ajax function to load my files. I tried to use the XHR object but could not get results on the server side with PHP.
var formData = new FormData();
formData.append('file', $('#file')[0].files[0]);
$.ajax({
url : 'upload.php',
type : 'POST',
data : formData,
processData: false, // tell jQuery not to process the data
contentType: false, // tell jQuery not to set contentType
success : function(data) {
console.log(data);
alert(data);
}
});
As you can see, you must create a FormData object, empty or from (serialized? - $('#yourForm').serialize()) existing form, and then attach the input file.
Here is more information:
- How to upload a file using jQuery.ajax and FormData
- Uploading files via jQuery, object FormData is provided and no file name, GET request
For the PHP process you can use something like this:
//print_r($_FILES);
$fileName = $_FILES['file']['name'];
$fileType = $_FILES['file']['type'];
$fileError = $_FILES['file']['error'];
$fileContent = file_get_contents($_FILES['file']['tmp_name']);
if($fileError == UPLOAD_ERR_OK){
//Processes your file here
}else{
switch($fileError){
case UPLOAD_ERR_INI_SIZE:
$message = 'Error al intentar subir un archivo que excede el tamaño permitido.';
break;
case UPLOAD_ERR_FORM_SIZE:
$message = 'Error al intentar subir un archivo que excede el tamaño permitido.';
break;
case UPLOAD_ERR_PARTIAL:
$message = 'Error: no terminó la acción de subir el archivo.';
break;
case UPLOAD_ERR_NO_FILE:
$message = 'Error: ningún archivo fue subido.';
break;
case UPLOAD_ERR_NO_TMP_DIR:
$message = 'Error: servidor no configurado para carga de archivos.';
break;
case UPLOAD_ERR_CANT_WRITE:
$message= 'Error: posible falla al grabar el archivo.';
break;
case UPLOAD_ERR_EXTENSION:
$message = 'Error: carga de archivo no completada.';
break;
default: $message = 'Error: carga de archivo no completada.';
break;
}
echo json_encode(array(
'error' => true,
'message' => $message
));
}
Simple Upload Form
<script>
//form Submit
$("form").submit(function(evt){
evt.preventDefault();
var formData = new FormData($(this)[0]);
$.ajax({
url: 'fileUpload',
type: 'POST',
data: formData,
async: false,
cache: false,
contentType: false,
enctype: 'multipart/form-data',
processData: false,
success: function (response) {
alert(response);
}
});
return false;
});
</script>
<!--Upload Form-->
<form>
<table>
<tr>
<td colspan="2">File Upload</td>
</tr>
<tr>
<th>Select File </th>
<td><input id="csv" name="csv" type="file" /></td>
</tr>
<tr>
<td colspan="2">
<input type="submit" value="submit"/>
</td>
</tr>
</table>
</form>
I'm pretty late for this but I was looking for an ajax based image uploading solution and the answer I was looking for was kinda scattered throughout this post. The solution I settled on involved the FormData object. I assembled a basic form of the code I put together. You can see it demonstrates how to add a custom field to the form with fd.append() as well as how to handle response data when the ajax request is done.
Upload html:
<!DOCTYPE html>
<html>
<head>
<title>Image Upload Form</title>
<script src="//code.jquery.com/jquery-1.9.1.js"></script>
<script type="text/javascript">
function submitForm() {
console.log("submit event");
var fd = new FormData(document.getElementById("fileinfo"));
fd.append("label", "WEBUPLOAD");
$.ajax({
url: "upload.php",
type: "POST",
data: fd,
processData: false, // tell jQuery not to process the data
contentType: false // tell jQuery not to set contentType
}).done(function( data ) {
console.log("PHP Output:");
console.log( data );
});
return false;
}
</script>
</head>
<body>
<form method="post" id="fileinfo" name="fileinfo" onsubmit="return submitForm();">
<label>Select a file:</label><br>
<input type="file" name="file" required />
<input type="submit" value="Upload" />
</form>
<div id="output"></div>
</body>
</html>
In case you are working with php here's a way to handle the upload that includes making use of both of the custom fields demonstrated in the above html.
Upload.php
<?php
if ($_POST["label"]) {
$label = $_POST["label"];
}
$allowedExts = array("gif", "jpeg", "jpg", "png");
$temp = explode(".", $_FILES["file"]["name"]);
$extension = end($temp);
if ((($_FILES["file"]["type"] == "image/gif")
|| ($_FILES["file"]["type"] == "image/jpeg")
|| ($_FILES["file"]["type"] == "image/jpg")
|| ($_FILES["file"]["type"] == "image/pjpeg")
|| ($_FILES["file"]["type"] == "image/x-png")
|| ($_FILES["file"]["type"] == "image/png"))
&& ($_FILES["file"]["size"] < 200000)
&& in_array($extension, $allowedExts)) {
if ($_FILES["file"]["error"] > 0) {
echo "Return Code: " . $_FILES["file"]["error"] . "<br>";
} else {
$filename = $label.$_FILES["file"]["name"];
echo "Upload: " . $_FILES["file"]["name"] . "<br>";
echo "Type: " . $_FILES["file"]["type"] . "<br>";
echo "Size: " . ($_FILES["file"]["size"] / 1024) . " kB<br>";
echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br>";
if (file_exists("uploads/" . $filename)) {
echo $filename . " already exists. ";
} else {
move_uploaded_file($_FILES["file"]["tmp_name"],
"uploads/" . $filename);
echo "Stored in: " . "uploads/" . $filename;
}
}
} else {
echo "Invalid file";
}
?>
An AJAX upload is indeed possible with XMLHttpRequest(). No iframes necessary. Upload progress can be shown.
For details see: Answer https://stackoverflow.com/a/4943774/873282 to question jQuery Upload Progress and AJAX file upload.
Here's how I got this working:
HTML
<input type="file" id="file">
<button id='process-file-button'>Process</button>
JS
$('#process-file-button').on('click', function (e) {
let files = new FormData(), // you can consider this as 'data bag'
url = 'yourUrl';
files.append('fileName', $('#file')[0].files[0]); // append selected file to the bag named 'file'
$.ajax({
type: 'post',
url: url,
processData: false,
contentType: false,
data: files,
success: function (response) {
console.log(response);
},
error: function (err) {
console.log(err);
}
});
});
PHP
if (isset($_FILES) && !empty($_FILES)) {
$file = $_FILES['fileName'];
$name = $file['name'];
$path = $file['tmp_name'];
// process your file
}
Using pure js it is easier
async function saveFile(inp)
{
let formData = new FormData();
formData.append("file", inp.files[0]);
await fetch('/upload/somedata', {method: "POST", body: formData});
alert('success');
}
<input type="file" onchange="saveFile(this)" >
In server side you can read original file name (and other info) which is automatically included to request.
You do NOT need to set header "Content-Type" to "multipart/form-data" browser will set it automatically
This solutions should work on all major browsers.
Here is more developed snippet with error handling, timeout and additional json sending
async function saveFile(inp)
{
let user = { name:'john', age:34 };
let formData = new FormData();
let photo = inp.files[0];
formData.append("photo", photo);
formData.append("user", JSON.stringify(user));
const ctrl = new AbortController() // timeout
setTimeout(() => ctrl.abort(), 50000);
try {
let r = await fetch('/upload/image',
{method: "POST", body: formData, signal: ctrl.signal});
console.log('HTTP response code:',r.status);
alert('success');
} catch(e) {
console.log('Huston we have problem...:', e);
}
}
<input type="file" onchange="saveFile(this)" >
<br><br>
Before selecting the file Open chrome console > network tab to see the request details.
<br><br>
<small>Because in this example we send request to https://stacksnippets.net/upload/image the response code will be 404 ofcourse...</small>
In case you want to do it like that:
$.upload( form.action, new FormData( myForm))
.progress( function( progressEvent, upload) {
if( progressEvent.lengthComputable) {
var percent = Math.round( progressEvent.loaded * 100 / progressEvent.total) + '%';
if( upload) {
console.log( percent + ' uploaded');
} else {
console.log( percent + ' downloaded');
}
}
})
.done( function() {
console.log( 'Finished upload');
});
than
https://github.com/lgersman/jquery.orangevolt-ampere/blob/master/src/jquery.upload.js
might be your solution.
Use FormData. It works really well :-) ...
var jform = new FormData();
jform.append('user',$('#user').val());
jform.append('image',$('#image').get(0).files[0]); // Here's the important bit
$.ajax({
url: '/your-form-processing-page-url-here',
type: 'POST',
data: jform,
dataType: 'json',
mimeType: 'multipart/form-data', // this too
contentType: false,
cache: false,
processData: false,
success: function(data, status, jqXHR){
alert('Hooray! All is well.');
console.log(data);
console.log(status);
console.log(jqXHR);
},
error: function(jqXHR,status,error){
// Hopefully we should never reach here
console.log(jqXHR);
console.log(status);
console.log(error);
}
});
$("#submit_car").click(function() {
var formData = new FormData($('#car_cost_form')[0]);
$.ajax({
url: 'car_costs.php',
data: formData,
contentType: false,
processData: false,
cache: false,
type: 'POST',
success: function(data) {
// ...
},
});
});
edit: Note contentype and process data
You can simply use this to upload files via Ajax...... submit input cannot be outside form element :)
2019 update:
html
<form class="fr" method='POST' enctype="multipart/form-data"> {% csrf_token %}
<textarea name='text'>
<input name='example_image'>
<button type="submit">
</form>
js
$(document).on('submit', '.fr', function(){
$.ajax({
type: 'post',
url: url, <--- you insert proper URL path to call your views.py function here.
enctype: 'multipart/form-data',
processData: false,
contentType: false,
data: new FormData(this) ,
success: function(data) {
console.log(data);
}
});
return false;
});
views.py
form = ThisForm(request.POST, request.FILES)
if form.is_valid():
text = form.cleaned_data.get("text")
example_image = request.FILES['example_image']
Use a hidden iframe and set your form's target to that iframe's name. This way, when the form is submitted, only the iframe will be refreshed.
Have an event handler registered for the iframe's load event to parse the response.
I have handled these in a simple code. You can download a working demo from here
For your case, these very possible. I will take you step by step how you can upload a file to the server using AJAX jquery.
First let's us create an HTML file to add the following form file element as shown below.
<form action="" id="formContent" method="post" enctype="multipart/form-data" >
<input type="file" name="file" required id="upload">
<button class="submitI" >Upload Image</button>
</form>
Secondly create a jquery.js file and add the following code to handle our file submission to the server
$("#formContent").submit(function(e){
e.preventDefault();
var formdata = new FormData(this);
$.ajax({
url: "ajax_upload_image.php",
type: "POST",
data: formdata,
mimeTypes:"multipart/form-data",
contentType: false,
cache: false,
processData: false,
success: function(){
alert("file successfully submitted");
},error: function(){
alert("okey");
}
});
});
});
There you are done . View more
Using FormData is the way to go as indicated by many answers. here is a bit of code that works great for this purpose. I also agree with the comment of nesting ajax blocks to complete complex circumstances. By including e.PreventDefault(); in my experience makes the code more cross browser compatible.
$('#UploadB1').click(function(e){
e.preventDefault();
if (!fileupload.valid()) {
return false;
}
var myformData = new FormData();
myformData.append('file', $('#uploadFile')[0].files[0]);
$("#UpdateMessage5").html("Uploading file ....");
$("#UpdateMessage5").css("background","url(../include/images/loaderIcon.gif) no-repeat right");
myformData.append('mode', 'fileUpload');
myformData.append('myid', $('#myid').val());
myformData.append('type', $('#fileType').val());
//formData.append('myfile', file, file.name);
$.ajax({
url: 'include/fetch.php',
method: 'post',
processData: false,
contentType: false,
cache: false,
data: myformData,
enctype: 'multipart/form-data',
success: function(response){
$("#UpdateMessage5").html(response); //.delay(2000).hide(1);
$("#UpdateMessage5").css("background","");
console.log("file successfully submitted");
},error: function(){
console.log("not okay");
}
});
});
I have implemented a multiple file select with instant preview and upload after removing unwanted files from preview via ajax.
Detailed documentation can be found here: http://anasthecoder.blogspot.ae/2014/12/multi-file-select-preview-without.html
Demo: http://jsfiddle.net/anas/6v8Kz/7/embedded/result/
jsFiddle: http://jsfiddle.net/anas/6v8Kz/7/
Javascript:
$(document).ready(function(){
$('form').submit(function(ev){
$('.overlay').show();
$(window).scrollTop(0);
return upload_images_selected(ev, ev.target);
})
})
function add_new_file_uploader(addBtn) {
var currentRow = $(addBtn).parent().parent();
var newRow = $(currentRow).clone();
$(newRow).find('.previewImage, .imagePreviewTable').hide();
$(newRow).find('.removeButton').show();
$(newRow).find('table.imagePreviewTable').find('tr').remove();
$(newRow).find('input.multipleImageFileInput').val('');
$(addBtn).parent().parent().parent().append(newRow);
}
function remove_file_uploader(removeBtn) {
$(removeBtn).parent().parent().remove();
}
function show_image_preview(file_selector) {
//files selected using current file selector
var files = file_selector.files;
//Container of image previews
var imageContainer = $(file_selector).next('table.imagePreviewTable');
//Number of images selected
var number_of_images = files.length;
//Build image preview row
var imagePreviewRow = $('<tr class="imagePreviewRow_0"><td valign=top style="width: 510px;"></td>' +
'<td valign=top><input type="button" value="X" title="Remove Image" class="removeImageButton" imageIndex="0" onclick="remove_selected_image(this)" /></td>' +
'</tr> ');
//Add image preview row
$(imageContainer).html(imagePreviewRow);
if (number_of_images > 1) {
for (var i =1; i<number_of_images; i++) {
/**
*Generate class name of the respective image container appending index of selected images,
*sothat we can match images selected and the one which is previewed
*/
var newImagePreviewRow = $(imagePreviewRow).clone().removeClass('imagePreviewRow_0').addClass('imagePreviewRow_'+i);
$(newImagePreviewRow).find('input[type="button"]').attr('imageIndex', i);
$(imageContainer).append(newImagePreviewRow);
}
}
for (var i = 0; i < files.length; i++) {
var file = files[i];
/**
* Allow only images
*/
var imageType = /image.*/;
if (!file.type.match(imageType)) {
continue;
}
/**
* Create an image dom object dynamically
*/
var img = document.createElement("img");
/**
* Get preview area of the image
*/
var preview = $(imageContainer).find('tr.imagePreviewRow_'+i).find('td:first');
/**
* Append preview of selected image to the corresponding container
*/
preview.append(img);
/**
* Set style of appended preview(Can be done via css also)
*/
preview.find('img').addClass('previewImage').css({'max-width': '500px', 'max-height': '500px'});
/**
* Initialize file reader
*/
var reader = new FileReader();
/**
* Onload event of file reader assign target image to the preview
*/
reader.onload = (function(aImg) { return function(e) { aImg.src = e.target.result; }; })(img);
/**
* Initiate read
*/
reader.readAsDataURL(file);
}
/**
* Show preview
*/
$(imageContainer).show();
}
function remove_selected_image(close_button)
{
/**
* Remove this image from preview
*/
var imageIndex = $(close_button).attr('imageindex');
$(close_button).parents('.imagePreviewRow_' + imageIndex).remove();
}
function upload_images_selected(event, formObj)
{
event.preventDefault();
//Get number of images
var imageCount = $('.previewImage').length;
//Get all multi select inputs
var fileInputs = document.querySelectorAll('.multipleImageFileInput');
//Url where the image is to be uploaded
var url= "/upload-directory/";
//Get number of inputs
var number_of_inputs = $(fileInputs).length;
var inputCount = 0;
//Iterate through each file selector input
$(fileInputs).each(function(index, input){
fileList = input.files;
// Create a new FormData object.
var formData = new FormData();
//Extra parameters can be added to the form data object
formData.append('bulk_upload', '1');
formData.append('username', $('input[name="username"]').val());
//Iterate throug each images selected by each file selector and find if the image is present in the preview
for (var i = 0; i < fileList.length; i++) {
if ($(input).next('.imagePreviewTable').find('.imagePreviewRow_'+i).length != 0) {
var file = fileList[i];
// Check the file type.
if (!file.type.match('image.*')) {
continue;
}
// Add the file to the request.
formData.append('image_uploader_multiple[' +(inputCount++)+ ']', file, file.name);
}
}
// Set up the request.
var xhr = new XMLHttpRequest();
xhr.open('POST', url, true);
xhr.onload = function () {
if (xhr.status === 200) {
var jsonResponse = JSON.parse(xhr.responseText);
if (jsonResponse.status == 1) {
$(jsonResponse.file_info).each(function(){
//Iterate through response and find data corresponding to each file uploaded
var uploaded_file_name = this.original;
var saved_file_name = this.target;
var file_name_input = '<input type="hidden" class="image_name" name="image_names[]" value="' +saved_file_name+ '" />';
file_info_container.append(file_name_input);
imageCount--;
})
//Decrement count of inputs to find all images selected by all multi select are uploaded
number_of_inputs--;
if(number_of_inputs == 0) {
//All images selected by each file selector is uploaded
//Do necessary acteion post upload
$('.overlay').hide();
}
} else {
if (typeof jsonResponse.error_field_name != 'undefined') {
//Do appropriate error action
} else {
alert(jsonResponse.message);
}
$('.overlay').hide();
event.preventDefault();
return false;
}
} else {
/*alert('Something went wrong!');*/
$('.overlay').hide();
event.preventDefault();
}
};
xhr.send(formData);
})
return false;
}
Yes you can, just use javascript to get the file, making sure you read the file as a data URL. Parse out the stuff before base64 to actually get the base 64 encoded data and then if you are using php or really any back end language you can decode the base 64 data and save into a file like shown below
Javascript:
var reader = new FileReader();
reader.onloadend = function ()
{
dataToBeSent = reader.result.split("base64,")[1];
$.post(url, {data:dataToBeSent});
}
reader.readAsDataURL(this.files[0]);
PHP:
file_put_contents('my.pdf', base64_decode($_POST["data"]));
Of course you will probably want to do some validation like checking which file type you are dealing with and stuff like that but this is the idea.
To get all your form inputs, including the type="file" you need to use FormData object.
you will be able to see the formData content in the debugger -> network ->Headers after you will submit the form.
var url = "YOUR_URL";
var form = $('#YOUR_FORM_ID')[0];
var formData = new FormData(form);
$.ajax(url, {
method: 'post',
processData: false,
contentType: false,
data: formData
}).done(function(data){
if (data.success){
alert("Files uploaded");
} else {
alert("Error while uploading the files");
}
}).fail(function(data){
console.log(data);
alert("Error while uploading the files");
});
<html>
<head>
<title>Ajax file upload</title>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script>
$(document).ready(function (e) {
$("#uploadimage").on('submit', (function(e) {
e.preventDefault();
$.ajax({
url: "upload.php", // Url to which the request is send
type: "POST", // Type of request to be send, called as method
data: new FormData(this), // Data sent to server, a set of key/value pairs (i.e. form fields and values)
contentType: false, // The content type used when sending data to the server.
cache: false, // To unable request pages to be cached
processData:false, // To send DOMDocument or non processed data file it is set to false
success: function(data) // A function to be called if request succeeds
{
alert(data);
}
});
}));
</script>
</head>
<body>
<div class="main">
<h1>Ajax Image Upload</h1><br/>
<hr>
<form id="uploadimage" action="" method="post" enctype="multipart/form-data">
<div id="image_preview"><img id="previewing" src="noimage.png" /></div>
<hr id="line">
<div id="selectImage">
<label>Select Your Image</label><br/>
<input type="file" name="file" id="file" required />
<input type="submit" value="Upload" class="submit" />
</div>
</form>
</div>
</body>
</html>
to upload a file which is submitted by user as a part of form using jquery please follow the below code :
var formData = new FormData();
formData.append("userfile", fileInputElement.files[0]);
Then send the form data object to server.
We can also append a File or Blob directly to the FormData object.
data.append("myfile", myBlob, "filename.txt");
You can use method ajaxSubmit as follow :)
when you select a file that need upload to server, form be submit to server :)
$(document).ready(function () {
var options = {
target: '#output', // target element(s) to be updated with server response
timeout: 30000,
error: function (jqXHR, textStatus) {
$('#output').html('have any error');
return false;
}
},
success: afterSuccess, // post-submit callback
resetForm: true
// reset the form after successful submit
};
$('#idOfInputFile').on('change', function () {
$('#idOfForm').ajaxSubmit(options);
// always return false to prevent standard browser submit and page navigation
return false;
});
});
If you want to upload file using AJAX here is code which you can use for file uploading.
$(document).ready(function() {
var options = {
beforeSubmit: showRequest,
success: showResponse,
dataType: 'json'
};
$('body').delegate('#image','change', function(){
$('#upload').ajaxForm(options).submit();
});
});
function showRequest(formData, jqForm, options) {
$("#validation-errors").hide().empty();
$("#output").css('display','none');
return true;
}
function showResponse(response, statusText, xhr, $form) {
if(response.success == false)
{
var arr = response.errors;
$.each(arr, function(index, value)
{
if (value.length != 0)
{
$("#validation-errors").append('<div class="alert alert-error"><strong>'+ value +'</strong><div>');
}
});
$("#validation-errors").show();
} else {
$("#output").html("<img src='"+response.file+"' />");
$("#output").css('display','block');
}
}
Here is the HTML for Upload the file
<form class="form-horizontal" id="upload" enctype="multipart/form-data" method="post" action="upload/image'" autocomplete="off">
<input type="file" name="image" id="image" />
</form>
var dataform = new FormData($("#myform")[0]);
//console.log(dataform);
$.ajax({
url: 'url',
type: 'POST',
data: dataform,
async: false,
success: function(res) {
response data;
},
cache: false,
contentType: false,
processData: false
});
<input class="form-control cu-b-border" type="file" id="formFile">
<img id="myImg" src="#">
In js
<script>
var formData = new FormData();
formData.append('file', $('#formFile')[0].files[0]);
$.ajax({
type: "POST",
url: '/GetData/UploadImage',
data: formData,
processData: false, // tell jQuery not to process the data
contentType: false, // tell jQuery not to set contentType
success: function (data) {
console.log(data);
$('#myImg').attr('src', data);
},
error: function (xhr, ajaxOptions, thrownError) {
}
})
</script>
In controller
public ActionResult UploadImage(HttpPostedFileBase file)
{
string filePath = "";
if (file != null)
{
string path = "/uploads/Temp/";
if (!Directory.Exists(Server.MapPath("~" + path)))
{
Directory.CreateDirectory(Server.MapPath("~" + path));
}
filePath = FileUpload.SaveUploadedFile(file, path);
}
return Json(filePath, JsonRequestBehavior.AllowGet);
}
Here was an idea I was thinking of:
Have an iframe on page and have a referencer.
Have a form in which you move the input type file element to.
Form: A processing page AND a target of the FRAME.
The result will post to the iframe, and then you can just send the fetched data up a level to the image tag you want with something like:
data:image/png;base64,asdfasdfasdfasdfa
and the page loads.
I believe it works for me, and depending you might be able to do something like:
.aftersubmit(function(){
stopPropagation(); // or some other code which would prevent a refresh.
});
This is my code that it works
var formData = new FormData();
var files = $('input[type=file]');
for (var i = 0; i < files.length; i++) {
if (files[i].value == "" || files[i].value == null) {
return false;
}
else {
formData.append(files[i].name, files[i].files[0]);
}
}
var formSerializeArray = $("#Form").serializeArray();
for (var i = 0; i < formSerializeArray.length; i++) {
formData.append(formSerializeArray[i].name, formSerializeArray[i].value)
}
$.ajax({
type: 'POST',
data: formData,
contentType: false,
processData: false,
cache: false,
url: '/Controller/Action',
success: function (response) {
if (response.Success == true) {
return true;
}
else {
return false;
}
},
error: function () {
return false;
},
failure: function () {
return false;
}
});
$("#form-id").submit(function (e) {
e.preventDefault();
});
$("#form-id").submit(function (e) {
var formObj = $(this);
var formURL = formObj.attr("action");
var formData = new FormData(this);
$.ajax({
url: formURL,
type: 'POST',
data: formData,
processData: false,
contentType: false,
async: true,
cache: false,
enctype: "multipart/form-data",
dataType: "json",
success: function (data) {
if (data.success) {
alert(data.success)
}
if (data.error) {
alert(data.error)
}
}
});
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
<form class="form-horizontal" id="form-id" action="masterFileController" enctype="multipart/form-data">
<button class="btn-success btn" type="submit" id="btn-save" >Submit</button>
</form>
servlet responce as "out.print("your responce");"

Sending image along other data in ajax to php

I need little help. I created ajax form and pass the data to the api.php. I have no problem sending normal value to the php. I currently facing problem on sending file through.
HTML
<form id="adding" enctype="multipart/form-data">
<input type="file" id="imgInp">
<input type="text" id="name">
<button type="submit" class="btn btn-default pull-right">Submit</button>
</form>
Javascript
$('#adding').submit(function(e) {
e.preventDefault();
$.ajax({
type: "POST",
url: 'api.php?do=add',
data: {
img: $("#imgInp").val(),
name: $("#name").val()
},
success: function(data)
{
if (data === 'KO'){
document.getElementById("error").innerHTML = "Alert";
}
if (data === 'OK'){
document.getElementById("error").innerHTML = "OK";
}
}
});
Data from variable name can be send but not from img. Please help. Thank you
Sounds to me like you need to use the form data object. In the data attribute, via your ajax call,
FYI: you need to have jquery libraries to get this working
This would grab all form contents and then you can receive theform contents including the image on your php controller
$('#adding').submit(function(e) {
var formData = new FormData($(this));
e.preventDefault();
$.ajax({
type: "POST",
url: 'api.php?do=add',
data: formData ,
contentType: false,
processData: false,
cache: false,
success: function(data)
{
if (data === 'KO'){
document.getElementById("error").innerHTML = "Alert";
}
if (data === 'OK'){
document.getElementById("error").innerHTML = "OK";
}
}
});
On your php side,
<?php
try{
if(isset($_FILES) && $_FILES['tmp_name'] != null){
//awesome, we have something here
//then check for extensions, validate and move upload
}else{
//no file
}
}catch(Exception $ex){
echo($ex->getMessage());
}
?>

How can find inputs in php codes?

I get some inputs from database with $.ajax in jQuery and it will appear when user click on button:
HTML
<div id="div1"></div>
<input type="button" id="button1"/>
JQuery
$("#button1").click(function() {
$.ajax({
type: 'POST',
url: "get.php",
data: {vals: "send"},
success : function(response) {
$("#div1").append(response);
}});
})
After import elements to div, it will have one input type="file" like this:
EDIT:
My Form Code is here:
HTML
<input name="upload1" id="upload1" type="file"/>
<input type="button" value="submit" id="button2"/>
JQuery
$("#button2").click(function() {
$.ajax({
type: 'POST',
url: "uploadPhoto.php",
data: {filename: filename},
success : function(response) {
alert(response);
}
});
})
PHP
$filename = $_POST['filename '];
$target_dir = "image/";
$target_file = $target_dir . $filename;
var $src_temp = $_FILES["upload1"]["tmp_name"];
if (move_uploaded_file($src_temp, $target_file)) {
echo 'success';
}
END EDIT 1
When I want get $_FILES["upload1"]["tmp_name"] for this button to find temp folder of uploaded file in PHP code, it can't find the input that have upload1 name.
How can find a input name in PHP codes?
Try following code to get values in $_FIELS
$("#button1").on('click', function() {
var filename = document.getElementById('image id here').value.replace(/C:\\fakepath\\/i, '');
var image = document.getElementById('image id here').files[0];
Data = new FormData();
Data.append('upload1', image);
Data.append('file_name', filename); //pass file name
var xmlReq = new XMLHttpRequest(); //creating xml request
xmlReq.open("POST", 'enter your url', true); //send request
xmlReq.onload = function(answer) {
if (xmlReq.status == 200) {
var response = jQuery.parseJSON(xmlReq.responseText);
console.log(response);
} else {
console.log("Error " + xmlReq.status + " occurred uploading your file.<br \/>");
}
};
xmlReq.send(Data); //send form data
});

Passing Image using Ajax to PHP

I am trying to pass an image and a title field value to PHP, I usually process file uploads straight with PHP using the $_FILES array, I am not sure how to create/pass this array using ajax to PHP.
My form:
<form role="form" name="updateProductForm" id="updateProductForm" method="POST" enctype="multipart/form-data">
<input name="imgOne" id="imgOne" type="file" title="Add Image">
<a class="btn btn-primary" name="updateProduct" id="updateProduct">Update Product</a></div>
</form>
And I am trying to use this to pass to PHP:
$('#updateProduct').on('click', function() {
try {
ajaxRequest = new XMLHttpRequest();
} catch (e) {
try {
ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try {
ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP");
} catch (e) {
alert("Your browser broke!");
return false;
}
}
}
ajaxRequest.open("POST", "../Controller/ProductController.php", true);
ajaxRequest.setRequestHeader("Content-type","application/x-www-form-urlencoded");
ajaxRequest.send("title=" + $("#title").val() + "&imgOne=" + $("#imgOne"));
// Create a function that will receive data sent from the server
ajaxRequest.onreadystatechange = function(){
if(ajaxRequest.readyState == 4){
console.log(ajaxRequest);
}
}
});
In PHP I am trying this:
if (isset($_POST["edit"])) {
$id = $_POST["edit"];
$imgName = $_FILES["file"]["imgName"];
}
Youssef
I did that in one of my project, and following code works for me.
Please do required modifications in code as your need.
My Form button:
<form name="upload_img" enctype="multipart/form-data" id="upload_img">
<input type="file" style="display:none" id="upload-image" name="upload-image"></input>
<button id="upload_image" type="button">Save</button>
</form>
My JQuery/Ajax :
$('#upload_image').click(function()
{
var form = new FormData(document.getElementById('upload_img'));
//append files
var file = document.getElementById('upload-image').files[0];
if (file) {
form.append('upload-image', file);
}
$.ajax({
type: "POST",
url: "URL",
data: form,
cache: false,
contentType: false, //must, tell jQuery not to process the data
processData: false,
//data: $("#upload_img").serialize(),
success: function(data)
{
if(data == 1)
$('#img_msg').html("Image Uploaded Successfully");
else
$('#img_msg').html("Error While Image Uploading");
}
});
//alert('names');
});
You can use jQuery file upload plugin
$('#imgOne').change(function(){
$.ajaxFileUpload({
fileElementId: 'imgOne',
url: "../Controller/ProductController.php",
dataType: 'json',
success: function(response)
{
//Success Code Here
},
error: function()
{
//Error Code Here
}
});
});
First You need to Select image file through following line of html code
input type="file" id="image_to_upload"
After that you need to write the following jQuery code to catch this event.
jQuery.noConflict();
formdata = new FormData();
jQuery("#image_to_upload").on("change", function() {
var file = this.files[0];
if (formdata) {
formdata.append("image", file);
jQuery.ajax({
url: "destination_ajax_file.php",
type: "POST",
data: formdata,
processData: false,
contentType: false,
success:function(){}
});
}
});
In the destination ajax file you can access image by the following variable
print_r($_FILES);
More Info: http://www.rscoder.com/2020/06/how-to-upload-image-file-using-ajax.html

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