Related
i have a function but it contains a lot of parameters something like this;
function F(param1=false,param2=false,param3=false,param4=false) { ... }
my question is that, can i create an array when i using the function and use that array in param. area instead of variables? like this:
$x = array(
'param1' => $param1,
.
.
.
);
//then
F($x);
You absolutely can. Try this:
$params = array(
'param1' => $param1,
'param2' => $param2,
'param3' => $param3,
);
function arrayParams($params=array()){
$param1 = $params['param1'];
// we want param2 to default to false
if (! array_key_exists('param2', $params)){
$params['param2'] = false;
}
echo "$param1\n";
echo "$param2\n";
}
arrayParams($params);
Yes, you can. But you will loose the possibility to easily set some variables to a default value.
A aesthetic solution would be to pass a class to the function instead of an array, in order to keep undefined parameters to a default value.
Is it possible in PHP to specify a named optional parameter when calling a function/method, skipping the ones you don't want to specify (like in python)?
Something like:
function foo($a, $b = '', $c = '') {
// whatever
}
foo("hello", $c="bar"); // we want $b as the default, but specify $c
No, it is not possible (before PHP 8.0): if you want to pass the third parameter, you have to pass the second one. And named parameters are not possible either.
A "solution" would be to use only one parameter, an array, and always pass it... But don't always define everything in it.
For instance :
function foo($params) {
var_dump($params);
}
And calling it this way : (Key / value array)
foo([
'a' => 'hello',
]);
foo([
'a' => 'hello',
'c' => 'glop',
]);
foo([
'a' => 'hello',
'test' => 'another one',
]);
Will get you this output :
array
'a' => string 'hello' (length=5)
array
'a' => string 'hello' (length=5)
'c' => string 'glop' (length=4)
array
'a' => string 'hello' (length=5)
'test' => string 'another one' (length=11)
But I don't really like this solution :
You will lose the phpdoc
Your IDE will not be able to provide any hint anymore... Which is bad
So I'd go with this only in very specific cases -- for functions with lots of optional parameters, for instance...
PHP 8 was released on November 26, 2020 with a new feature called named arguments.
In this major version release, "named parameters" (aka "named arguments") afford developers some really cool new techniques when calling native and custom functions.
The custom function in this question can now be called with the first parameter (because there is no default for it) and then only the third parameter passed by using named parameters like this: (Demo)
function foo($a, $b = '', $c = '') {
echo $a . '&' . $b . '&' . $c;
}
foo("hello", c: "bar");
// output: hello&&bar
Notice that the second parameter did not need to be declared in the function call because it has a default value defined -- the default value is automatically used within the function body.
Part of the beauty of this new feature is that you don't need to be careful about the order of your named parameters -- the order of their declaration is irrelevant. foo(c: "bar", a: "hello"); works just the same. Having the ability to "skip" declarations and write declarative parameters will improve the readability of your scripts. The only downside of this new feature is that there will be a little bit more bloat in the function calls, but I (and many others) think the benefits outweigh this "cost".
Here is an example of a native function omitting the limit parameter, writing the parameters out of their normal order, and declaring a reference variable. (Demo)
echo preg_replace(
subject: 'Hello 7',
pattern: '/[a-z ]/',
count: $counted,
replacement: ''
)
. " & " . $counted;
// output: H7 & 5
There is more to tell about this new feature. You can even use an associative array to pass the named parameters to the function where the spread/splat operator can be used to unpack the data!
(*notice the slight difference in declaring the reference variable.) (Demo)
$params = [
'subject' => 'Hello 7', // normally third parameter
'pattern' => '/[a-z ]/', // normally first parameter
// 'limit' // normally fourth parameter, omitted for this demonstration; the default -1 will be used
'count' => &$counted, // normally fifth parameter
// ^-- don't forget to make it modifiable!
'replacement' => '', // normally second parameter
];
echo preg_replace(...$params) . " & " . $counted;
// same output as the previous snippet
For more information, here are a few leads that explain further about this feature and some common related errors: (I have no affiliation with the following sites)
https://wiki.php.net/rfc/named_params
https://stitcher.io/blog/php-8-named-arguments
https://stitcher.io/blog/why-we-need-named-params-in-php
No, PHP cannot pass arguments by name.
If you have a function that takes a lot of arguments and all of them have default values you can consider making the function accept an array of arguments instead:
function test (array $args) {
$defaults = array('a' => '', 'b' => '', 'c' => '');
$args = array_merge($defaults, array_intersect_key($args, $defaults));
list($a, $b, $c) = array_values($args);
// an alternative to list(): extract($args);
// you can now use $a, $b, $c
}
See it in action.
No, it isn't.
The only way you can somewhat do that is by using arrays with named keys and what not.
As of PHP 5.4 you have shorthand array syntax (not nessecary to specify arrays with cumbersome "array" and instead use "[]").
You can mimic named parameters in many ways, one good and simple way might be:
bar('one', ['a1' => 'two', 'bar' => 'three', 'foo' => 'four']);
// output: twothreefour
function bar ($a1, $kwargs = ['bar' => null, 'foo' => null]) {
extract($kwargs);
echo $a1;
echo $bar;
echo $foo;
}
You can keep the phpdoc and the ability to set defaults by passing an object instead of an array, e.g.
class FooOptions {
$opt1 = 'x';
$opt2 = 'y';
/* etc */
};
That also lets you do strict type checking in your function call, if you want to:
function foo (FooOptions $opts) {
...
}
Of course, you might pay for that with extra verbosity setting up the FooOptions object. There's no totally-free ride, unfortunately.
It's not exactly pretty, but it does the trick, some might say.
class NamedArguments {
static function init($args) {
$assoc = reset($args);
if (is_array($assoc)) {
$diff = array_diff(array_keys($assoc), array_keys($args));
if (empty($diff)) return $assoc;
trigger_error('Invalid parameters: '.join(',',$diff), E_USER_ERROR);
}
return array();
}
}
class Test {
public static function foobar($required, $optional1 = '', $optional2 = '') {
extract(NamedArguments::init(get_defined_vars()));
printf("required: %s, optional1: %s, optional2: %s\n", $required, $optional1, $optional2);
}
}
Test::foobar("required", "optional1", "optional2");
Test::foobar(array(
'required' => 'required',
'optional1' => 'optional1',
'optional2' => 'optional2'
));
Normally you can't but I think there a lot of ways to pass named arguments to a PHP function. Personally I relay on the definition using arrays and just call what I need to pass:
class Test{
public $a = false;
private $b = false;
public $c = false;
public $d = false;
public $e = false;
public function _factory(){
$args = func_get_args();
$args = $args[0];
$this->a = array_key_exists("a",$args) ? $args["a"] : 0;
$this->b = array_key_exists("b",$args) ? $args["b"] : 0;
$this->c = array_key_exists("c",$args) ? $args["c"] : 0;
$this->d = array_key_exists("d",$args) ? $args["d"] : 0;
$this->e = array_key_exists("e",$args) ? $args["e"] : 0;
}
public function show(){
var_dump($this);
}
}
$test = new Test();
$args["c"]=999;
$test->_factory($args);
$test->show();
live example here:
http://sandbox.onlinephpfunctions.com/code/d7f27c6e504737482d396cbd6cdf1cc118e8c1ff
If I have to pass 10 arguments, and 3 of them are the data I really need, is NOT EVEN SMART to pass into the function something like
return myfunction(false,false,10,false,false,"date",false,false,false,"desc");
With the approach I'm giving, you can setup any of the 10 arguments into an array:
$arr['count']=10;
$arr['type']="date";
$arr['order']="desc";
return myfunction($arr);
I have a post in my blog explaining this process in more details.
http://www.tbogard.com/2013/03/07/passing-named-arguments-to-a-function-in-php
With PHP, the order of arguments is what matters. You can't specify a particular argument out of place, but instead, you can skip arguments by passing a NULL, as long as you don't mind the value in your function having a NULL value.
foo("hello", NULL, "bar");
If you really really want, try the reflection.
And skip with null.
function getDefaultValueByNull($fn, $inputs) {
$ref = new ReflectionFunction($fn);
$args = array_map(function($p) {
return [
$p->getName(),
$p->isDefaultValueAvailable() ? $p->getDefaultValue() : NULL,
];
}, $ref->getParameters());
foreach($inputs as $i=>$val) { if ($val!==NULL) $args[$i][1] = $val; }
return array_column($args, 1, 0);
}
function sum($a=9, $b) {
extract(getDefaultValueByNull(__FUNCTION__, func_get_args()));
return $a+$b;
}
echo sum(NULL, 1); // 10
Here's what I've been using. A function definition takes one optional array argument which specifies the optional named arguments:
function func($arg, $options = Array()) {
$defaults = Array('foo' => 1.0,
'bar' => FALSE);
$options = array_merge($default, $options);
// Normal function body here. Use $options['foo'] and
// $options['bar'] to fetch named parameter values.
...
}
You can normally call without any named arguments:
func("xyzzy")
To specify an optional named argument, pass it in the optional array:
func("xyzzy", Array('foo' => 5.7))
No not really. There are a few alternatives to it you could use.
test(null,null,"hello")
Or pass an array:
test(array('c' => "hello"));
Then, the function could be:
function test($array) {
$c = isset($array[c]) ? $array[c] : '';
}
Or add a function in between, but i would not suggest this:
function ctest($c) { test('','',$c); }
I dont think so...
If you need to call, for example, the substr function, that has 3 params, and want to set the $length without set the $start, you'll be forced to do so.
substr($str,0,10);
a nice way to override this is to always use arrays for parameters
In very short, sometimes yes, by using reflection and typed variables. However I think this is probably not what you are after.
A better solution to your problem is probably to pass in the 3 arguments as functions handle the missing one inside your function yourself
<?php
function test(array $params)
{
//Check for nulls etc etc
$a = $params['a'];
$b = $params['b'];
...etc etc
}
You can't do it the python way. Anway, you could pass an associative array and than use the array entries by their name:
function test ($args=array('a'=>'','b'=>'','c'=>''))
{
// do something
}
test(array('c'=>'Hello'));
This doesn't reduce the typing, but at least it's more descriptive, having the arguments' names visible and readable in the call.
Here is a work around:
function set_param_defaults($params) {
foreach($params['default_values'] as $arg_name => $arg_value) {
if (!isset($params[$arg_name])) {
$params[$arg_name] = $arg_value;
}
}
return $params;
}
function foo($z, $x = null, $y = null) {
$default_values = ['x' => 'default value for x', 'y' => 'default value for y'];
$params = set_param_defaults(get_defined_vars());
print "$z\n";
print $params['x'] . "\n";
print $params['y'] . "\n";
}
foo('set z value', null, 'set y value');
print "\n";
foo('set z value', 'set x value');
ALTERNATIVELY:
Personally I would go with this method.
function foo($z, $x_y) {
$x_y += ['x' => 'default value for x', 'y' => 'default value for y'];
print "$z\n";
print $x_y['x'] . "\n";
print $x_y['y'] . "\n";
}
foo('set z value', ['y' => 'set y value']);
print "\n";
foo('set z value', ['x' => 'set x value']);
Print outs for both examples.
1st call:
set z value
default value for x
set y value
2nd call:
set z value
set x value
default value for y
Just use the associative array pattern Drupal uses. For optional defaulted arguments, just accept an $options argument which is an associative array. Then use the array + operator to set any missing keys in the array.
function foo ($a_required_parameter, $options = array()) {
$options += array(
'b' => '',
'c' => '',
);
// whatever
}
foo('a', array('c' => 'c’s value')); // No need to pass b when specifying c.
So I've got a class that I'd like to have it just set defaults if they're not passed in. For example, I can pass it an array called $options.
function new_score($options)
{
}
Then I'd like to have a different function that I can set a var to a default if a key with that var's name doesn't exist in the $options array;
The function definition could look like this:
function _set(&$key, $options, $default)
{
}
I know there's array_key_exists(), and I guess I'm sort of looking for a way to access the variables name.
For example:
$apple = 'orange';
How can I get the string 'apple', so I can look for that key? I know I could take the function _set() and have it look for $key, $var, $options, and $default, but I'd rather abstract it further.
function method($options)
{
//First, set an array of defaults:
$defaults = array( "something" => "default value",
"something_else" => "another default");
//Second, merge the defaults with the $options received:
$options = array_merge($defaults, $options);
//Now you have an array with the received values or defaults if value not received.
echo($options["something"]);
//If you wish, you can import variables into local scope with "extract()"
//but it's better not to do this...
extract($options);
echo($something);
}
References:
http://ar.php.net/manual/en/function.array-merge.php
http://ar.php.net/manual/en/function.extract.php
there's two ways of doing this:
One at a time with the ternary operator:
$key = isset($array['foo']) ? $array['foo'] : 'default';
Or, as an array as a whole:
$defaults = array('foo' => 'bar', 'other' => 'default value');
$array = $array + $defaults;
How about this:
class Configurable
{
private static $defaults = array (
'propertyOne'=>'defaultOne',
'propertyTwo'=>'defaultTwo'
);
private $options;
public function __construct ($options)
{
$this->options = array_merge (self::$defaults, $options);
}
}
From the documentation for array_merge:
If the input arrays have the same
string keys, then the later value for
that key will overwrite the previous
one.
Is it possible in PHP to specify a named optional parameter when calling a function/method, skipping the ones you don't want to specify (like in python)?
Something like:
function foo($a, $b = '', $c = '') {
// whatever
}
foo("hello", $c="bar"); // we want $b as the default, but specify $c
No, it is not possible (before PHP 8.0): if you want to pass the third parameter, you have to pass the second one. And named parameters are not possible either.
A "solution" would be to use only one parameter, an array, and always pass it... But don't always define everything in it.
For instance :
function foo($params) {
var_dump($params);
}
And calling it this way : (Key / value array)
foo([
'a' => 'hello',
]);
foo([
'a' => 'hello',
'c' => 'glop',
]);
foo([
'a' => 'hello',
'test' => 'another one',
]);
Will get you this output :
array
'a' => string 'hello' (length=5)
array
'a' => string 'hello' (length=5)
'c' => string 'glop' (length=4)
array
'a' => string 'hello' (length=5)
'test' => string 'another one' (length=11)
But I don't really like this solution :
You will lose the phpdoc
Your IDE will not be able to provide any hint anymore... Which is bad
So I'd go with this only in very specific cases -- for functions with lots of optional parameters, for instance...
PHP 8 was released on November 26, 2020 with a new feature called named arguments.
In this major version release, "named parameters" (aka "named arguments") afford developers some really cool new techniques when calling native and custom functions.
The custom function in this question can now be called with the first parameter (because there is no default for it) and then only the third parameter passed by using named parameters like this: (Demo)
function foo($a, $b = '', $c = '') {
echo $a . '&' . $b . '&' . $c;
}
foo("hello", c: "bar");
// output: hello&&bar
Notice that the second parameter did not need to be declared in the function call because it has a default value defined -- the default value is automatically used within the function body.
Part of the beauty of this new feature is that you don't need to be careful about the order of your named parameters -- the order of their declaration is irrelevant. foo(c: "bar", a: "hello"); works just the same. Having the ability to "skip" declarations and write declarative parameters will improve the readability of your scripts. The only downside of this new feature is that there will be a little bit more bloat in the function calls, but I (and many others) think the benefits outweigh this "cost".
Here is an example of a native function omitting the limit parameter, writing the parameters out of their normal order, and declaring a reference variable. (Demo)
echo preg_replace(
subject: 'Hello 7',
pattern: '/[a-z ]/',
count: $counted,
replacement: ''
)
. " & " . $counted;
// output: H7 & 5
There is more to tell about this new feature. You can even use an associative array to pass the named parameters to the function where the spread/splat operator can be used to unpack the data!
(*notice the slight difference in declaring the reference variable.) (Demo)
$params = [
'subject' => 'Hello 7', // normally third parameter
'pattern' => '/[a-z ]/', // normally first parameter
// 'limit' // normally fourth parameter, omitted for this demonstration; the default -1 will be used
'count' => &$counted, // normally fifth parameter
// ^-- don't forget to make it modifiable!
'replacement' => '', // normally second parameter
];
echo preg_replace(...$params) . " & " . $counted;
// same output as the previous snippet
For more information, here are a few leads that explain further about this feature and some common related errors: (I have no affiliation with the following sites)
https://wiki.php.net/rfc/named_params
https://stitcher.io/blog/php-8-named-arguments
https://stitcher.io/blog/why-we-need-named-params-in-php
No, PHP cannot pass arguments by name.
If you have a function that takes a lot of arguments and all of them have default values you can consider making the function accept an array of arguments instead:
function test (array $args) {
$defaults = array('a' => '', 'b' => '', 'c' => '');
$args = array_merge($defaults, array_intersect_key($args, $defaults));
list($a, $b, $c) = array_values($args);
// an alternative to list(): extract($args);
// you can now use $a, $b, $c
}
See it in action.
No, it isn't.
The only way you can somewhat do that is by using arrays with named keys and what not.
As of PHP 5.4 you have shorthand array syntax (not nessecary to specify arrays with cumbersome "array" and instead use "[]").
You can mimic named parameters in many ways, one good and simple way might be:
bar('one', ['a1' => 'two', 'bar' => 'three', 'foo' => 'four']);
// output: twothreefour
function bar ($a1, $kwargs = ['bar' => null, 'foo' => null]) {
extract($kwargs);
echo $a1;
echo $bar;
echo $foo;
}
You can keep the phpdoc and the ability to set defaults by passing an object instead of an array, e.g.
class FooOptions {
$opt1 = 'x';
$opt2 = 'y';
/* etc */
};
That also lets you do strict type checking in your function call, if you want to:
function foo (FooOptions $opts) {
...
}
Of course, you might pay for that with extra verbosity setting up the FooOptions object. There's no totally-free ride, unfortunately.
It's not exactly pretty, but it does the trick, some might say.
class NamedArguments {
static function init($args) {
$assoc = reset($args);
if (is_array($assoc)) {
$diff = array_diff(array_keys($assoc), array_keys($args));
if (empty($diff)) return $assoc;
trigger_error('Invalid parameters: '.join(',',$diff), E_USER_ERROR);
}
return array();
}
}
class Test {
public static function foobar($required, $optional1 = '', $optional2 = '') {
extract(NamedArguments::init(get_defined_vars()));
printf("required: %s, optional1: %s, optional2: %s\n", $required, $optional1, $optional2);
}
}
Test::foobar("required", "optional1", "optional2");
Test::foobar(array(
'required' => 'required',
'optional1' => 'optional1',
'optional2' => 'optional2'
));
Normally you can't but I think there a lot of ways to pass named arguments to a PHP function. Personally I relay on the definition using arrays and just call what I need to pass:
class Test{
public $a = false;
private $b = false;
public $c = false;
public $d = false;
public $e = false;
public function _factory(){
$args = func_get_args();
$args = $args[0];
$this->a = array_key_exists("a",$args) ? $args["a"] : 0;
$this->b = array_key_exists("b",$args) ? $args["b"] : 0;
$this->c = array_key_exists("c",$args) ? $args["c"] : 0;
$this->d = array_key_exists("d",$args) ? $args["d"] : 0;
$this->e = array_key_exists("e",$args) ? $args["e"] : 0;
}
public function show(){
var_dump($this);
}
}
$test = new Test();
$args["c"]=999;
$test->_factory($args);
$test->show();
live example here:
http://sandbox.onlinephpfunctions.com/code/d7f27c6e504737482d396cbd6cdf1cc118e8c1ff
If I have to pass 10 arguments, and 3 of them are the data I really need, is NOT EVEN SMART to pass into the function something like
return myfunction(false,false,10,false,false,"date",false,false,false,"desc");
With the approach I'm giving, you can setup any of the 10 arguments into an array:
$arr['count']=10;
$arr['type']="date";
$arr['order']="desc";
return myfunction($arr);
I have a post in my blog explaining this process in more details.
http://www.tbogard.com/2013/03/07/passing-named-arguments-to-a-function-in-php
With PHP, the order of arguments is what matters. You can't specify a particular argument out of place, but instead, you can skip arguments by passing a NULL, as long as you don't mind the value in your function having a NULL value.
foo("hello", NULL, "bar");
If you really really want, try the reflection.
And skip with null.
function getDefaultValueByNull($fn, $inputs) {
$ref = new ReflectionFunction($fn);
$args = array_map(function($p) {
return [
$p->getName(),
$p->isDefaultValueAvailable() ? $p->getDefaultValue() : NULL,
];
}, $ref->getParameters());
foreach($inputs as $i=>$val) { if ($val!==NULL) $args[$i][1] = $val; }
return array_column($args, 1, 0);
}
function sum($a=9, $b) {
extract(getDefaultValueByNull(__FUNCTION__, func_get_args()));
return $a+$b;
}
echo sum(NULL, 1); // 10
Here's what I've been using. A function definition takes one optional array argument which specifies the optional named arguments:
function func($arg, $options = Array()) {
$defaults = Array('foo' => 1.0,
'bar' => FALSE);
$options = array_merge($default, $options);
// Normal function body here. Use $options['foo'] and
// $options['bar'] to fetch named parameter values.
...
}
You can normally call without any named arguments:
func("xyzzy")
To specify an optional named argument, pass it in the optional array:
func("xyzzy", Array('foo' => 5.7))
No not really. There are a few alternatives to it you could use.
test(null,null,"hello")
Or pass an array:
test(array('c' => "hello"));
Then, the function could be:
function test($array) {
$c = isset($array[c]) ? $array[c] : '';
}
Or add a function in between, but i would not suggest this:
function ctest($c) { test('','',$c); }
I dont think so...
If you need to call, for example, the substr function, that has 3 params, and want to set the $length without set the $start, you'll be forced to do so.
substr($str,0,10);
a nice way to override this is to always use arrays for parameters
In very short, sometimes yes, by using reflection and typed variables. However I think this is probably not what you are after.
A better solution to your problem is probably to pass in the 3 arguments as functions handle the missing one inside your function yourself
<?php
function test(array $params)
{
//Check for nulls etc etc
$a = $params['a'];
$b = $params['b'];
...etc etc
}
You can't do it the python way. Anway, you could pass an associative array and than use the array entries by their name:
function test ($args=array('a'=>'','b'=>'','c'=>''))
{
// do something
}
test(array('c'=>'Hello'));
This doesn't reduce the typing, but at least it's more descriptive, having the arguments' names visible and readable in the call.
Here is a work around:
function set_param_defaults($params) {
foreach($params['default_values'] as $arg_name => $arg_value) {
if (!isset($params[$arg_name])) {
$params[$arg_name] = $arg_value;
}
}
return $params;
}
function foo($z, $x = null, $y = null) {
$default_values = ['x' => 'default value for x', 'y' => 'default value for y'];
$params = set_param_defaults(get_defined_vars());
print "$z\n";
print $params['x'] . "\n";
print $params['y'] . "\n";
}
foo('set z value', null, 'set y value');
print "\n";
foo('set z value', 'set x value');
ALTERNATIVELY:
Personally I would go with this method.
function foo($z, $x_y) {
$x_y += ['x' => 'default value for x', 'y' => 'default value for y'];
print "$z\n";
print $x_y['x'] . "\n";
print $x_y['y'] . "\n";
}
foo('set z value', ['y' => 'set y value']);
print "\n";
foo('set z value', ['x' => 'set x value']);
Print outs for both examples.
1st call:
set z value
default value for x
set y value
2nd call:
set z value
set x value
default value for y
Just use the associative array pattern Drupal uses. For optional defaulted arguments, just accept an $options argument which is an associative array. Then use the array + operator to set any missing keys in the array.
function foo ($a_required_parameter, $options = array()) {
$options += array(
'b' => '',
'c' => '',
);
// whatever
}
foo('a', array('c' => 'c’s value')); // No need to pass b when specifying c.
This question already has answers here:
Does PHP allow named parameters so that optional arguments can be omitted from function calls?
(17 answers)
Closed 1 year ago.
I have this:
function foo($a='apple', $b='brown', $c='Capulet') {
// do something
}
Is something like this possible:
foo('aardvark', <use the default, please>, 'Montague');
If it’s your function, you could use null as wildcard and set the default value later inside the function:
function foo($a=null, $b=null, $c=null) {
if (is_null($a)) {
$a = 'apple';
}
if (is_null($b)) {
$b = 'brown';
}
if (is_null($c)) {
$c = 'Capulet';
}
echo "$a, $b, $c";
}
Then you can skip them by using null:
foo('aardvark', null, 'Montague');
// output: "aarkvark, brown, Montague"
If it's your own function instead of one of PHP's core, you could do:
function foo($arguments = []) {
$defaults = [
'an_argument' => 'a value',
'another_argument' => 'another value',
'third_argument' => 'yet another value!',
];
$arguments = array_merge($defaults, $arguments);
// now, do stuff!
}
foo(['another_argument' => 'not the default value!']);
Found this, which is probably still correct:
http://www.webmasterworld.com/php/3758313.htm
Short answer: no.
Long answer: yes, in various kludgey ways that are outlined in the above.
You pretty much found the answer, but the academic/high-level approach is function currying which I honestly never found much of a use for, but is useful to know exists.
You can use some quirks, either passing all arguments as an array like ceejayoz suggests, or some overcomplicated code that parses func_get_args() and merges with a list of defaults. Not to copy-paste it, you'll have to use objects and traits. Finally, to be able to pass all kinds of values (not excluding null or false by making them a signal for default param substitution), you'll have to declare a dummy special type DefaultParam.
Another minus is that you have to duplicate the names and default values in the function declaration, if you want to get type hints or help in any IDE.
class DefaultParam {}
trait multi_arg_functions
{
private static function multi_arg($defaults, $list, $preserve_index = false)
{
$arg_keys = array_slice(array_keys($defaults), 0, count($list));
if ($preserve_index) {
$listed_arguments = array_slice($list, 0, count($arg_keys));
$extras = array_slice($list, count($arg_keys), null, true);
} else {
$listed_arguments = array_splice($list, 0, count($arg_keys));
$extras = &$list;
}
unset($list);
$arguments = array_combine($arg_keys, $listed_arguments);
$arguments = array_filter($arguments, function ($entry) {
return !($entry instanceof DefaultParam); //remove entries that mean default, a special class in this case
});
$arguments = array_merge($defaults, $arguments);
return [$arguments, $extras];
}
}
class b {
use multi_arg_functions;
static function func1($an_argument = 'a value', $another_argument = 'another value', $third_argument = 'yet another value') { //give defaults here to get hints in an IDE
list($args, $extras) = self::multi_arg( //note: duplicate names and defaults
[
'an_argument' => 'a value',
'another_argument' => 'another value',
'third_argument' => 'yet another value!',
], func_get_args());
echo json_encode(['args' => $args, 'extras' => $extras])."\n";
}
}
$default_param = new DefaultParam();
b::func1('value 1');
b::func1('value 2', $default_param, 'third argument');
b::func1('value 3', $default_param, 'third argument', 'fourth argument');
Note: by using preserve_index = true you get the extra arguments to start from their original index.
As of PHP 8, use named parameters:
function foo($a='apple', $b='brown', $c='Capulet') {
// do something
}
foo('apple', c:'Montague');
This let's you bypass as many parameters as you want, allowing them to take on their default value. This is helpful in long-winded functions like setcookie:
setcookie('macadamia', httponly:true); // skips over 5 parameters
Note that named parameters require all non-optional parameters to be passed. These may be passed positionally (as I've done here, no names on them) or with names in any order.