I'm trying to write a method in my controller to allow searching the results of my query on my view page. The query selects all results from the "ads" table and this method should allow filtering results by the ad's name inputting keywords in the search bar.
The controller code goes like this:
public function index(Request $request)
{
$title = trans('ad.title');
$ads = Ad::paginate(10);
if (!empty($request->input('search_all'))) {
$search_all = urldecode($request->input('search_all'));
$ads->where(function ($query) use ($search_all) {
$query->where('name', 'like', '%'.$search_all.'%')->get();
});
}else {
// Returning to view
return view('admin.ad.list')
->with('ads', $ads)
->with('title', $title);
}
}
However, when I run a search I get the following error: "Missing argument 2 for Illuminate\Support\Collection::where()".
What am I doing wrong?
At the top, when doing $ads = Ad::paginate(10); you have already pulled the results from the database so no more filtering can be done at DB level.
I'd do something like this instead:
public function index(Request $request)
{
$title = trans('ad.title');
$ads = Ad::select();
if ($request->input('search_all')) {
$search_all = urldecode($request->input('search_all'));
$ads->where('name', 'like', '%'.$search_all.'%');
}
// Returning to view
return view('admin.ad.list')
->with('ads', $ads->paginate(10))
->with('title', $title);
}
I'm new at laravel. I'm working on new web application using laravel 5.4. I want to count the number of data in a database and show the result in view. So, I have used this code in controller:
public function bending_img(){
$counts = requestImg::where('is_done', '=', '0')->count();
return view('/dashboard')->with(['counts'=> $counts]);
}
public function uploaded_img(){
$count = requestImg::where('is_done', '=', '1')->count();
return view('/dashboard')->with(['count'=> $count]);
}
and in view:
#if(count($counts)== 0)
no call record to be viewed
#else
<div class="huge">{{$counts}}</div>
#endif
#if(count($count)==0)
no call record to be viewed
#else
<div class="huge">{{$count}}</div>
#endif
but there is an error: undefined variable.
Please resolve this error.
public function bendingImgCount() {
return requestImg::where('is_done', '0')->count();
}
public function uploadedImgCount() {
return = requestImg::where('is_done', '1')->count();
}
public function showDashboard() {
$bendingImgCount = $this->bendingImgCount();
$uploadedImgCount = $this->uploadedImgCount();
return view('/dashboard')->with(compact(['bendingImgCount', 'uploadedImgCount']));
}
Call the showDashboard function and change in the view the counts to bendingImgCount and count to uploadedImgCount.
First you check wherether you get correct data at controller
You just simply
public function bending_img(){
$counts = requestImg::where('is_done', '=', '0')->count();
dd($counts);
return view('/dashboard')->with(['counts'=> $counts]);
}
public function uploaded_img(){
$count = requestImg::where('is_done', '=', '1')->count();
dd($count);
return view('/dashboard')->with(['count'=> $count]);
}
And check you get correct answer or not .
I am getting Correct count in browser
1.Controller Page:
2.web.php Page:
3.Web Browser:
If you are even not getting correct value then just show your whole code of page.
Thank you.
TRY THIS:
In Controller:
public function bending_img(){
$counts = requestImg::where('is_done', '=', '0')->count();
return view('/dashboard')->with('this_is_it', $counts);
}
public function uploaded_img(){
$count = requestImg::where('is_done', '=', '1')->count();
return view('/dashboard')->with('count_1',$count);
}
In View:
#if(count($this_is_it)== 0)
no call record to be viewed
#else
<div class="huge">{{$this_is_it}}</div>
#endif
#if(count($count_1)==0)
no call record to be viewed
#else
<div class="huge">{{$count_1}}</div>
#endif
I have some problem here.
I wanna view all data sort by "kelompok".
*kelompok means group
This is the code :
Controller
public function pengelompokan()
{
$view = DB::table('tb_siswa')->where('id', $kelompok)->get();
return view('pengelompokan')
->with('view', $view);
}
Route
Route::get('kelompok', 'belajarController#kelompok');
You can use the groupBy collection method:
$view = DB::table('tb_siswa')
->where('id', $kelompok)
->get()
->groupBy('kelompok');
Edit
Based on your comments, you could do this:
Route::get('kelompok/{groupId}', 'belajarController#kelompok');
public function pengelompokan($kelompok)
{
$view = DB::table('tb_siswa')
->where('id', $kelompok)
->get()
->groupBy('kelompok');
return view('pengelompokan', compact('view'));
}
Following is the code to resolve this
public function pengelompokan()
{
$view = DB::table('tb_siswa')->where('id', $kelompok)
->groupBy('kelompok')->get();
return view('pengelompokan')->with('view');
}
You can access groupBy data using a variable $view on blade as well.
I am using Routes but you can apply it on your Controller#show
Route::get('tutorial/{id}', function($id){
$tutorial = Tutorial::findOrFail($id);
return view('tutorial.show')->with('tutorial', $tutorial);})->name('show-tutorial');
and Also Check on your show.blade.php
I am new in laravel and php. I am developing a magazine site with laravel 4. I want to store home page in laravel cache . But In my homepage , there are many queries . Please see details below.:
My HomepageController index method:
public function index()
{
return View::make('homepage');
}
My Query Helper Function which is used for post by category in my Homepage:
public static function cat_post($category, $limit)
{
$posts = Post::whereHas('categories', function($q) use ($category)
{
$q->where('category_slug', 'like', $category);
})->with('categories')->take($limit)->orderBy('created_at', 'DESC')->get();
return $posts;
}
In My homepage.blade.php , I used this helper function many times. like below:
<?php $national = Helper::cat_post('national', 3); ?>
#foreach ($national as $post)
{{ Helper::img_src($post) }}
<h4>{{ $post->title }}</h4>
</div>
#endforeach
Now i want to put homepage in cache and when new post created, then delete old homepage from cache and store new one.
Please help me. Is it possible ?????
To store a value in cache you can use Laravel's Cache:
public function index()
{
return Cache::rememberForever('homepageCache', function()
{
return View::make('homepage');
});
}
This snipped tries to retrieve a cached version of View::make('homepage') and otherwise creates it.
Every time a post is created, updated or deleted you need to invalide your homepageCache:
Cache::forget('homepageCache');
I am trying to create a page where I can see all the people in my database and create edits on them. I made a form where I fill in the data from the database of certain fields.
I would like to navigate trough them by a Next and Previous button.
For generating the next step I have to take the ID larger than the current one to load the next profile.
For generating the previous step I have to take the ID smaller than the current one to load the previous profile.
My route:
Route::get('users/{id}','UserController#show');
Controller:
public function show($id)
{
$input = User::find($id);
// If a user clicks next this one should be executed.
$input = User::where('id', '>', $id)->firstOrFail();
echo '<pre>';
dd($input);
echo '</pre>';
return View::make('hello')->with('input', $input);
}
View:
The buttons:
Next
What is the best approach to get the current ID and increment it?
Below are your updated controller and view files derived from #ridecar2 link,
Controller:
public function show($id)
{
// get the current user
$user = User::find($id);
// get previous user id
$previous = User::where('id', '<', $user->id)->max('id');
// get next user id
$next = User::where('id', '>', $user->id)->min('id');
return View::make('users.show')->with('previous', $previous)->with('next', $next);
}
View:
Previous
Next
// in your model file
public function next(){
// get next user
return User::where('id', '>', $this->id)->orderBy('id','asc')->first();
}
public function previous(){
// get previous user
return User::where('id', '<', $this->id)->orderBy('id','desc')->first();
}
// in your controller file
$user = User::find(5);
// a clean object that can be used anywhere
$user->next();
$user->previous();
In your App\Models\User.php
...
protected $appends = ['next', 'previous'];
public function getNextAttribute()
{
return $this->where('id', '>', $this->id)->orderBy('id','asc')->first();
}
public function getPreviousAttribute()
{
return $this->where('id', '<', $this->id)->orderBy('id','asc')->first();
}
In your Controller you can simply do this:
public function show(User $user)
{
return View::make('users.show')
->with('user', $user)
->with('previous', $user->previous)
->with('next', $user->next);
}
I understand the approach being taken here by user2581096 but I am not sure it is efficient (by any standards). We are calling the database 3 times for really no good reason. I suggest an alternative that will be way more efficient and scalable.
Do not pass the previous and next IDs to the view. This eliminates 2 unnecessary database calls.
Create the following routes:
users/{id}/next
users/{id}/previous
These routes should be used in the href attributes of the anchor tags
Add methods in the controller to handle each of the new routes you have created. For example:
public function getPrevious(){
// get previous user
$user = User::where('id', '<', $this->id)->orderBy('id','desc')->first();
return $this->show($user->id);
}
This function will only be called when you actually click on the button. Therefore, the database call is only made when you need to actually look up the user.
in-case you want to retrieve the prev/next records along with their data,
you can try
$id = 7; // for example
$prev = DB::table('posts')->where('id', '<', $id)->orderBy('id','desc')->limit(1);
$next = DB::table('posts')->where('id', '>', $id)->limit(1);
$res = DB::table('posts')
->where('id', '=', $id)
->unionAll($prev)
->unionAll($next)
->get();
// now $res is an array of 3 objects
// main, prev, next
dd($res);
1- the query builder is usually much faster than eloquent.
2- with union we are now only hitting the db once instead of 3.
To get next and previous post we can use max and min functions on Model id in laravel. here is an example to get this
https://usingphp.com/post/get-next-and-previous-post-link-in-laravel
The Controller:
public function post($id)
{
$post = Post::find($id);
$previous = Post::where('id', '<', $post->id)->max('id');
$next = Post::where('id', '>', $post->id)->min('id');
return view( 'post', compact( 'post', 'next', 'previous' ));
}
The View:
#if($next)
{{$next->title}}
#endif
#if($previous)
{{$previous->title}}
#endif
Here's a link I found that should help: http://maxoffsky.com/code-blog/laravel-quick-tip-get-previous-next-records/
It looks like for next you want to use: $next = User::where('id', '>', $id)->min('id'); and have the view as: Next
Also don't forget to pass $next to the view.
Simplest approach
// User.php
public static function findNext($id)
{
return static::where('id', '>', $id)->first();
}
// UserController.php
$nextUser = User::findNext($id);
// view
Next
Lazy approach :
// view
Next
// routes.php (should be optimized, this is just to show the idea)
Route::get('users/{user}/next', function($id) {
$nextUser = User::findNext($id);
return Redirect::to('user/' . $id);
});
// yourModel.php
public function previous()
{
return $this->find(--$this->id);
}
public function next()
{
return $this->find(++$this->id);
}
Works like magic, you can chain it:
$prevprev = Model::find($id)->previous()->previous();
$nextnext = Model::find($id)->next()->next();
First, get a record out of the database.
$post = Post::where('slug', $slug)->first();
With a database record, we can get the previous record where the record id is less than the id stored inside $post order by the id in descending order and use first() to get a single record back.
$previous = Post::where('id', '<', $post->id)->orderBy('id','desc')->first();
To get the next record it's almost the same query, this time get the record where the id is more than the id stored in $post.
$next = Post::where('id', '>', $post->id)->orderBy('id')->first();
Controller:
public function show($id)
{
// get the current user
$user = User::find($id);
// get previous user id
$previous = User::offset($user->id-2)->first();
// get next user id
$next = User::offset($user->id)->first();
return View::make('users.show')->with('previous', $previous)->with('next', $next);
}
i developed the code.
it work all times, even if we don't have any next or prev post
public function nextPost($table, $id)
{
$next = DB::table($table)->where('id', '>', $id)->orderBy('id','asc')->first();
if(!$next)
$next = DB::table($table)->orderBy('id','asc')->first();
return $next;
}
public function prevPost($table, $id)
{
$prev = DB::table($table)->where('id', '<', $id)->orderBy('id','desc')->first();
if(!$prev)
$prev = DB::table($table)->orderBy('id','desc')->first();
return $prev;
}