Subsequent HTML not being displayed after PHP call - php

Question

I am relatively new to PHP programming. I am building a small crud app (to-do list) to be exact for practice. I am working on fleshing out the UI and testing how information displays from my database on the page.
When a user logs in, they are shown a table of all the items they have saved.
table listing items
<div class="container">
<table class="table">
<tr>
<th>Completed</th>
<th>Description</th>
<th>Actions</th>
</tr>
<tr>
<td colspan="3"></td>
</tr>
<?php
$document_get = mysql_query("SELECT * FROM todolist WHERE user_id='$user_id' ORDER BY id DESC");
while($match_value = mysql_fetch_array($document_get)) {
?>
<tr>
<td>
Hi
</td>
</tr>
</table>
<?php
}
?>
</div>
php call to display list item
<?php
$document_get = mysql_query("SELECT * FROM todolist WHERE user_id='$user_id' ORDER BY id DESC");
while($match_value = mysql_fetch_array($document_get)) {
?>
Anything under this PHP request does not show up for some reason. I have looked at other posts where people have mentioned the same thing but I did not see anything specific that matched my issue per say.

Answer 1

Try to alter your query from:
$document_get = mysql_query("SELECT * FROM todolist WHERE user_id='$user_id' ORDER BY id DESC");
to
$document_get = mysql_query("SELECT * FROM todolist WHERE user_id='".$user_id."' ORDER BY id DESC");

Answer 2

mysql_fetch_array returns an array. The structure of your while statement will not have the outcome that you desire. The while loop will continue to be true forever because nothing is changing in the while condition.
This should have the effect closer to what you are looking for:
$document_get = mysql_query("SELECT * FROM todolist WHERE user_id='$user_id' ORDER BY id DESC");
$match_value = mysql_fetch_array($document_get);
foreach ($match_value as $value){
//Do something
}
As a side note - I would highly recommend using PDO and not putting php in-line with html. Tutorial here: https://phpdelusions.net/pdo
If you use PDO your loop would look more like this:
while($row = $st->fetch(PDO::FETCH_ASSOC)){
//Do something
}

Answer 3

enter code here <?php
$document_get = mysql_query("SELECT * FROM todolist WHERE user_id='$user_id' ORDER BY id DESC");
while($match_value = mysql_fetch_array($document_get)) {
echo "
<tr>
<td>
Hi
</td>
</tr>
";
}
echo " </table>";
?>
Do the whole thing in php using echo to display the table elemts and Hi. Remove the extra php tags so loop and echo all php. Also look at security issues mentioned in comments. By the way, I moved the table end tag outside loop after reading comment below the question.