I Have two tables "Personal_data" and "Students", Student has Personal_data.
I used Gii to generate the code for views, controlers and models, and I need to show all "Personal_data" from "Students" in a GridView, but i cant get it.
Code from models/PersonalDataSearch.php
public function search($params)
{
$query = PersonalData::find()->joinWith('Students'])->all();
$dataProvider = new ActiveDataProvider([
'query' => $query,
]);
$this->load($params);
if (!$this->validate()) {
return $dataProvider;
}
$query->andFilterWhere([
'id' => $this->id,
'document' => $this->document,
'telephone' => $this->telephone,
'direction' => $this->direction,
'sex' => $this->sex,
]);
$query->andFilterWhere(['like', 'names', $this->names])
->andFilterWhere(['like', 'lastNames', $this->lastNames])
->andFilterWhere(['like', 'email', $this->email])
->andFilterWhere(['like', 'movile', $this->movile]);
return $dataProvider;
}
Code from controllers/PersonalDataController.php
public function actionIndex()
{
$searchModel = new PersonalDataSearch();
$dataProvider = $searchModel->search(Yii::$app->request->queryParams);
return $this->render('index', [
'searchModel' => $searchModel,
'dataProvider' => $dataProvider,
]);
}
Code from views/personal-data/index.php
<?= GridView::widget([
'dataProvider' => $dataProvider,
'filterModel' => $searchModel,
'columns' => [
['class' => 'yii\grid\SerialColumn'],
'names',
'lastNames',
'email:email',
'movile',
['class' => 'yii\grid\ActionColumn'],
],
]); ?>
This view originally show all rows from Personal_data table from all registered people, but I want just show Personal_Data from Students, I added this line:
$query = PersonalData::find()->joinWith('Students'])->all();
and I have this error:
PHP Fatal Error – yii\base\ErrorException
Call to a member function andFilterWhere() on array
how can i solve this problem?
Remove ->all() from
$query = PersonalData::find()->joinWith('Students'])->all();
Data provider is taking care of fetching the data from DB, you just need to build the query (all() is fetching the data). With just a query you can add filters to it so there will be no error for andFilterWhere()
Related
I want to use Select2 dr as filter in Yii Grid view, but it doesn't filter at all, only refreshes the page.
I take the data from 2 tables - from accounts I take only user_id, and from credits I take everything else. And every filter works, except And the 'user_id' one.
<?php
echo GridView::widget(
[
'dataProvider' => $dataProvider,
'filterModel' => $searchModel,
'columns' => [
[
'attribute' => 'wp_id',
'value' => 'accounts.user_id',
'filter' => Select2::widget(
[
'model' => $searchModel,
'attribute' => 'wp_id',
'data' => ArrayHelper::map(Accounts::find()->all(), 'wp_id', 'user_id'),
'options' => ['placeholder' => ' --Filter by user id-- '],
'language' => 'en',
'pluginOptions' => [
'allowClear' => true,
],
]
),
],
],
]
); ?>
Here is the action in the controller.
<?php
public function actionIndex()
{
$searchModel = new CreditsSearch();
$dataProvider = $searchModel->search(Yii::$app->request->queryParams);
return $this->render('index', [
'searchModel' => $searchModel,
'dataProvider' => $dataProvider,
]);
} ?>
And this is the search model method
<?php
public function search($params)
{
$query = Credits::find()->with('accounts');
$dataProvider = new ActiveDataProvider([
'query' => $query
]);
$this->load($params);
if (!$this->validate()) {
// uncomment the following line if you do not want to return any records when validation fails
// $query->where('0=1');
return $dataProvider;
}
if(!empty($this->user_id)) {
$query->andFilterWhere(['=', 'accounts.user_id', $this->user_id]);
}
// grid filtering conditions
$query->andFilterWhere([
'user_id' => $this->user_id,
'wp_id' => $this->wp_id,
'credits_bought' => $this->credits_bought,
'purchase_date' => $this->purchase_date,
'id' => $this->id,
]);
return $dataProvider;
}
} ?>
Thanks in advance!
Because you are passing the wp_id under the GridView filter and selecting the wp_id from the Accounts model as the value of the select2-dropdown
ArrayHelper::map(Accounts::find()->all(), 'wp_id', 'user_id')
Although it is confusing that you use the gridview column attribute wp_id and use the select2 to filter the user_id for the same column but if you are looking to do that you might need to change the above to
ArrayHelper::map(Accounts::find()->all(), 'user_id', 'wp_id')
I have a relation between User and Thesis and my dataProvider just displays user attributes and not thesis'ones in the Gridview. Is there a better way to print join attributes than: ['attribute'] => ['table.attribute']?
model:
public function search($params)
{
$query = Request::find()->joinWith('user')->joinWith('thesis')->where(['thesis.staff'=> Yii::$app->user->identity->id]);
$dataProvider = new ActiveDataProvider([
'query' => $query,
]);
$this->load($params);
if (!$this->validate()) {
// uncomment the following line if you do not want to return any records when validation fails
// $query->where('0=1');
return $dataProvider;
}
view:
<?= GridView::widget([
'dataProvider' => $dataProvider,
'filterModel' => $searchModel,
'columns' => [
['class' => 'yii\grid\SerialColumn'],
//'id',
'title',
['attribute' => 'thesis',
'value' => 'thesis.title'],
//'company',
'description:ntext',
'duration',
['attribute' => 'user'
'value' => 'user.id'],
//'requirements',
//'course',
'n_person',
'ref_person',
'is_visible:boolean',
//'created_at',
//'staff',
['class' => 'yii\grid\ActionColumn'],
],
]); ?>
controller:
public function actionIndex()
{
$searchModel = new SearchRequest();
$dataProvider = $searchModel->search(Yii::$app->request->queryParams);
return $this->render('index', [
'searchModel' => $searchModel,
'dataProvider' => $dataProvider,
]);
}
You need to add the relation getters on your model.
On your Thesis model, you need to add something like
public function getUser0 () {
return $this->hasOne(\your\user\model\location\User::className(), ['id' => 'user']);
}
Having this on your model will populate via lazy-load the user relation when you call Thesis::user0, in your case, something like this:
<?= GridView::widget([
'dataProvider' => $dataProvider,
'filterModel' => $searchModel,
'columns' => [
['class' => 'yii\grid\SerialColumn'],
/// ---- other attributes
['attribute' => 'user0.name'],
/// ---- other attributes
],
]); ?>
Is better to add your code after $this->load($params);
My example is:
.
.
.
$this->load($params);
if (!$this->validate()) {
// uncomment the following line if you do not want to return any records when validation fails
// $query->where('0=1');
return $dataProvider;
}
$query->joinWith('user');
$query->joinWith('thesis');
$query->andFilterWhere(['thesis.staff'=> Yii::$app->user->identity->id]);
.
.
.
i want to join my company table name to employee id. here my code in
employee model
public function attributeLabels()
{
return [
'id' => 'ID',
//'company_id' => 'Company ID',
'emp_name' => 'Emp Name',
'emp_email' => 'Emp Email',
'emp_salery' => 'Emp Salery',
];
}
public function getCompany()
{
return $this->hasOne(Company::className(),['id' => 'company_id']);
}
in index file i use this code
<?php PJax::begin();?>
<?= GridView::widget([
'dataProvider' => $dataProvider,
'filterModel' => $searchModel,
'columns' => [
//['class' => 'yii\grid\SerialColumn'],
//'id',
[
'attribute' => 'company_id',
'value' => 'company.name',
],
'emp_name',
'emp_email:email',
'emp_salery',
['class' => 'yii\grid\ActionColumn'],
],
]); ?>
<?php PJax::end();?></div>
in employee search table i use this code
public function search($params)
{
$query = Employee::find();
$query->joinWith(['company']);
// add conditions that should always apply here
$dataProvider = new ActiveDataProvider([
'query' => $query,
]);
$this->load($params);
if (!$this->validate()) {
// uncomment the following line if you do not want to return any records when validation fails
$query->where('0=1');
return $dataProvider;
}
// grid filtering conditions
$query->andFilterWhere([
'id' => $this->id,
]);
$query->andFilterWhere(['like', 'company_id', $this->company_id])
->andFilterWhere(['like', 'emp_name', $this->emp_name])
->andFilterWhere(['like', 'emp_email', $this->emp_email])
->andFilterWhere(['like', 'emp_salery', $this->emp_salery])
->andFilterWhere(['like', 'Company.name', $this->company_id])
->andFilterWhere(['like', 'company.name', $this->company])
;
return $dataProvider;
}
http://localhost/test/web/employee/
is shows in company field (not set)
pls help me
you can do this in two difference way : 1 . If you want use active record you must set property in first model you want to select it and join table with that like:
public $pin;
then when you get data you can access to pin in second table
the second way is you use asArray() that return all off data in both table
$model = News::find()->leftJoin('comment', 'news.id = comment.news_id')->asArray()->all();
then you can use it in your gridview
You should add a getter eg:getCompanyname()n your base model
......
public function attributeLabels()
{
return [
'id' => 'ID',
//'company_id' => 'Company ID',
'emp_name' => 'Emp Name',
'emp_email' => 'Emp Email',
'emp_salery' => 'Emp Salery',
'companyName' => 'Company Name')
];
}
public function getCompany()
{
return $this->hasOne(Company::className(),['id' => 'company_id']);
}
You should add a getter for company name
/*
Getter for company name
*/
public function getCommpanyName() {
return $this->company->name;
}
and in your gridview you should use the new get name (companyName)
<?= GridView::widget([
'dataProvider' => $dataProvider,
'filterModel' => $searchModel,
'columns' => [
'companyName',
'emp_name',
'emp_email:email',
'emp_salery',
['class' => 'yii\grid\ActionColumn'],
],
]); ?>
see this for more complete samples
http://www.yiiframework.com/wiki/621/filter-sort-by-calculated-related-fields-in-gridview-yii-2-0/
The following code is used to display gridview but it shows "data provider" error.
MODELS:
Subcategory.php:
public function getCountries()
{
return $this->hasOne(Subcategories::className(),['id'=>'catid']);
}
VIEW:
subcategory.php:
i have added this following coding to view the saved data in a grid view.
<?= GridView::widget([
'dataProvider' => $dataProvider,
'filterModel' => $searchModel,
'columns'=>[
['class'=>'yii\grid\SerialColumn'],
'id',
'categoryname',
[
'attribute' => subcategory,
'value'=>getCountries.subcatname,
],
['class'=>'yii\grid\ActionColumn'],
],
]); ?>
CONTROLLER
public function actionView2()
{
$dataProvider = new ActiveDataProvider([
'query' => Subcategory::find(),
'pagination' => [
'pageSize' => 20
]
]);
$posts = $dataProvider->getModels();
return $this->render('subcategory' [
'dataProvider' => $dataProvider,
]);
}
I have applied this coding but I get the following error:
PHP Notice – yii\base\ErrorException Undefined variable: dataProvider
I have two tables staff with columns id, name and attendance. staff_id is used as foreign key in attendance table.
I want to display staff name in attendance gridview.
Attendance model:
public function getStaff()
{
return $this->hasOne(Staff::className(), ['id' => 'staff_id']);
}
public function getStaffName() {
return $this->staff->name;
}
and in index.php I used this code
<?= GridView::widget([
[
'attribute'=>'staff_id',
'value'=>'StaffName',
],
]); ?>
to get value of staff name. In this way I am getting staff name successfully but the problem is that when I make search for staff name in gridview it say "staff_id" should be integer as I define it as integer, but here I want to search name of staff instead of id.
How is this possible ? Thanks in advance
Add this in search model
$query->joinWith(['staff(relation name)']);
And add below code at filter query.
$query->andFilterWhere(['like', 'staff.name', $this->staff_id])
In staff.name that in staff is table name.
You can use this code
<?= GridView::widget([
'dataProvider' => $dataProvider,
'columns' => [
'staff.name',
],
]); ?>
OR use this code
<?= GridView::widget([
'dataProvider' => $dataProvider,
'columns' => [
[
'attribute' => 'staff.name',
'header' => 'Staff title'
'value'=> 'function ($model, $key, $index, $grid){
return $model->staff->name;
}'
],
],
]); ?>
OR in your code you can use this
<?= GridView::widget([
[
'attribute'=>'staff_id',
'value'=>'getStaffName()',
],
]); ?>
and for search you can watch this video Searching Related Table Data
You can use this code
1. relation in models
public function getCountry()
{
return $this->hasOne(Country::className(), ['id' => 'country_id']);
}
2. in grid view
<?= GridView::widget([
'dataProvider' => $dataProvider,
'filterModel' => $searchModel,
'columns' => [
['class' => 'yii\grid\SerialColumn'],
'id',
'state_name',
// 'country_id',
[
'attribute'=>'country_id',
'value'=>'country.country_name',
],
['class' => 'yii\grid\ActionColumn'],
],
]); ?>
3. Search Models
change country_id from integer to safe than change on search function
public function search($params)
{
$query = State::find();
$query->joinWith(['country']);
$dataProvider = new ActiveDataProvider([
'query' => $query,
]);
$this->load($params);
if (!$this->validate()) {
return $dataProvider;
}
$query->andFilterWhere([
'id' => $this->id,
]);
$query->andFilterWhere(['like', 'state_name', $this->state_name])
->andFilterWhere(['like', 'country.country_name', $this->country_id]);
return $dataProvider;
}