Create Table In PDO Transaction - php

Question

How can I fix this transaction so that the pdo query makes a new table in step #4?
The first three steps work, but I can't seem to get #4 to work.
STEPS
Finds a user with a chattingstatus of 0 in the database
Add a user into the database (with predetermined variables)
change the chattingstatus from 0 to 1 for both the user with a 0 status and the inserted user
4. Create a table with the id of both users as the title like this 2+13 (2 being the id and 13 being the id)
$userid = "123456";
$firstname = "Dae";
$oglang = "engs";
$status = 0;
$pdo->beginTransaction();
try{
// Find a user with a status of 0
$sql = "SELECT id FROM users WHERE chattingstatus = :status";
$stmt = $pdo->prepare($sql);
$stmt->execute(array(':status' => $status)
);
$freeuser = $stmt->fetchColumn();
//put the original user into the database with userid firstname and language
$sql = "INSERT INTO users (userid, firstname, oglang, chattingstatus) VALUES (:userid, :firstname, :oglang, :chattingstatus)";
$stmt = $pdo->prepare($sql);
$stmt->execute(array(':userid' => $userid, ':firstname' => $firstname, ':oglang' => $oglang, ':chattingstatus' => 0)
);
$ogID = $pdo->lastInsertId();
// change the chattingstatus of 0 of the free user to 1
$sql = "UPDATE users SET chattingstatus = 1 WHERE id = :freeuser";
$stmt = $pdo->prepare($sql);
$stmt->execute(array(':freeuser' => $freeuser)
);
//query 3 CHANGE STATUS OF ORIGINAL USER from 0 to 1
$sql = "UPDATE users SET chattingstatus = 1 WHERE userid = :oguser";
$stmt = $pdo->prepare($sql);
$stmt->execute(array(':oguser' => $userid)
);
//query 4: Make a table between the 2 users with their IDs
$table = $freeuser."+".$ogID;
$sql ="CREATE table $table(
ID INT( 11 ) AUTO_INCREMENT PRIMARY KEY,
Messages VARCHAR( 50 ) NOT NULL);";
$stmt = $pdo->exec($sql);
print("Created $table Table.\n");
$pdo->commit();
}
//Our catch block
catch(Exception $e){
//Print out the error message.
echo $e->getMessage();
//Rollback the transaction.
$pdo->rollBack();
}
Thanks in advance.

Answer 1

Since your table name includes the special character +, you need to put it in backticks to quote it.
$sql ="CREATE table `$table` (
ID INT( 11 ) AUTO_INCREMENT PRIMARY KEY,
Messages VARCHAR( 50 ) NOT NULL);";
You'll need to remember to put backticks around the table name whenever you use it in other queries. If you insist on having per-user tables like this, you might want to use a different character to connect them, like underscore.

Answer 2

Creating table in transation doesn't work in MySQL:
Some databases, including MySQL, automatically issue an implicit COMMIT when a database definition language (DDL) statement such as DROP TABLE or CREATE TABLE is issued within a transaction. The implicit COMMIT will prevent you from rolling back any other changes within the transaction boundary.
Source: https://www.php.net/manual/en/pdo.begintransaction.php