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I have an error probably because of the syntax and I cant find how to do it correctly.
This is my code
function myFunction($id = 'ID')
{
if (!$this->$id) {
// TO DO SOMETHING
}
}
I have the next error
Notice: Undefined property: Base::$ID ..... on line 278
I tried with
if (!$this->{$id}) {
but nothing
anyone know the correct syntax is. I cant find it on google neither.
You may use property_exists instead of using direct access if(!$this->$id):
function myFunction($id = 'ID')
{
if (!property_exists($this, $id)) {
// TO DO SOMETHING
}
}
If you are defining a property on your class, you should access it like such:
$this->id
not
$this->$id
I created an example how your code might work, and I kept the idea of accessing a property by a string. The first step is to have the class actually have a field named "ID". I set this field value in the constructor.
class My {
private $ID;
public function __construct($id) {
$this->ID = $id;
}
public function myFunction($id='ID'){
if(!property_exists($this, $id)){
echo "$id not found";
} else {
echo $this->$id;
}
}
}
$my = new My(4);
$my->myFunction();
Simply use
if(!$this->id) {
or
if(!$id) {
Try this method to get the output.
$this->id
or
$id
Related
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Closed 6 years ago.
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I have declared an array assigned to a variable called $PHPFiles but when I try to do anything with the array inside the function such as printing it in the example below I am getting an error stating it is undefined, any help in trying to solve this would be appreciated as I have tried making the variable global and public with no luck.
<?php
$PHPFiles = array();
$PHPFiles[] = 'sql1.php';
$PHPFiles[] = 'sql2.php';
$PHPFiles[] = 'sql3.php';
function push($PHPFiles) {
print_r(array_values($PHPFiles));
}
push();
?>
Cheers,
Jamie
Your function push requires an argument $PHPFiles, use it like this:
push($PHPFiles);
try this
<?php
$PHPFiles = array();
$PHPFiles[] = 'sql1.php';
$PHPFiles[] = 'sql2.php';
$PHPFiles[] = 'sql3.php';
function push($PHPFiles) {
print_r(array_values($PHPFiles));
}
// here you were not passed the variable while calling the `push()` method
push($PHPFiles);
?>
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Closed 6 years ago.
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My php code is:
<?php
class Product {
var $product_name;
var $retailer;
function __constructor($product, $retailer) {
$this->product_name = $product;
$this->retailer = $retailer;
}
function getProduct() {
return $this->product_name;
}
}
$product_arr = array();
for ($f = 0; $f < 100; $f++) {
array_push($product_arr, new Product("asd", "xcxcxc"));
}
print_r($product_arr);
?>
The code is pretty simple, I have a class called "Product", I build an array consists of 100 Product object, but when I tried to print the array, I found out all the object's product_name and retailer fields are empty. Not sure why this happens.
Wrong name:
function __constructor($product, $retailer) {
^^^
PHP's standard constructor name is simply __construct (no or). So you never actually called a constructor, which means your variable assignments never executed.
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Closed 7 years ago.
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I want to check if user is logged on site or not, so I made a function:
function isLogged()
{
if($_SESSION['logged']=='1')
{
return true;
}
elseif($_SESSION['logged']!=='1')
{
return false;
}
}
On my site Im trying to induce function like this:
if('isLogged')
{
echo 'yes';
}
else
{
echo 'no';
}
Even if $_SESSION['logged'] is set to 0 (I just checked by echo value), it returns "yes". What is wrong with this code?
You have to actual call the function, not check if the string returns true:
if(isLogged())
{
echo 'yes';
}
else
{
echo 'no';
}
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Closed 8 years ago.
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I want to use ternary operator to assign two different values to the class variable.
I have following code sample where i am getting fatal error.
class test {
public $data = (true) ? "working" : "not working"; //Parse error: syntax error, unexpected '(' in C:\xampp\htdocs\Faltu\test.php on line 15
function __construct() {
echo $this->data;
}
}
$test = new test();
I have tried without class and it's working fine but in class I'm getting error.
Can anyone guide me how to achieve this?
Thanks in advance
You may only assign constant values when declaring properties, you cannot perform logical operations, like a ternary.
You can perform your logic in your __construct function:
class test {
public $data = NULL;
function __construct() {
$this -> data = true ? "working" : "not working";
echo $this -> data; // working
}
}
$test = new test();
From the documentation:
This declaration may include an initialization, but this initialization must be a constant value--that is, it must be able to be evaluated at compile time and must not depend on run-time information in order to be evaluated.
it works have a look
class test {
public $data = NULL;
function __construct() {
echo $this -> data = true ? "working" : "not working"; //working
}
}
$test = new test();
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Closed 8 years ago.
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I was making a class in PHP for validation of a contact form, when I hit a problem. I eventually tracked it down to an array within the class, and wrote a test script to try to solve the problem:
<?php
class Object {
public $testArray = array(5);
function __construct() {
$testArray[] = 7;
}
function addNumber() {
$testArray[] = mt_rand(10,20);
}
function returnArray() {
return var_dump($testArray);
}
}
$object = new Object;
$object->addNumber();
echo($object->returnArray());
var_dump($object->testArray);
This outputs NULL array(1) { [0]=> int(5) }.
I am confused as to why this does not work. Eventually I would like the array to be private, but I can't find a way similar to get and set in C#. Any ideas?
Give this a go:
class Object {
public $testArray = array(5);
function __construct() {
$this->testArray[] = 7;
}
function addNumber() {
$this->testArray[] = mt_rand(10,20);
}
function returnArray() {
return var_dump($this->testArray);
}
}
You have to reference the class variable using $this - otherwise it'll try to set a variable local to the function you're in.
You can use PHP's magic __set() and __get() methods for similar functions to C# that you mentioned: PHP Overloading.
$testArray[] = mt_rand(10,20);
Should be:
$this->testArray[] = mt_rand(10,20);
$testArray is just another local variable (local to the function, no the class). If it has no value it is null. This is consistent with the output you're seeing. $object->testArray is never modified.
You have to access class variables using $this. So $testArray should be $this- >testArray.