How to create PHP array from MySQL table - php

Question

I have a MySQL table:
-------------------
|type_id|type_name|
-------------------
| 22 | Toyota |
| 22 | Mazda |
| 23 | Volvo |
| 23 | Man |
| 25 | Scania |
| 25 | Iveco |
| 25 | Fiat |
-------------------
which is created dynamically from user input. I want to create an array from the table using PHP like this:
array(
'22' => array('Toyota', 'Mazda'),
'23' => array('Volvo', 'Man'),
'25' => array('Scania', 'Iveco','Fiat'),
);
where array id will be type_id and elements will be type_name's of the type_id.I tried this:
$results = array();
while($line = mysqli_fetch_array($result, MYSQL_ASSOC))
{
$results[] = $line;
}
print_r($results);
But I am getting:
Array (
[0] => Array (
[type_id] => 22
[type_name] => Toyota
)
[1] => Array (
[type_name] => 22
[type_name] => Mazda
)
...so on
Please help!

Answer 1

You need to change your code a bit and it will work fine:-
$results = array();
while($line = mysqli_fetch_array($result, MYSQL_ASSOC)) {
$results[$line['type_id']][] = $line['Type_name']; //check change here
}
print_r($results);
Note:- check your column-names and correct them if any mistake is there.

Answer 2

Please replace your db name and table name in the code-
$conn = mysqli_connect("localhost","root","","dbname");
$query ="select * from table";
$exe = mysqli_query($conn,$query);
$input = array();
$type = array();
while ($result = mysqli_fetch_array($exe))
{
if(array_key_exists($result['type_id'], $input))
{
$type[] = $result['type_name'];
}
else
{
$type = array($result['type_name']);
}
$input[$result['type_id']] = $type;
}
echo "<pre>";
print_r($input);

Answer 3

select type_id and Type_name columns from table and in foreach loop do this:
$output = array();
foreach ($result as $item){
$output[$item['type_id']][] = $item['Type_name'];
}