I would like to count all the users who have the state "visible" and "ghost" like this :
public function getStatsUser() {
$data = self::whereIn('state', array('Visible', 'Ghost'))
->count();
return $data;
}
But i would like to have these data each month from the first user, like this :
['Month', 'Data'],
['December 2016', 4000],
['January 2017', 4600],
['February 2017', 11020],
['March 2017', 5400]
And for the date i have a row with "created_at" but not a specific row for the month.
I tried this, but it's not working
$data= self::select(DB::raw('count(*) as monthly_total'), DB::raw('MONTH(created_at) as month'))
->whereIn('state', array('visible', 'Ghost'))
->whereYear('created_at', '=', date('Y'))
->groupBy('month')
->count();
The error :
SQLSTATE[42S22]: Column not found: 1054 Champ 'month' inconnu dans group statement (SQL: select count(*) as aggregate from `oiseau` where `etat_actuel` in (Relaché, En convalescence) and year(`date_signalement`) = 2017 group by `month`)
Thanks for your help !
This should get you started:
self::selectRaw('CONCAT_WS(" ", MONTHNAME(created_at), YEAR(created_at)) as date, COUNT(*) as count')
->whereIn('state', array('visible', 'Ghost'))
->groupBy(DB::raw('YEAR(created_at)', MONTH(created_at)))
->get()
The query will return a Collection of objects with a date and a count.
Probably the most important part is to group by both the year and the month and you can use functions there instead of raw columns.
PS: This will get you Laravel Models from the self class, which they really aren't... so maybe replace the self with DB::table('users') or similar.
You can try like:
$data = self::whereIn('state', array('Visible', 'Ghost'))
->select(DB::raw('count(*) as monthly_total') , DB::raw('MONTH(created_at) month'))
->groupBy('month ')
->get();
Or try Join Query if Month is stored in other Table.
Related
I need to convert this query into Laravel query builder or ORM
SET #start_date = '2020-11-01';
SET #end_date = '2020-11-08';
SET #duration = CONVERT(#end_date, DATE) - CONVERT(#start_date, DATE);
SELECT item_id, days
FROM (
SELECT item_id, sum(end_date - start_date) AS days
FROM schedule WHERE start_date >= #start_date AND end_date <= #end_date
GROUP BY item_id) AS virtual
WHERE days = #duration;
(i use Laravel 8)
i could not find similar example I could analize and try by myself :(
i try this :
$res = DB::table('schedule')
->select('schedule.item_id' , DB::raw("SUM(schedule.end_date - schedule.start_date) as days"))
->where('start_date', '>=', $start_date)
->where('end_date', '<=', $end_date)
->groupBy('item_id')
->where('days', '=', $duration)
->get();
but i get error :
Column not found: 1054 Unknown column 'days' in 'where clause'
ok i know what is wrong
i tried to access 'days' column before it is created with AS
that column will be available after line ->get() is executed.
So I changed order of these 2 lines :
->where('days', '=', $duration)
->get();
to
->get()
->where('days', '=', $duration);
and now works :)
I have a query builder to select all users created in the last 12 months
$range = \Carbon\Carbon::now()->subYears(1);
$countUser = DB::table('users')
->select(DB::raw('month(created_at) as getMonth'),
DB::raw('year(created_at) as getYear'),
DB::raw('COUNT(*) as value'))
->where('created_at', '>=', $range)
->groupBy('getMonth','getYear')
->orderBy('getMonth', 'ASC')
->get();
This query works fine with MySQL, However, when I deploy it on Heroku which runs with PostgreSQL database it returns an error
column "getMonth" does not exist LINE 1: ...end date)", "extract(year from created_at)" order by "getMonth"... ^ (SQL: select extract(month from created_at) as getMonth, extract(year from created_at) as getYear, COUNT(*) as value from "users" where "created_at" >= 2019-10-01 03:16:43 group by "extract(month from created_at)", "extract(year from created_at)" order by "getMonth" asc)
I tried to search and figured out that postgest has a different statement to get month and year in created_at column and I change my code to this and it also returns the error not found column getMonth for the GroupBy()
$range = \Carbon\Carbon::now()->subYears(1);
$countUser = DB::table('users')
->select(DB::raw('extract(month from created_at) as getMonth'),
DB::raw('extract(year from created_at) as getYear'),
DB::raw('COUNT(*) as value'))
->where('created_at', '>=', $range)
->groupBy('getMonth','getYear')
->orderBy('getMonth', 'ASC')
->get();
Does PostgreSQL have any naming rules to set a name for a selected column or does it has any way to solve my problem?
Thanks for reading!
If you use mixed-case aliases in postgresql, they have to be quoted. Use get_month instead of getMonth, or use AS "getMonth" and groupBy('"getMonth"',...
I have a function that returns the count of sales each day. The problem with this approach is that I want the data to be stored by date but I am getting them in the following order:
01-Dec
02-Dec
03-Dec
03-Nov
04-Nov
05-Nov
etc.
I understand why that happens but I am not sure how to solve it. I can replace subMonth(1) with startofmonth which woul partially solve my problem but this is not what I want. I instead want to return the last 30 days ordered.
return DB::table('sales')
->select(\DB::RAW('DATE_FORMAT(created_at, "%d-%M") as date'), \DB::raw('COUNT(*) as count'))
->where('created_at', '>=', Carbon::now()->subMonth(1))
->orderBy('date')
->groupBy('date')
->get(['date', 'count'])
->keyBy('date')
->transform(function ($data) {
return $data->count;
});
I also tried orderBy('created_at') but it gives me the error below and I'd like to avoid changing the sql mode.
Syntax error or access violation: 1055 Expression #3 of SELECT list is not in GROUP BY clause and contains nonaggregated column 'x.sales.created_at' which is not functionally dependent on columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by
EDIT:
As requested, this the sql query of the return statement
select DATE_FORMAT(created_at, "%d-%M") as date, COUNT(*) as count from `sales` where `created_at` >= ? group by `date` order by `date` asc
i don't have much idea about your framework query syntax. but you can take one more column DATE_FORMAT(created_at, "%Y%m%d") AS order_column and apply order, and group by on column "order_column" and use column "data" while display data.
select DATE_FORMAT(created_at, "%Y%m%d") AS order_column, DATE_FORMAT(created_at, "%d-%M") as date, COUNT(*) as count from `sales` where `created_at` >= ? group by `order_column` order by `order_column` asc
return DB::table('sales')
->select(\DB::RAW('DATE_FORMAT(created_at, "%Y%m%d") AS order_column'),\DB::RAW('DATE_FORMAT(created_at, "%d-%M") as date'), \DB::raw('COUNT(*) as count'))
->where('created_at', '>=', Carbon::now()->subMonth(1))
->orderBy('order_column')
->groupBy('order_column')
->get(['date', 'count'])
->keyBy('date')
->transform(function ($data) {
return $data->count;
});
If you make this in 2 steps does it work?
Step1 in which you create date column:
$step1 = DB::table('sales') ->select(\DB::RAW('DATE_FORMAT(created_at, "%d-%M") as date')))
->where('created_at', '>=', Carbon::now()->subMonth(1))
->orderBy('date')
->get(['date', 'count'])
and after that you make the agregation:
$step2 = $step1->select('date'), \DB::raw('COUNT(date) as count'))
->groupBy('date') ->get(['date', 'count']) ->keyBy('date')
Hope it helps!
I'd like to get the difference between two dates on two tables. The uploads.published_at compared to the completed_guides.created_at
I keep getting an error which says:
SQLSTATE[42000]: Syntax error or access violation: 1582 Incorrect parameter count in the call to native function 'datediff' (SQL: select users.*,completed_guides.created_at as completed_at,uploads.published_at,datediff(HOUR, published_at, completed_at) from `users` inner join `uploads` on `users`.`id` = `uploads`.`user_id` inner join `completed_guides` on `uploads`.`id` = `completed_guides`.`upload_id` where `completed_guides`.`upload_id` = 2839 limit 10)
Here is my code. Any help would be appreciated.
$select = [
'users.*',
'completed_guides.created_at as completed_at',
'uploads.published_at',
'datediff(HOUR, published_at, completed_at) as date_diff'
];
return User::select(DB::raw(join(',', $select)))
->join('uploads', 'users.id', '=', 'uploads.user_id')
->join('completed_guides', 'uploads.id', '=', 'completed_guides.upload_id')
->where('completed_guides.upload_id', $this->id)
->take(10)
->get();
You can use Laravel Query Builder's whereRaw() like this:
return User::select(DB::raw(join(',', $select)))
->join('uploads', 'users.id', '=', 'uploads.user_id')
->join('completed_guides', 'uploads.id', '=', 'completed_guides.upload_id')
->where('completed_guides.upload_id', $this->id)
->whereRaw('datediff(uploads.published_at, completed_guides.completed_at) as date_diff')
->take(10)
->get();
To set the format of date you can use SQL method - date_format(date, format) like this:
->select(DB::raw("DATE_FORMAT(date_diff, '%b %d %Y %h:%i %p') as formatted_date_diff"));
See more about SQL Date Format
Hope this helps!
The one with units, is timestampdiff, not datediff.
timestampdiff(HOUR, published_at, completed_at) as date_diff
i'm trying to group my data by month and year.
$data ->select(DB::raw('count(id) as `data`'),DB::raw('YEAR(created_at) year, MONTH(created_at) month'))
->groupby('year','month')
->get();
The output is :
{
"data": 19215,
"year": 2016,
"month": 10
},
if i group only by month, i don't know from which year belong this month, my expected output is :
{
"clicks": 19215,
"month": 11-2016,
},
{
"clicks": 11215,
"month": 12-2016,
},
i want to do it in sql, not in php.
You can try as:
->select(DB::raw('count(id) as `data`'), DB::raw("DATE_FORMAT(created_at, '%m-%Y') new_date"), DB::raw('YEAR(created_at) year, MONTH(created_at) month'))
->groupby('year','month')
->get();
Note: This is solution based on eloquent, and yes, it not the best approach, but as the question is, this is using eloquent. If you want faster way, you can do it with raw query.
If you want to group your results for example by year, you can use closure where you will parse your datetime to desired format (year or month).
Here is example of the code:
$res= ModelName::where('someColumn','test')
->get()
->groupBy(function($val) {
return Carbon::parse($val->created_at)->format('Y');
});
$result = ModelName::selectRaw('year(created_at) year, monthname(created_at) month, count(*) data')
->groupBy('year', 'month')
->orderBy('year', 'desc')
->get();
for latest version of mysql, the accepted answer will give error, so instead try
$data
->selectRaw("
count(id) AS data,
DATE_FORMAT(created_at, '%Y-%m') AS new_date,
YEAR(created_at) AS year,
MONTH(created_at) AS month
")
->groupBy('new_date')
->get();
ref: https://dev.mysql.com/doc/refman/8.0/en/date-and-time-functions.html#function_date-format
The answer by #Amit Gupta is a good, but it isn't working >= MySQL 5.7/MariaDB 10.2 and calls the error:
Syntax error or access violation: 1055 Expression #2 of SELECT list is not in GROUP BY clause and contains nonaggregated column
To solve that issue, you can use eg. MIN() on the nonaggregated column:
->select(
DB::raw("
count(id) as data,
MIN(DATE_FORMAT(created_at, '%m-%Y')) as new_date,
YEAR(created_at) year,
MONTH(created_at) month
")
)
->groupBy('year', 'month')
->get();
$data ->select(DB::raw('count(id) as `data`'),DB::raw('YEAR(created_at) year'),DB::raw('MONTH(created_at) month'))
->groupBy(DB::raw('YEAR(created_at)'), DB::raw('MONTH(created_at)'))
->get();
=>this might help someone in 2019
$date = "2019-06-16";
return date('m', strtotime($date)); //this return you 06(edited)
so you can do foreach by this method , so you don't need to do the all sql things..