Trying to delete all rows in database that do not match array - php

Question

I am trying to figure out how to delete all ids in the database that do not exist in an array. I have been trying to use NOT IN in my query but I am not sure why it wont work when running it in a script the same way it works when I manually enter it into mysql. Here is an example.
mysqli_query($con, "DELETE FROM table WHERE id NOT IN ($array)");
$array is a list of ids from a json api. I use CURL to fetch the ids and I am trying to delete all ids in the database that do not match the ids in $array.
First I use another simple CURL script to scrape the apis and insert the ids found into the database and what I am trying to do here is basically make a link/data checker.
If the ids in the database are not found in the array when rechecking them then I want them deleted.
I thought that the query above would work perfect but for some reason it doesn't. When the query is ran from a script the mysql log shows the queries being ran as this.
Example:
DELETE FROM table WHERE id NOT IN ('166')
or this when I am testing multiple values.
DELETE FROM table WHERE id NOT IN ('166', '253', '3324')
And what happens is it deletes every row in the table every time. I don't really understand because if I copy/paste the same query from the log and run it manually myself it works perfect.
I have been trying various ways of capturing the array data such as array_column, array_map, array_search and various functions I have found but the end result is always the same.
For right now, just for testing I am using these 2 bits of code for testing 2 different apis which gives me the same sql query log output as above. The functions used are just a couple random ones that I found.
//$result is the result from CURL using json_decode
function implode_r($g, $p) {
return is_array($p) ?
implode($g, array_map(__FUNCTION__, array_fill(0, count($p), $g), $p)) :
$p;
}
foreach ($result['data'] as $info){
$ids = implode_r(',', $info['id']);
mysqli_query($con, "DELETE FROM table WHERE id NOT IN ($ids)");
}
And
$arrayLength = count($result);
for($i = 0; $i < $arrayLength; $i++) {
mysqli_query($con, "DELETE FROM table WHERE id NOT IN ('".$result[$i]['id']."')");
}
If anyone knows what is going on i'd appretiate the help or any suggestions on how to achieve the same result. I am using php 7 and mysql 5.7 with innodb tables if that helps.

Answer 1

It probably doesn't work because your IN value is something like this
IN('1,2,3,4');
When what you want is this
IN('1','2','3','4')
OR
IN( 1,2,3,4)
To get this with implode include the quotes like this
$in = "'".implode("','", $array)."'";
NOTE whenever directly inputting variables into SQL there is security Implications to consider such as SQLInjection. if the ID's are from a canned source you're probably ok, but I like to sanitize them anyway.

Answer 2

You can't mix array and string.
This works:
mysqli_query($con, "DELETE FROM table WHERE id NOT IN (".implode(',', $ids).")");