PHP issues displaying image gallery - php

Question

I'm trying to make a gallery with PHP. I want to get all of the images out of a folder and then display them in rows of 3. I kind of have it working but the first 2 images mess up.
This is what I've tried:
$images = glob("$_SERVER[DOCUMENT_ROOT]/gallery/img*.{png,jpg,gif}", GLOB_BRACE);
echo '<table width="100%>';
$count="-1";
foreach($images as $image) {
if ($count%3 == 1) {
echo '<tr>';
}
$url=str_replace("/home/#####/public_html/gallery", "", $image);
echo '<td width="33%"><div class="gallery">';
echo '<img onclick="window.location='.$url.'" src="'.$url.'" alt="Image Alt" width="400" height="300">';
echo '</div></td>';
if ($count%3 == 3) {
echo '</tr>';
}
//echo $count;
$count++;
//echo "|".$count;
}
if ($count%3 != 1) {
echo ',</tr>';
}
echo '</table>';
//echo print_r($images);
This works kind of but it makes this:
(These are just stock photos, the real photos are a bit.. offensive)
I know I'm doing something wrong but I don't know what!

Answer 1

There were some errors in your code (see comments). Maybe try this:
$images = glob("$_SERVER[DOCUMENT_ROOT]/gallery/img/*.{png,jpg,gif}", GLOB_BRACE);
echo '<table style="width:100%">'; // error was here (missing ")
$count = 0; // error was here (counter = "-1")
foreach ($images as $image) {
// start <tr> on 0
if ($count == 0) {
echo '<tr>';
}
$url=str_replace("/home/#####/public_html/gallery/", "", $image);
echo '<td style="width:33%"><div class="gallery">'; // alternative
echo '<img onclick="window.location='.$url.'" src="'.$url.'" alt="Image Alt" width="400" height="300">';
echo '</div></td>';
// end tr at 3
if ($count == 3) {
echo '</tr>';
// reset counter
$count = -1;
}
$count++;
}
echo '</table>';

Answer 2

I think you have trouble with your $count initial value.
Try this:
$count="3";
foreach($images as $image) {
if ($count%3 == 0) {
echo '<tr>';
}
$count++;
...