sort array based on other array sort - php

Question

I have an array as follows:
$aq=['jonathan','paul','andy','rachel'];
Then I have an array as follows:
$bq=['rachel','andy','jonathan'];
What I need is to use the ordering of the first array to sort my second array.
So for this instance, the resulting sorted array should be:
$cq=['jonathan','andy','rachel'];
I started working on a solution that uses the highest key as the top value (the head of the array) because what Im looking for is the top value but that ran into issues and seemed more like a hack so i think sorting is what im looking for.
Is there a simple function in php that can sort my data based on my first array and there respective positions in the array

Answer 1

please try this short and clean solution using array_intersect:
$aq = ['jonathan','paul','andy','rachel'];
$bq = ['rachel','andy','jonathan'];
$cq = array_intersect($aq, $bq);
var_export($cq);
the output will be :
array ( 0 => 'jonathan', 2 => 'andy', 3 => 'rachel', )

Answer 2

You'll have to use a custom sort function. Here we grab the keys of corresponding entries in the "ordering" array and use them to order the working array.
In this example, we give up (return 0) if the key doesn't exist in the ordering array; you may wish to customize that behavior, but this should give you the general idea.
$order = ['jonathan','paul','andy','rachel'];
$arrayToSort =['rachel','andy','jonathan'];
usort($arrayToSort,function($a,$b) use ($order){
if( ! array_key_exists($a,$order) ) return 0;
if( ! array_key_exists($b,$order) ) return 0;
if( array_search($a,$order) > array_search($b,$order)
return 1;
return -1;
});