Number to Words Conversion (Indian Rupee) decimal String issue in php - php

I using Following function to convert numbers to word Conversion in PHP.
I Expected Result.
one thousand five hundred and forty two Rupees twenty six Paise Only
but, its Display
one thousand five hundred and forty two Rupees two six Paise Only
My Function is :
function displaywords($number){
$no = round($number);
$point = round($number - $no, 2) * 100;
$hundred = null;
$digits_1 = strlen($no);
$i = 0;
$str = array();
$words = array('0' => '', '1' => 'one', '2' => 'two',
'3' => 'three', '4' => 'four', '5' => 'five', '6' => 'six',
'7' => 'seven', '8' => 'eight', '9' => 'nine',
'10' => 'ten', '11' => 'eleven', '12' => 'twelve',
'13' => 'thirteen', '14' => 'fourteen',
'15' => 'fifteen', '16' => 'sixteen', '17' => 'seventeen',
'18' => 'eighteen', '19' =>'nineteen', '20' => 'twenty',
'30' => 'thirty', '40' => 'forty', '50' => 'fifty',
'60' => 'sixty', '70' => 'seventy',
'80' => 'eighty', '90' => 'ninety');
$digits = array('', 'hundred', 'thousand', 'lakh', 'crore');
while ($i < $digits_1) {
$divider = ($i == 2) ? 10 : 100;
$number = floor($no % $divider);
$no = floor($no / $divider);
$i += ($divider == 10) ? 1 : 2;
if ($number) {
$plural = (($counter = count($str)) && $number > 9) ? 's' : null;
$hundred = ($counter == 1 && $str[0]) ? ' and ' : null;
$str [] = ($number < 21) ? $words[$number] .
" " . $digits[$counter] . $plural . " " . $hundred
:
$words[floor($number / 10) * 10]
. " " . $words[$number % 10] . " "
. $digits[$counter] . $plural . " " . $hundred;
} else $str[] = null;
}
$str = array_reverse($str);
$result = implode('', $str);
$points = ($point) ?
"" . $words[$point / 10] . " " .
$words[$point = $point % 10] : '';
if($points != ''){
echo $result . "Rupees " . $points . " Paise Only";
} else {
echo $result . "Rupees Only";
}
}
$ins=1542.26;
echo displaywords($ins);

function displaywords($number){
$no = (int)floor($number);
$point = (int)round(($number - $no) * 100);
$hundred = null;
$digits_1 = strlen($no);
$i = 0;
$str = array();
$words = array('0' => '', '1' => 'one', '2' => 'two',
'3' => 'three', '4' => 'four', '5' => 'five', '6' => 'six',
'7' => 'seven', '8' => 'eight', '9' => 'nine',
'10' => 'ten', '11' => 'eleven', '12' => 'twelve',
'13' => 'thirteen', '14' => 'fourteen',
'15' => 'fifteen', '16' => 'sixteen', '17' => 'seventeen',
'18' => 'eighteen', '19' =>'nineteen', '20' => 'twenty',
'30' => 'thirty', '40' => 'forty', '50' => 'fifty',
'60' => 'sixty', '70' => 'seventy',
'80' => 'eighty', '90' => 'ninety');
$digits = array('', 'hundred', 'thousand', 'lakh', 'crore');
while ($i < $digits_1) {
$divider = ($i == 2) ? 10 : 100;
$number = floor($no % $divider);
$no = floor($no / $divider);
$i += ($divider == 10) ? 1 : 2;
if ($number) {
$plural = (($counter = count($str)) && $number > 9) ? 's' : null;
$hundred = ($counter == 1 && $str[0]) ? ' and ' : null;
$str [] = ($number < 21) ? $words[$number] .
" " . $digits[$counter] . $plural . " " . $hundred
:
$words[floor($number / 10) * 10]
. " " . $words[$number % 10] . " "
. $digits[$counter] . $plural . " " . $hundred;
} else $str[] = null;
}
$str = array_reverse($str);
$result = implode('', $str);
if ($point > 20) {
$points = ($point) ?
"" . $words[floor($point / 10) * 10] . " " .
$words[$point = $point % 10] : '';
} else {
$points = $words[$point];
}
if($points != ''){
echo $result . "Rupees " . $points . " Paise Only";
} else {
echo $result . "Rupees Only";
}
}
echo displaywords(1542.26);
echo "\n";
echo displaywords(1542.58);

I reworked the code slightly to a more efficient code. (I think).
It uses less variables, no imploding, no array functions, less ifs, and less calculations.
It explodes the number at . and makes it an array and handles them seperatly in the same code ($val).
Then it takes each number of the string and str_pads it to it's "main number" (don't know a better way of saying it).
So 1526, it looks at the 1, and makes it 1000 with str_pad.
If it's above 90 use both $words and $digits.
This code will also handle numbers like 0.50, or 10.
function displaywords($number){
$words = array('0' => '', '1' => 'one', '2' => 'two',
'3' => 'three', '4' => 'four', '5' => 'five', '6' => 'six',
'7' => 'seven', '8' => 'eight', '9' => 'nine',
'10' => 'ten', '11' => 'eleven', '12' => 'twelve',
'13' => 'thirteen', '14' => 'fourteen',
'15' => 'fifteen', '16' => 'sixteen', '17' => 'seventeen',
'18' => 'eighteen', '19' =>'nineteen', '20' => 'twenty',
'30' => 'thirty', '40' => 'forty', '50' => 'fifty',
'60' => 'sixty', '70' => 'seventy',
'80' => 'eighty', '90' => 'ninety');
$digits = array('', '', 'hundred', 'thousand', 'lakh', 'crore');
$number = explode(".", $number);
$result = array("","");
$j =0;
foreach($number as $val){
// loop each part of number, right and left of dot
for($i=0;$i<strlen($val);$i++){
// look at each part of the number separately [1] [5] [4] [2] and [5] [8]
$numberpart = str_pad($val[$i], strlen($val)-$i, "0", STR_PAD_RIGHT); // make 1 => 1000, 5 => 500, 4 => 40 etc.
if($numberpart <= 20){ // if it's below 20 the number should be one word
$numberpart = 1*substr($val, $i,2); // use two digits as the word
$i++; // increment i since we used two digits
$result[$j] .= $words[$numberpart] ." ";
}else{
//echo $numberpart . "<br>\n"; //debug
if($numberpart > 90){ // more than 90 and it needs a $digit.
$result[$j] .= $words[$val[$i]] . " " . $digits[strlen($numberpart)-1] . " ";
}else if($numberpart != 0){ // don't print zero
$result[$j] .= $words[str_pad($val[$i], strlen($val)-$i, "0", STR_PAD_RIGHT)] ." ";
}
}
}
$j++;
}
if(trim($result[0]) != "") echo $result[0] . "Rupees ";
if($result[1] != "") echo $result[1] . "Paise";
echo " Only";
}
$ins=1516.16;
echo displaywords($ins);
https://3v4l.org/rFvbJ
added some comments to the code.
Noticed it was giving wrong outputs on larger numbers, corrected.

<?php
set_error_handler('exceptions_error_handler');
function exceptions_error_handler($severity, $message, $filename, $lineno) {
if (error_reporting() == 0) {
return;
}
if (error_reporting() & $severity) {
throw new ErrorException($message, 0, $severity, $filename, $lineno);
}
}
function convert_number_to_words($number) {
$hyphen = '-';
$conjunction = ' and ';
$separator = ', ';
$negative = 'negative ';
$decimal = ' point ';
$dictionary = array(
0 => 'zero',
1 => 'one',
2 => 'two',
3 => 'three',
4 => 'four',
5 => 'five',
6 => 'six',
7 => 'seven',
8 => 'eight',
9 => 'nine',
10 => 'ten',
11 => 'eleven',
12 => 'twelve',
13 => 'thirteen',
14 => 'fourteen',
15 => 'fifteen',
16 => 'sixteen',
17 => 'seventeen',
18 => 'eighteen',
19 => 'nineteen',
20 => 'twenty',
30 => 'thirty',
40 => 'fourty',
50 => 'fifty',
60 => 'sixty',
70 => 'seventy',
80 => 'eighty',
90 => 'ninety',
100 => 'hundred',
1000 => 'thousand',
100000 => 'lakh',
10000000 => 'crore'
);
if (!is_numeric($number)) {
return false;
}
if (($number >= 0 && (int) $number < 0) || (int) $number < 0 - PHP_INT_MAX) {
// overflow
trigger_error(
'convert_number_to_words only accepts numbers between -' . PHP_INT_MAX . ' and ' . PHP_INT_MAX,
E_USER_WARNING
);
return false;
}
if ($number < 0) {
return $negative . convert_number_to_words(abs($number));
}
$string = $fraction = null;
if (strpos($number, '.') !== false) {
list($number, $fraction) = explode('.', $number);
}
switch (true) {
case $number < 21:
$string = $dictionary[$number];
break;
case $number < 100:
$tens = ((int) ($number / 10)) * 10;
$units = $number % 10;
$string = $dictionary[$tens];
if ($units) {
$string .= $hyphen . $dictionary[$units];
}
break;
case $number < 1000:
$hundreds = $number / 100;
$remainder = $number % 100;
$string = $dictionary[$hundreds] . ' ' . $dictionary[100];
if ($remainder) {
$string .= $conjunction . convert_number_to_words($remainder);
}
break;
case $number < 100000:
$thousands = ((int) ($number / 1000));
$remainder = $number % 1000;
$thousands = convert_number_to_words($thousands);
$string .= $thousands . ' ' . $dictionary[1000];
if ($remainder) {
$string .= $separator . convert_number_to_words($remainder);
}
break;
case $number < 10000000:
$lakhs = ((int) ($number / 100000));
$remainder = $number % 100000;
$lakhs = convert_number_to_words($lakhs);
$string = $lakhs . ' ' . $dictionary[100000];
if ($remainder) {
$string .= $separator . convert_number_to_words($remainder);
}
break;
case $number < 1000000000:
$crores = ((int) ($number / 10000000));
$remainder = $number % 10000000;
$crores = convert_number_to_words($crores);
$string = $crores . ' ' . $dictionary[10000000];
if ($remainder) {
$string .= $separator . convert_number_to_words($remainder);
}
break;
default:
$baseUnit = pow(1000, floor(log($number, 1000)));
$numBaseUnits = (int) ($number / $baseUnit);
$remainder = $number % $baseUnit;
try
{
$string = convert_number_to_words($numBaseUnits) . ' ' . $dictionary[$baseUnit];
}catch(Exception $e)
{
return "Value too large";
}
if ($remainder) {
$string .= $remainder < 100 ? $conjunction : $separator;
$string .= convert_number_to_words($remainder);
}
break;
}
if (null !== $fraction && is_numeric($fraction)) {
$string .= $decimal;
$words = array();
foreach (str_split((string) $fraction) as $number) {
$words[] = $dictionary[$number];
}
$string .= implode(' ', $words);
}
return $string;
}
echo convert_number_to_words(100000000);
?>

Related

Currency Convert to Word in PHP INR way

I am fatriedg an issue while converting the currency in the INR case.
I want to make a function where if the amount does not have 'paisa' then in the last of the word will shows the 'only' word.
e.g 1: INR '100.23' will show: One Hundred and Two Three Paisa Only
e.g 2: INR '100' will show: One hundred Only
I have tried this code but I don't how I implement this same.
function getIndianCurrency(float $number)
{
$decimal = round($number - ($no = floor($number)), 2) * 100;
$hundred = null;
$digits_length = strlen($no);
$i = 0;
$str = array();
$words = array(0 => '', 1 => 'one', 2 => 'two',
3 => 'three', 4 => 'four', 5 => 'five', 6 => 'six',
7 => 'seven', 8 => 'eight', 9 => 'nine',
10 => 'ten', 11 => 'eleven', 12 => 'twelve',
13 => 'thirteen', 14 => 'fourteen', 15 => 'fifteen',
16 => 'sixteen', 17 => 'seventeen', 18 => 'eighteen',
19 => 'nineteen', 20 => 'twenty', 30 => 'thirty',
40 => 'forty', 50 => 'fifty', 60 => 'sixty',
70 => 'seventy', 80 => 'eighty', 90 => 'ninety');
$digits = array('', 'hundred','thousand','lakh', 'crore');
while( $i < $digits_length ) {
$divider = ($i == 2) ? 10 : 100;
$number = floor($no % $divider);
$no = floor($no / $divider);
$i += $divider == 10 ? 1 : 2;
if ($number) {
$plural = (($counter = count($str)) && $number > 9) ? 's' : null;
$hundred = ($counter == 1 && $str[0]) ? ' and ' : null;
$str [] = ($number < 21) ? $words[$number].' '. $digits[$counter]. $plural.' '.$hundred:$words[floor($number / 10) * 10].' '.$words[$number % 10]. ' '.$digits[$counter].$plural.' '.$hundred;
} else $str[] = null;
}
$rupees = implode('', array_reverse($str));
$paise = '';
if ($decimal) {
$paise = ' and ';
$decimal_length = strlen($decimal);
if ($decimal_length == 2) {
if ($decimal >= 20) {
$dc = $decimal % 10;
$td = $decimal - $dc;
$ps = ($dc == 0) ? '' : '-' . $words[$dc];
$paise .= $words[$td] . $ps;
} else {
$paise .= $words[$decimal];
}
} else {
$paise .= $words[$decimal % 10];
}
$paise .= ' paise only';
}
return ($rupees ? $rupees . 'rupees' : '-') . $paise ;
}
Here You go.
try this.
<?php
function getIndianCurrency(float $number)
{
$decimal = round($number - ($no = floor($number)), 2) * 100;
$hundred = null;
$digits_length = strlen($no);
$i = 0;
$str = array();
$words = array(0 => '', 1 => 'one', 2 => 'two',
3 => 'three', 4 => 'four', 5 => 'five', 6 => 'six',
7 => 'seven', 8 => 'eight', 9 => 'nine',
10 => 'ten', 11 => 'eleven', 12 => 'twelve',
13 => 'thirteen', 14 => 'fourteen', 15 => 'fifteen',
16 => 'sixteen', 17 => 'seventeen', 18 => 'eighteen',
19 => 'nineteen', 20 => 'twenty', 30 => 'thirty',
40 => 'forty', 50 => 'fifty', 60 => 'sixty',
70 => 'seventy', 80 => 'eighty', 90 => 'ninety');
$digits = array('', 'hundred','thousand','lakh', 'crore');
while( $i < $digits_length ) {
$divider = ($i == 2) ? 10 : 100;
$number = floor($no % $divider);
$no = floor($no / $divider);
$i += $divider == 10 ? 1 : 2;
if ($number) {
$plural = (($counter = count($str)) && $number > 9) ? 's' : null;
$hundred = ($counter == 1 && $str[0]) ? ' and ' : null;
$str [] = ($number < 21) ? $words[$number].' '. $digits[$counter]. $plural.' '.$hundred:$words[floor($number / 10) * 10].' '.$words[$number % 10]. ' '.$digits[$counter].$plural.' '.$hundred;
} else $str[] = null;
}
$Rupees = implode('', array_reverse($str));
$paise = ($decimal > 0) ? "and " . ($words[$decimal / 10] . " " . $words[$decimal % 10]) . 'Paise' : '';
return ($Rupees ? $Rupees . '' : '') . $paise . ' Only';
}
echo getIndianCurrency(100.20);

Error in convert number to word

I am try to convert number to word. so I use below this code. But when convert Some of numbers are show error. Error is "Undefined offset: -4" in line number 47 and 48. how to solve this error. My Code is below
<?php
$total_amount=8123.52;
$number = $total_amount;
$no = round($number);
$point = round($number - $no, 2) * 100;
$hundred = null;
$digits_1 = strlen($no);
$i = 0;
$str = array();
$words = array('0' => '', '1' => 'one', '2' => 'two',
'3' => 'three', '4' => 'four', '5' => 'five', '6' => 'six',
'7' => 'seven', '8' => 'eight', '9' => 'nine',
'10' => 'ten', '11' => 'eleven', '12' => 'twelve',
'13' => 'thirteen', '14' => 'fourteen',
'15' => 'fifteen', '16' => 'sixteen', '17' => 'seventeen',
'18' => 'eighteen', '19' =>'nineteen', '20' => 'twenty',
'30' => 'thirty', '40' => 'forty', '50' => 'fifty',
'60' => 'sixty', '70' => 'seventy',
'80' => 'eighty', '90' => 'ninety');
$digits = array('', 'hundred', 'thousand', 'lakh', 'crore');
while ($i < $digits_1) {
$divider = ($i == 2) ? 10 : 100;
$number = floor($no % $divider);
$no = floor($no / $divider);
$i += ($divider == 10) ? 1 : 2;
if ($number) {
$plural = (($counter = count($str)) && $number > 9) ? 's' : null;
$hundred = ($counter == 1 && $str[0]) ? ' and ' : null;
$str [] = ($number < 21) ? $words[$number] .
" " . $digits[$counter] . $plural . " " . $hundred
:
$words[floor($number / 10) * 10]
. " " . $words[$number % 10] . " "
. $digits[$counter] . $plural . " " . $hundred;
} else $str[] = null;
}
$str = array_reverse($str);
$result = implode('', $str);
$points = ($point) ?
"." . $words[$point / 10] . " " .
$words[$point = $point / 10] : '';
echo $result . "(Approx)" ;
?>
Problem is in fourth line $point = round($number - $no, 2) * 100;. It throws error when subtraction give minus output.
try something like this
$point = round($no - $number, 2) * 100 ;
if($point < 0 ){
$point = $point * (-1);
}
And problem solved.

How to add total price in words in Prestashop invoice?

I have a PHP code that converts numbers to words. How I can implement that to Prestashop 1.6.0.14 invoice?
I tried to write this code:
<?php
$num = '123';
list($p1, $p2) = explode('.', str_replace(',','.',$num));
?>
<table style="width: 100%;">
<tr>
<td>Amout in words: <?php echo ucfirst(words( $p1 )) . ' eur ' . ' and '.$p2 . ' ct' ; ?></td>
</tr>
</table>
Refer the below code
<?php
$number = 1052;
$no = round($number);
$point = round($number - $no, 2) * 100;
$hundred = null;
$digits_1 = strlen($no);
$i = 0;
$str = array();
$words = array('0' => '', '1' => 'One', '2' => 'Two',
'3' => 'Three', '4' => 'Four', '5' => 'Five', '6' => 'Six',
'7' => 'Seven', '8' => 'Eight', '9' => 'Nine',
'10' => 'Ten', '11' => 'Eleven', '12' => 'Twelve',
'13' => 'Thirteen', '14' => 'Fourteen',
'15' => 'Fifteen', '16' => 'Sixteen', '17' => 'Seventeen',
'18' => 'Eighteen', '19' =>'Nineteen', '20' => 'Twenty',
'30' => 'Thirty', '40' => 'Forty', '50' => 'Fifty',
'60' => 'Sixty', '70' => 'Seventy',
'80' => 'Eighty', '90' => 'Ninety');
$digits = array('', 'Hundred', 'Thousand', 'Lakh', 'Crore');
while ($i < $digits_1) {
$divider = ($i == 2) ? 10 : 100;
$number = floor($no % $divider);
$no = floor($no / $divider);
$i += ($divider == 10) ? 1 : 2;
if ($number) {
$plural = (($counter = count($str)) && $number > 9) ? 's' : null;
$hundred = ($counter == 1 && $str[0]) ? ' and ' : null;
$str [] = ($number < 21) ? $words[$number] .
" " . $digits[$counter] . $plural . " " . $hundred
:
$words[floor($number / 10) * 10] . " " . $words[$number % 10] . " " . $digits[$counter] . $plural . " " . $hundred;
} else $str[] = null;
}
$str = array_reverse($str);
$rupees = implode('', $str);
$points = ($point) ? "" . $words[$point / 10] . " " . $words[$point = $point % 10] : '';
if($points!="")
echo $rupees . "rupees and " . $points . " paise .";
else
echo $rupees . "rupees .";
?>

how to convert number to word

Here is the code this code is convert number to word
like this
100000 one hundred thousand
10000000 ten million
But i want convert a number like that
100000 1 lakh
10000000 1 crore
how can i do this please help me to fix this issue
thanks
<?php
function convert_number_to_words($number) {
$hyphen = '-';
$conjunction = ' and ';
$separator = ', ';
$negative = 'negative ';
$decimal = ' point ';
$dictionary = array(
0 => 'zero',
1 => 'one',
2 => 'two',
3 => 'three',
4 => 'four',
5 => 'five',
6 => 'six',
7 => 'seven',
8 => 'eight',
9 => 'nine',
10 => 'ten',
11 => 'eleven',
12 => 'twelve',
13 => 'thirteen',
14 => 'fourteen',
15 => 'fifteen',
16 => 'sixteen',
17 => 'seventeen',
18 => 'eighteen',
19 => 'nineteen',
20 => 'twenty',
30 => 'thirty',
40 => 'fourty',
50 => 'fifty',
60 => 'sixty',
70 => 'seventy',
80 => 'eighty',
90 => 'ninety',
100 => 'hundred',
1000 => 'thousand',
1000000 => 'million',
1000000000 => 'billion',
1000000000000 => 'trillion',
1000000000000000 => 'quadrillion',
1000000000000000000 => 'quintillion'
);
if (!is_numeric($number)) {
return false;
}
if (($number >= 0 && (int) $number < 0) || (int) $number < 0 - PHP_INT_MAX) {
// overflow
trigger_error(
'convert_number_to_words only accepts numbers between -' . PHP_INT_MAX . ' and ' . PHP_INT_MAX,
E_USER_WARNING
);
return false;
}
if ($number < 0) {
return $negative . convert_number_to_words(abs($number));
}
$string = $fraction = null;
if (strpos($number, '.') !== false) {
list($number, $fraction) = explode('.', $number);
}
switch (true) {
case $number < 21:
$string = $dictionary[$number];
break;
case $number < 100:
$tens = ((int) ($number / 10)) * 10;
$units = $number % 10;
$string = $dictionary[$tens];
if ($units) {
$string .= $hyphen . $dictionary[$units];
}
break;
case $number < 1000:
$hundreds = $number / 100;
$remainder = $number % 100;
$string = $dictionary[$hundreds] . ' ' . $dictionary[100];
if ($remainder) {
$string .= $conjunction . convert_number_to_words($remainder);
}
break;
default:
$baseUnit = pow(1000, floor(log($number, 1000)));
$numBaseUnits = (int) ($number / $baseUnit);
$remainder = $number % $baseUnit;
$string = convert_number_to_words($numBaseUnits) . ' ' . $dictionary[$baseUnit];
if ($remainder) {
$string .= $remainder < 100 ? $conjunction : $separator;
$string .= convert_number_to_words($remainder);
}
break;
}
if (null !== $fraction && is_numeric($fraction)) {
$string .= $decimal;
$words = array();
foreach (str_split((string) $fraction) as $number) {
$words[] = $dictionary[$number];
}
$string .= implode(' ', $words);
}
return $string;
}
echo convert_number_to_words(100000 );
// one hundred thousand
?>

How to modify the following code to express the numeric value into word value according to Indian counting system

The following code expresses the numeric value into word value by categorizing the number into different cases and using the default case for finding the baseunit and the number and the remainder and recursively calling the following function to express the number into words. What I want to achieve is to get the value expresed into Indian counting system and not using million, billion etc.
I feel if modify this line in default: $baseUnit = pow(1000, floor(log($number, 1000)));
correctly then I will be able to solve the problem.
Any help will be highly appreciated. Thanks.
function convert_number_to_words($number) {
$hyphen = '-';
$conjunction = ' and ';
$separator = ', ';
$negative = 'negative ';
$decimal = ' point ';
$dictionary = array(
0 => 'zero',
1 => 'one',
2 => 'two',
3 => 'three',
4 => 'four',
5 => 'five',
6 => 'six',
7 => 'seven',
8 => 'eight',
9 => 'nine',
10 => 'ten',
11 => 'eleven',
12 => 'twelve',
13 => 'thirteen',
14 => 'fourteen',
15 => 'fifteen',
16 => 'sixteen',
17 => 'seventeen',
18 => 'eighteen',
19 => 'nineteen',
20 => 'twenty',
30 => 'thirty',
40 => 'fourty',
50 => 'fifty',
60 => 'sixty',
70 => 'seventy',
80 => 'eighty',
90 => 'ninety',
100 => 'hundred',
1000 => 'thousand',
//Instead of the following values I would like to have Indian counting system values
/*
1000000 => 'million',
1000000000 => 'billion',
1000000000000 => 'trillion',
1000000000000000 => 'quadrillion',
1000000000000000000 => 'quintillion'
*/
100000 => 'lakhs',
10000000 =>'crore',
1000000000 =>'arab',
100000000000 =>'kharab'
);
if (!is_numeric($number)) {
return false;
}
if (($number >= 0 && (int) $number < 0) || (int) $number < 0 - PHP_INT_MAX) {
// overflow
trigger_error(
'convert_number_to_words only accepts numbers between -' . PHP_INT_MAX . ' and ' . PHP_INT_MAX,
E_USER_WARNING
);
return false;
}
if ($number < 0) {
return $negative . convert_number_to_words(abs($number));
}
$string = $fraction = null;
if (strpos($number, '.') !== false) {
list($number, $fraction) = explode('.', $number);
}
switch (true) {
case $number < 21:
$string = $dictionary[$number];
break;
case $number < 100:
$tens = ((int) ($number / 10)) * 10;
$units = $number % 10;
$string = $dictionary[$tens];
if ($units) {
$string .= $hyphen . $dictionary[$units];
}
break;
case $number < 1000:
$hundreds = $number / 100;
$remainder = $number % 100;
$string = $dictionary[$hundreds] . ' ' . $dictionary[100];
if ($remainder) {
$string .= $conjunction . convert_number_to_words($remainder);
}
break;
default:
$baseUnit = pow(1000, floor(log($number, 1000)));
$numBaseUnits = (int) ($number / $baseUnit);
$remainder = $number % $baseUnit;
$string = convert_number_to_words($numBaseUnits) . ' ' . $dictionary[$baseUnit];
if ($remainder) {
$string .= $remainder < 100 ? $conjunction : $separator;
$string .= convert_number_to_words($remainder);
}
break;
}
if (null !== $fraction && is_numeric($fraction)) {
$string .= $decimal;
$words = array();
foreach (str_split((string) $fraction) as $number) {
$words[] = $dictionary[$number];
}
$string .= implode(' ', $words);
}
return $string;
}
For public benefit I would Like to post the full solution.
The following PHP function provides us with a way to convert from numeric to word format expressed in Indian counting sytem.
Thanks goes to Patashu and rici for helping me finding my way through :-
function convert_number_to_words($number) {
$hyphen = '-';
$conjunction = ' and ';
$separator = ', ';
$negative = 'negative ';
$decimal = ' point ';
$dictionary = array(
0 => 'zero',
1 => 'one',
2 => 'two',
3 => 'three',
4 => 'four',
5 => 'five',
6 => 'six',
7 => 'seven',
8 => 'eight',
9 => 'nine',
10 => 'ten',
11 => 'eleven',
12 => 'twelve',
13 => 'thirteen',
14 => 'fourteen',
15 => 'fifteen',
16 => 'sixteen',
17 => 'seventeen',
18 => 'eighteen',
19 => 'nineteen',
20 => 'twenty',
30 => 'thirty',
40 => 'fourty',
50 => 'fifty',
60 => 'sixty',
70 => 'seventy',
80 => 'eighty',
90 => 'ninety',
100 => 'hundred',
1000 => 'thousand',
//Instead of the following values I would like to have Indian counting system values
/*
1000000 => 'million',
1000000000 => 'billion',
1000000000000 => 'trillion',
1000000000000000 => 'quadrillion',
1000000000000000000 => 'quintillion'
*/
100000 => 'lakhs',
10000000 =>'crore',
1000000000 =>'arab',
100000000000 =>'kharab'
);
if (!is_numeric($number)) {
return false;
}
if (($number >= 0 && (int) $number < 0) || (int) $number < 0 - PHP_INT_MAX) {
// overflow
trigger_error(
'convert_number_to_words only accepts numbers between -' . PHP_INT_MAX . ' and ' . PHP_INT_MAX,
E_USER_WARNING
);
return false;
}
if ($number < 0) {
return $negative . convert_number_to_words(abs($number));
}
$string = $fraction = null;
if (strpos($number, '.') !== false) {
list($number, $fraction) = explode('.', $number);
}
switch (true) {
case $number < 21:
$string = $dictionary[$number];
break;
case $number < 100:
$tens = ((int) ($number / 10)) * 10;
$units = $number % 10;
$string = $dictionary[$tens];
if ($units) {
$string .= $hyphen . $dictionary[$units];
}
break;
case $number < 1000:
$hundreds = $number / 100;
$remainder = $number % 100;
$string = $dictionary[$hundreds] . ' ' . $dictionary[100];
if ($remainder) {
$string .= $conjunction . convert_number_to_words($remainder);
}
break;
default:
$baseUnit = 10 * pow(100, floor(log($number/10, 100)));// Thanks to rici and Patashu
$numBaseUnits = (int) ($number / $baseUnit);
$remainder = $number % $baseUnit;
$string = convert_number_to_words($numBaseUnits) . ' ' . $dictionary[$baseUnit];
if ($remainder) {
$string .= $remainder < 100 ? $conjunction : $separator;
$string .= convert_number_to_words($remainder);
}
break;
}
if (null !== $fraction && is_numeric($fraction)) {
$string .= $decimal;
$words = array();
foreach (str_split((string) $fraction) as $number) {
$words[] = $dictionary[$number];
}
$string .= implode(' ', $words);
}
return $string;
}

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