Print number with spaces as thousands place separator [duplicate] - php

This question already has answers here:
PHP - Correct way to add space between numbers?
(3 answers)
Closed 1 year ago.
I'm trying to reverse a string and add spaces from 3 in 3 characters the code I have right now is this:
$rowPreco = "925000"
$rowPreco = strrev($rowPreco);
$rowPreco = wordwrap($rowPreco , 3 , ' ' , true );
$rowPreco = strrev($rowPreco);
if I take the strrev out it prints how I want ("925 000") but if I have the strrev it will print ("92 500 0").
But I need to use the strrev because if the value is ("1200000") it will print ("120 000 0") instead of ("1 200 000").
Any help would be appreciated.
Thanks!
UPDATE!
When I use the number_format it will ignore a jQuery code that I have.
echo "<script>"
."jQuery(document).ready(function() {"
."var parts = jQuery('.casaPreco').text().split('|');"
."jQuery('.casaPreco2').text(parts[4]);"
."});"
."</script>";
Basically the initial string is something like this: "3880562|1|1|925000|||0|0|0"
I need to grab the 4th number so I'm splitting the string on the "|" and use the array parts[4] but when I use the number_format it will grab the number "3880562"

Please do not invent the wheel:
echo number_format('925000', 0, '.', ' '); // 925 000
echo number_format('1200000', 0, '.', ' '); // 1 200 000
number_format manual.

Related

php: why 14 + ' ' + 12 returns 26? [duplicate]

This question already has answers here:
Adding string with number in php
(6 answers)
Closed 2 years ago.
I'm a beginner in PHP. with my experience something like "number + String + number" should be a string.
But apparently, it's a number in php.
in my case:
echo 14 + ' ' + 12;
// returns 26
// expected: "14 12"
why did this happen?
and how to fix it?
You are adding a '+' for adding two numbers. These are not a string so it will do a addition.
Use this if you want to add these couple of number as a couple of string :-
echo '14'.' '.'12';
// result "14 12";
You can also use with a html code for a blank space :
echo '14&nbsp12';
// result "14 12";
Because echo accepts parameters only inside quotes. If you want text being returne use:
echo"14 12";
In you case PHP does 2 things
Takes 14 adds to 12
Concatenates space.

How to change all front decimal to 0 in php [duplicate]

This question already has answers here:
Add zero to before decimal point of a number
(2 answers)
Closed 2 years ago.
I have some data from database like this :
43966.31875
how to change 43966 to 0 and keep decimal number to 31875, What should I do?
well, for the final result like this :
0.31875
If my explanation is incomprehensible, I apologize, and you can ask me again, Thank You
The regex method:
$string = '43966.31875';
echo preg_replace('/(\d+).(\d+)/i', '0.${2}', $string);
Will split number into 2 parts then replace the part 1 with "0."
The strstr method:
$string = '43966.31875';
echo '0'.strstr($string, '.');
Also split the number into 2 parts and take the second part and add "0" before
$number = 43966.31875;
$decimalPart = fmod($number, 1);
$decimalCount = explode('.', $number)[1];
$result = round($decimalPart, strlen($decimalCount));
Refer the Official Documentation:
PHP fmod

convert a number to decimal number without rounding [duplicate]

This question already has answers here:
How to make number_format() not to round numbers up
(18 answers)
Closed 3 years ago.
I have this number
$sku = '2200081005966';
and I want to convert the number like this without rounding the number
$new_sku = '5.96'
I already try this number_format(substr($sku, 7, 12), 0, '', '.')
but the output that I get 5.97.
Any ideas how can I make this work?
Thank you.
Add floor() around your number_format:
$sku = '2200081005966';
echo floor(number_format(substr($sku, 7, 12), 0, '', '.')*100)/100;
Outputs:
5.96
Note: It would works well in case of positive numbers, your substr always take a positive number, that's why it would be enough.
<?php
$sku = '2200081005966';
$foo=substr($sku, 9, 12);
echo substr($foo, 0,2).".".substr($foo, 3,3);
?>
first you get the last 4 charakters of the string, then you split that part and put a dot between.

reverse chunk split of integer in PHP [duplicate]

This question already has answers here:
Formatting numbers with commas PHP [duplicate]
(4 answers)
Closed 7 months ago.
I need split by gap like when we write count numbers we will give gap for every 3 integer.
echo chunk_split(1000255869,3," ");
I got output like: 100 025 586 9
But I need output like: 1,000,255,869
How to reverse that one?
Try this,
<?php
$a = 1000255869;
echo $a;//output - 1000255869
$a = number_format($a);
echo $a;//output - 1,000,255,869
?>
if you want to do a number format, you should do it with number_format.
echo number_format(1000255869,0,".",",");
This should work number_format(1000255869, 0, '.', ',');
Try this.Reference
$number= 1000255869;
echo number_format($number);

simple regex in php, formatting decimal number [duplicate]

This question already has answers here:
Show a number to two decimal places
(25 answers)
Closed 11 months ago.
I need to convert numbers to have .00 after them, but only if the number is an integer, or it has just 1 number after the decimal point, like so:
1.4 = 1.40
45 = 45.00
34.77 = 34.77
What reg exp to use for this simple case?
You can also use printf or sprintf
printf("%01.2f", '34.77');
$formatted_num = sprintf("%01.2f", '34.77');
number_format($number, 2, '.', '');
Read more at PHP.net. You don't need to determine if a number is an integer or not -- as long as it's a number, it will be formatted to two decimal places.
If you'd like the thousands separator, change the last parameter to ','.
Check out PHP's built-in function number_format
You can pass it a variable and it'll format it to the correct decimal places
$number = 20;
if (is_int($number)) {
$number = number_format($number, 2, '.', '');
}
read number_format
number_format($number, 2, '.', '');
$num = 0.00638835;
$avg = sscanf($num,"%f")[0] /100;
echo sprintf("%.10f", $avg);
result 0.0000638835

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