How to run python script from web page? - php

Question

Im quite new in web developing, could someone please point me in the right direction of help with the scripts to run a .py script on a web page. Below are the ones that i am using. Do i have to create a html file and a php file??
If so please help me. I have a internal server running on XAMPP with Apache and configured to run CGI, .py scripts.
Work flow:
Upload > button to run the below .py script > download
Upload script(php):
<?php
if(isset($_POST['UploadButton'])){ //check if form was submitted
$target_dir = '/opt/lampp/htdocs/pic-el/Dump/';
$target_file = $target_dir . basename($_FILES["filepath"]["name"]);
$imageFileType = pathinfo($target_file,PATHINFO_EXTENSION);
move_uploaded_file($_FILES["filepath"]["tmp_name"], $target_file);
}
?>
Python script:
#!/usr/bin/env python
import CGIHTTPServer
CGIHTTPServer.test()
import os
import urllib
import cgi
import webcolors
import xlsxwriter
from PIL import Image
filename = "/home/Desktop/tess/test1"
imageNameArray = []
def downloadfile(urlData):
urllib.urlretrieve(urlData[0], urlData[1])
print " image downloaded: " + str(urlData[1])
return
# open file to read
with open("{0}.csv".format(filename), 'r') as csvfile:
# iterate on all lines
i = 0
for line in csvfile:
splitted_line = line.split(',')
# check if we have an image URL
if splitted_line[1] != '' and splitted_line[1] != "\n":
# urllib.urlretrieve(splitted_line[1], '/home/tf_files/images/{0}.jpg'.format (splitted_line[0]))
imageNameArray.append(
(splitted_line[1], '/home/Desktop/tess/images/{0}.jpg'.format(splitted_line[0])))
print "Image added to list for processing for {0}".format(splitted_line[0])
i += 1
else:
print "No result for {0}".format(splitted_line[0])
os.environ['TF_CPP_MIN_LOG_LEVEL'] = '2'
from multiprocessing import Pool
processPool = Pool(5)
processPool.map(downloadfile, imageNameArray)
# Create a workbook and add a worksheet.
workbook = xlsxwriter.Workbook('output1.xlsx')
worksheet = workbook.add_worksheet()
# Start from the first cell. Rows and columns are zero indexed.
row = 0
col = 0
# search for files in 'images' dir
files_dir = os.getcwd() + '/images'
files = os.listdir(files_dir)
def closest_colour(requested_colour):
min_colours = {}
for key, name in webcolors.css3_hex_to_names.items():
r_c, g_c, b_c = webcolors.hex_to_rgb(key)
rd = (r_c - requested_colour[0]) ** 2
gd = (g_c - requested_colour[1]) ** 2
bd = (b_c - requested_colour[2]) ** 2
min_colours[(rd + gd + bd)] = name
return min_colours[min(min_colours.keys())]
def get_colour_name(requested_colour):
try:
closest_name = actual_name = webcolors.rgb_to_name(requested_colour)
except ValueError:
closest_name = closest_colour(requested_colour)
actual_name = None
return actual_name, closest_name
for f in files:
if f.lower().endswith(('.png', '.jpg', '.jpeg')):
image_path = files_dir + '/' + f
im = Image.open(image_path)
n, cl = max(im.getcolors(im.size[0] * im.size[1]))
requested_colour = cl
actual_name, closest_name = get_colour_name(requested_colour)
width = im.size
if width < (500, 500):
worksheet.write(row, 4, "False")
else:
worksheet.write(row, 4, "True")
print image_path
print cl
print width
print "Actual colour name:", actual_name, ", closest colour name:", closest_name
worksheet.write_string(row, 1, image_path)
worksheet.write(row, 3, closest_name)
row += 1
workbook.close()

Answer 1

you can't run .py on a web page, only u can run on the server since Python's a server side programming. But you can run python script from PHP (since u r using XAMPP.)
Example -
<?php
$output = exec('./filename.py');
?>

Answer 2

You don't need to create separate php and html files.
First, when the server goes back to apache2
sudo apt-get install libapache2-mod-wsgi
(It connects apache2 with wsgi.)
Second, you need to create a configuration file and
Move the configuration file to Document_Root.
ex> server.conf
WSGIScriptAlias /test /var/www/wsgi/main.py
MainOption |  Address to be connected | Python file location
Third, restart apache2 service.
EXAMPLE_CODES
main.py
server.conf