How do I remove quotation from csv?
Code
use Goutte\Client;
$client = new Client();
$response = $client->request('GET', 'http://c-manage.herokuapp.com/login');
$login_form = $response->filter('form')->form();
$login_form["account"] = '1';
$login_form["password"] = 'rpa1001';
$client->submit($login_form);
$client->request('GET', 'http://c-manage.herokuapp.com/client/download?searchQuery%5Bstatus%5D=1&searchQuery%5BregisterStartDate%5D=2010-01-01&searchQuery%5BregisterEndDate%5D=2020-01-01');
$csvResponse = $client->getResponse()->getContent();
return $csvResponse;
response is ...
ID,ステータス,分類,名前,名前（カナ）,誕生日,郵便番号,住所,メールアドレス,電話番号,FAX,メモ,登録日,更新日\r\n
213,契約中,個人,"鶴田 秀夫","ツルタ ヒデオ",2000/07/24,1508207,神奈川県吉田市北区佐々木町小林7-4-5,hiroshi.nakatsugawa#yamaguchi.net,0310-282-609,0730-327-581,,"2010-01-25 00:00:
00","2010-01-25 00:00:00"\r\n
221,契約中,個人,"桑原 彩羅","クワハラ サイラ",2008/04/03,8103797,青森県杉山市西区石田町浜田3-4-10,vwakamatsu#kiriyama.jp,090-5710-4350,03849-5-5746,,"2010-01-09 00:00:00","2010-0
1-09 00:00:00"\r\n
237,契約中,個人,"堤 悟志","ツツミ サトシ",2001/04/29,6875750,栃木県佐々木市東区中島町浜田6-6-6,xtsuda#suzuki.com,022-557-4260,0573-01-2822,,"2010-02-07 00:00:00","2010-02-07 00:0
0:00"\r\n
273,契約中,個人,"富永 圭三","トミナガ ケイゾウ",2003/03/16,6314524,静岡県若松市東区廣川町青山10-9-6,yamaguchi.takuma#kondo.com,0020-062-493,06-3862-0779,,"2010-02-13 00:00:00","2
010-02-13 00:00:00"\r\n
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What I want to do
I want to remove quotation from csv.
not
213,契約中,個人,"鶴田 秀夫","ツルタ ヒデオ",2000/07/24,1508207,
but
213,契約中,個人,鶴田 秀夫,ツルタ ヒデオ,2000/07/24,1508207,
※This personal information is fake.
What I did
str_replace(""", "", $csvResponse);
str_replace("\xEF\xBB\xBF", '', $csvResponse);
but, not working
The quotes serve a purpose here so you shouldn't be removing them haphazardly. The quotes prevent columns from breaking when they need to contain text that can also contain the delimiter. Like "Foo, bar, baz" for example. Removing the quotes turns this one column into 3 columns, which is obviously wrong.
Though, if you did want to remove them str_replace would certainly not be the way to go, because the quotes can be escaped to be literals inside the column. For example, using str_replace on this column: "He said \"this is crazy\", and left." would strip literals from the column value.
Instead you should load the CSV data with fgetcsv() or str_getcsv() and rebuild the CSV without the quotes like so...
foreach (str_getcsv($csvData) as $row) {
echo implode(",", $row), "\n";
}
This will give you back the literal values of each row without the quotes. Though any literal quotes inside those values will become quotes.
I'm sorry that this is basic. When I use this PHP code it works fine:
$data = '{"reportID":1092480021}';
However, when I run my URL like this:
http://localhost:8000/new/reportget.php?type=1092480021
and use this PHP code:
$reportref = $_GET['type'];
$data = '{"reportID:".$reportref."}"';
I get the error
Error_description:reportID is required
I think it's an error with how I am joining my variable to the string but I can't understand where I am going wrong.
Your string is improperly quoted. To match the format in your first example use:
$data = '{"reportID":' . $reportref.'}';
Note there are no double quotes on the last curly.
Even better:
$reportref = 1092480021;
$data = [ 'reportId' => $reportref ];
var_dump(json_encode($data));
Output:
string(23) "{"reportId":1092480021}"
For simple view and understanding, can you try out:
$data = "{\"reportID\":$reportref}";
Think that should sort it out
Use it like this
data = '{"reportID:"'.$reportref.'"}"';
It isn't working because you wrap all the value within single quote and when it come to concatenate the $reprtref you put directly .$reportref without closing the first single quote and after putting the value to concatenate you forget to open another single quote
'{"reportID:".$reportref."}"';
the correct value is
'{"reportID:"' . $reportref . '"}"';
and to match the way you specify your $data value It must be like this
'{"reportID":' . $reportref . '}';
I am simply trying to echo or print out specific data from a DB into a string (i hope thats the right name), which should be a very simple process as I've done it before. The point is everytime a user inserts information into the database this string echo's or prints out the inserted data.
But for some very odd reason this time around when i try to echo out the data, I literally get this.
Very frustrating. As you can see from the image above i have tried using 2 different ways to do this a variable and a session, but the echo literally just prints it out. I have done this before so i am aware that it is possible. I am just a little lost into how i am meant to achieve this or even better where i went wrong. I know how to do this using a different style of coding, but i am trying to keep everything uniformed (newbie).
$addon_name = $_SESSION['Add_On_OpName'];
mysqli_report(MYSQLI_REPORT_INDEX); //overrid a common php nonsense error
$prod_sel = $dbc->query("SELECT * FROM Add_On WHERE Add_On_OpName = '$addon_name'");
$prod_sel->data_seek(0);
while ($output = $prod_sel->fetch_assoc()) {
$prod_run .= $output['Add_On_OpName'] . $output['Prod_Name'] . $output['Add_On_Price'] . $output['Add_On_Select'] . '<br>';
$addon = $output['Add_On_OpName']; //echo out product name
$_SESSION['Prod_Name'] = $output['Prod_Name']; //echo out product desc
$_SESSION['Add_On_Price'] = $output['Add_On_Price']; //echo out price
echo '
<p>$addon . " " . $_SESSION["Add_On_Price"]; </p>
';
My session is started and the php file is connected to the DB.
I also have error handling which has not given out any error messages.
You must do:
echo "<p>$addon ".$_SESSION["Add_On_Price"]."; </p>";
A string encapsulated into ' is rendered just as it is.
Use " to render a string that contains variables. Example:
$a = 3;
$a++;
echo "the result is $a";
will result in the result is 4.
On the other hand,
echo 'the result is $a';
gives the result is $a.
As the documentation points out:
Single quoted ¶ The simplest way to specify a string is to enclose it
in single quotes (the character ').
Doued ¶
If the string is enclosed in double-quotes ("), PHP will interpret
more escape sequences for special characters
Try not mix it..
And if within double quotes you have an associative array you may concat.
echo "string $variable". $array["index"];
or
echo "string $variable {$array["index"]}";
Then your code should look like
$addon_name = $_SESSION['Add_On_OpName'];
mysqli_report(MYSQLI_REPORT_INDEX); //overrid a common php nonsense error
$prod_sel = $dbc->query("SELECT * FROM Add_On WHERE Add_On_OpName = '$addon_name'");
$prod_sel->data_seek(0);
while ($output = $prod_sel->fetch_assoc()) {
$prod_run .= $output['Add_On_OpName'] . $output['Prod_Name'] . $output['Add_On_Price'] . $output['Add_On_Select'] . '<br>';
$addon = $output['Add_On_OpName']; //echo out product name
$_SESSION['Prod_Name'] = $output['Prod_Name']; //echo out product desc
$_SESSION['Add_On_Price'] = $output['Add_On_Price']; //echo out price
echo "<p>$addon {$_SESSION["Add_On_Price"]}; </p>'";
}
Long time ago
I never use double quotes due to it require parse the whole string for special notations. However it.
Try not mix single quotes with double quotes. pick up a standard for you code you will not notice any difference than is easy to code and read without surprises
You're mixing single quotes and double quotes. Single quotes do not perform interpolation of variables so when you write this:
echo '... whatever including " char and $ sign';
PHP will just literally print everything inside.
You forget some ' or " !
echo '<p>' . $addon . ' ' . $_SESSION["Add_On_Price"] . '</p>';
Use double quotes
echo "<p>$addon $_SESSION['Add_On_Price']; </p>";
I need to get this output.
the result is"random"safdsaf
I am using this piece of code
<?php
$x = "random";
echo 'the result is' .$x. 'safdsaf';
?>
But i am getting this
the result israndomsafdsaf
I have to define random before printing it.
i.e. I do not want to change this piece of code
<?php
$x = "random";
What change should i make inside echo to get the desired output?
If you are using the same type of quotes delimit the quotes in your string like this:
echo "The result is\"" .$x. "\"safdsaf";
or simply use two sets of different quotes:
echo 'the result is"' .$x. '"safdsaf';
Output of either line of code:
The result is"random"safdsaf
Try this
Added the little bit space befor ' and added ", it will give the some out put as you want
echo 'the result is "' .$x. '" safdsaf';
the result will be
The result is "random" safdsaf
If you want to print out double quotes you can include them in single quotes
Something like this would do the trick.
$x = '"random"';
If for whatever reason you don't want to use single quotes you can also escape them like :
$x = "\"random\"";
As you want to keep the string, I suggest you change the original line where you put it in :
echo 'the result is"' .$x. '"safdsaf';
the principle stays the same
Here's some reading material : http://php.net/manual/en/language.types.string.php
You can use simply :-
echo 'the result is "' .$x. '" safdsaf';
OR you can use .
echo "the result is \" $x\" safdsaf";
Using the \ before the quote like this: the result is \"random\" safdsaf.
if you have alot of quotes and such in a string, i would suggest using the addslashes(). This method will do the work for you for you.
For more info, take a look here - http://www.w3schools.com/php/func_string_addslashes.asp
I am trying to read a file as a string and return it to the client to be executed as javascript code in order to save it as a variable. Like so
<?php
$fileName = 'target.js';
$codeAsString = file_get_contents($fileName);
$script = 'var code=\'' . $codeAsString . '\'';
echo $script;
?>
Once returned, I want the variable code to have a string representation of the contents of target.js. However, it isn't working. I suspect it has to do with new line characters and single/double quotes... In Python they have a multi line quote
"""This
is
a "multi"
line
'quote'
"""
Is there anything like this in Javascript/php? I can't even wrap my head around whether I need the single quotes around $codeAsString when appending it to $script. Do I have to manually go in and prepend backslashes before all quotes, double quotes, back slashes...Surely they have helper functions for this
thanks.
json_encode is your friend...
<?php
$fileName = 'target.js';
$codeAsString = file_get_contents($fileName);
$script = 'var code= '.json_encode($codeAsString) .';';
echo $script;
?>
Use PHP function json_encode.