I want to convert my HTML page to pdf but I can not do it. Maybe you know what I am doing wrong? Here is my code
web.php
Route::get('print/{id}',array('as'=>'htmltopdfview','uses'=>'ClientController#htmltopdfview'));
controller:
public function htmltopdfview(Request $request)
{
$products = Client::all();
view()->share('products',$products);
if($request->has('download')){
$pdf = PDF::loadView('client/print');
return $pdf->download('client/print');
}
return view('client/print' compact('client'));
}
and view:
Download PDF
<div class="panel-body">
{!! Form::open(['action' => ['ClientController#doEdit', $client->id]]) !!}
{!! Form::label('name', 'Imie i nazwisko:'); !!}
{!! Form::text('name', null, ['class' => 'form-control']) !!}
{!! Form::submit('Edit!', ['class' => 'btn btn-success']) !!}
{!! Form::close() !!}
So first you make a blade without that anchor tag, just keep plain html in your view i.e. blade.I don't get the form part but you mostly need static page for that apart from accessing the products like
{{$products->id}}
Also for accessing the data in
In controller, instead of returning view, return the below code right after the view()->share. I have mentioned below why you won't need that if condition
return $pdf->stream();
The download option will be automatically available in browsers like chrome.
Also If you aren't using any data from request,why don't you try removing it.
Also you never defined $client in that view.
Related
I have abstracts table in my database with the Abstract_Status_ID column, I am trying to create a button that changes every Status from '2' to '3'
I have tried to do this:-
My controller
public function publish($A_ID)
{
$abstracts = Project::find($A_ID);
$abstracts->Abstract_Status_ID= 3;
$abstracts->save();
return redirect('/AdvertisedProjects')->with ('success', 'Abstracts Published' );
}
my route
Route::put( '/projects', 'AbstractsController#publish');
Route::post( '/projects', 'AbstractsController#publish');
my view (projects)
Tried with the csrf token and without as eloquent docs says any post/put will be restricted without it.
#if (count ($abstracts)> 0)
#foreach ($abstracts as $abstract)
#if($abstract->Abstract_Status_ID == 2)
{!! Form::open(['action' => ['AbstractsController#publish' , $abstract->A_ID], 'method' => 'post' ]) !!}
{{ csrf_field() }}
{{Form::hidden('_method', 'PUT') }}
{{Form::Submit('Submit Changes',['class' => 'btn btn-primary'])}}
{!! Form::close() !!}
#endif
#endforeach
The error I am getting when clicking the button
(1/1) ErrorException
Missing argument 1 for App\Http\Controllers\AbstractsController::publish()
Also, the code above will show more than one button, any suggestions to make one button change all of them ?
A: If you want to have a button for each ABSTRACTS just change your route to :
Route::put( '/projects/{A_ID}', 'AbstractsController#publish');
B: If you want to have only one button that change all , you can echo their ID in hidden input then send form
so your view would be:
#if (count ($abstracts)> 0)
{!! Form::open(['action' => ['AbstractsController#publish'], 'method' => 'post' ]) !!}
{{ csrf_field() }}
{{Form::hidden('_method', 'PUT') }}
#foreach ($abstracts as $abstract)
#if($abstract->Abstract_Status_ID == 2)
{{Form::hidden('abstract_ids[]', $abstract->A_ID) }}
#endif
#endforeach
{{Form::Submit('Submit Changes',['class' => 'btn btn-primary'])}}
{!! Form::close() !!}
And Your Controller :
public function publish()
{
foreach(request('abstract_ids') as $A_ID){
$abstracts = Project::find($A_ID);
$abstracts->Abstract_Status_ID= 3;
$abstracts->save();
}
return redirect('/AdvertisedProjects')->with ('success', 'Abstracts Published' );
}
You are using form method="POST". I think it should be method="PUT".
The main problem in your code is the definition of your routes, You are passing an argument ($A_ID) to the controllers publish method,
But in your routes, you did never mention that you are passing any argument through your route. So for passing the argument, you can use {$A_ID} in your route URL.
One thing you should always remember is that you should always give your route a name and call it by using its name and route() Laravel helper method.
The benefit of using route name is that if you decide to change the URL-Structure of your route later in the development process, you'll never have to change it everywhere in your application because you did not call it by its URL.
And route name is less error prone
In total, You should define your routes like this
Route::put('projects/{A_ID}/update', 'AbstractsController#publish')->name('projects.update');
Route::post('projects/{A_ID}/post', 'AbstractsController#publish')->name('projects.store');
Then in you blade files now you can call it like
{!! Form::open(['action' => route('projects.store', $abstract->A_ID), 'method' => 'post' ]) !!}
Hope this will clarify and resolve your problem.
So I have this CRUD where I use the same form to create and edit entries.
I need in several form selects, when creating (no data present for that particular field yet) my select to show the placeholder, but when editing, my select to show whatever is stored on database for that particular id filed. So I have:
Controller:
...
public function create()
{
$house = houses::pluck('name', 'id');
//$thisclient = null;
$clients = client::pluck('last_name', 'id');
$reps = user::where('role_id', 5)->orderBy('first_name')->get()->pluck('full_name', 'id');
return view('prospects.create', compact('house', 'clients', 'reps'));
}
...
public function edit($id)
{
$house = houses::pluck('name', 'id');
//$thisclient = user::whereId($id)->first();
$clients = client::pluck('last_name', 'id');
$reps = user::where('role_id', 5)->orderBy('first_name')->get()->pluck('full_name', 'id');
$prospect = Prospect::findOrFail($id);
return view('prospects.edit', compact('prospect', 'house', 'clients', 'reps'));
}
and my view form:
Working for create:
{!!Form::select('client_id', $clients, null, ['class' => 'form-control', 'placeholder' => 'Please Select'] ) !!}
Working for edit:
{!! Form::select('client_id', $clients, $prospect->client_id, ['class' => 'form-control'] ) !!}
I'm having 2 troubles here, if I have null as my selected field, it won't bring the selected data on edit, if I have $prospect->client_id , it will return a error on create as there's no data yet.
I tried to solve this by creating a variable $thishouse on controller and passing it to view on return view('prospects.create', compact('house', 'thisclient','clients', 'reps')); and view Form::select('client_id', $clients, $thisclient, ['class' => 'form-control'] ) !!} but seems a bit dirty whne having several form selects...
The second trouble is if I leave a placeholder on Edit, it will show the placeholder, not $prospect->client_id itself.
What's the best and simplest way to achieve all of this and use the same form for create and edit?
Thanks
You can use Form::open and Form::model to create and edit. As an example, you can set in your view:
#if(isset($prospect))
{!! Form::model($prospect, ['action' => ['ProspectController#update', $prospect->id], 'method' => 'patch']) !!}
#else
{!! Form::open(array('action' => 'ProspectController#store', 'method' => 'POST')) !!}
#endif
And then you can create the select like this:
{!! Form::select('client_id', $clients, old('client_id'), ['class' => 'form-control'] ) !!}
So, when you are editing, Laravel will select the attribute from the variable on model function.
And since you are using Laravel 5.5, you could also use #isset instruction.
I am using the HtmlServiceProvider in laravel 5.1 to build my form , I want to set the selected option in select dropdown list tag when I get the data from my model class
My code so far:
{!! Form::model($advertisment,['url'=>'dashboard/edit/advertisment']) !!}
{!! Form::select('Gender', [""=>'Select Gender',"Male"=>'Male', "Female"=>'Female'],0, ['class' => 'form-control', 'id' => 'form_control_6' ,'required']) !!}
{!! Form::close() !!}
Set the 0 parameter to "Male" for example and you will figure it out
If you don't want to override the value from the model, pass in null
I have seen similar questions asked before, but was unable to find a solution to my problem. So I have a ClientController and within it this function
public function edit(Client $client)
{
return view('clients.edit', compact('client'));
}
So that passes the client object to my edit view. This view is pretty much the following
{!! Form::model($client, ['method' => 'PATCH', 'route' => ['clients.update', $client->slug]]) !!}
#include('clients/partials/_form', ['submit_text' => 'Edit Client'])
{!! Form::close() !!}
So it is using a partial for the form. At the moment, the partial looks like so
<div class="form-group">
{!! Form::label('clientName', 'Client Name:') !!}
{!! Form::text('clientName') !!}
</div>
<div class="form-group">
{!! Form::label('clientStatus', 'Client Status:') !!}
{!! Form::select('clientStatus') !!}
</div>
When I visit the edit page for a client, I can see the form. The clientName is populated with the clientName value. The clientStatus is populated if I put it as a text input, but I cant get it to populate within a select as shown above. Furthermore, clientStatus can either be New or Existing. I need the select box to be pre-populated with the status of the client that is being edited, but I need the other option available within the select as well. So if the clientStatus is New, New should be pre-selected within the select box and if I open the select, Existing should be the other option.
What would be the best way to achieve this?
Thanks
Modify your select to include an array of the possible values.
Basic Select - Label is value
{!! Form::select('clientStatus',['New','Existing']) !!}
Key Value Select - Key is value
{!! Form::select('clientStatus',[ 1 => 'New', 2 => 'Existing']) !!}
Form model will then set the value in the select to the one in the model.
More information see the docs.
I want to create a two buttons buyer and seller in the home page, and on click of these buttons, I want the guest to get directed register page with a ~hidden input~ placed in the form depending on the value of the button pressed.
I am using Laravel 5.1
For what I am trying to achieve, do I need to register a new route and a new function?
First, do I need to use a {!! link_to !!} or {!! Form submit !!}. I thought form submit would work:
{!! Form::open(array('url' => '/auth/register', 'profession' => 'seller')) !!}
{!! Form::submit('Seller', array('class' => 'btn btn-warning')) !!}
{!! Form::close() !!}
My routes are:
Route::get('auth/register', 'Auth\AuthController#getRegister');
Route::post('auth/register', 'Auth\AuthController#postRegister');
auth/register and AuthController is the one that comes with Laravel default. I also didn't register a new public function. Is this the reason? Do I need to send the data from view to controller and then other view (view->controller->view). I am really confused on this one.
This is how it seems in the view-source:
<form method="POST" action="http://app.com/auth/register" accept-charset="UTF-8" profession="seller"><input name="_token" type="hidden" value="Cw4Het1A1M6020oQL45Cy2Q0ct46TSe6ba2g4r4C">
<input class="btn btn-warning" type="submit" value="Seller">
</form>
Edit:
I think I can't send variables between views. So do I need to register a completely new route and a controller, and two methods in it? I am really confused on this stage.
Check out my answer to your previous similar question for details on the implementation:
Laravel Passing Data From One View to Another View
To answer the questions you are posing
You can use two forms one for buyer and one for seller
{!! Form::open(['route' => ['type_path']]) !!}
{!! Form::hidden('type', 'buyer') !!}
{!! Form::submit('Buyer', array('class' => 'btn btn-warning')) !!}
{!! Form::close() !!
{!! Form::open(['route' => ['type_path']]) !!}
{!! Form::hidden('type', 'seller') !!}
{!! Form::submit('Seller', array('class' => 'btn btn-warning')) !!}
{!! Form::close() !!
on your landing page and then have both of this forms direct to a same named route (in this case 'type_path')
Then in your routes.php file you would reference only one controller and one method and handle the logic in that method. Again see the link to my answer to see a full implementation of this for the example of writer and reader.
Essentially as you say, you'd be sending as the hidden inputs from the view to the controller to the second view.
You could register a new route like:
Route::get('auth/{TYPE}/register', 'Auth\AuthController#getRegisterType')
Your home page would have something like this:
seller
Your controller method would be something like this:
public function getRegisterType($type)
{
Session::put('registerType', $type);
return redirect('/auth/register');
}
Then you can access you set session variable from the controller methods getRegister & postRegister
Have you two buttons direct to the register page with a query string parameter:
Buyer
Seller
And then just check for the query string parameter in your register.blade.php view:
{!! Form::hidden('account_type', Request::query('type')) !!}
If you need to validate one of the two is present, then you could create a middleware class you apply to the login route only:
public function handle($request, Closure $next)
{
if (! in_array($request->query('type'), ['buyer', 'seller'])) {
// Error
}
return $next($request);
}