I have code in controller Codeigniter:
<?php
defined('BASEPATH') OR exit('No direct script access allowed');
class Home extends CI_Controller {
public function __construct()
{
parent:: __construct();
$this->load->model('berita');
}
public function index()
{
$data['newsone'] = $this->berita->get_one_top_data();
if(width.screen > 1000px){ // i need the true code in here
$this->load->view('home_view_1',$data);
}
else{
$this->load->view('home_view_2',$data);
}
}
}
how can i open specific page depend on screen size...?
Related
My Project Structure is
application
controllers/site
core/
views/site
I want when i entered http://mywebsite admin has to be loaded and when i entered http://mywebsite/site frontend has to be loaded
I went through some tutorials and i have done changes below
In config/routes.php
$route['default_controller'] = 'admin';
$route['404_override'] = '';
$route['translate_uri_dashes'] = FALSE;
$route['site'] = 'site/home';
In core/My_Controller.php
defined('BASEPATH') or exit('No direct script access allowed');
class MY_Controller extends CI_Controller
{
function __construct()
{
parent::__construct();
}
}
class Admin_Controller extends MY_Controller
{
function __construct()
{
parent::__construct();
}
}
class Site_Controller extends MY_Controller
{
function __construct()
{
parent::__construct();
}
}
In controller/site/Home.php
defined('BASEPATH') or exit('No direct script access allowed');
class Home extends Site_Controller
{
public function __construct()
{
parent::__construct();
}
public function index()
{
$this->load->view("site/index.php");
}
}
But I am getting 404 when I opened http://mywebsite/site
Please help me
$route['site'] = 'site/home';
What that line does is that it defines a route that looks for a method called home inside the controller called Site viz. Site_Controller.
So you are getting the 404 error because your Site_Controller does not have the home method.
Try changing the Site_Controller like so...
class Site_Controller extends MY_Controller
{
function __construct()
{
parent::__construct();
}
# added this method
public function home()
{
$this->load->view("site/index.php");
}
}
I am new in codeigniter and i am working on ecommerce template. By default whenever index() has been hit, it's showing all products in different sections (in html) and I want to make this dynamic so should I use queries in index() for get different type of records or there is any other way? This is my code:
<?php
defined('BASEPATH') OR exit('No direct script access allowed');
class Home extends CI_Controller {
public function index()
{
//echo "hello world";
$this->load->view('index');
}
}
?>
First need to create database and table as per your requirement.
Then you can create model for reference check this link : https://www.codeigniter.com/userguide3/general/models.html
<?php
class Blog_model extends CI_Model {
public function get_data_first()
{
$query = $this->db->get('entries', 10);
return $query->result();
}
public function get_data_second()
{
$query = $this->db->get('entries', 10);
return $query->result();
}
}
?>
After making model go to your controller and include it like:
<?php
defined('BASEPATH') OR exit('No direct script access allowed');
class Home extends CI_Controller {
public function index()
{
$this->load->model('my_model');
$data['first_list'] = $this->my_model->get_data_first();
$data['second_list'] = $this->my_model->get_data_second();
//echo "hello world";
$this->load->view('index', $data);
}
}
?>
Then use you param in index file like :
<html>
<head></head>
<body>
<?php
if($first_list){
foreach($first_list as $each){
echo $each->my_param;
}
}
?>
<?php
if($second_list){
foreach($second_list as $each){
echo $each->my_param2;
}
}
?>
</body>
</html>
I hope this helpful for you.
In Models folder write Home_model.php file for querying database.
Suppose you have a table called 'products'.
<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');
class Home_model extends CI_Model{
public function __construct()
{
parent::__construct();
}
public function getProducts()
{
$this->db->from('products');
$query=$this->db->get();
$out = $query->result_array();
return $out;
}
}
The function 'getProducts' will get you all the products from 'products' table.
Now in your controller load the 'database' library and the model.
<?php
defined('BASEPATH') OR exit('No direct script access allowed');
class Home extends CI_Controller {
function __construct(){
parent::__construct();
$this->load->model('home_model');
$this->load->library('database');
}
public function index(){
$products = array();
$products = $this->home_model->getProducts();
$this->load->view('index',$products);
}
}
In index function function of controller you can call the 'getProduct' function of model.And can pass the data to view.
Documentation link for model.
enter link description here
I hope this helps.
I just started my website developing using the CodeIgniter framework.
My working steps are given below:
1. I created a controller named by Home.php
2. Then I go to the view folder and created a file named by index.php under sub-directory 'home'.
3. When I browse my website it shows me an error
Fatal error: Call to a member function view() on null in /home/ontutors/public_html/application/controllers/Home.php on line 18
Home.php code
<?php
defined('BASEPATH') OR exit('No direct script access allowed');
/**
*
*/
class Home extends CI_Controller
{
function __construct()
{
}
function index()
{
//echo "Hello welcome";
$this->load->view('home/index');
}
}
?>
<?php
defined('BASEPATH') OR exit('No direct script access allowed');
/**
*
*/
class Home extends CI_Controller
{
function __construct()
{
parent::__construct();
}
function index()
{
//echo "Hello welcome";
$this->load->view('home/index');
}
}
?>
Overwrite your code like this.
<?php
defined('BASEPATH') OR exit('No direct script access allowed');
class Home extends CI_Controller
{
function index()
{
//echo "Hello welcome";
$this->load->view('home/index');
}
}
?>
I'm working on a calendar planning provided by [easyappointments][1] but now I'm stuck on this error by yesterday. In the main page users.php I've added the following:
<?php
require_once("application/models/impostazioni_model.php");
$this->load->model('impostazioni_model');
$this->impostazioni_model->load_colours();
?>
the require_once find correctly the file impostazioni_model.php but when I enter in the page users.php I see this error:
Fatal error: Call to a member function load_colours() on a non-object
on this line: $this->impostazioni_model->load_colours();
in the class impostazioni_model.php I've this content:
<?php if ( ! defined('BASEPATH')) exit('Direct execution not allowed.');
class Impostazioni_Model extends CI_Model
{
public function __construct()
{
parent::__construct();
}
public function load_colours()
{
echo "print";
}
}
?>
I've followed the codeigniter documentation, in particular the class model must be in capital letter so I don't know what I'm wrong. Someone could help me out?
In Controller
Path - application/controllers
<?php
if (!defined('BASEPATH'))
exit('No direct script access allowed');
class Admin extends CI_Controller {
function __construct() {
parent::__construct();
$this->load->model('impostazioni_model'); //this will show "Print" word on browser.
}
function index() {
$this->impostazioni_model->load_colours();
}
}
In Model
Path - application/model
<?php
if (!defined('BASEPATH'))
exit('No direct script access allowed');
class Impostazioni_model extends CI_Model {
function __construct() {
parent::__construct();
}
function load_colours() {
echo "print";
}
}
I have been working on a session validation for my login to make sure that a user is logged in to view pages. I keep getting this error:
Fatal error: Class 'MY_Staffcontroller' not found in /usr/local/var/www/CodeTest
/ci/application/controllers/staff_c.php on line 3
My staff_c page looks like so :
<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');
class Staff_c extends MY_Staffcontroller {
function homepage()
{
$data['main_content'] = 'homepage_view';
$this->load->view('includes/template', $data);
}
}
I have been reading same questions all over the place and they say the same thing pretty much...
Is your controller located in application/core?
Well yes it is. I can't seem to get passed this hump!
This is the code within My_Staffcontroller.php:
<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');
class MY_staffcontroller extends CI_Controller {
function __construct()
{
parent::__construct();
$loggedin = $this->session->userdata('loggedin');
if(!isset($loggedin) || $loggedin != TRUE);
{
die($this->load->view('denied'));
}
}
}
I know this is user error as this is only my second day with CodeIgniter but I can't seem to find proper workaround for this?
I have tried this tutorial and still nothing and also this
Even following this video has me stuck on the session part.
And I just can not get this to work.
Remember Linux is case-sensative whereas Windows is case-insensative.
place you're MY_Staffcontroller inside application/core/MY_Controller.php file
Your MY_Controller.php file should look like this (minus all you're other functions, this is a minimal example)
<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');
class MY_Controller extends CI_Controller
{
public function __construct()
{
parent::__construct();
}
}
class MY_Staffcontroller extends MY_Controller
{
public function __construct()
{
parent::__construct();
}
public function sayHello()
{
echo "Hello, I am a function within MY_Staffcontroller.php";
}
}
Example
This will be located in /application/controllers directory
Basically any protected and public functions located in either MY_Controller OR MY_Staffcontroller will be accessible from derived controllers that extend the extended controller. In this case it would be MY_Staffcontroller
class Public_Staff_Controller extends MY_Staffcontroller
{
public function __construct()
{
parent::__construct();
}
public function index()
{
$this->sayHello();
}
}
/* end of file /application/core/MY_Controller.php */