I have this variable that should be in my url but includes the "." (dot). Sorry I am still noob in laravel.
Expected Result is localhost/myProject/public/var_name
Eror says View [.sampleVariable] not found.
my line is
return view('/'.$create->var_name)->compact('anotherVar','anotherVar');
and my route is Route::get('{var_name}', 'MyController#index');
Route is
Route::get('/{var_name}', 'MyController#index');
MyController
public function index($var_name)
{
return view('template.index', ['var_name' => $var_name])->compact('anotherVar','anotherVar');
}
Try below code.
Your controller function code like:
public function index($var_name)
{
//Initiate your variable...
$anotherVar = '';
//Replace 'BLADEFILENAME' to you want to execute blade file name...
return view('BLADEFILENAME', compact('var_name','anotherVar'));
}
You can read more about php compact(). You can also pass variable value from controller to view by wrapping the variable in curly braces
Your route code like:
Route::get('/{var_name}', 'MyController#index');
Now you can use $var_name & $anotherVar into your blade file.
Related
I'm brand new to CodeIgniter, so apologies if I'm missing something obvious here.
I'm comfortable with sending data from a controller to a view file using return view('default/blog/index', $data);. My issue is accessing the same data in a layout file which is extended by the view file using <?= $this->extend('layouts/default'); ?>.
For example, if I insert <?= $data['content'] ?> in my view file, it displays as expected. If I insert the same code in the layout file that is extended by my view file, I get the "Trying to access array offset on value of type null" exception.
What am I missing that will allow me to access my data from within the layout file?
Thanks in advance.
Update:
So in my BlogController I've got
class BlogController extends BaseController
{
public function index()
{
$model = new Blog();
$data = $model->getBlog();
return view('default/blog/index', ['data' => $data]);
}
public function item($slug = null){
$model = new Blog();
$data = $model->getBlog($slug);
return view('default/blog/item', ['data' => $data]);
}
}
And then in my item.php and index.php files, I have
<?= $this->extend('layouts/default', ['data' => $data]); ?>
My Blog Model's getBlog() method:
public function getBlog($slug = false)
{
if ($slug === false) {
return $this->orderBy('bs_created_dt', 'desc')->findAll();
}
return $this->where(['bs_slug' => $slug])->first();
}
When I use the debug toolbar to inspect the data, it is showing as expected, and I can display it in the view files, but not in the layout file.
In Codeigniter, you need to pass data also in an extended file called layouts.
Because you want to access data inside the extended file and for that, you just need to pass data to that file.
So replace the line of code of extended view with this :
$this->extend('layouts/default', ['data' => $data]);
Figured this out - absolute rookie mistake.
I'm working off of a pre-existing template, and the previous developer had overwritten the $data variable in layout file before where I was trying to use it.
I'm off to stand in the corner for a while.
In my web file, I have a route that accepts a $id as a value to be passed to a function within my PagesController. However, I want the function to still execute and show the intended form even when the $id is not passed to the function.
web.php file
Route::get('/request/{id}', 'PagesController#makeRequest');
PagesController.php file
public function makeRequest($id)
{
if(!empty($id)){
$target = Partner::find($id);
}
return view('pages.makeRequest')->with('target', $target);
}
makeRequest.blade.php
<input type="text" class="form-control" value="{{$target->inst_name}}" required disabled>
I want the page to display details from the database with the $id when provided or have empty spaces when the $id isn't provided.
As the Laravel Documentation states: Use Optional Parameters like this:
Route::get('/request/{id?}', 'PagesController#makeRequest'); //Optional parameter
Controller
public function makeRequest($id = null)
{
if(!empty($id)){
$target = User::find($id);
return view('pages.makeRequest')->with('target', $target);
} else {
return view('pageslist'); ///set default list..
}
}
This is the way I did it:
Route::get('index', 'SeasonController#index');
// controller
public function index(Request $request )
{
$id= $request->query('id');
}
The way you call it:
localhost/api/index?id=7
All your solutions were helpful. The main thing was that when I called just the view without passing $target to the view, the page displayed an error. So this is what I did.
Route::get('/request/{id?}', 'PagesController#makeRequest');
Then in the controller,
public function makeRequest(Request $request, $id=null)
{
if ($id != null) {
$target = Partner::find($id);
return view('pages.makeRequest')->with('target', $target);
}
return view('pages.makeNullRequest');
}
If you didn't understand what happened, I created a new view which had this instead of what I had posted in the question.
<input type="text" class="form-control" value="" required readonly>
Sorry I didn't update you guys in time. I think Jignesh Joisar came closest to helping me solve this issue. really appreciate all you guys. You're just awesome
You can use optional parameter :
Route::get('/request/{id?}', 'PagesController#makeRequest');
Now, as the parameter is optional, while defining the controller function you need to assign its default value to null in argument declaration.
<?php
public function makeRequest($id = null)
{
if($id){
$target = Partner::findOrFail($id);
return view('pages.makeRequest')->with(compact('target'));
}
// Return different view when id is not present
// Maybe all targets if you want
$targets = Partner::select('column1', 'column2')->get();
return view('pages.all')->with('targets');
}
I am using findOrFail instead of find. Its Laravel's very handy function which automatically throws a ModelNotFound exception and for frontend user throws a simple 404 page.
So if anyone is accessing www.url.com/request/2, its a valid id then it will show a valid page with data. If the accessed url is www.url.com/request/blahblah then it will throw 404. It avoids efforts of handling this manually.
For optional parameter pass id with ? in route and give $id = null in your function's parameter like this:
Route::get('/request/{id?}', 'PagesController#makeRequest'); //Optional parameter
makeRequest($id = null) {
// Code here...
...
}
in your routes file (web.php , as mentioned in your question)
Route::get('/request/{id?}', 'PagesController#makeRequest');
and in your controller PagesController.php
public function makeRequest($id = null)
{
}
To read more about this, just read https://laravel.com/docs/5.7/routing#parameters-optional-parameters
For me the answer was in the order that I listed the Routes in the routes file.
The routes file will call the first one that matches the pattern.
Route::get('/ohmy/{id?}', 'OhMyController#show');
Route::get('/ohmy/all', 'OhMyController#all'); //never gets called
Instead, put optional parameters at end of list:
Route::get('/ohmy/all', 'OhMyController#all');
Route::get('/ohmy/{id?}', 'OhMyController#show');
the answer has been said. just a side note: optional parameters won't work if you are using resource routes.
for example:
Route::resource('items',itemController::class)->except([
'create',
]);
Route::get('/items/create/{category_id?}',function($category_id = 'abc'){
dd($category_id);
});
if i go to " items/create/1 ", the result will be "1".
if i go to " items/create ", it will return 404. ( but we expect it to say "abc".)
this happens because other routes that start with "items" are expected to be generated from "resource" functionality.
so if you use resource routes, you should consider that.
I cannot figure out how to display the route name in the blade template of laravel. Please find below the sample code. Thank you.
from the controller (StaffsController.php)
public function index()
{
$thisRoute = Route::current()->uri();
return view('staff.list')>with(compact('thisRoute'));
}
Blade:
{{ $thisRoute }}
This is the var_dump
/home/vagrant/Code/spark/app/Http/Controllers/StaffsController.php:20:string 'staffs' (length=6)
Error:
(1/1) UnexpectedValueException
The Response content must be a string or object implementing __toString(), "boolean" given.
When i change the code in the controller to:
public function index()
{
$thisRoute = Route::current()->uri();
return dd($thisRoute);
}
I get "staffs" as output which is correct which is a string from the dump, right?
change your return statement to be like this :
return view('staff.list', compact('thisRoute'));
if you are using laravel 5.3 or above you can get route name like this:
Route::currentRouteName();
with this, you really don't have to passe it from your controller to the view just use it directly from your blade view :
{{ Route::currentRouteName() }}
Sorry guys, I solved the issue. I missed - in the line
return view('staff.list')>with(compact('thisRoute'));
Changed it to
return view('staff.list')->with(compact('thisRoute'));
I made a mistake.
Thank you
I'm trying to pass an array from a function to another function in laravel.
In my PageController.php, I have
public function show($code, $id){
//some code
if(isset($search))
dd($search);
}
and another function
public function search($code, $id){
//some queries
$result = DB::table('abd')->get();
return Redirect::action('PageController#show, ['search'=>$search]);
}
But this returns me an error like this: ErrorException (E_UNKNOWN)
Array to string conversion
I'm using laravel.
You could maybe get it to work with passing by the URL by serialization, but I'd rather store it in a session variable. The session class has this nice method called flash which will keep the variable for the next request and then automatically remove it.
Also, and that's just a guess, you probably need to use the index action for that, since show needs the id of a specific resource.
public function search($code, $id){
//some queries
$result = DB::table('abd')->get();
Session::flash('search', $search); // or rather $result?
return Redirect::action('PageController#index');
}
public function index($code){
//some code
if(Session::has('search')){
$search = Session::get('search');
dd($search);
}
}
Hello I'm creating an API using REST and Laravel following this article.
Everything works well as expected.
Now, I want to map a GET request to recognise a variable using "?".
For example: domain/api/v1/todos?start=1&limit=2.
Below is the contents of my routes.php :
Route::any('api/v1/todos/(:num?)', array(
'as' => 'api.todos',
'uses' => 'api.todos#index'
));
My controllers/api/todos.php :
class Api_Todos_Controller extends Base_Controller {
public $restful = true;
public function get_index($id = null) {
if(is_null($id)) {
return Response::eloquent(Todo::all(1));
} else {
$todo = Todo::find($id);
if (is_null($todo)) {
return Response::json('Todo not found', 404);
} else {
return Response::eloquent($todo);
}
}
}
}
How do I GET a parameter using "?" ?
Take a look at the $_GET and $_REQUEST superglobals. Something like the following would work for your example:
$start = $_GET['start'];
$limit = $_GET['limit'];
EDIT
According to this post in the laravel forums, you need to use Input::get(), e.g.,
$start = Input::get('start');
$limit = Input::get('limit');
See also: http://laravel.com/docs/input#input
On 5.3-8.0 you reference the query parameter as if it were a member of the Request class.
1. Url
http://example.com/path?page=2
2. In a route callback or controller action using magic method Request::__get()
Route::get('/path', function(Request $request){
dd($request->page);
});
//or in your controller
public function foo(Request $request){
dd($request->page);
}
//NOTE: If you are wondering where the request instance is coming from, Laravel automatically injects the request instance from the IOC container
//output
"2"
###3. Default values
We can also pass in a default value which is returned if a parameter doesn't exist. It's much cleaner than a ternary expression that you'd normally use with the request globals
//wrong way to do it in Laravel
$page = isset($_POST['page']) ? $_POST['page'] : 1;
//do this instead
$request->get('page', 1);
//returns page 1 if there is no page
//NOTE: This behaves like $_REQUEST array. It looks in both the
//request body and the query string
$request->input('page', 1);
###4. Using request function
$page = request('page', 1);
//returns page 1 if there is no page parameter in the query string
//it is the equivalent of
$page = 1;
if(!empty($_GET['page'])
$page = $_GET['page'];
The default parameter is optional therefore one can omit it
###5. Using Request::query()
While the input method retrieves values from entire request payload (including the query string), the query method will only retrieve values from the query string
//this is the equivalent of retrieving the parameter
//from the $_GET global array
$page = $request->query('page');
//with a default
$page = $request->query('page', 1);
###6. Using the Request facade
$page = Request::get('page');
//with a default value
$page = Request::get('page', 1);
You can read more in the official documentation https://laravel.com/docs/5.8/requests
We have similar situation right now and as of this answer, I am using laravel 5.6 release.
I will not use your example in the question but mine, because it's related though.
I have route like this:
Route::name('your.name.here')->get('/your/uri', 'YourController#someMethod');
Then in your controller method, make sure you include
use Illuminate\Http\Request;
and this should be above your controller, most likely a default, if generated using php artisan, now to get variable from the url it should look like this:
public function someMethod(Request $request)
{
$foo = $request->input("start");
$bar = $request->input("limit");
// some codes here
}
Regardless of the HTTP verb, the input() method may be used to retrieve user input.
https://laravel.com/docs/5.6/requests#retrieving-input
Hope this help.
This is the best practice. This way you will get the variables from
GET method as well as POST method
public function index(Request $request) {
$data=$request->all();
dd($data);
}
//OR if you want few of them then
public function index(Request $request) {
$data=$request->only('id','name','etc');
dd($data);
}
//OR if you want all except few then
public function index(Request $request) {
$data=$request->except('__token');
dd($data);
}
Query params are used like this:
use Illuminate\Http\Request;
class MyController extends BaseController{
public function index(Request $request){
$param = $request->query('param');
}
In laravel 5.3 $start = Input::get('start'); returns NULL
To solve this
use Illuminate\Support\Facades\Input;
//then inside you controller function use
$input = Input::all(); // $input will have all your variables,
$start = $input['start'];
$limit = $input['limit'];
In laravel 5.3
I want to show the get param in my view
Step 1 : my route
Route::get('my_route/{myvalue}', 'myController#myfunction');
Step 2 : Write a function inside your controller
public function myfunction($myvalue)
{
return view('get')->with('myvalue', $myvalue);
}
Now you're returning the parameter that you passed to the view
Step 3 : Showing it in my View
Inside my view you i can simply echo it by using
{{ $myvalue }}
So If you have this in your url
http://127.0.0.1/yourproject/refral/this#that.com
Then it will print this#that.com in you view file
hope this helps someone.
It is not very nice to use native php resources like $_GET as Laravel gives us easy ways to get the variables. As a matter of standard, whenever possible use the resources of the laravel itself instead of pure PHP.
There is at least two modes to get variables by GET in Laravel (
Laravel 5.x or greater):
Mode 1
Route:
Route::get('computers={id}', 'ComputersController#index');
Request (POSTMAN or client...):
http://localhost/api/computers=500
Controler - You can access the {id} paramter in the Controlller by:
public function index(Request $request, $id){
return $id;
}
Mode 2
Route:
Route::get('computers', 'ComputersController#index');
Request (POSTMAN or client...):
http://localhost/api/computers?id=500
Controler - You can access the ?id paramter in the Controlller by:
public function index(Request $request){
return $request->input('id');
}