I have below code which creates drop-down from php. I want to achieve 2 things here.
1. I want to set one of the option to be set default. It may be hard coded or selected from query.
2. When hit button, it should retain selected option. I could retrieve selected option using session data with this: echo $print_version1[array_keys($print_version1)[0]];
Drop-down code:
$result = $conn->query("SELECT DISTINCT nx_version FROM workflow1 ORDER BY id DESC");
echo "<form action='http://localhost/w_5aug/process.php' method='get'>";
echo "<html>";
echo "<body>";
echo "<p></p>";
echo "<center>";
echo "<strong> Select Base Verison To Compare With : </strong>";
echo "<select name='nx_version' id='nx_version'>";
while ($row = $result->fetch_assoc()) {
$nx_version = $row['nx_version'];
echo '<option>'.$nx_version.'</option>';
}
echo "</select>";
echo " <button type='submit'><b>Add Base Verison</b></button>";
echo "</center>";
echo "</body>";
echo "</html>";
echo "<p></p>";
$array_select = $_SESSION['data'];
print_r($array_select);
echo "<form>";
i assume that the option that should be selected is$print_version1[array_keys($print_version1)[0]
while ($row = $result->fetch_assoc()) {
$nx_version = $row['nx_version'];
if($_SESSION["id"]) {
if($nx_version == "the hardcode value you want to be selected"){
echo '<option selected="selected">'.$nx_version.'</option>';
}else{
echo '<option>'.$nx_version.'</option>';
}
}else{
if($print_version1[array_keys($print_version1)[0]] == $nx_version){
echo '<option selected="selected">'.$nx_version.'</option>';
}else{
echo '<option>'.$nx_version.'</option>';
}
}
}
Related
I have below code which creates drop-down from php. I want to achieve 2 things here.
1. I want to set one of the option to be set default. It may be hard coded or selected from query.
2. When hit button, it should retain selected option. I could retrieve selected option using session data with this: echo $print_version1[array_keys($print_version1)[0]];
Drop-down code:
$result = $conn->query("SELECT DISTINCT nx_version FROM workflow1 ORDER BY id DESC");
echo "<form action='http://localhost/w_5aug/process.php' method='get'>";
echo "<html>";
echo "<body>";
echo "<p></p>";
echo "<center>";
echo "<strong> Select Base Verison To Compare With : </strong>";
echo "<select name='nx_version' id='nx_version'>";
while ($row = $result->fetch_assoc()) {
$nx_version = $row['nx_version'];
echo '<option>'.$nx_version.'</option>';
}
echo "</select>";
echo " <button type='submit'><b>Add Base Verison</b></button>";
echo "</center>";
echo "</body>";
echo "</html>";
echo "<p></p>";
$array_select = $_SESSION['data'];
print_r($array_select);
echo "<form>";
i assume that the option that should be selected is$print_version1[array_keys($print_version1)[0]
while ($row = $result->fetch_assoc()) {
$nx_version = $row['nx_version'];
if($_SESSION["id"]) {
if($nx_version == "the hardcode value you want to be selected"){
echo '<option selected="selected">'.$nx_version.'</option>';
}else{
echo '<option>'.$nx_version.'</option>';
}
}else{
if($print_version1[array_keys($print_version1)[0]] == $nx_version){
echo '<option selected="selected">'.$nx_version.'</option>';
}else{
echo '<option>'.$nx_version.'</option>';
}
}
}
I have been trying to work this out for a while.
I have created a form with a dropdown box that gets results from a database. from this i then $_POST that from to another page. From that second page i wish to get the ID number and then get the records and display them on screen.
I will then put them in a table to organise the results better.
can anyone help me in achieving this.
Here is the code for the form (which works and sends the $PlantID)
$sql = "SELECT DISTINCT * FROM PLANTS";
$result = mysqli_query($mysqli,$sql)or die(mysqli_error());
//********************* Botannical name drop down box
echo "<form name='selection' id='selection' action='profile.php' method='post'>";
echo "<select name='flower'>";
while($row = mysqli_fetch_array($result)) {
$plantid = $row['FlowerID'];
$plantname = $row['Botannical_Name'];
$plantcommon = $row['Common_Name'];
/* $plantheight = $row['Height'];
$plantav = $row['AV'];
$plantcolours = $row['Colours'];
$plantflowering = $row['Flower_Time'];
$plantspecial = $row['Special_Conditions'];
$plantfrost = $row['Frost_Hardy'];
$plantaspect = $row['Aspect'];
$plantspeed = $row['Growth_Speed'];*/
echo "<option value=".$plantid.">".$plantname." -> AKA -> ".$plantcommon."</option>";
}
echo "</select>";
echo "<br />";
//********************* End of form
echo "<input type='submit' name='submit' value='Submit'/>";
echo "</form>";
I have created this page to get the ID and display that ID on screen. AS you can tell i have probably doubled up on ways to try work this out.
$sql = "SELECT * FROM PLANTS";
$result = mysqli_query($mysqli,$sql)or die(mysqli_error());
if(isset($_POST['submit'])){
$selected_val = $_POST['Botannical_Name']; // Storing Selected Value In Variable
echo "You have selected :" .$selected_val; // Displaying Selected Value
}
echo "<br />";
echo "well:".$_POST["Botannical_Name"]."<br/>";
echo "now:".$plantquery."<br />";
echo $_POST;
echo "<table>";
foreach ($_POST as $key => $value) {
echo "<tr>";
echo "<td>";
echo $key;
echo "</td>";
echo "<td>";
echo $value;
echo "</td>";
echo "</tr>";
}
echo "</table>";
Any help would be greatly appreciated.
you should use following to get the selected value,
$selected_val = $_POST['flower'];
if(isset($_POST['submit'])){
$selected_val = $_POST['flower']; // Storing Selected Value In Variable
echo "You have selected :" .$selected_val; // Displaying Selected Value
$sql = "SELECT * FROM PLANTS WHERE FlowerID='.$selected_val.'";
$result = mysqli_query($mysqli,$sql)or die(mysqli_error());
while ($row=mysqli_fetch_assoc($result))
{
echo $row['Botannical_Name'];
}
}
echo "<br />";
print_r($_POST);
if(!empty(_POST)) {
echo "<table>";
foreach ($_POST as $key => $value) {
echo "<tr>";
echo "<td>";
echo $key;
echo "</td>";
echo "<td>";
echo $value;
echo "</td>";
echo "</tr>";
}
echo "</table>";
}
I am currently working on a PHP and SQLite application. It does have HTML for the webpages being created. I am currently using PDO to connect the database to my online server. When I get to the webpage that allows me to type in what I am searching for then it will display what I have found in the echo statements below. I want to be able to have just the item name, that acts as a hyperlink; when it is clicked on it will go to another webpage (I believe) that will display the item's name, amount, and a short description. Is there a way to use PHP for this action or should I go with the HTML tagging?
if($_POST && isset($_POST['search'])) {
echo "<br>\n";
$query = $mysql->prepare('SELECT * FROM Items WHERE Name = :partname');
$subst = array ('partname' => $_POST['search']);
$query->execute($subst);
echo "<TABLE>";
echo "<tr>";
echo "<td>Name</td>";
echo "<td>Amount</td>";
echo "<td>Detail</td>";
echo "</tr>";
while ($row = $query->fetch()) {
//print_r($row);
echo "<tr>";
echo "<td>$row[Name]</td>";
echo "<td>$row[Amount]</td>";
echo "<td>$row[Detail]</td>";
echo "</tr>";
}
echo "</TABLE>";
} else echo "Item searched for was not found.";
from what i understand
if($_POST && isset($_POST['search'])) {
echo "<br>\n";
$query = $mysql->prepare('SELECT * FROM Items WHERE Name = :partname');
$subst = array ('partname' => $_POST['search']);
$query->execute($subst);
echo "<TABLE>";
echo "<tr>";
echo "<td>Name</td>";
echo "</tr>";
while ($row = $query->fetch()) {
//print_r($row);
$name = $row['Name'];
echo "<tr>";
echo "<td><a href='details.php?name={$name}'>{$name}</a></td>";
echo "</tr>";
}
echo "</TABLE>";
} else echo "Item searched for was not found.";
To use Associative Arrays within double quotes, you need to use curly braces:
echo "<td>{$row['Name']}</td><td>{$row['Amount']}</td><td>{$row['Detail']}</td>";
<?php
$id = $_SESSION['user_id'] ;
echo "<form method='post' action='#'>";
echo "</select>
<p>Which Hospital Would You Like to Submit To?</p>";
$queryitem = "SELECT * FROM vendor_hospital WHERE vendor_hospital.user_id = '$id' AND vendor_hospital.approval_status = '1'" or die('MYSQL error: ' . mysql_error());
if ($result = mysql_query($queryitem)) {
if ($success = mysql_num_rows($result) > 0) {
echo "<select name='hospital_name'>";
echo "<option>-- Select A Facility --</option>";
while ($row = mysql_fetch_array($result))
echo "<option value='$row[manufacturer_id]'>$row[manufacturer_id]</option>";
echo "</select><br><br>";
} else {
echo "No results found.";
}
} else {
echo "Failed to connect to database.";
}
echo "<input type='submit' value='Submit' name='submit' class='button' /></form>";
?>
For some reason I'm stuck here. I'm just trying to get the manufacturer name to show in my options instead of the manufacturer_id. The manufacturer name is a foreign key in another table so I can't simply call $row[manufacturer_id] in my option tag. What should I do here? My only thought is to run a query inside the option tag for every manufacturer_id listed as a value but I'm sure that is overkill. Can someone point me in the right direction of a more elegant solution than that?
Not really sure what you are trying to do...but try this.
Replace this:
while ($row = mysql_fetch_array($result))
echo "<option value='$row[manufacturer_id]'>$row[manufacturer_id]</option>";
echo "</select><br><br>";
With this:
while ($row = mysql_fetch_array($result)){
echo "<option value='".$row['manufacturer_id']."'>".$row['manufacturer_id']."</option>";
}
echo "</select><br><br>";
Also be sure to double check and make sure that you are pulling from the right database, that it is populated, you are calling the right table names, etc...
I have an error here, the data retrived from mysql database and listed in listbox or dropdown, when i need to update my form i get the result after refresh.
I have tried but need to sortout
<?
include("connect.php");
mysql_select_db("joblisting") or die(mysql_error());
$result = mysql_query("SELECT * FROM positiontitle") or die(mysql_error());
$ans=$positiontitle;
echo $ans;
?><select size=1 name="positiontitle" id="positiontitle"><?
echo '<option value="'.$ans.'">';
echo "</option>";
while ($row = mysql_fetch_array($result))
{
echo "<option>";
echo $row['positiontitle'];
echo "</option>";
}
echo "<br />";
?>
where are you defining $positiontitle ? shouldn't it be $_POST['positiontitle']?