How do I remove time from a date in PHP, for example:
20170803173418 I want to take 4 minutes and 13 seconds away and get the new datestamp that would be 20170803173005
What code do I use to get this?
EDIT
I currently have:
$dbTime = $row['aptDeadline']; // This is the appointment end time stored in DB
$dbTime = new DateTime($dbTime);
$currentTime = date("YmdHis"); // This is the current time
$currentTime = new DateTime($currentTime);
$counterTime = $row['aptDeadline']; //This is the time a countdown clock works from inDB
$counterTime = new DateTime($counterTime);
$difference = $currentTime->diff(new DateTime($dbTime)); // Calculate the time between now and the apt time in the db
I now need some code that if the $difference is positive, can take this figure away from the $counterTime stamp
You can use the modify method of the DateTime class in PHP:
<?php
$time = new \DateTime('20170803173418');
$time->modify('-4 minutes')->modify('-13 seconds');
echo $time->format('YmdHis');
This will print the result you want.
Related
in my sql table I save the date and time of a certain action, how can I print it via php on the contrary, or how long ago did it take place?
for example
|date |
|05-28-2020 17:12:05 |
and at 17:30:05 it will be written on my php page
"18 minutes ago"
Load the date from the database using a mysqli_query and store the result in $original_date.
Create a date object from the string in the database.
$old_date = new DateTime($original_date);
Get the current date in the same format and store it in another variable.
$current_date = new DateTime(date("m-d-Y H:m:s"));
Get the difference between the two dates.
$difference = $old_date->diff($current_date);
Convert the difference to minutes and display message.
echo($difference->m . "minutes ago");
Here is the full code for you to use:
# Get database value and store in $original_date
$old_date = new DateTime($original_date);
$current_date = new DateTime(date("m-d-Y H:m:s"));
$difference = $old_date->diff($current_date);
echo($difference->m . "minutes ago");
I have stored date field at DB.
In PHP, i am getting that field and converted into date.
I want to compare that time with current time. If that difference is above 60 minutes. It will return some value.
I dont know how to write logic for that
$lastUpdatedField = $rows_fetch['lastUpdatedTime'];
$lastUpdatedDate = new DateTime($lastUpdatedField);
$nowDate = new DateTime(date('y-m-d h:m:s'));
I have old date&time is in $lastUpdatedDate variable, and current time is in $nowDate.
How to compare these two
$interval = $nowDate->diff($lastUpdatedDate);
echo $interval->h;
DateDiff: http://www.php.net/manual/en/datetime.diff.php
DateInterval: http://www.php.net/manual/en/class.dateinterval.php
Had The same problem earlier its actually quit simple
heres the piece where you declare your variables
$lastUpdateddate = new DateTime($lastUpdatedField);
$nowDate = new DateTime(date('y-m-d h:m:s'));
Then you have to convert them to second - format so that you can do math with them
To do that use strtotime
$Diff = strtotime($lastUpdatedDate) - strtotime($nowDate);
Then just check to see if the difference in time is more then 60 minutes,
So devide by 60 seconds to get minutes and by 60 to get hours
if ($diff/60/60 <= 1){
//do your thing here
{
First convert the current time and old time to one unit like Unix timestamp passing it through strtotime(). Then differentiate both the timestamp to get the difference between two times.
$difftime = strtotime(date('Y-m-d H:i:s')) - strtotime($rows_fetch['lastUpdatedTime']);
Then convert the difference to days as follows :
$days=$difftime/24*60*60;
Once you get the days you can get the minutes from it as below to compare to meet your need.
$timediff = $days * 24 * 60;
I want to check if 30 min passed after created time in database. created is a time column having time stamp in this format 1374766406
I have tried to check with date('m-d-y H:i, $created) but than of course it is giving human readable output so don't know how to perform check if current time is not reached to 30min of created time.
Something like if(created > 30){}
Try this:
$created = // get value of column by mysql and save it here.
if ($created >= strtotime("-30 minutes")) {
// its over 30 minutes old
}
The better approach is to use DateTime for (PHP 5 >= 5.3.0)
$datenow = new DateTime();
$datenow->getTimestamp();
$datedb = new DateTime();
$datedb->setTimestamp(1374766406);
$interval = $datenow->diff($datedb);
$minutes = $interval->format('%i');
$minutes will give you the difference in minutes, check here for more
http://in3.php.net/manual/en/datetime.diff.php
Here is the working code
http://phpfiddle.org/main/code/jxv-eyg
You need to use strtotime(); to convert the date in human form back to a timestamp, then you can compare.
EDIT: Maybe I misread.
So something like;
if(($epoch_from_db - time()) >= 1800){
//do something
}
How can I compute time difference in PHP?
example: 2:00 and 3:30.
I want to convert the time to seconds then subtract them then convert it back to hours and minutes to know the difference. Is there an easier way to get the difference?
Look at the PHP DateTime object.
$dateA = new DateTime('2:00');
$dateB = new DateTime('3:00');
$difference = $dateA->diff($dateB);
(assuming you have >= PHP 5.3)
You can also do it the procedural way...
$dateA = strtotime('2:00');
$dateB = strtotime('3:00');
$difference = $dateB - $dateA;
See it on CodePad.org.
You can get the hour offset like so...
$hours = $difference / 3600;
If you are dealing with times that fall between a 24 hour period (0:00 - 23:59), you could also do...
$hours = (int) date('g', $difference);
Though that is probably too inflexible to be worth implementing.
Check this link ...
http://www.onlineconversion.com/days_between_advanced.htm
I used this to calculate the difference between server time and the users local time. Grab the hour difference and drop that in a form when the user is registering. I then use it to update the time on the site for the user when they do stuff online.
Once I got it working, I switched this line ...
if (form.date1.value == "")
form.date1.value = s;
to ...
form.date1.value = "<?PHP echo date("m/d/Y H:i:s", time()) ?>";
Now I can compare the user time and the server time! You can grab the seconds and mins as well.
How can I identify the time passed after an user updated his account in my MySQL database? I have a timestamp in my MySQL table (to store user update time) so now how can I identify the time passed from last user update, using PHP?
As example:
User last update time: 2012-04-08 00:20:00;
Now: 2012-04-08 00:40:00;
Time passed since last update: 20 (minutes) ← I need this using PHP
If you have the data on
$last_update_time = '2012-04-08 00:20:00';
$now = time(); //this gets you the seconds since epoch
you can do
$last_update_since_epoch = strtotime($last_update_time); //this converts the string to the seconds since epoch
aand... now, since you have seconds on both variables
$seconds_passed = $now - $last_update_since_epoch;
now, you can do $seconds_passed / 60 to get the minutes passed since the last update.
Hope this helps ;)
In pseudo-code:
$get_user_time = mysql_query("SELECT timestamp FROM table");
$row = mysql_fetch_array($get_user_time);
$user_time = $row['timestamp']; //This is the last update time for the user
$now_unformatted = date('m/d/Y h:i:s a', time());
$now = date("m/d/y g:i A", $now_unformatted); // This is the current time
$difference = $now->diff($user_time); // This is the difference
echo $difference;
diff() is supported in >= PHP 5.3. Otherwise you could do:
$difference = time() - $user_time;
$secs=time()-strtotime($timestamp);
would give u number of seconds before it was updated and then you can convert this seconds into your needed time format like
echo $secs/60." minutes ago";
why not do it with mysql:
select TIMEDIFF(NOW(),db_timestamp) as time_past