This question already has answers here:
How to pass a variable inside a function?
(1 answer)
How to access array element inside another array [duplicate]
(1 answer)
Closed 5 years ago.
I have an API's Function :
$transaction=$tran[4];
function coinpayments_api_call($cmd, $req = array(),$transaction) {
curl_init($transaction);
}
$transaction variable not passing into function coinpayments_api_call.
function not taking values from out side.
I also make $transaction varible GLOBAL ,but still same problem ,
Please Help
Make your code like this
$transaction=$tran[4];
function coinpayments_api_call($transaction,$cmd, $req = array(),$txnid) {
curl_init($transaction);
}
Related
This question already has answers here:
Reference - What does this error mean in PHP?
(38 answers)
Closed 3 years ago.
My goal is set value if field is empty.
But get "Trying to get property of non-object" error.
last_day is empty field, how to assign value 1 ?
public function getPointsForExercises(){
$ls = Auth::user()->lessons()->get();
$last_day = Auth::user()->user_settings->last_day;
if (empty($user->user_settings->last_lesson)) {
$user->user_settings->last_lesson = 1;
}
First problem: $user variable is not defined.
What you are trying to achieve can be done using the exists function to make sure the relation exists, and then update the value using the update function, like this:
public function getPointsForExercises() {
$ls = Auth::user()->lessons()->get();
$last_day = Auth::user()->user_settings->last_day;
if (Auth::user()->user_settings()->exists() && empty(Auth::user()->user_settings->last_lesson)) {
Auth::user()->user_settings()->update([
'last_lesson' => 1
]);
}
The code above is not ending the function nor is it using the variables $ls and $last_day as your code.
You did not set the $user object.
firstly you have to make object :
$user = Auth::user()
This question already has answers here:
Using braces with dynamic variable names in PHP
(9 answers)
Closed 6 years ago.
Using PHP variable variables with mysqli_fetch_assoc to auto-format variables like $column_name="some_value" (code below):
while ($account_row=mysqli_fetch_assoc($account_results))
{
foreach ($account_row as $key=>$value)
{
$$key=trim(stripslashes($value));
}
}
So if I have a column "username" and row value "someuser", this code creates:
$username="someuser";
However, in some cases I need variable names to be DIFFERENT from column names. For example, I need code to create:
$username_temp="someuser";
How could I do that? Using this code gives an error:
$$key."_temp"=trim(stripslashes($value));
No other ideas in my head.
change $$key."_temp" to ${$key."_temp"} have a look on below solution:
$value = 'test';
$key="someuser";
${$key."_temp"}=$value;
echo $someuser_temp; //output test
Please try this ${$key . "_temp"} = trim(stripslashes($value));
This question already has answers here:
Passing an optional parameter in PHP Function [duplicate]
(6 answers)
Closed 7 years ago.
Okay - I was able to the pass a string assigned to the variable $myfile into the function. If it could be better, please provide feedback- learning PHP.
<?php
$myfile = $row_rs_recordview['headstone'];
echo "$myfile"; // verify the file name
function readGPSinfoEXIF($myfile)
{
global $myfile;
$exif= exif_read_data("headstone/".$myfile, 0, true); //
if(!$exif || $exif['GPS']['GPSLatitude'] == '') //Determines if the
//geolocation data exists in the EXIF data
{
return false; //no GPS Data found
echo "No GPS DATA in EXIF METADATA";
}
?>
Insights appreciated!
Thanks
you can't access the global variables inside function directly.
//add global before variable declaration like this
function fun(){
global $row_rsUpdate['headstone'];
}
This question already has answers here:
Only variables should be passed by reference
(12 answers)
Closed 7 years ago.
I have the following code :
$_SESSION['aParties'] = time();
$aParties[] = $_SESSION['aParties'];
error_log(print_r($aParties,true), 3, "/var/tmp/error.log");
$first = reset(ksort($aParties));
The array aParties is like this :
Array
(
[0] => 1433841062
)
But I get the error :
'Only variables should be passed by reference in the method ksort'
Help me please! Thx in advance
You need to do it as
ksort($aParties);
$first = reset($aParties);
Note: There is no reference sign on a function call - only on function definitions. Function definitions alone are enough to correctly pass the argument by reference.
Check Docs
This question already has answers here:
Passing arrays as url parameter
(11 answers)
Closed 9 years ago.
$deposit=$_POST['amountdeposit'];
$arr= array();
for($i=0;$i<10;$i++)
{
if($arr[$i]=='\0')
{ $arr[$i]= array("$deposit");
}
break;
}
$page= "step2.php?arr=$arr";
header("Location:$page");
?>
what i want to do is each time there's a change in $deposit , this value is stored in $arr[$i] and then it is passed in a url so that i could use GET on that step2.php page.
What I see is just arr=array instead of values :/ please help me.
You want http_query_string. It will do exactly what you want.
A couple of other comments have recommended http_query_string, however I would use serialize along with urlencode.
Replace:
$page= "step2.php?arr=$arr";
with:
$page= "step2.php?arr=" . urlencode(serialize($arr));
Then when you get to step2.php, unserialize(urldecode($_GET['arr'])) will contain your array as you originally built it.