Displaying Only the Items in the Cart? - php

Question

So I need to display items that were added on the Vend Page and are now in the cart array over onto the cart page in a list
Array
(
[cart] => Array
(
[BRB] => 1
)
)
Here is my code for the cart page that I'm working on:
if (isset($_SESSION['cart'])) {
foreach ($vend as $vendID => $items) {
//if (array_search($vendID, $_SESSION['cart'])) {
echo "<article class ='cart' id='cart-$vendID'>";
echo "<h1 class = 'item-h1' id = 'h1'>{$items['title']}</h1>";
echo "<div class ='item-no'>";
echo "<p class = 'pro-id'><b>Product ID: </b>{$vendID}</p></div>";
echo "<div class ='img-div'>";
echo "<img src =../images/{$items['img']} alt='' height='196' width='200'></div>";
echo "<div class='pricing'>";
echo "<p><b>Price: $</b>{$items['price']}</p></div>";
echo "</article>";
//}
}
}
I commented out code that I attempted but didn't work. So I need an IF statement which says, If the vendID is in the cart array display it in the list.
Some help is appreciated here as I'm stuck.

Answer 1

Your cart should be as follows:
$cart = array(
[0] => Array
(
[item_id] => 1,
[title] => "your title",
[price] => 100,
[img] => "name of the file",
),
[1] => Array
(
[item_id] => 2,
[title] => "your title",
[price] => 200,
[img] => "name of the file",
)
);
And Then Try as follows:
if (isset($_SESSION['cart'])) {
foreach ($cart as $key => $items) { //$key = [0], [1] ....
echo "<article class ='cart' id='cart-$key'>";
echo "<h1 class = 'item-h1' id = 'h1'>".$items['title']."</h1>";
echo "<div class ='item-no'>";
echo "<p class = 'pro-id'><b>Product ID: </b>".$items['item_id']."</p></div>";
echo "<div class ='img-div'>";
echo "<img src =../images/".$items['img']." alt='' height='196' width='200'></div>";
echo "<div class='pricing'>";
echo "<p><b>Price: $</b>".$items['price']."</p></div>";
echo "</article>";
}
}
Mark, it accepted if it works.

Answer 2

Did you try in_array() ?
It checks if a value exists in an array.