Laravel: MYSQL query in laravel - php

I have a working query goes like this
SELECT s.name as status, q.name as quality, p.name process, count(*)
FROM plates
JOIN equipment_status_codes s on equipment_status_code_id = s.id
JOIN plate_qualities q on plate_quality_id = q.id
JOIN processes p on process_id = p.id WHERE project_id in
(SELECT id
from projects
WHERE name like 'SPIRIT')
GROUP BY s.name, q.name, p.name ASC with ROLLUP
This works just and returns results just fine.
Now I am trying to put this in laravel syntax, but having some difficulties.
So I was thinking something along these lines.
return Plate::select('equipment_status_codes.name as Status', 'plate_qualities.name as Quality', 'processes.name as Process')
->join('equipment_status_codes', 'plates.equipment_status_code_id', '=', 'equipment_status_codes.id')
->join('plate_qualities', 'plates.plate_quality_id', '=', 'plate_qualities.id')
->join('processes', 'plates.process_id', '=', 'processes.id')
->groupBy(DB::raw('equipment_status_code_id WITH ROLLUP'))
...
...
->get();
Would someone help out. Thanks in advance!
Update:
#Govind Samrow
I have tried this query. It works (with couple of small adjustment) But I am not getting the same results as the one I get when I run the sql query.
I included screen shots.
So when I run the sql query.
I get the following results.
When I run the laravel query.
return DB::table('plates')
->join('equipment_status_codes', 'equipment_status_code_id', '=', 'equipment_status_codes.id')
->join('plate_qualities', 'plate_quality_id', '=', 'plate_qualities.id')
->join('processes', 'process_id', '=', 'processes.id')
->whereRaw("project_id IN(SELECT id from projects WHERE name like 'SPIRIT')")
->select(DB::raw('equipment_status_codes.name as Status'), DB::raw('IFNULL(plate_qualities.name, NULL) as Quality'), DB::raw('IFNULL(processes.name, NULL) as process'), DB::raw("COUNT(*) as Total" ))
->groupBy(DB::raw('equipment_status_codes.name WITH ROLLUP', 'plate_qualities.name WITH ROLLUP', 'processes.name WITH ROLLUP', 'asc'))
->get();
I get the following.
Almost there, but I am not sure what's going on?! Any ideas?

Try following Query for Joining with where Condition
return Plate::select('equipment_status_codes.name as Status', 'plate_qualities.name as Quality', 'processes.name as Process')
->join('equipment_status_codes', 'plates.equipment_status_code_id', '=', 'equipment_status_codes.id')
->join('plate_qualities', 'plates.plate_quality_id', '=', 'plate_qualities.id')
->join('processes', function($join)
{
$join->on('plates.process_id', '=', 'processes.id')
->whereIn('project_id', DB::table('projects')->where('name','LIKE','SPIRIT')->select('id')->get()->toArray());
})
->groupBy(DB::raw('equipment_status_code_id WITH ROLLUP'))
->get();
Hope this will help.

Use whereRaw for sub query in where clause Try this:
DB::table('plates')
->join('equipment_status_codes', 'equipment_status_code_id', '=', 'equipment_status_codes.id')
->join('plate_qualities', 'plate_quality_id', '=', 'plate_qualities.id')
->join('processes', 'process_id', '=', 'processes.id')
->whereRaw("project_id IN(SELECT id from projects WHERE name like 'SPIRIT')")
->select('equipment_status_codes.name as status', 'plate_qualities.name as quality', 'q.name as quality', 'processes.name as Process', DB::raw("COUNT(*) as Total"))
->groupBy(DB::raw('equipment_status_codes.name, plate_qualities.name, processes.name ASC with ROLLUP'))->get();
Here is raw sql result of above that got with toSql():
select `equipment_status_codes`.`name` as `status`, `plate_qualities`.`name` as `quality`, `q`.`name` as `quality`,
`processes`.`name` as `Process`, COUNT(*) as Total from `plates`
inner join `equipment_status_codes` on `equipment_status_code_id` = `equipment_status_codes`.`id`
inner join `plate_qualities` on `plate_quality_id` = `plate_qualities`.`id`
inner join `processes` on `process_id` = `processes`.`id`
where project_id IN(SELECT id from projects WHERE name like 'SPIRIT')
group by equipment_status_codes.name, plate_qualities.name, processes.name ASC with ROLLUP
Note: You can use SQL output with $query->toSql() and then compare with your actual SQL query.

You may use the table method on the DB facade to begin a query. The table method returns a fluent query builder instance for the given table, allowing you to chain more constraints onto the query and then finally get the results using the get method:
Check its link and get knowladge for laravel query builder:-
https://laravel.com/docs/5.4/queries

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i'm using raw query on my laravel function, and i wanna make it into laravel query builder, but i really have no idea how to do it, i've read laravel documentary about advanced join clause or subquery joins, but still cant figuring it out how to convert it
raw query :
$buku = DB::select(
DB::raw('
SELECT buku.*, kategory, tag
FROM buku
LEFT JOIN kategori_buku ON buku.id_kategori = kategori_buku.id
LEFT JOIN detail_buku_tag ON buku.id = detail_buku_tag.id_buku
LEFT JOIN (SELECT tag_buku.id, GROUP_CONCAT(tag) AS tag FROM tag_buku) AS tag_buku ON tag_buku.id = detail_buku_tag.id_tag
GROUP BY buku.id')
);
there some sql chaining issue. #Ramiz Kongulov forget to split group by clause try this.
$buku = \DB::table('buku')
->select(['buku.*','kategory.*', 'tag.*'])
->leftJoin('kategori_buku', 'kategori_buku.id', '=', 'buku.id_kategori')
->leftJoin('detail_buku_tag', 'detail_buku_tag.id_buku', '=', 'buku.id')
->leftJoin(\DB::raw('(SELECT tag_buku.id, GROUP_CONCAT(tag) AS tag FROM tag_buku) AS tag_buku'),
'tag_buku.id', '=', 'detail_buku_tag.id_tag')
->groupBy('buku.id')
->get();
try this
$buku = \DB::table('buku')
->select([
'buku.*',
'kategory.*',
'tag.*'
])
->leftJoin('kategori_buku', 'kategori_buku.id', '=', 'buku.id_kategori')
->leftJoin('detail_buku_tag', 'detail_buku_tag.id_buku', '=', 'buku.id')
->leftJoin(DB::raw('SELECT tag_buku.id, GROUP_CONCAT(tag) AS tag FROM tag_buku) AS tag_buku ON tag_buku.id = detail_buku_tag.id_tag GROUP BY buku.id'))
->get();

Laravel 7: getting rows between two dates where the column is datetime

I'm having trouble building an eloquent query wherein I can recreate this sql command:
The date_created column is datetime.
SELECT * FROM covidchecklist cc
LEFT JOIN patient_appointment pa ON cc.appointment_id = pa.appointment_id
LEFT JOIN users pat ON pa.user_id = pat.id
WHERE DATE_FORMAT(cc.date_created,'%Y-%m-%d') BETWEEN '2021-01-27' AND '2021-01-27'
What I have right now:
CovidChecklist::
leftJoin('patient_appointment', 'covidchecklist.appointment_id', '=', 'patient_appointment.appointment_id')
->leftJoin('users as patient', 'patient_appointment.user_id', '=', 'patient.id')
->whereRaw(' DATE_FORMAT(covidchecklist.date_created,"%Y-%m-%d") BETWEEN '.'$this->date_from'.' AND '.'$this->date_to'.' ')
->select(
*select stuff*
)
->get();
I am using whereRaw since I can't get this to work:
->whereBetween('covidchecklist.date_created', [$this->date_from, $this->date_to])
Try this, mate
->whereBetween(\DB::raw('DATE_FORMAT(covidchecklist.date_created,"%Y-%m-%d")'), [$this->date_from, $this->date_to])

Left join 2 times raw query laravel doesn't work (Laravel)

I tried my raw query sql in laravel and i need to left join it 2 times but the print out is wrong. It different from mysql. I've tried in mysql and it works well
this is my code :
$tabel = DB::SELECT(DB::RAW("
SELECT codeh.info_code kh_infocode, codep.no_code khp_nocode,
codep.info_code khp_infocode,
codep.name_code khp_namecode, t.* FROM transactions t
LEFT JOIN users u ON t.user_id=u.id
LEFT JOIN divisions d ON d.id=u.division_id
LEFT JOIN all_codes codep ON t.code_p_id=codep.id
LEFT JOIN all_codes codeh ON t.allcode_id=codeh.id
WHERE 1=1
AND d.id=$div_id
AND codep.no_code LIKE '$allcode->no_code%'
$db_date
ORDER BY t.date, khp_nocode
"));
it works really well in sql but when i put it in laravel kh_infocode change and the value same like khp_infocode even though kh_infocode has different value with khp_infocode
Everything is in the official docs. It's not even long, go give it a read.
DB::table('transactions as t')
->select(
'codeh.info_code',
'kh_infocode',
'codep.no_code',
'khp_nocode',
'codep.info_code',
'khp_infocode',
'codep.name_code',
'khp_namecode',
't.*',
)
->leftJoin('users as u', 't.user_id', '=', 'u.id')
->leftJoin('all_codes as codep', 't.code_p_id', '=', 'codep.id')
->leftJoin('all_codes as codeh', 't.allcode_id', '=', 'codeh.id')
->where('d.id', '=', $div_id)
->where('codep.no_code', 'like', $allcode->no_code.'%')
->orderBy('t.date')
->orderBy('khp_nocode')
->get();
simply set SQL string directly without DB::RAW()
$tabel = DB::SELECT('your select statment');

How to create SQL Join Statement in Laravel Controller

I have two table customer_id namely tbl_customer and tbl_stocks connected on the same database. My logic about this problem is JOIN sql statement.
This is for Laravel and MySQL, so far i've tried this on PHP and is working fine but when I implement it on laravel it is not working i wonder why?
here is my code in PHP and want to convert it to laravel but I dont know where to put? will i put it in the View or in the Controller
$query = "SELECT c.*, s.* FROM tbl_customer c JOIN tbl_stock s ON s.customer_id = c.customer_id AND c.customer_id = 1";
Controller
$data = DB::table('tbl_customer')
->join ...... //Im not sure about this
->select .... // neither this
->get();
print_r($data)
Model
I have no codes on my model
Routes
Route::get('/admin/shopcontrol', 'Admin\ShopsController#testquery');
I expect a result of fetching or getting the query or result of the values in just a simple echo and the fetch join is connected
Have you checked the Laravel site?
https://laravel.com/docs/5.7/queries#joins
It has a demonstration you could use to reorganize your code.
As it follows below from the site.
Joins
Inner Join Clause
The query builder may also be used to write join statements. To perform a basic "inner join", you may use the join method on a query builder instance. The first argument passed to the join method is the name of the table you need to join to, while the remaining arguments specify the column constraints for the join. Of course, as you can see, you can join to multiple tables in a single query:
$users = DB::table('users')
->join('contacts', 'users.id', '=', 'contacts.user_id')
->join('orders', 'users.id', '=', 'orders.user_id')
->select('users.*', 'contacts.phone', 'orders.price')
->get();
You may find more information there if it suits you.
Try this:
$data = DB::table('tbl_customer')
->join('tbl_stock', 'customer_id', '=', 'tbl_customer.customer_id')
->select('tbl_customer.*', 'tbl_stock.*')
->where('customer_id', '=', 1)
->get();

Laravel 5: Native SQL to Query Builder

I am trying to join 2 tables on Laravel 5 and have to use Query Builder. I have already got the sql for it but i am not able to convert it to Query Builder syntax. SQL is below
SELECT v.id, r.full_name, b.full_name, s.full_name
FROM vehicles v
LEFT JOIN clients r ON v.representive_client_id = r.id
LEFT JOIN clients b ON v.buyer_client_id = b.id
LEFT JOIN clients s ON v.seller_client_id = s.id
and what i tried is
$query_result = DB::table('vehicles')
->selectRaw($query)
->leftJoin('clients', 'vehicles.representive_client_id', '=', 'clients.id')
->leftJoin('clients', 'vehicles.buyer_client_id ', '=', 'clients.id')
->leftJoin('clients', 'vehicles.seller_client_id ', '=', 'clients.id')
->paginate(30);
The problem is i dont know how to use AS caluse for Query Builder as i need to retrive 3 different types of full_name columns from vehicles table.Anybody can help me about how to write it in a proper Query Builder syntax ?. Any help would be appreciated.
You can use aliases with select columns and tables as well as joins, because the Query Builder will know to quote them correctly. So you can do this without any problems:
$query_result = DB::table('vehicles v')
->select('v.id', 'r.full_name as r_name', 'b.full_name as b_name', 's.full_name as s_name')
->leftJoin('clients r', 'vehicles.representive_client_id', '=', 'r.id')
->leftJoin('clients b', 'vehicles.buyer_client_id ', '=', 'b.id')
->leftJoin('clients s', 'vehicles.seller_client_id ', '=', 's.id')
->paginate(30);
Of course, you can use whatever aliases you want for the selected columns. Actually one of the examples in the Query Builder Selects Documentation uses aliases: email as user_email.
To check the SQL query generated by the Query Builder you can use the toSql method. So in your case instead of ->paginate(30) you can have ->toSql(), which will return a string with the SQL generated by the Query Builder, which you can compare to your raw query and see if it matches.

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