how to create an array using days key in php - php

Question

I have an array of object with dynamic date and days. I want to sort array with days keys in php in the order of the days.
Given input like this:
array(
[17-08-2017] => stdClass Object
(
[days] => Thu
)
[21-08-2017] => stdClass Object
(
[days] => Mon
)
[22-08-2017] => stdClass Object
(
[days] => Tue
)
[23-08-2017] => stdClass Object
(
[days] => Wed
)
);
I want result like this:
array(
[21-08-2017] => stdClass Object
(
[days] => Mon
)
[22-08-2017] => stdClass Object
(
[days] => Tue
)
[23-08-2017] => stdClass Object
(
[days] => Wed
)
[17-08-2017] => stdClass Object
(
[days] => Thu
)
);
I know this is the stupid idea but how can I do this. Please help me.

Answer 1

convert your key to strtotime($key)
then apply ksort($dates) but it will eliminate the duplicate key.
Probably the same question

Answer 2

You need a custom sorting function.
$t = new DateTime('this week'); //Using this to hopefully adapt for locale wrt which day is first
$daysOrder = [];
for ($i=0;$i<7;$i++) {
$daysOrder [] = $t->format("D");
$t->add(new DateInterval("P1D"));
}
$daysOrder = array_flip($daysOrder); //Days as keys, order as values
Then you can sort:
$array = uasort($array, function ($x,$y) use ($daysOrder) {
//May need to do some checks here to determine if $x and $y are valid days
return $daysOrder[$x] <=> $daysOrder[$y]; //PHP 7 syntax
});
The PHP 5.x syntax would be something like:
return $daysOrder[$x] < $daysOrder[$y]?-1:($daysOrder[$x]==$daysOrder[$y]?0:1);