I have a code for days interval
<?php
$datetime1 = new DateTime(); // Today's Date/Time
$datetime2 = new DateTime('2012-07-17 15:30:17');
$interval = $datetime1->diff($datetime2);
echo $interval->format('%D days %H hours %I minutes ago');
?>
How can I include time from database
example
<?php echo htmlentities($row['date']); ?>
I know you're using PHP, but if you want this on the front end you could consider moment.js: https://momentjs.com/ it handles human-like date outputs.''
Edit: after further searching, this is exactly what you're looking for momentPHP: https://github.com/fightbulc/moment.php
Related
Sorry if this is not the correct place to post this but doing research on Google I haven't been able to find a suitable answer.
What I want to achieve is a user types in a date and time on the site and this gets inserted into the database (two different fields, a date field and a time field).
I then need to get the total of minutes until that day/time. I have the following code which prints out the days, hours and minutes. But I'm unsure of how to convert it to a total of minutes:
date_default_timezone_set("Europe/London");
$now = new DateTime();
$future_date = new DateTime(''.$Date.''.$Time.'');
$interval = $future_date->diff($now);
echo $interval->format("%a days, %h hours & %i minutes");
$now = new DateTime();
$future_date = new DateTime($Date.' '.$Time);
$minutes = ($future_date->getTimestamp() - $now->getTimestamp())/60;
Unix timestamp stores the date in seconds. So you can calculate it without initialize a DateInterval with the diff() function.
I'm calculating the difference between 2 dates using DateTime() and it's working fine. The problem is that I want to have the days format be able to go above a full month so 30/31 or higher.
$now = new DateTime();
$future_date = new DateTime($contest->expires_at);
$interval = $future_date->diff($now);
$enddate = $interval->format("%m month, %d days, %h hours, %i minutes");
The current problem with this is that when I don't display the months, the days can only go up to 30/31 and anything over that will be carried over to make a new month resetting the days count with the leftover days.
I want to be able to display 42 days when the difference is 6 weeks with this kind of format:
$enddate = $interval->format("%d days, %h hours, %i minutes");
Is there a quick fix for this or do I need to manually convert the timestamp to seconds and use my own function with modulus operators for this?
You can try:
$enddate = $interval->format("%a days, %h hours, %i minutes");
See the DateInterval::format in the manual.
NOTE
Take care of the bug if you're working on windows.
This should solve your porblem:
$now = new DateTime();
$future_date = new DateTime();
// a period of 2 months
$addPeriod = new DateInterval('P2M');
// adding the period
$future_date->add($addPeriod);
// get the differnce
$interval = $future_date->diff($now);
echo($interval->days) . ' days';
For today: echo returns '61 days'
// EDIT
To avoid running into the dataInterval-Bug you can use:
$now = new DateTime();
$future_date = new DateTime();
// a period of 2 months
$addPeriod = new DateInterval('P2M');
// adding the period
$future_date->add($addPeriod);
// get the difference in second
$diffTimestamp = $future_date->getTimestamp() - $now->getTimestamp();
// convert to days
// 1 day = 86.400 seconds
$diffDays = $diffTimestamp/86400;
echo(floor($diffDays)) . ' days';
Update my php version since this is a bug in my old and it works perfectly now.
How to get aggregate days from PHP's DateTime::diff?
So I have a question about a DateTime in php.
$datetime1 = new DateTime('2013-02-01 10:40:00');
$datetime2 = new DateTime('2013-02-03 19:13:00');
$interval = $datetime1->diff($datetime2);
echo $interval->format('%d day %h hours %i minutes');
What echo outputs is: 2day 8hours 33minutes.
Ok I know that the difference between first and the second variable is equal to the output. But is there any way that the output could be some sort of count down.
For example:
$datetime1 = new DateTime('2013-01-01 00:00:00');
$datetime2 = new DateTime('2013-01-01 13:30:00');
What I want to be output is: 13:30:00, and 2 minutes later there would be 13:28:00.
Is there any way to be done that with diff function.
Thanks for help
Sebastian
This will only work if:
one of the times in now
the page refreshes or you use ajax. PHP is executed on the server-side.
So you basically already have the code with just a tweak:
$datetime1 = new DateTime();
$datetime2 = new DateTime('2013-02-03 19:13:00');
$interval = $datetime1->diff($datetime2);
echo $interval->format('%d day %h hours %i minutes');
I've a date like this: 2011-01-28 00:37:15.
What would be the most efficient way to get days from now till this date? I want like number of full days till this date so I could display message: "after X days" rather than showing ugly date.
I am using php 5.2.6.
<?
$date = "2011-01-28 00:37:15";
$date_2 = date("Y-m-d H:i:s");
$date_diff=(strtotime($date)-strtotime($date_2)) / 86400;
?>
Have a look at http://de.php.net/manual/de/datetime.diff.php (PHP >=5.3.0)
This will return you a DateIntervall wich has a public attribute days
<?php
$datetime1 = new DateTime('2011-01-28 00:37:15');
$datetime2 = new DateTime('now');
$interval = $datetime1->diff($datetime2);
echo $interval->format('%R%d days');
?>
Looks like this should help:
http://www.prettyscripts.com/code/php/php-date-difference-in-days
I want to get the absolute days away a datetime is from today. For example, i would like to know if a date is 2 days away, or 78 days away, or even 5,239 days away (not likely, but you get the idea). I am using an MS SQL database which is returning datetimes where the time components are all 00:00:00.
date_diff returns relative values that you then have to do some crazy math with to get absolute dates do to calculating months, years, etc.
Also, i am having issues getting the date component only of today's date in php.
Edit:
Thanks to mr. w. This is what i ended up with:
$date = $row['AirdateDateTime'];
$today = date_create(date("Y-m-d"));
$away = date_diff($today, $date);
$d = $away->format("%R%a");
The date_create() part was the part i was originally missing to convert to an actual datetime. Also, the format needs to be %R%a. Using %R%d only works for dates in this month.
The date_diff() function (really, the DateTime::diff() method) is what you want, and it's actually not hard. In fact, I think the example in the docs is exactly what you're after:
<?php
$datetime1 = new DateTime('2009-10-11');
$datetime2 = new DateTime('2009-10-13');
$interval = $datetime1->diff($datetime2);
echo $interval->format('%R%d days');
?>
or
<?php
$datetime1 = date_create('2009-10-11');
$datetime2 = date_create('2009-10-13');
$interval = date_diff($datetime1, $datetime2);
echo $interval->format('%R%d days');
?>
What's returned is a DateInterval object, which you can format any way you want with its format() method. Above, it's being formatted to days, but you have a ton of options; see http://us.php.net/manual/en/dateinterval.format.php.
You shouldn't need to do any math yourself.
[EDIT - forgot this part]
As for getting the date component of today's date, you can do something like this:
<?php
echo date('Y-m-d');
?>
See http://us.php.net/manual/en/function.date.php.
Try this
$date1 = new DateTime('2012-10-28 00:00:00',new DateTimeZone('Europe/London'));
$date2 = new DateTime('2012-10-28 03:00:00',new DateTimeZone('Europe/London'));
$interval = date_diff($date1, $date2);
$format = '%y years, %m months, %d days, %h hours, %i minutes, %s seconds, %a total days %R';
echo $interval->format($format);
if want to change the format try this
http://www.w3schools.com/php/func_date_date.asp
It's probably easiest to convert to unix timestamps (seconds since 1970) and then get the difference.
strtotime() and time() are your friends.
An alternative to what has already been suggested is the DateTime library:
$today = date("Y-m-d");
$today = new DateTime($today);
$future = new DateTime('2010-10-25');
$interval = $today->diff($future);
echo $interval->format('%d days away'); //outputs 17 days away
It sounds like what you want is
<?php
$yourDate = '2010-10-05';
echo ciel((strtotime($yourDate) - time()) / 60 / 60 / 24);