I'm trying to build an html form and connecting it to a php file which is doing the query and insert the information to mysql database.
Here is my html code:
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Add Record Form</title>
</head>
<body>
<form action="/joomla_31/insert.php" method="post">
<label for="MGMT_IP">MGMT IP</label>
<input type="text" name="MGMT_IP" id="MGMT_IP">
</p>
<p>
<label for="Vendor">Vendor</label>
<input type="text" name="Vendor" id="Vendor">
</p>
<p>
<label for="Version">Version</label>
<input type="text" name="Version" id="Version">
</p>
<p>
<label for="GUI_User">GUI User</label>
<input type="text" name="GUI_User" id="GUI_User">
</p>
<p>
<label for="GUI_Pass">GUI Pass</label>
<input type="text" name="GUI_Pass" id="GUI_Pass">
</p>
<input type="submit" value="submit">
</form>
</body>
</html>
And Here is my insert.php file:
<?php
$link = mysqli_connect("localhost", "root", "", "mysql");
// Check connection
if($link === false){
die("ERROR: Could not connect. " . mysqli_connect_error());
}
// Escape user inputs for security
$MGMT_IP = mysqli_real_escape_string($link, $_REQUEST['MGMT IP']);
$Vendor = mysqli_real_escape_string($link, $_REQUEST['Vendor']);
$Version = mysqli_real_escape_string($link, $_REQUEST['Version']);
$GUI_User = mysqli_real_escape_string($link, $_REQUEST['GUI User']);
$GUI_Pass = mysqli_real_escape_string($link, $_REQUEST['GUI Pass']);
// attempt insert query execution
$sql = "INSERT INTO `cloud_team` (MGMT IP, Vendor, Version, GUI User, GUI Pass) VALUES (`$customer_number`, `$customer_name`, `$MGMT_IP`, `$Vendor`, `$Version`, `$GUI_User`, `$GUI_Pass`)";
if(mysqli_query($link, $sql)){
echo "Records added successfully.";
} else{
echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}
// close connection
mysqli_close($link);
?>
But every time I click on the submit button I get a blank page ...
It is like it is redirecting the correct file (http://x.x.x.x/joomla_31/insert.php) .. but nothing executed ...no error displayed .. only a blank page
Enable PHP error display to better debug your code. Look at this answer for more details.
Related
I'm using Cloud9 to create a website. For whatever reason, the data taken from a HTML page will not get inserted into the Database.
I have tested to see if the Database is connected and it is. I would like to be able to get the data to be inserted into the Database.
The HTML code and PHP code is:
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Add Record Form
</title>
</head>
<body>
<form action="../php/keithphp/address_submit.php" method="post">
<p>
<label for="address_street">Street</label>
<input type="text" name="address_street" id="address_street">
</p>
<p>
<label for="address_street2">Street 2</label>
<input type="text" name="address_street2" id="address_street2">
</p>
<p>
<label for="address_city">City</label>
<input type="text" name="address_city" id="address_city">
</p>
<p>
<label for="address_county">County</label>
<input type="text" name="address_county" id="address_county">
</p>
<p>
<label for="eircode">Eircode</label>
<input type="text" name="eircode" id="eircode">
</p>
<!-- <p>
<label for="address_geo_latitude">Latitude</label>
<input type="float" name="address_geo_latitude" id="address_geo_latitude">
</p>
<p>
<label for="address_geo_longtitude">Longitude</label>
<input type="float" name="address_geo_longtitude" id="address_geo_longtitude">
</p> -->
<input type="submit" value="Submit">
</form>
</body>
</html>
*****************
<?php
$servername = getenv('IP');
$username = getenv('C9_USER');
$password = "";
$database = "c9";
$dbport = 3306;
// Create connection
$db = new mysqli($servername, $username, $password, $database, $dbport);
// Check connection
if ($db->connect_error) {
die("Connection failed: " . $db->connect_error);
}
/*$address_id = $_POST['address_id'];*/
$address_street = $_POST['address_street'];
$address_street2 = $_POST['address_street2'];
$address_city = $_POST['address_city'];
$address_county = $_POST['address_county'];
$address_eircode = $_POST['address_eircode'];
/*$address_geo_latitude = $_POST['address_geo_latitude'];
$address_geo_longtitude = $_POST['address_geo_longtitude'];*/
$sql = "INSERT INTO Address(address_id, address_street, address_street2, address_city, address_county, address_eircode, address_geo_latitude, address_geo_longtitude) VALUES ('$address_id', '$address_street', '$address_street2', '$address_city', '$address_county', '$address_eircode', '$address_geo_latitude', '$address_geo_longtitude')";
$success = $db->query($sql);
if (!$sucess){
die("Could not enter data: ".$db->error);
}
echo "Thank you. Address submitted!"
/*my$db->close();*/
?>
And the result after typing in test data is (no error message after text), I get;
Could not enter data:
I have created two files on remote server. One is html form which asks to enter some fields and another is a php file which will get all the data and insert into the database.
For this from html file on click of submit button I am calling php file, but the file is not getting execute I think because when I click on submit it again reloads the same html page.
html :
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>MCQ Questions</title>
</head>
<body>
<form method="post" >
<p> Enter the question :</p> <input name="question" type="input"> <br><br>
<p> Enter options :</p>
Enter option 1 : <input name="opt1" type="input"> <br><br>
Enter option 2 : <input name="opt2" type="input"> <br><br>
Enter option 3 : <input name="opt3" type="input"> <br><br>
Enter option 4 : <input name="opt4" type="input"> <br><br>
<p> Enter correct answer :</p>
<input name="ans" type="input"> <br><br>
<input type="submit" value = "Submit" onClick = "uploadQuestion.php">
</form>
</body>
</html>
php file:
<?php
$question=$_POST['question'];
$option1=$_POST['opt1'];
$option2=$_POST['opt2'];
$option3=$_POST['opt3'];
$option4=$_POST['opt4'];
$ans=$_POST['ans'];
$db_server = mysql_connect("address","username","pass");
if(!$db_server) {
die("Database connection failed: " . mysql_error());
}else{
$db_select = mysql_select_db("mlm",$db_server);
if (!$db_select) {
die("Database selection failed:: " . mysql_error());
}
}
$sql = "INSERT INTO questions (question,answer_a,answer_b,answer_c,answer_d,answer) VALUES ('$question','$option1',$option2,$option3,$option4,$ans)";
if (!mysql_query($sql)) {
die('Error: ' . mysql_error());
}
?>
I also tried this way :
<input type="submit" value = "Submit" onClick = "http://address/uploadQuestion.php">
But nothing is working. Whats going wrong here? I am a beginner in web development,, can anyone help please? Thank you..
EDIT :
$database = new Database('addredd','username','pass','handbook');
$dbConnection = $database->getDB();
$stmt = $dbConnection->prepare("insert into questions(question,answer_a,answer_b,answer_c,answer_d,answer) values(?,?,?,?,?,?)");
$stmt->execute(array($question,$option1,$option2,$option3,$option4,$ans));
I tried to use pdo statement but getting this error :
Fatal error: Class 'Database' not found in /var/www/html/uploadQuestion.php on line 12
EDIT2 :
I am trying to upload one file on server and want to save it in database also, so for this I have created 2 files one is index.php and another is uploadFile.php.
As you shown now I used pdo for this but when I click on upload image again same page is getting load.
index.php
<form action="index.php" method="post" enctype="multipart/form-data">
<p> Select image to upload:</p>
<input name = "file" type="file" id="fileToUpload"><br><br>
Enter chapter name :
<input name = "chapterName" type = "text"><br><br>
<input type="submit" value = "Upload Image">
</form>
<?php
if (isset($_FILES['file']['tmp_name']))
{
$ch = curl_init();
$cfile = new CURLFile($_FILES['file']['tmp_name'],$_FILES['file']['type'],$_FILES['file']['name']);
$data = array("myfile" => $cfile);
curl_setopt($ch, CURLOPT_URL, "http://host/NewProject/uploadFile.php");
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOTP_POSTFIELDS, $data);
$response = curl_exec($ch);
if($response == true)
{
echo "File posted";
}
else{
echo "Error: " . curl_error($ch);
}
}
?>
uploadFile.php
<?php
ini_set('display_errors', 1);
if(isset($_FILES['myfile']['tmp_name']))
{
$path = "files/" . $_FILES['myfile']['name'];
move_uploaded_file($_FILES['myfile']['tmp_name'], $path);
$chapterName=$_POST['chapterName'];
$dbh = new PDO('mysql:host=host;dbname=database_name','username', 'password');
$stmt = $dbh->prepare("INSERT INTO chapters (title,file) VALUES (?, ?)");
$stmt->execute(array($chapterName,$path));
if ($dbh->lastInsertId())
{
echo 'File upploaded.';
}
else
{
echo 'File could not upload.';
}
}
?>
Please help.. Thank you..
First repair your form, type="" can't be named input u can check here https://www.w3schools.com/tags/att_input_type.asp
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>MCQ Questions</title>
</head>
<body>
<form action="uploadQuestion.php" method="post" enctype="multipart/form-data">
<p> Enter the question :</p> <input name="question" type="text"> <br><br>
<p> Enter options :</p>
Enter option 1 : <input name="opt1" type="text"> <br><br>
Enter option 2 : <input name="opt2" type="text"> <br><br>
Enter option 3 : <input name="opt3" type="text"> <br><br>
Enter option 4 : <input name="opt4" type="text"> <br><br>
<p> Enter correct answer :</p>
<input name="ans" type="text"> <br><br>
<input type="submit" value="Submit">
</form>
</body>
</html>
Then yours php code
<?php
// mysql connection
$db_server = mysql_connect("address","username","pass");
// check for mysql connection
if(!$db_server)
{
die("Database connection failed: " . mysql_error());
}
else
{
// check if database exists
$db_select = mysql_select_db("mlm",$db_server);
if (!$db_select)
{
die("Database selection failed:: " . mysql_error());
}
}
// escape post variables
$question = mysql_real_escape_string($_POST['question']);
$option1 = mysql_real_escape_string($_POST['opt1']);
$option2 = mysql_real_escape_string($_POST['opt2']);
$option3 = mysql_real_escape_string($_POST['opt3']);
$option4 = mysql_real_escape_string($_POST['opt4']);
$ans = mysql_real_escape_string($_POST['ans']);
// make query
$sql = "INSERT INTO questions (question,answer_a,answer_b,answer_c,answer_d,answer) VALUES ('$question', '$option1', '$option2', '$option3', '$option4', '$ans')";
// check if query runs
if (!mysql_query($sql)) {
die('Error: ' . mysql_error());
}
?>
Or php with mysqli
<?php
// host, username, password, database name
$db_server = mysqli_connect("address", "username", "pass", "mlm");
// check for connection
if(!$db_server)
{
die("Database connection failed: " . mysqli_error($db_server));
}
// escape post variables
$question = mysqli_real_escape_string($db_server, $_POST['question']);
$option1 = mysqli_real_escape_string($db_server, $_POST['opt1']);
$option2 = mysqli_real_escape_string($db_server, $_POST['opt2']);
$option3 = mysqli_real_escape_string($db_server, $_POST['opt3']);
$option4 = mysqli_real_escape_string($db_server, $_POST['opt4']);
$ans = mysqli_real_escape_string($db_server, $_POST['ans']);
// make query
$sql = "INSERT INTO questions (question,answer_a,answer_b,answer_c,answer_d,answer) VALUES ('$question', '$option1', '$option2', '$option3', '$option4', '$ans')";
// check if query runs
if (!mysqli_query($db_server, $sql))
{
die('Error: ' . mysqli_error($db_server));
}
?>
Or php with prepared statements
<?php
// mysql connection
$dbh = new PDO('mysql:host=adress;dbname=database_name', 'username', 'password');
// escape post variables
$question = $_POST['question'];
$option1 = $_POST['opt1'];
$option2 = $_POST['opt2'];
$option3 = $_POST['opt3'];
$option4 = $_POST['opt4'];
$ans = $_POST['ans'];
$stmt = $dbh->prepare("INSERT INTO questions (question,answer_a,answer_b,answer_c,answer_d,answer) VALUES ( ?, ?, ?, ?, ?, ?)");
$stmt->execute(array($question, $option1, $option2, $option3, $option4, $ans));
if ($dbh->lastInsertId())
{
echo 'Sucess.';
}
else
{
echo 'Fail.';
}
?>
Change your from code to this
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>MCQ Questions</title>
</head>
<body>
<form action="uploadQuestion.php" method="post" enctype="multipart/form-data">
<p> Enter the question :</p> <input name="question" type="input"> <br><br>
<p> Enter options :</p>
Enter option 1 : <input name="opt1" type="input"> <br><br> Enter option 2 : <input name="opt2" type="input"> <br><br> Enter option 3 : <input name="opt3" type="input"> <br><br> Enter option 4 : <input name="opt4" type="input"> <br><br>
<p> Enter correct answer :</p>
<input name="ans" type="input"> <br><br>
<input type="submit" value="Submit">
</form>
</body>
</html>
When I press the submit button I get error.
object not found error.
And the page automatically adds empty entries with auto incremented primary key (without pressing the submit button).
I am still a beginner in PHP, I searched thoroughly but I can't find out what's wrong in code.
<html>
<head>
<title>Add New Record in MySQL Database</title>
</head>
<body>
<form action="insert.php" method="post">
<p>
<label for="Name">Full Name:</label>
<input type="text" name="Name" id="Name">
</p>
<p>
<label for="Code">Code:</label>
<input type="text" name="Code" id="Code">
</p>
<p>
<label for="GPA">GPA:</label>
<input type="text" name="GPA" id="GPA">
</p>
<input type="submit" value="Submit">
</form>
<?php
/* Attempt MySQL server connection. Assuming you are running MySQL
server with default setting (user 'root' with no password) */
$link = mysqli_connect("localhost", "username", "password", "students");
// Check connection
if ($link === false) {
die("ERROR: Could not connect. " . mysqli_connect_error());
}
// Escape user inputs for security
$full_name = filter_input(INPUT_POST, 'full_name');
$code = filter_input(INPUT_POST, 'code');
$gpa = filter_input(INPUT_POST, 'gpa');
// attempt insert query execution
$sql = "INSERT INTO info VALUES ('$full_name', '$code', '$gpa')";
if (mysqli_query($link, $sql)) {
echo "Records added successfully. $full_name";
} else {
echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}
// close connection
mysqli_close($link);
?>
</body>
</html>
Try this:
$full_name = filter_input(INPUT_POST, 'Name');
$code = filter_input(INPUT_POST, 'Code');
$gpa = filter_input(INPUT_POST, 'GPA');
The reason why I wrote that is because your input names contain Name, Code and GPA so you need to write this exactly as your input names (case-sensitive).
Do with isset(). when the submit button clicks only the code runs.
Inside the php you should use the form input name field.
<?php
if(isset($_POST['submit'])){
$link = mysqli_connect("localhost", "username", "password", "students");
if ($link === false) {
die("ERROR: Could not connect. " . mysqli_connect_error());
}
// Escape user inputs for security
$full_name = filter_input(INPUT_POST, 'full_name');
$code = filter_input(INPUT_POST, 'code');
$gpa = filter_input(INPUT_POST, 'gpa');
//to prevent sql injection attack
$full_name = mysqli_real_escape_string($link, $full_name);
$code = mysqli_real_escape_string($link, $code);
$gpa = mysqli_real_escape_string($link, $gpa);
// attempt insert query execution
$sql = "INSERT INTO info (Name,Code,GPA) VALUES ('$full_name', '$code', '$gpa')";
if (mysqli_query($link, $sql)) {
echo "Records added successfully. $full_name";
} else {
echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}
// close connection
mysqli_close($link);
}
?>
<html>
<head>
<title>Add New Record in MySQL Database</title>
</head>
<body>
<form action="insert.php" method="post">
<p>
<label for="Name">Full Name:</label>
<input type="text" name="full_name" id="Name">
</p>
<p>
<label for="Code">Code:</label>
<input type="text" name="code" id="Code">
</p>
<p>
<label for="GPA">GPA:</label>
<input type="text" name="gpa" id="GPA">
</p>
<input type="submit" name="submit" value="submit">
</form>
</body>
</html>
The problem is the input name. You named Full Name input with name="Name", but you declare $full_name = filter_input(INPUT_POST, 'full_name'); in php section. you must change full_name to Name. As well as the Code and GPA input.
I am fairly new to PHP and I was following a simple tutorial on youtube, I followed the youtube video, double and tripple checked to make sure everything I typed was correct and data was still not being inserted.
I searched the internet for hours and I came up with a fix, sort of but I don't think it's the correct way to do it
HTML
<html>
<head>
<title>Insert Form Data In MYSQL Database Using PHP</title>
</head>
<body>
<form action="insert.php" method="post">
Name : <input type="text" name="username">
<br/>
Email : <input type="text" name="email">
<br/>
<input type="submit" value="Insert">
</form>
</body>
</html>
PHP
<?php
$con = mysqli_connect('localhost','root','');
if (!$con) {
echo 'Not Connected To Server';
}
if (!mysqli_select_db($con,'tutorial')) {
echo 'Database Not Selected';
}
if (isset($_POST['username'])){
$Name = $_POST['username'];
}
if (isset($_POST['email'])){
$Email = $_POST['email'];
}
$sql = "INSERT INTO person (Name, Email) VALUES ('John', 'john#gmail.com')";
if (!mysqli_query($con,$sql)) {
echo 'Not Inserted';
} else {
echo 'Inserted Successfully!';
}
header("refresh:10; url=index.html");
?>
I replaced '$Name' and '$Email' with John and john#gmail.com, then I type it into the html form and the data goes into the database correctly.
I then found another HTML form online with more PHP but it does the same thing(not inserting any data to the database)
HTML
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Add Record Form</title>
</head>
<body>
<form action="insert1.php" method="post">
<p>
<label for="firstName">First Name:</label>
<input type="text" name="firstname" id="firstName">
</p>
<p>
<label for="lastName">Last Name:</label>
<input type="text" name="lastname" id="lastName">
</p>
<p>
<label for="emailAddress">Email Address:</label>
<input type="text" name="email" id="emailAddress">
</p>
<input type="submit" value="Submit">
</form>
</body>
</html>
PHP
<?php
/* Attempt MySQL server connection. Assuming you are running MySQL
server with default setting (user 'root' with no password) */
$link = mysqli_connect("localhost", "root", "", "demo");
// Check connection
if($link === false){
die("ERROR: Could not connect. " . mysqli_connect_error());
}
// Escape user inputs for security
$first_name = mysqli_real_escape_string($link, $_POST['firstname']);
$last_name = mysqli_real_escape_string($link, $_POST['lastname']);
$email_address = mysqli_real_escape_string($link, $_POST['email']);
// attempt insert query execution
$sql = "INSERT INTO persons (first_name, last_name, email_address) VALUES ('$first_name', '$last_name', '$email_address')";
if(mysqli_query($link, $sql)){
echo "Records added successfully.";
} else{
echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}
// close connection
mysqli_close($link);
?>
The fields are blank, any help will be greatly appreacited!
Btw This is how the fields display I'm using xampp server.
I had used the below code and it works fine for me.
<?php
$link = mysqli_connect("localhost", "root", "", "dummy");
// Check connection
if($link === false){
die("ERROR: Could not connect. " . mysqli_connect_error());
}
/* Collect below values from $_POST
$firstname = 'John';
$lastname = 'Doe';
$email = 'test#gmail.com';
*/
// Escape user inputs for security
$first_name = mysqli_real_escape_string($link, $firstname);
$last_name = mysqli_real_escape_string($link, $lastname);
$email_address = mysqli_real_escape_string($link, $email);
// attempt insert query execution
$sql = "INSERT INTO accounts (account_firstname, account_lastname, account_email) VALUES ('$first_name', '$last_name', '$email_address')";
if(mysqli_query($link, $sql)){
echo "Records added successfully.";
} else{
echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}
// close connection
mysqli_close($link);
?>
<!DOCTYPE html>
<html>
<head>
<title>Sign up page</title>
</head>
<body>
<form method="post" action="signup_redirect.php">
username: <input type="text" name="username" placeholder="username"><br>
Password: <input type="password" name="password" placeholder="password"><br>
<input type="submit" value="Create Account">
</form>
// The user would enter the desired username and password.
<?php
if(isset($_POST['submit'])) {
$dbCon = mysqli_connect("localhost", "root", "", "test");
if (mysqli_connect_errno()) {
echo "Failed to connect" .mysqli_connect_error();
}
$sql = "INSERT INTO test (username, password)
VALUES ('".$_POST['username']."','".$_POST['password']."')";
}//Takes the values that the user has submitted and inserts them into my table called "test".
?>
</body>
</html>
I have a form which would take the users desired details then if the submit button is pressed it runs through the rest of the php code.I also have the sql statement which is meant to add data but when i check my database there are no new entries.
$sql = "INSERT INTO test (username, password)
VALUES ('".$_POST['username']."','".$_POST['password']."')";
After that run query
$sql_qry=mysqli_query($dbCon, $sql);
add
if (mysqli_query($dbCon, $sql)) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . mysqli_error($dbCon);
}
after, $sql query you have written