Map two dimensional php array to 1 dimension - php

Question

I have array inside array:
{
"0" => array("key" => "code", "id" => "4", "value" => "yes"),
"1" => array("key" => "parameter", "id" => "4", "value" => "0"),
"2" => array("key" => "code", "id" => "5", "value" => "no"),
etc...
}
This is what I want to do: I want to have one dimension array in which key would be "id" and value would be "value". However, I need to filter out entries whose key is "parameters". So, in this example, the final array should look like this:
{
"4" => "yes",
"5" => "no"
}
I just can't seem to figure out how to do this. Could you please help me a bit? I tried writing this foreach inside foreach but I just can't wrap my head around how to filter data.
foreach ($settings AS $key => $value) {
$id = null;
$value = null;
foreach ($value AS $key2 => $value2) {
// No idea how to filter out uneccesary entries and save the correct ones
}
$finalArray[$id] = $value;
}

Answer 1

This should do it :
$finalArray = array();
foreach ($settings as $setting) {
if ($setting['key'] != 'parameter') {
$finalArray[$setting['id']] = $setting['value'];
}
}
Assuming all your entries have keys 'key', 'id' and 'value'.

Answer 2

use array_column and array_filter like this, if you want to filter more keys add them to out_keys array :
<?php
$array = [
["key" => "code", "id" => "4", "value" => "yes"],
["key" => "parameter", "id" => "4", "value" => "0"],
["key" => "code", "id" => "5", "value" => "no"]
];
$out_keys = ['parameter'];
$result = array_column(array_filter($array, function($item) use($out_keys) {
return !in_array($item['key'], $out_keys);
}), 'value', 'id');
echo "<pre>";
print_r($result);
output:
Array
(
[4] => yes
[5] => no
)

Answer 3

Assuming $data is your starting array, the code below will output what you want in $result
$result = [];
foreach(array_filter($data, function($el){return $el['key']!='parameter';}) as $el){
$result[$el['id']] = $el['value'];
}
Live demo