I am playing around with PHP, however I am stuck on this part. I created a table which inserts all the information from the MySQL database, this is working perfectly, however: I want if the 'type' in the MySQL database is 1 that the entire of the table has a red background and if it's something else, it should be a green background.
Could anybody give me advise, where to start?
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['date'] ."</td>";
echo "<td>" . $row['type'] ."</td>";
echo "<td>" . $row['amount'] . "</td>";
echo "<td>" . $row['transaction'] . "</td>";
echo "</td>";
}
echo "</table>";
?>
You need to mark the rows you want to effect somehow. You could do this with a data-type attribute, but if you are just starting and want to keep things simple, a class is the most straightforward.
while($row = mysqli_fetch_array($result))
{
echo "<tr class=\"type" . $row['type'] . "\">";
echo "<td>" . $row['date'] ."</td>";
echo "<td>" . $row['type'] ."</td>";
echo "<td>" . $row['amount'] . "</td>";
echo "<td>" . $row['transaction'] . "</td>";
echo "</td>";
}
echo "</table>";
?>
Then within a stylesheet or <style> tag you can add
.type1 {
background-color: red;
}
You can edit your code to place a condition in the 'type' 'td' :
echo "<td";
if($row['type'] === 1){
echo "class=\"redbg\";
else
echo "class=\"otherbg\";
echo >" . $row['type'] ."</td>";
Or, simply :
echo "<td";
if($row['type'] === 1){
echo "class=\"redbg\";
echo >" . $row['type'] ."</td>";
Then make a standard rule in your css for td:not(redbg).
Related
I need to retrieve the color hex code stored in a database and display it as seen on screen within a table cell. i'm trying to find a way to convert the hex code the db query returns for that specific table cell into the actual color that the hex denotes. Here's my code...
<?php
// Include config file
require_once "config.php";
$pdo = new PDO($dsn, $username, $password, $options);
// Attempt select query execution
$sql = "SELECT * FROM sales";
if($result = $pdo->query($sql)){
if($result->rowCount() > 0){
echo "<table class='table table-bordered table-striped'>";
echo "<thead>";
echo "<tr>";
echo "<th>S/N</th>";
echo "<th>Transaction Date</th>";
echo "<th>Customer Name</th>";
echo "<th>Address</th>";
echo "<th>Phone Number</th>";
echo "<th>Vehicle Model</th>";
echo "<th>Vehicle Chassis Number</th>";
echo "<th>Vehicle Registration Number</th>";
echo "<th>Vehicle Color</th>";
echo "<th>Amount Paid</th>";
echo "<th>Advance</th>";
echo "<th>Balance</th>";
echo "<th>Balance Due Date</th>";
echo "<th>Paid To</th>";
echo "</tr>";
echo "</thead>";
echo "<tbody>";
while($row = $result->fetch()){
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['transactiondate'] . "</td>";
echo "<td>" . $row['customername'] . "</td>";
echo "<td>" . $row['address'] . "</td>";
echo "<td>" . $row['phonenumber'] . "</td>";
echo "<td>" . $row['vehiclemodel'] . "</td>";
echo "<td>" . $row['vehiclechassisnumber'] . "</td>";
echo "<td>" . $row['vehicleregistrationnumber'] . "</td>";
echo "<td>" . $row['vehiclecolor'] . "</td>";
echo "<td>" . $row['amountpaid'] . "</td>";
echo "<td>" . $row['advance'] . "</td>";
echo "<td>" . $row['balance'] . "</td>";
echo "<td>" . $row['balancedate'] . "</td>";
echo "<td>" . $row['paidto'] . "</td>";
echo "<td>";
echo "</tr>";
}
echo "</tbody>";
echo "</table>";
// Free result set
unset($result);
} else{
echo "<p class='lead'><em>No records were found.</em></p>";
}
} else{
echo "ERROR: Could not able to execute $sql. " . $mysqli->error;
}
// Close connection
unset($pdo);
?>
It is a bit unclear about where you wish to use the colour but I'm assuming it is here. And also my assumption is the retrieved value for vehiclecolor column is a HEX value
echo "<td>" . $row['vehiclecolor'] . "</td>";
You can use tag property 'background-color' for this.
$temp = $row['vehiclecolor'];
echo "<td style='background-color:" . $temp ."'></td>";
Pretty self-explanatory I guess. String concatenation.
Two questions in one:
First question, mainly about presentation:
I'm echo-ing the following code which should create a table. The table should have a single column, but it's being rendered with the elements above the image as a single line. can anyone see why?
<?php
$sql = "SELECT * FROM catdata WHERE featured='yes' LIMIT 2";
if($result = mysqli_query($link, $sql)){
if(mysqli_num_rows($result) > 0){
echo "<table>";
while($row = mysqli_fetch_array($result)){
echo "<tr>";
echo "<td>" . $row['manufacturer'] . "</td>";
echo "</tr";
echo "<tr>";
echo "<td>" . $row['title'] . "</td>";
echo "</tr";
echo "<tr>";
echo "<td><img src=\"6.diesel.png\"></td>";
echo "</tr>";
echo "<tr>";
echo "<td>" . $row['size'] . "l</td>";
echo "</tr>";
echo "<tr>";
echo "<td>" . $row['mileage'] . "</td>";
echo "</tr>";
echo "<tr>";
echo "<td>" . $row['fitsmodel'] . "</td>";
echo "</tr>";
echo "<tr class=\"tablePriceBlock\">";
echo "<td>£" . $row['pricefitted'] . "</td>";
echo "</tr>";
echo "<tr>";
echo "<td>£" . $row['pricedel'] . "</td>";
echo "</tr>";
}
echo "</table>";
// Free result set
mysqli_free_result($result);
} else {
echo "No records matching your query were found.";
}
} else{
echo "ERROR: Unable to execute $sql. " . mysqli_error($link);
}
?>
Question 2:
Can I show the second result in a second column, or as a separate table? Also, is it possible to access the $result elements like say, $[manufacturer][1]?
Always look at the emitted source your code generates by either "View Source" or using a tool like curl. You'll find this mistake:
echo "</tr";
You're missing a >.
Many people who write HTML have browser plugins that can link through to an HTML validator to ensure they've got the correct syntax. You may want to find and install one of these.
To generate the second result is a separate table follow the following code.
echo "<table>";
$count = 1;
while($row = mysqli_fetch_array($result)){
if($count == 2){
echo "<table>";
echo "<tr>";
echo "<td>put your code here</td>";
echo "</tr>"
echo </table>
}else{
echo "<tr>";
echo "<td>" . $row['manufacturer'] . "</td>";
echo "</tr";
echo "<tr>";
echo "<td>" . $row['title'] . "</td>";
echo "</tr";
echo "<tr>";
echo "<td><img src=\"6.diesel.png\"></td>";
echo "</tr>";
echo "<tr>";
echo "<td>" . $row['size'] . "l</td>";
echo "</tr>";
echo "<tr>";
echo "<td>" . $row['mileage'] . "</td>";
echo "</tr>";
echo "<tr>";
echo "<td>" . $row['fitsmodel'] . "</td>";
echo "</tr>";
echo "<tr class=\"tablePriceBlock\">";
echo "<td>£" . $row['pricefitted'] . "</td>";
echo "</tr>";
echo "<tr>";
echo "<td>£" . $row['pricedel'] . "</td>";
echo "</tr>";
}
$count ++;
}
echo "</table>";
As you are limiting your query to only two record so this method is not bad for that and hope this will help.
I have a PHP code, showing me raw data from a MySQL database in a table.
I want to add some text to one of the existing cells, depending on a value in another column which is not displayed in the table.
My code looks like this:
while($row = mysqli_fetch_array($rs))
{
echo '<tr class="lokbes">';
echo "<td class='blaa'>" . $row['Navn'] . "</td>"; // I want the extra text here.
echo "<td>" . $row['Stilling'] . "</td>";
echo "<td>" . $row['Institution'] . "</td>";
echo "<td><a href='mailto:$row[Email]'>" . $row['Email'] . "</a></td>";
echo "<td>" . $row['Mobiltelefon'] . "</td>";
}
echo "</tr>";
echo "</table>";
This outputs a table consisting of Name, job, workplace etc.
In the cell displaying the name, I would like to add some text if a column in my MySQL DB has the value 1 in the row.
What to do? I've tried using if, as seen below - but that doesn't seem to work.
echo "<td class='blaa'>" . $row['Navn'] .
if ($row['Formand'] == 1) {
echo "(Formand)";
} "</td>";
You have to do multiple echos :
echo "<td class='blaa'>" . $row['Navn'];
if ($row['Formand'] == 1) {
echo "(Formand)";
}
echo "</td>";
Or, with ternary operator :
echo "<td class='blaa'>" . $row['Navn'] . ($row['Formand'] == 1 ? "(Formand)" : "") . "</td>";
update like this.
echo "<td class='blaa'>" . $row['Navn'];
if ($row['Formand'] == 1) {
echo " (Formand)";
}
echo "</td>";
or you can use short PHP tag in HTML code.
?>
<td class="blaa">
<?php echo $row['Navn']?><?php echo ($row['Formand'] == 1)?' (Formand)':'';?>
</td>
<?php
Try below code.
while($row = mysqli_fetch_array($rs))
{
echo '<tr class="lokbes">';
echo "<td class='blaa'>" . $row['Navn']." ".($row['Formand'] == 1 ? "(Formand)" : ""). "</td>"; // I want the extra text here.
echo "<td>" . $row['Stilling'] . "</td>";
echo "<td>" . $row['Institution'] . "</td>";
echo "<td><a href='mailto:$row[Email]'>" . $row['Email'] . "</a></td>";
echo "<td>" . $row['Mobiltelefon'] . "</td>";
}
echo "</tr>";
echo "</table>";
I have one while loop which displays data from the database. Now I want multiply two values in one row and display the result in the same row, the same way multiply the values and display the result in every row. I am not getting the result. Can anyone help me? I am new to PHP.
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td class='alt'>" . $row['id'] . "</td>";
echo "<td>" . $row['item'] . "</td>";
echo "<td>" . $row['amount'] . "</td>";
$ss=$row['amount'];
echo '<td >'.'<input type="checkbox" name="status" value="" >'.'</td>';
echo '<td >'.'<input type="text" name="qty">'.'</td>';
echo "<td>" . $rr1 . "</td>";
echo "</tr>";
}
From Where you are getting $rr1??
You can have
echo "<td>" . $row['item'] * $row['amount'] . "</td>";
Hope this is what you want...
you can try
printf('amount is %d',$row['item'] * $row['amount']);
reference
Try below :
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td class='alt'>" . $row['id'] . "</td>";
echo "<td>" . $row['item'] . "</td>";
echo "<td>" . $row['amount'] . "</td>";
echo "<td>" .($row['item'] * $row['amount']). "</td>";
echo "</tr>";
}
Change the query as
$result= mysql_query("Select id, item, amount, (item * amount) total
from table_name");
then in while loop
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td >" . $row['id'] . "</td>";
echo "<td>" . $row['item'] . "</td>";
echo "<td>" . $row['amount'] . "</td>";
echo "<td>" .($row['total'] "</td>";
echo "</tr>";
}
$sql = ""
$result = mysql_query($sql);
while ($row = #mysql_fetch_row($result)) {
echo "<tr bgcolor='#dcdcdc'>" ;
echo "<td>$row[0] </td>";
echo "<td>" . $row[1] . "</td>";
echo "<td>" . $row[2] . "</td>";
echo "<td>" . $row[3] . "</td>";
echo "<td>" . $row[4] . "</td>";
echo "<td>" . $row[5] . "</td>";
echo "<td>" . $row[6] . "</td>";
}
when I run the above php code on my local mysql server , my last row value is correctly displayed.
But when the same is deployed on the server and access from client PC , last cell value is empty.
Please help me how to sort this issue out.
I think you're missing the trailing </tr> from your code, that could potentially do it:
while ($row = #mysql_fetch_row($result)) {
echo "<tr bgcolor='#dcdcdc'>" ;
echo "<td>$row[0] </td>";
echo "<td>" . $row[1] . "</td>";
echo "<td>" . $row[2] . "</td>";
echo "<td>" . $row[3] . "</td>";
echo "<td>" . $row[4] . "</td>";
echo "<td>" . $row[5] . "</td>";
echo "<td>" . $row[6] . "</td>";
echo "</tr>";
}
I'd check the database to make sure you have all of the rows in your table. That would pretty much have to be the problem.
Make sure you have at least 7 columns in there.