I am trying to send my form values to php page in order to perform SQL requests to my server according to my form values. This is original php with form and ajax script:
<script type='text/javascript' src="http://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js">
</script>
<form enctype="multipart/form-data" method="post">
<input type="datetime-local" name="start" id="start">
<input type="datetime-local" name="finish" id="finish">
<input type="checkbox" name="consta" id="consta" value="tru"> Remove const
<input type="submit" name="apply" id="apply">
</form>
<script>
$('#apply').click(function(){
var data= $('form').serialize();
$.post('gensetapply.php', data);
});
</script>
And in gensetapply.php I am trying to get variables through $_POST:
<?php
$con=$_POST['consta'];
$str=$_POST['start'];
$fin=$_POST['finish'];
echo $con.", ".$str.", ".$fin;
?>
So, I am sure my ajax request is not working.
I am new to this things and have wrote code above looking to similar examples, so please feel welcome to point out my mistakes. There might be a typo cause I am handtyping it again here, not copy-paste from source.
EDIT:
It was working, I just couldn't see it when i refresh the page, but through devtools in Chrome (Network>Response) I. Hope it'd help some other fools like me ;)
1st : Your using post method to post the data to server so you need to prevent the default submit
<script>
$('#apply').submit(function(e){
e.preventDefault();
var data= $('form').serialize();
$.post('gensetapply.php', data);
});
</script>
2nd : or Simple change the type="submit" to type="button".
Here 'Apply 'button type is submit. Therefore your form submits immediately. As you are handling form submission through ajax so the solution is you need to stop submitting form. You can fix it returning false in click event like following
<script>
$('#apply').click(function(){
var data= $('form').serialize();
$.post('gensetapply.php', data);
return false;
});
</script>
Related
My if(isset) validation is returning false after I have submitted the form through jQuery ,however works fine when done without jquery. Reason I am using jQuery is because I need to submit multiple forms:
Button
<input class="btn btn-primary" type ="submit" id="myButton"
name="create_record" value="Submit 1">
jQuery:
<script>
$(document).ready(function () {
$("#myButton").click(function (event) {
event.preventDefault();
$("#form1").submit();
// $("#form2").submit();
});
});
</script>
PHP
<?php
if(isset($_POST['create_record'])){
$ecode = $_POST['ecode'];
$ename = $_POST['ename'];
$date = $_POST['date'];
$jobRole = $_POST['jobRole'];
}else{
echo "did not receive anything";
}
?>
Always getting "did not receive anything" . Can someone please help.
The submit button value only gets sent if the form is submitted in the traditional way by a button click. Since you are submitting the form via javascript, you'll need to explicitly include the submit button's value or validate your post data in some other way. If you need the value of the specific button that was clicked, something like this should work:
$("#myButton").click(function (event) {
event.preventDefault();
var el = '<input type="hidden" name="' + $(this).prop('name') + '" value="' + $(this).val() + '">';
$("#form1").append(el).submit();
});
As for your objective of submitting multiple forms at once, I believe it's impossible without using ajax as discussed here. If you need guidance on how to do that, better to open a new question.
Your code, isset($_POST['create_record']) maybe false or it didn't receive any values. If your query is only in one PHP file together with your jQuery, you need to check first your algorithm or use var_dump() for testing. Second, If it didn't work, make an alternative solution for it. Do the proper HTML code when using form or make another PHP file for receiving post purpose only.
<form action="directory_to_another_file" method="POST">
<!-- SOME INPUTS HERE -->
<input type="submit" value="Submit 1" name="create_record">
</form>
Try to test all of your codes.
You have to set form method as "POST" type and if you want to receive the form data in same page then empty the "action" key otherwise give the target link.
<?php
if(isset($_POST['create_record'])){
print_r($_POST);
}
?>
<form action="" method="POST" id="form1">
<input type="text" name="create_record" value="Submit 1"/>
</form>
Submit
<script>
$(function(){
$("#myButton").click(function (event) {
event.preventDefault();
$("#form1").submit();
});
})
</script>
Let me know if it's work for you.
Because of my web style, i don't want to use input & textarea and get information by using $_POST[] and i need to get information that is in DIV element.
For example , I want to get information in this :
<div class="mine" name"myname">
this is information that i want to get and put into database by PHP !
</div>
and :
$_POST[myname];
But i can't do it with $_POST , How can i do it ??
And if this method can't do this , do you know any other method to get information from DIV like this ?
you can call a onsubmit function and make a hidden field at the time of form submission like this
HTML
need to give a id to your form id="my_form"
<form action="submit.php" method="post" id="my_form">
<div class="mine" name"myname">
this is information that i want to get and put into database by PHP !
</div>
<input type="submit" value="submit" name="submit" />
</form>
Jquery call on submit the form
$(document).ready(function(){
$("#my_form").on("submit", function () {
var hvalue = $('.mine').text();
$(this).append("<input type='hidden' name='myname' value=' " + hvalue + " '/>");
});
});
PHP : submit.php
echo $_POST['myname'];
You can use this method. First, with javascript get content of <div>
Code:
<script type="text/javascript">
var MyDiv1 = Document.getElementById('DIV1');
</script>
<body>
<div id="DIV1">
//Some content goes here.
</div>
</body>
And with ajax send this var to page with get or post method.
You would need some JavaScript to make that work, e.g. using jQuery:
$.post('http://example.org/script.php', {
myname: $('.mine').text()
});
It submits text found inside your <div> to a script of your choosing.
You can use following structure;
JS:
$(document).ready(function() {
$("#send").on("click", function() {
$.ajax({
url: "your_url",
method: "POST",
data: "myname=" + $(".mine").text(),
success: function(response) {
//handle response
}
})
})
})
HTML:
<div class="mine" name"myname">
this is information that i want to get and put into database by PHP !
</div>
<input type="button" name="send" id="send" value="Send"/>
You can see a simulation here: http://jsfiddle.net/cubuzoa/2scaJ/
Do this in jquery
$('.mine').text();
and post data using ajax.
Put the content of DIV in a variable like below:
var x = document.getElementById('idname').innerHTML;
I'm clearly doing something wrong here, but I can't figure out why the Ajax isn't firing and instead insists upon a page load. The newBatable() fires fine, I just can't seem to get the vote to respect the ajax call.
HTML - not sure how to put html in here as code :/ - I feel dumb.
<form class="form-horizontal" id="batable1" action="vote.php" method="GET">
<div id="success-vote-1"></div>
<input type="radio" name="batableResult" value=" include ()" /> include ()<br/>
<input type="radio" name="batableResult" value="require ()" />require ()<br/>
<input type="radio" name="batableResult" value="both of above" />both of above<br/>
<input type="radio" name="batableResult" value="None of above" />None of above<br/>
<button class="btn btn-primary" onClick="vote(1)">Vote</button>
<input type="hidden" name="batableId" id="batable-id" value="1"/>
</form>
JS - the console display everything I want, the php script processes everything nicely and functions perfectly, it is just it has to load the php in the browser so it's not using AJAX
/***************************************/
function newBatable() {
var batableData = $('#new-batable').serialize();
//console.log(batableData);
$.ajax({
url: "process.php",
data: batableData,
success: function(data){
$('#success-new-batable').html(data);
}
});
}
/***************************************/
function vote(poll_id) {
//console.log(poll_id)
var batableId = "#batable" + poll_id;
//console.log(batableId)
var pollData = $(batableId).serialize();
//console.log(pollData);
$.ajax({
url: "vote.php",
data: pollData,
success: function(data){
var batable_success_id = "#success-vote" + poll_id;
$(batable_success_id).html(data);
}
});
}
The submit button fires the JavaScript and then immediately submits the form.
If you are using onclick, then return false to stop that.
You would be better off using a more modern event binding technique though.
how about attaching a click event via jquery to the button?
$(".btn").on('click', function(e){
e.stopPropagation()
e.preventDefault();
vote(1);
});
this would usually be placed in document .ready jquery in an external file or somewhere near the bottom of your page inside script tags.
Does this help?
Since you're already using jQuery, as SubstanceD, you should use jQuery's on() method and stop the event propagation and prevent the default action (submitting the form).
I also noticed a possible bug in your code. It looks like there is a typo. You have
var batable_success_id = "#success-vote" + poll_id;
and <div id="success-vote-1"></div>. You have a dash after vote in the div's ID while you are concatenating batable_success_id into #success-vote1, for example. So even if the AJAX call is made, it probably won't update your HTML like you're expecting.
I have a problem with my page refreshing after ajax posts, I've tried like 6 differing variations and at one point I was getting the proper result but couldn't stop the page from refreshing and after searching the net and around on this site now none of it is working and it's still refreshing...
current code is:
$('#submit_btn').click(function() {
/*event.preventDefault();*/
var curPassword = $("input#curPassword").val();
var newPassword = $("input#newPassword").val();
var new2Password = $("input#new2Password").val();
/*var params = 'curPassword='+ curPassword + '&newPassword=' + newPassword + '&new2Password=' + new2Password; */
var params = {
curPassword: curPassword,
newPassword: newPassword,
new2Password:new2Password
};
$.ajax({
type: "POST",
url: "testAjax.php",
data: params,
success: function(msg){
alert(msg);
}
});
return false;
});
the form is:
<form method="post" action="" name="confirmChange" class="confirmChange">
<label for="curPassword">Current Password:</label>
<input type="password" name="curPassword" id="curPassword" value="" />
<label for="newPassword">New Password:</label>
<input type="password" name="newPassword" id="newPassword" value="" />
<label for="new2Password">Confirm New Password:</label>
<input type="password" name="new2Password" id="new2Password" value="" />
<br />
<input type="button" name="confirmChange" class="confirmChange" id="submit_btn" value="Change" />
Appreciate any help in getting this to work =/
Update:
Took out the other non-directly-related code as it kinda cluttered the question. Also updated code to refelect latest revision.
I changed the ajax url to a simple textAjax.php with a simple echo hello world nothing else, where I'm still getting nothing.
Update 2
Tried changing javascript code to:
$('#submit_btn').click(function() {
alert('Button Clicked');
});
And I'm getting nothing... If that is the form below how is it possible the click function isn't working at all?
You don't need to use the type="submit" for your input. Just use type="button" and call the ajax function on the button's click event.
<input type="button" name="confirmChange" class="confirmChange" id="submit_btn" value="Change">
$('#submit_btn').click(function() {
(ajax code here)
});
preventDefault() would also work, but, in my opinion, why prevent an event from naturally occurring when you can just avoid using the submit button altogether?
Update: I just realised that using the submit would allow users to hit enter to trigger your actions, so perhaps there's also some merit in that. In any case, here's a similar question that contains elaborations into preventDefault().
Update 2: You need to fix your parameters in the ajax function. Use an array instead of trying to build a query string:
var params = {
curPassword: curPassword,
newPassword: newPassword,
new2Password:new2Password
};
Encapsulate your AJAX call within the following code block
$('form.confirmChange').submit(function(event) {
event.preventDefault();
#Rest of your code goes in here
});
preventDefault() will prevent the default action of an event from triggering.
Try this
<script>
function refreshpage(){
(ajax code here)
return false;
}
</script>
<form onsubmit="return refreshpage();">
<input type = "submit" value="submit_btn">
</form>
I think I fixed it by using:
$('#submit_btn').live('click', (function() {
I at least started getting a response when clicking, but I'm not updating or getting any echo's back from the php file but hopefully that'll be easier to debug. :)
I had the same problem. Just like you, I had wrapped my <input> tags inside a <form> tag pair. Even though there was no <submit>, I found that when I clicked my button to trigger the Ajax call, it was refreshing the page - and actually submitting the form to the page.
I ended up removing the <form> tags and this behaviour stopped, but the Ajax still works as expected. I hope this helps anyone else that is experiencing this.
Use a loop to run the ajax call only once.
var i;
for(i=0;i<1;i++){
//ajax code here
}
So, then it will not call again and again..
Greetings from some noob trying to learn JQuery,
I am attempting to make it when you type something in a box below a div layer it reloads that layer upon submission of the form with a php get of the text box in the form. Expected behavior is it would reload that box, actual behavior is it don't do anything. Can someone help me out here.... Below is the code.
<div id="currentwxdiv">This is where the new stuff happens
</div>
<form name="changewx" action="/">
<input type="text" id="city">
<input type="submit" name="submit" class="button" id="submit_btn" value="New City" />
</form>
<script>
/* attach a submit handler to the form */
$('form[name="changewx"]').submit(function(event) {
/* get some values from elements on the page: */
var $form = $( this ),
city = $('#city').val()
/* Send the data using post and put the results in a div */
$('#currentwxdiv').load('http://api.mesodiscussion.com/?location=' + city);
return false;
});
</script>
Its giving the Javascript Console Error Error....
"XMLHttpRequest cannot load http://api.mesodiscussion.com/?location=goodjob. Origin http://weatherofoss.com is not allowed by Access-Control-Allow-Origin."
You are using POST method? is impossible to post to an external url because with ajax, the url fails the "Same Origin POlice".
If you use GET method, is possible to do that.
Another solution is to make a proxy. A little script that recive the params and then... using CURL or another thing you have to post to the external URL... finally, you jquery have to do the post thing to the proxy:
For example:
$.ajax({
url: '/proxy.php?location=' + city,
success: function(data) {
$('#currentwxdiv').html(data);
}
});
I do it so:
<div id="currentwxdiv">This is where the new stuff happens
</div>
<form name="changewx" action="/">
<input type="text" id="city">
</form>
<script>
$('#city').keyup(function() {
var city = $('#city').val()
$.ajax({
url: 'http://api.mesodiscussion.com/?location=' + city,
success: function(data) {
$('#currentwxdiv').html(data);
}
});
});
</script>
To help you out, i need to test this.
What's the url address of your html code working ?
http://api.mesodiscussion.com/?location= doesn't work... only list the directory content... maybe that's de problem?
Greatings.