I want to get image source from user uploaded image and save it to my sql table.
I am using a Wordpress site and the Ultimate Member plugin. Uploaded images are saved in public_html/wp-content/uploads/ultimatemember, but I need image source, so that an admin can view the image in a browser.
What I would like to do is to get the image source and save it to my sql table.
I got an image source in HTML and jQuery with the following code:
<div hidden id="image_1"></div>
<div hidden id="image_2"></div>
<script>
var $ = jQuery;
$(document).ready(function(){
var passport_url = $('img[alt="I_1"]').attr("src");
document.getElementById("image_1").innerHTML = image_1_url;
var proof_url = $('img[alt="I_2"]').attr("src");
document.getElementById("image_2").innerHTML = image_2_url;
});
</script>
I want to write PHP code that gets content of <div id="image_1>" and <div id="image_2>" and saves it to mysql table. I know how to save the path to the sql table, I just don't know how to get the div content in PHP from HTML. What is the proper way to do it?
I don't know why you're trying saving data using manually created script.
Because in wordpress you can easily save meta data (that can be image src) using add_user_meta();
<?php add_user_meta( $user_id, $meta_key, $meta_value, $unique ); ?>
You don't even need to add src using js/innerHtml (as I don't think you want to save src using AJAX)
As you asked a proper way
So, I suggest you,
create a simple form
submit hidden feilds ie 'src'
use $_POST, and save data using add_user_meta();
Full article for add_user_meta
Thanks
Related
I've been looking around for solutions for this for quite sometime and sadly, haven't found a proper solution for it.
Here's the situation.
I have a Bootstrap modal that displays text ( let's call it 'header' ) depending on which button was clicked. The header value is picked up from the data-attribute of the button and using jQuery, I update the text for the respective modal. I hope I've been clear enough about this.
Now, I want to use the same header text in a PHP Script that queries my MySQL table with this 'header' value in the LIKE clause of my query as '%header%'.
Seems simple enough but I can't get my head around it.
Here are some issues that I face:
The header value is empty in the PHP script when I try to pass it to the script. I tried using script_tags to strip the tags around the HTML of the header and just extract the text and also tried PHP DOM but it did not work.
Here are the basic steps for further clarity:
I have a PHP script that needs to get a text value from the HTML on the same page.
This text value was picked up from a data-attribute of a button and updated via jQuery to the HTML.
This text value must be included in the LIKE clause of MySQL query in the PHP script for any updates to the table.
I can handle everything else except the extraction of text and sending it to the PHP script part.
Thank you.
Adding Code for reference:
This is the HTML code that houses the data-attribute:
The $project_title variable was set previously and appended to the button.
echo "<a class='delete_icon' data-project_title='$project_title'><i class='fa fa-trash'></i></a>";
This is the jQuery code:
$('#project_profile_modal').on('show.bs.modal', function (event) {
var del_icon = $(event.relatedTarget);
var project_title = del_icon.data('project_title');
modal.find('h4').text(project_title);
}
This is the excerpt of the PHP script that is relevant:
<?php
$result = "SELECT content FROM my_table WHERE content LIKE '%$project_title%';
?>
Question is: how do I get the text contained in h4 to $project_title/my LIKE clause.
Assuming button looks something like:
<button class="modal-button" data-text="..." data-row_id="...">
Then in click handler you gather all the data and send to server:
$('.modal-button').click(function(){
var data = $(this).data();
// send to server
$.post(url, data, function(response){
// update modal header and content
$('modal-header-selector').text(data.text);
$('modal-content-selector').html(response);
})
})
I've put a set of small images to function as links (around 50 more or less) on a page. In that same page I have a content place holder to display data from the database, and I have a table saved in phpmyadmin that has a set of fields filled with data.
What I want is when the user clicks on a certain image link, the data related to that image gets retrieved into the site. So I want the data to be retrieved to match the image clicked.
I know how to retrieve data from a database using the binding pannel in dreamweaver, and I know this has to do with filtering the data retrieved but I don't know how to do it.. How can I make this process work?
If it helps I'm also using Jquery CSS and javascript in this project.
The project looks like this:
http://i725.photobucket.com/albums/ww256/flower1991a/world_zps26b7083d.png
HTML code:
it doesnt show I took a screenshot of it:
http://i725.photobucket.com/albums/ww256/flower1991a/a_zpsa138aa52.png
jQuery code:
$(document).ready(function() {
// begin Ready
//...................................................
// When the form changes
$('#mapForm').change(function() {
var selectedContinent = $('#mapForm option:selected').val();
if (selectedContinent == 'ALL'){
$('a.dot').slideDown(1000);
}else{
$('a.dot[continent = "'+selectedContinent+'"]').slideDown(1000);
$('a.dot[continent != "'+selectedContinent+'"]').slideUp(1000);
}
});
//...................................................
// When a dot is clicked
$('a.dot').click(function(){
$('a.dot').removeClass('selected');
$(this).addClass('selected');
var city = '.city_detail#' + $(this).attr('city');
var htmlCode = $(city).html();
$('.detail_container').fadeOut(500, function(){
$('.detail_container .city_detail').html(htmlCode);
$('.detail_container').fadeIn(500);
});
});
// end Ready
});
You need to create a PHP script which takes a REQUEST variable parameter depending on the image that has been clicked, and which returns the data for that image.
You can then make a call to that PHP script via AJAX and populate whichever area of the page you want to with the data retrieved.
I have a page called test.html. This HTML page will contain 2 JavaScripts file. I need to pass a variable value to a PHP file using the first JavaScript file. The user can copy this javascript on as many pages as he wants for displaying output.
The PHP file that receives the variable from the JavaScript file retrieves some data from database depending upon the variable's value. This retrieved value can contain HTML content. This PHP file will always reside on my server.
All of the retrieved content (from the PHP file) needs to be passed to the second JavaScript file so that the data can be displayed in browser. This JS file will need to stay together with the first JS file in order for the data to be displayed.
So I have this:
JavaScript File
<script type= "text/javascript" src="http://www.myserver.com/custom_script.php?unique_id=12"></script>
PHP FILE
//custom_script.php
<?php
$unique_id= (int)$_GET['unique_id'];
$res = db_res(" SELECT col1, col2, col3, .... col10 FROM table WHERE unique_id = $unique_id
LIMIT 1 ");
$rows = mysql_fetch_array($res);
?>
<div id="1"><?php echo $rows['col1']; ?></div>
<div id="2"><?php echo $rows['col2']; ?></div>
<div id="3"><?php echo $rows['col3']; ?></div>
.
.
.
<div id="10"><?php echo $rows['col10']; ?></div>
I need to send all the HTML above from the PHP file to the second JavaScript file so that the output can be displayed. Please note that the CSS styling is also applied using Div ID, so I am expecting those styles would show up too. Please note that there may be more than 10 columns, so an efficient way of passing data is highly appreciated.
So what would be the easiest and the best way to send all the HTML data from the PHP file in one go to the 2nd javascript file residing in test.html page, so that the HTML data can be displayed in test.html file?
EDIT 1:
I apologize to everyone if my question has been confusing. I just thought of an example and hence wanted to add it my edit. I hope you are all aware of what Google Analytics (GA)(or any other Website Visits Stats Tracker) does. Right? You register for a Analytics account and Google gives you a piece of JS code that you copy and paste in your website. And after couple of days, you can login into your GA account to see the stats. Correct? What I am trying to do here is just the same.
Users come to MY WEBSITE and register for an account and I give them JS files that they can paste in their website. The only difference between GA and my website is that GA is personal to you and no one else, but you, the account holder can see it. Whereas in my case, your data can BE SEEN by others as well, as long as you include the JS file on your website. Because users can't just take my PHP file and run it on their server, I am trying to access MY PHP file by giving the full path to it in the JS file.
For example:
<script type= "text/javascript" src="http://www.myserver.com/custom_script.php?unique_id=12"></script>
This is not an actual JS file, rather it is just a medium for my custom_script.php script to receive the unique_id of the user, query MY database and send back the HTML data related to this requesting user. And I am stuck with this part. Hope this clairifies what I am trying to do.
The jQuery documentation actually gives an example almost identical to your problem:
http://api.jquery.com/jQuery.get/
$.get('ajax/test.html', function(data) {
$('.result').html(data);
alert('Load was performed.');
});
This will get an html page and insert it under an html element with class 'result'.
You should be able to replace your php script url and specify where the output should be displayed.
If youre worried about conflicts with other jQuery instances, have a read of this:
http://api.jquery.com/jQuery.noConflict/
If you want to write your own AJAX handler check out this page :
https://developer.mozilla.org/en-US/docs/DOM/XMLHttpRequest/Using_XMLHttpRequest
Essentially you will do something like this (taken from the link):
function reqListener () {
console.log(this.responseText);
};
var oReq = new XMLHttpRequest();
oReq.onload = reqListener;
oReq.open("get", "yourFile.txt", true);
oReq.send();
I think its worth doing if you've never had to do it before, but you will open yourself up to lots of potential problems that have been solved for you.
Ideally if I were doing this I would return json from the handler and allow the user to decide how to display it, but thats your call.
I added an image to PDF using $p->load_image (http://www.php.net/manual/en/function.pdf-fit-image.php). Now, I want to write JavaScript in it so that the user can manipulate image in the PDF. How can I get access to the image in PDF using Javascript?
Using PdfLib, add the following option to the load_image call:
"iconname=HelloImage" where HelloImage is the name of the image. The complete call would be,
$p->load_image('jpeg', 'C:/hello.jpg', "iconname=HelloImage");
In Javascript code, you can access it. For example,
var hello_image = this.getIcon("HelloImage");
Now hello_image points to the HelloImage.
I have this form and I would like to read the uploaded file and then fill out the form using this read information without refreshing the page.
For example the first word might be "Bob" and so I would want that to go in my input text "First_name." I've been trying to searching online for a way to do this using JQuery or Ajax but I can't seem to find a solution.
Can this be done using the two methods previously mentioned? If so and if not can someone point me to a link or to where I can learn how to do this? The instances I have found include where one uses JQuery to upload the file and display the size without refresh (which is not exactly what I want).
I have also found how one can use an iFrame but this again is not what I want. I suppose I could always just submit the part of the page containing the textfile related information and show the same form but with the filled out information. But I feel as if this is kind of sloppy and I want to know if there is a better way.
Thanks.
Firefox has a method to do this, the File and FileList API provide a way to get at the files selected by a file input element and have a text retrieval method.
A very basic example:
NB. Not all browsers support this code.
[I think Chrome, Firefox and Opera do at time of writing.]
HTML:
<form>
<input type="file" name="thefile" id="thefile" />
</form>
<div id="text"></div>
JS (using jQuery):
$(document).ready(function() {
$('#thefile').change(function(e) {
if (e.target.files != undefined) {
var reader = new FileReader();
reader.onload = function(e) {
$('#text').text(e.target.result);
};
reader.readAsText(e.target.files.item(0));
}
return false;
});
});
Demo: http://jsfiddle.net/FSc8y/2/
If the selected file was a CSV file, you could then process it directly in javascript.
.split() will be useful in that case to split lines and then fields.
the only way I know would be to submit the form to a hidden iframe. this will upload teh file without refreshing the page. you can then use any returned info using javascript. this is what they use for fake ajax style image uploads that let you preview an image before uploading. the truth is it already has been uploaded via a hidden iframe. unfortunately however iframes are not xhtml 1.0 compliant.
something like this article may help:
http://djpate.com/2009/05/24/form-submit-via-hidden-iframe-aka-fake-ajax/
The question you might ask is :
why should I use this method instead of real ajax ?
Well they’re is numereous answer to that but one good reason it that
is doesnt require any type of ajax libs and you can start using it
even if you never used ajax before.
So here it goes.
<form method=”post” action=”formProcess.php” target=”hiddenIFrame”>
<input type=”text” name=”test” /> </form>
<iframe style=”width:0px;height:0px;border:0px;” name=hiddenIFrame />
This is just a normal form but you’ll notice the target in the form
tag, this tells the form to submit in the iframe instead of the
current page.
It’s works exactly as the target attribut on the A tag.
Also the iframe is hidden from the user using
style=”width:0px;height:0px;border:0px;”
now the file formProcess.php is not different from your normal form
processing file but if you want do something on the main page you have
to use JS like that :
window.parent.whatEverYouWannaDoInParentForm();
You can also upload file with this method !
Please checkout the formphp for full example.
Cheers !
Nb : You will see the status bar acts like the page is reloading but
it’s really not.