Fill array with same data in php - php

Question

I have an array with some data that returns me from the database, the problem is that not all the keys are associated, I should fill the missing keys with data to 0.
My array is by default is:
array:1 [▼
9 => array:2 [▼
4 => array:3 [▼
"Orange" => array:3 [▼
"price" => "600.00"
"total" => "690.00"
]
"Apple" => array:3 [▼
"price" => "650.00"
"total" => "870.00"
]
"Banana" => array:3 [▼
"price" => "50"
"total" => "40"
]
]
21 => array:1 [▼
"Apple" => array:3 [▼
"price" => "44"
"total" => "33"
]
]
]
]
The array should have the same structure but with data at 0
Result:
array:1 [▼
9 => array:2 [▼
4 => array:3 [▼
"Orange" => array:2 [▼
"price" => "600.00"
"total" => "690.00"
]
"Apple" => array:2 [▼
"price" => "650.00"
"total" => "870.00"
]
"Banana" => array:2 [▼
"price" => "50"
"total" => "40"
]
]
21 => array:3 [▼
"Apple" => array:2 [▼
"price" => "44"
"total" => "33"
],
"Orange" => array:2 [▼
"price" => "0"
"total" => "0"
],
"Banana" => array:2 [▼
"price" => "0"
"total" => "0"
]
]
]
]

Answer 1

The "for" below modify each array with adding any new value and also avoid duplicate values. Basically, it finds the differences and then merge that, setting the first array to clone each array.
$fruits = array (
1 => array('Manzana', 'Naranja', 'Pera'),
2 => array('Pera', 'Sandia'),
3 => array('Manzana', 'Melocotones')
);
print_r($fruits);
for ($i = 1; $i <= count($fruits)-1; $i++) {
$result = array_diff($fruits[1], $fruits[1+$i]);
$merge = array_merge($fruits[1+$i], $result);
$fruits[1+$i] = $merge;
$fruits[1] = $merge;
}
print_r($fruits);
?>
Here to see how run it!
https://repl.it/KqUi/3

Answer 2

If you will always use the first element as boilerplate you can do something like this:
$boilerplate = reset($array);
array_walk_recursive($boilerplate, function (&$value) {
$value = 0;
});
$array = array_map(function ($items) use ($boilerplate) {
return array_merge($items, array_diff_key($boilerplate, $items));
}, $array);
Here is working demo.