Refactor to show link or not in blade - php

Question

I felt this code look a bit messy, the logic is to show a link <a href or otherwise show text only.
How can I refactor this to look cleaner and maintainable?
<ol class="breadcrumb">
<li class="{{ $active == 'sign_in'? 'active':'' }}">
#if($active != 'sign_in')
#php($showLink = true)
#else
#php($showLink = false)
#endif
#if($showLink)
<a href="{{ url_secure('sign_in') }}">
#endif
Sign In
#if($showLink)
</a>
#endif
</li>
<li class="{{ $active == 'article'? 'active':'' }}">
#if($active != 'article' && $showLink)
#php($showLink= true)
#else
#php($showLink= false)
#endif
#if($showLink)
<a href="{{ url_secure('article')}}">
#endif
Articles
#if($showLink)</a>#endif
</li>
<li> </li> //repeat the code logic like above
</ol>
It would be good if there a way to reduce if conditions and use loop.

Answer 1

Why not just:
<li class="{{ $active == 'sign_in'? 'active':'' }}">
#if ($active != 'sign_in')
Sign In
#else
Sign In
#endif
</li>
Also it is unclear why you check $showLink that was set previoulsy.
Okay, as I've read your comments, I've modified template a bit with using foreach loop:
#php
// some initial variables
$allowed_to_click = true;
// this is a link to selected page
$selected_link = 'something';
#endphp
#foreach ($links as $link)
#php
// check if this link is ACTIVE
$active = $link == $selected_link;
// check if we can CLICK this link
$allowed_to_click = $active || $allowed_to_click;
#endphp
<li class="{{ $active ? 'active':'' }}">
#if ($allowed_to_click)
Some Caption
#else
Some Caption
#endif
</li>
#php
// if link is ACTIVE - following links are unclickable
if ($active) {
$allowed_to_click = false;
}
#endphp
#endforeach