How to starts adding data to MySQL table with id of !=0 - php

Question

I have a page to add new users to the MySQL with PHP. And the problem with this is, that it sets id of a new user to 0 whenever it runs. So I don't want that.. I want it to start from id of 1 and if it exists in table, try more than that like 2 for example.
I don't think for this example, you won't need to look at my php files but if you do, here you can see the admin_new.php:
<?php
$notice = array();
if (isset($_POST['submit'])){
$username = $_POST['uname'];
$email = $_POST['email'];
$password = $_POST['pass'];
$groups = $_POST['groups'];
if($groups == "Main Admin"){
$level = 1;
}else if($groups == "Administrator"){
$level = 2;
}else if($groups == "Content Creator"){
$level = 3;
}else if($groups == "Social Media Manager"){
$level = 4;
}else{
$level = 5;
}
if (filter_var($email, FILTER_VALIDATE_EMAIL) === false) {
$notice['email'] = "The email that you have entered is not a valid one";
}else{
$registration = new Register();
$registration->CheckUname($username,$email,$password,$groups,$level);
}
}
?>
<div class="content-wrapper">
<section class="content-header">
<h1>
Add New Admin
<small>You can add new admin here</small>
</h1>
<ol class="breadcrumb">
<li class="active">addnewadmin.php</li>
</ol>
</section>
<?php
if(isset($notice['validation_email'])) {
echo "
<div class='alert alert-danger'>
<strong>Hey!</strong> ".$notice['validation_email'].".
</div>
";
}
if(isset($notice['username_exists'])) {
echo "
<div class='alert alert-danger'>
<strong>Hey!</strong> ".$notice['username_exists'].".
</div>
";
}
if(isset($notice['email_exists'])) {
echo "
<div class='alert alert-danger'>
<strong>Hey!</strong> ".$notice['email_exists'].".
</div>
";
}
if(isset($notice['success_message'])) {
echo "
<div class='alert alert-danger'>
<strong>Hey!</strong> ".$notice['success_message'].".
</div>
";
}
?>
<section class="content">
<div class="row">
<div class="col-md-6">
<div class="box box-primary">
<div class="box-header with-border">
<h3 class="box-title">Required Information</h3>
</div>
<form role="form" method="POST" action="">
<div class="box-body">
<div class="form-group">
<label>User name</label>
<input type="text" class="form-control" placeholder="Enter username" name="uname" required>
</div>
<div class="form-group">
<label for="exampleInputEmail1">Email address</label>
<input type="email" class="form-control" id="exampleInputEmail1" placeholder="Enter email" name="email" required>
</div>
<div class="form-group">
<label for="exampleInputPassword1">Temporary password</label>
<input type="password" class="form-control" id="exampleInputPassword1" placeholder="Enter password" name="pass" required>
</div>
<div class="form-group">
<label>Group admin</label>
<select class="form-control" name="groups">
<option value="Main Admin">Main Admin</option>
<option value="Administrator">Administrator</option>
<option value="Content Creator">Content Creator</option>
<option value="Social Media Manager">Social Media Manager</option>
<option value="Analyst">Analyst</option>
</select>
</div>
</div>
<div class="box-footer">
Visit admin types documentation to know the differences between each admin.
</div>
<div class="box-footer">
<button name="submit" type="submit" class="btn btn-primary">Submit</button>
</div>
</form>
</div>
</div>
</div>
</section>
</div>
And here is the class that I have used which is called Register.class.php:
<?php
class Register
{
private $db;
public function __construct()
{
$this->db = new Connection();
$this->db = $this->db->dbConnect();
}
public function CheckUname($username,$email,$password,$groups,$level)
{
if(!empty($username)&&($email))
{
$chk1 = $this->db->prepare("SELECT username FROM admins WHERE user_name= ?");
$chk1->bindParam(1,$username);
$chk1->execute();
if($chk1->rowCount() == 1)
{
$notice['username_exists'] = "Try different username";
return $notice;
}else{
$chk2 = $this->db->prepare("SELECT email FROM admins WHERE email_address= ?");
$chk2->bindParam(1,$email);
$chk2->execute();
if($chk2->rowCount() == 1)
{
$notice['email_exists'] = "The email address that you have entered is already exists in database";
return $notice;
}else{
$this->NewAdmin($username,$email,$password,$groups,$level);
$notice['success_message'] = "New admin was successfully added";
return $notice;
}
}
}
}
public function NewAdmin($username,$email,$password,$groups,$level)
{
if(!empty($username)&&!empty($email)&&!empty($password)&&!empty($groups)&&!empty($level))
{
$reg = $this->db->prepare("INSERT INTO admins (user_name, email_address, password_hash, group_admin, date_joined, admin_level) VALUES ( ?, ?, ?, ?, NOW(), ?)");
$reg->bindParam(1,$username);
$reg->bindParam(2,$email);
$reg->bindParam(3,$password);
$reg->bindParam(4,$groups);
$reg->bindParam(5,$level);
$reg->execute();
}
}
}
?>

Answer 1

Run this commend on mysql terminal:
ALTER TABLE tablename MODIFY COLUMN id INT auto_increment PRIMARY KEY
the above command will make the id an auto_increment as well as primary key. So for every value you insert, auto_increment will generate a new value for column id, you don't have to assign some value in it.