First word of a comma separated sentence php - php

Question

My string is : Hi my, name is abc
I would like to output "Hi Name".
[Basically first word of comma separated sentences].
However sometimes my sentence can also be Hi my, "name is, abc"
[If the sentence itself has a comma then the sentence is enclosed with ""].
My output in this case should also be "Hi Name".
So Far I've done this
$str = "hi my,name is abc";
$result = explode(',',$str); //parsing with , as delimiter
foreach ($result as $results) {
$x = explode(' ',$results); // parsing with " " as delimiter
forach($x as $y){}
}

Answer 1

You can use explode to achieve YOUR RESULT and for IGINORE ' OR " use trim
$str = 'hi my,"name is abc"';
$result = explode(',',$str); //parsing with , as delimiter
$first = explode(' ',$result[0]);
$first = $first[0];
$second = explode(' ',$result[1]);
$second = trim($second[0],"'\"");
$op = $first." ".$second;
echo ucwords($op);
EDIT or if you want it for all , separated values use foreach
$str = 'hi my,"name is abc"';
$result = explode(',',$str); //parsing with , as delimiter
$op = "";
foreach($result as $value)
{
$tmp = explode(' ',$value);
$op .= trim($tmp[0],"'\"")." ";
}
$op = rtrim($op);
echo ucwords($op);

Answer 2

Basically it's hard to resolve this issue using explode, str_pos, etc. In this case you should use state machine approach.
<?php
function getFirstWords($str)
{
$state = '';
$parts = [];
$buf = '';
for ($i = 0; $i < strlen($str); $i++) {
$char = $str[$i];
if ($char == '"') {
$state = $state == '' ? '"' : '';
continue;
}
if ($state == '' && $char == ',') {
$_ = explode(' ', trim($buf));
$parts[] = ucfirst(reset($_));
$buf = '';
continue;
}
$buf .= $char;
}
if ($buf != '') {
$_ = explode(' ', trim($buf));
$parts[] = ucfirst(reset($_));
}
return implode(' ', $parts);
}
foreach (['Hi my, "name is, abc"', 'Hi my, name is abc'] as $str) {
echo getFirstWords($str), PHP_EOL;
}
It will output Hi Name twice
Demo