Problem
I created a simple friendship relationship for my Laravel app which all worked ok until I noticed that when I queried the friendship of a user it would only search the current user on the UID1 field.
Since friendships are in essence a two-way relationship, Im trying to find a way in a laravel Model to retrieve ALL friendships relations by multiple columns.
Current Implementation
public function friends()
{
return $this->belongsToMany( App\Modules\Users\Models\User::class ,'friends', 'uid1');
}
Ideal Implementation
public function friends()
{
$a = $this->belongsToMany( App\Modules\Users\Models\User::class ,'users_friends', 'uid1');
$b = $this->belongsToMany( App\Modules\Users\Models\User::class ,'users_friends', 'uid2');
return combine($a,$b);
}
Table Structure
+----------------------+
| users table |
+----------------------+
+----| id: primary UserID |
| | fname: string |
| +----------------------+
|
|
| +----------------------+
| | friends table |
| +----------------------+
| | id: primary iD |
| | |
+----| uid1: user_id |
| | |
+----| uid2: user_id |
+----------------------+
The current implementation will only result in 1 of these records returning if the Current UserID = 1 as per the data in the friends table below.
+-------------------------------+
| friends table (data) |
+--------|---------|------------+
| id | uid1 | uid2 |
+--------|---------|------------+
| 1 | 1 | 7 |
| 2 | 7 | 1 |
| 3 | 9 | 1 |
+-------------------------------+
User Model
<?php
namespace App\Modules\Users\Models;
use Illuminate\Database\Eloquent\Model;
class User extends Model
{
protected $table = 'users';
protected $fillable = [
'username', 'email', 'password', .... .
];
public function friends()
{
return $this->belongsToMany( App\Modules\Users\Models\User::class ,'users_friends', 'uid1');
}
Environment
Server = Homestead/linux
PHP = 7
MySQL
Update
I have a FriendShip helper class I created which does something similar, however in this function I pass in the UserID explicitly
Friendship::where( [
[ 'uid1' ,'=', $uid],
])->orWhere( [
[ 'uid2', '=', $uid]
])->all();
You can add additional conditions when you're declaring relationship by simply chaining it.
<?php
//...
class User extends Model {
//...
public function friends() {
return $this->hasMany(/*...*/)->orWhere('uid2', $this->id);
}
//...
But keep in mind that eloquent is not grouping the first conditions of relation in parenthesis so you might end with SQL that will not work as expected in some cases (if using or, and should be fine)
For example the above might result in a SQL that looks like this
SELECT * FROM users_friends WHERE uid1 = ? AND uid1 IS NOT NULL OR uid2 = ?
Which is a correct SQL statement but without grouping you will not get the result that you're expecting.
Another way is to use accessor and two separate relationships
<?php
//...
public function friends1() {
return $this->belongsToMany(User::class, 'users_friends', 'uid1');
}
public function friends2() {
return $this->belongsToMany(User::class, 'users_friends', 'uid2');
}
public function getFriendsAttribute() {
return $this->friends1->merge($this->friends2);
}
//...
But this way you get two separate trips to DB.
Related
I have Two Table
1- projects
User with id 5 has created 3 project - which means he will have 3 unique conversation with our different agent
----------------------------------------
|id | user_id | title | time |
|1 | 5 | Example | 2018-06-30 |
|2 | 5 | Example | 2018-06-30 |
|3 | 5 | Example | 2018-06-30 |
----------------------------------------
2- conversation
-------------------------------------------
|id | project_id | user_one | user_two |
|1 | 1 | 5 | 3 |
|2 | 2 | 5 | 7 |
|3 | 3 | 5 | 10 |
-------------------------------------------
Whenever a project is created, a conversation is created with that project id, Now in Laravel i want to get that project detail using Eloquent Relationships.
User_one is the project creator and user_two is our agent assigned to that product.
This is What I've tried
class Chat extends Model {
public function project()
{
return $this->belongsTo('App\ProjectModel');
}
}
class ProjectModel extends Model
{
public $table = 'projects';
}
Here is the controller function
public function Progress($id){ // Id passed here is 2, so it should show detail of project number 2
return \App\Chat::find($id)->project()->get();
}
After all this I'm getting an error - Call to a member function project() on null
You can try like this with creating 2 Models Project and Conversation
table
conversations(id, project_id, creator, agent)
Project Model
public function conversations(){
return $this->hasMany('App\Conversation');
}
Conversation Model
public function project(){
return $this->belongsTo('App\Project', 'project_id');
}
public function creatorUser(){
return $this->belongsTo('App\User', 'creator');
}
public function agentUser(){
return $this->belongsTo('App\User', 'agent');
}
Fetch Data
public function Progress($id){ // Id passed here is 2, so it should show detail of project number 2
$chats = Conversation::with('project', 'creatorUser', 'agentUser')->where('project_id', 2)->get();
foreach($chats as $chat){
dd($chat->project); //it will always print same project because we have filter the conversation by project_id
dd($chat->creatorUser);
dd($chat->agentUser);
}
}
you can create a relation Along with specifying foreign Key and owner key like:
class Chat extends Model {
public function project()
{
return $this->belongsTo(App\ProjectModel::class, 'project_id', 'id');
}
}
and then you will be able to get:
\App\Chat::where('id', $id)->first()->project;
I'm trying to get the output of a belongstoMany relationship between users and sections database, which are tied to User and Section model, respectively.
User model has this method:
public function section()
{
return $this->belongsToMany('App\Models\Section','user_section')->withTimestamps();
}
Section model has this method:
public function user()
{
return $this->belongsToMany('App\Models\User','user_section')->withTimestamps();
}
My user_section table looks like this:
+----+---------+------------+------------+------------+
| id | user_id | section_id | created_at | updated_at |
+----+---------+------------+------------+------------+
| 1 | 1 | 1 | NULL | NULL |
| 2 | 2 | 1 | NULL | NULL |
+----+---------+------------+------------+------------+
2 rows in set (0.00 sec)
So why when I do this in the business logic:
$user = User::where("id",Auth::user()->id)->first(); //user with id of 1 in my case
return json_encode($user->section());
Do I get {} as output?
$user->section() will return the BelongsToMany relationship instead of the model object itself. You can do $user->section instead to load the relationship and have the model returned.
I'm new to Laravel, and I got stuck with the following issue:
I have a table for the users, and groups, and a table for connecting them. The general task any user can join any group.
----------------------------------------------
| users | groups | user_groups |
|--------------------------------------------|
| id - int pk | id - pk | id - pk |
| name text | name | user_id - fk |
| email | | group_id - fk |
| phone | | any_attr |
----------------------------------------------
I have the following models:
class User
{
...
public function groups()
{
return $this->belongsToMany(Group::class, 'user_groups')->withPivot(['is_notification_requested']);
}
...
}
class Group
{
...
public function users()
{
return $this->belongsToMany(User::class, 'user_groups');
}
...
}
How do I get all of the groups, with a count of the members? I need the Group model, and a count of the users in the group.
If you're using Laravel 5.3, you can simply add withCount('relationship') as documented here: https://laravel.com/docs/5.3/eloquent-relationships#counting-related-models
Here's an example following your code:
$groups = Group::withCount('users')->get();
Now you can do this:
foreach($groups as $group) {
echo $group->user_count
}
I am trying to learn laravel and currently using eloquent to interact with the database. I am stuck on how I could use eloquent to get a kind of a join in eloquent.
I have a many to many relation between two tables :users and projects , I use sharedProject table to be the intermediate table .
The tables are as such
Users:
| iduser | name | password |
----------------------------------------
| 1 | somename | hashPassword |
| 2 | somename2 | hashPassword |
| 3 | somename3 | hashPassword |
| 4 | somename4 | hashPassword |
----------------------------------------
Projects:
| pid | projectname
-------------------
| 1 | somename
| 2 | somename
SharedProjects:
| pid | iduser | sharedProjectid |
----------------------------------
| 1 | 1 | 1 |
| 1 | 2 | 2 |
Now I want to get all the users who are not sharing a given project, for example in the above case for project with id 1 , I should get user 3 and user 4.
Here are my relationships in User model
/**
* User can have many projects
*
* #var array
*/
public function projects(){
return $this->hasMany('App\Project','pid','iduser'); // hasmany(model,foreignkey,localkey)
}
/**
* The user can have many shared projects
*/
public function sharedProjects()
{
return $this->belongsToMany('App\SharedProject', 'sharedProjects', 'iduser', 'pid');// belongsToMany('intermediate tablename','id1','id2')
}
and in the Project model:
/**
* The project can be shared by many users
*/
public function sharedProjects()
{
return $this->belongsToMany('App\SharedProject', 'sharedProjects', 'pid', 'iduser');// belongsToMany('intermediate tablename','id1','id2')
}
/**
* a project belongs to a single user
*
* #var array
*/
public function user()
{
return $this->belongsTo('App\User');
}
I would prefer a eloquent way to do this , but would also except it, if can't be done in eloquent and I have to see a alternate approach I would appreciate a plain mysql query as well.
Thanks
Once you define your Eloquent models and your many-to-many relationships, you can use them to get the data you're looking for.
Assuming a User model that has a projects relationship defined, you can use the whereDoesntHave() method to query for a list of users that are not related to a specific project.
$projectId = 1;
$users = User::whereDoesntHave('projects', function ($q) use ($projectId) {
return $q->where('projects.id', $id);
})->get();
You can read about defining many-to-many relationships in Eloquent here.
You can read about querying relationship existence here.
As you may notice, not all methods are documented (like whereDoesntHave()), so you may have to go source code diving. You can dig into the Eloquent codebase here.
I resort to use plain mysql queries, this seems to work for me:
$nonSharedUsers = DB::select( DB::raw("SELECT iduser FROM users WHERE NOT EXISTS (SELECT * FROM sharedProjects WHERE sharedProjects.iduser= users.iduser and sharedProjects.pid=:projectId)"), array(
'projectId' => $pid,
));
I need to refactor project and I have problem. Below is old, working model, where 'active' column is in "people" table. I need to move 'active' column into "people_translations" table.
Do you have any Idea to modify scopeActive method?
Thanks a lot!
Old working model:
class BaseModel extends Eloquent
{
public function scopeActive($query)
{
return $query->where($this->table . '.active', '=', 1);
}
}
class People extends BaseModel
{
protected $table = 'peoples';
protected $translationModel = 'PeopleTranslation';
}
class PeopleTranslation extends Eloquent
{
public $timestamps = false;
protected $table = 'peoples_translations';
}
Old tables structure:
Table: peoples
id | type | date | active
-------------------------
7 | .... | ... | 1
Table: peoples_translations
id | people_id | language_id | name
-----------------------------------
1 | 7 | 1 | Ann
Old query:
$peoples = \People::active()->get();
New tables structure:
Table: peoples
id | type | date
----------------
7 | .... | ...
Table: peoples_translations
id | people_id | language_id | name | active
--------------------------------------------
1 | 7 | 1 | Ann | 1
Create a relation for translations inside People Model
public function translations()
{
return $this->hasMany('PeopleTranslation', 'people_id');
}
Create active scope in People model
public function scopeActive($query)
{
return $query->whereHas('translations', function($query) {
$query->where('active', 1);
});
}
It will make subquery for this table and as a result it will get where (count of translations with active = 1) > 0.
If you have one-to-one relation - look for hasOne relation method instead of hasMany.