How to loop 2 dates to output like this? - php

Question

Here's my code that display date with for loop.
Topic: Im creating a script to generate payment due(from to start).
$y = 1;
$period = 3;
$start = date('m/15/Y');
echo "<table>";
echo '<thead><th>From</th>';
echo '<th>To</th></thead>';
for ($y; $y <= $period; $y++) {
$month_mid = date("m/15/Y", strtotime($start));
$month_last = date("m/t/Y", strtotime($start));
echo '<td>'.$month_mid = date("m/t/Y", strtotime($start)).'</td>';
echo '<td>'.$month_last = date("m/15/Y", strtotime($start)).'</td></tr>';
$start = date("m/d/Y",strtotime($start." +1month"));
}
echo '</table>';
output I get:
09/15/2017 09/30/2017
10/15/2017 10/31/2017
11/15/2017 11/31/2017
I want to appear like this:
09/15/2017 09/30/2017
09/30/2017 10/15/2017
10/15/2017 10/31/2017
Im new in date php hope you can help me with this thanks.

Answer 1

Here you go:
$y = 1;
$period = 5;
$start = date('m/15/Y');
echo "<table>";
echo '<thead><th>From</th>';
echo '<th>To</th></thead>';
for ($y; $y <= $period; $y++) {
$month_mid = date("m/15/Y", strtotime($start));
$month_last = date("m/t/Y", strtotime($start));
echo '<tr><td>'.$month_mid = date("m/t/Y", strtotime($start)).'</td>';
echo '<td>'.$month_last = date("m/15/Y", strtotime($start)).'</td></tr>';
$start = date("m/d/Y",strtotime($start." +1month"));
}
echo "</table>";
You missed the opening and clousure of table and <tr>.

Answer 2

You don't want to be skipping ahead by a month in your loop. Well, not the way you are doing it here.
You should use DatePeriod::getEndDate and DatePeriod::getStartDate, along with DateTime::add to skip by semi-monthly amounts. The idea is that you only get to the next month by letting the datetime API add 15 days to a given start date, and use that to figure out the mid-month and end-month dates.
Keep everything in these date objects until you need to format and print them, and save the second one in the pair as input for the next round of the loop at the end where you just have to calculate the new second value.
I feel like you could write a function that gets the "next" date from any other first or last date of the month to simplify the loop.
(Since this is semi-monthly and not bi-weekly, you can actually just walk the months in your period, hard-coding the 15th for one value and using your end-of-month function for the second. It depends on your requirements and how complicated the API gets.)
Or
For each month in your period, calculated the mid-month (i.e., exactly 15 days from the start of the month) and end-month dates. Save them in a Collection of couplets of some sort.
Write a display routine that takes this Collection and outputs the dates, but saves the previous formatted string made from the second item in the couplet as the first item to be printed (after the first line.)
I actually prefer this one because it separates the presentation from the data abstraction, allowing you freedom to display and format the date how you see fit.
But, at the end of the day (pun not intended, but what a great pun), stop using date strings as input to figure out other dates when you have access to normalized epoch representations. This will only lead to madness.

Answer 3

$y = 1;
$period = 3;
$start = date('m/d/Y');
$end = date('m/t/Y');
echo "<table>";
echo '<thead><th>From</th>';
echo '<th>To</th></thead>';
for ($y; $y <= $period; $y++) {
echo '<tr><td>'.$start.'</td>';
echo '<td>'.$end.'</td></tr>';
$getLast = date('d',strtotime($end));
if($getLast >= 28) {
$start = date("m/t/Y", strtotime($start));
$end = date("m/d/Y", strtotime("+15 day", strtotime($end)));
}else {
$start = date("m/d/Y", strtotime("+15 day", strtotime($start)));
$end = date("m/t/Y",strtotime($end));
}
}
echo "</table>";
Result:
From To
09/15/2017 09/30/2017
09/30/2017 10/15/2017
10/15/2017 10/31/2017