Unable to use an array as an array? - php

Question

I am in the process of building a software download site for my company.
However, I have come across a problem that I am unsure how to get past.
I am retrieving all the information from a table about a particular software release and placing them in a multidimensional array. I am then trying to run a foreach (I have even tried a for loop) against that array and I get an error shown below:
When I run var dump against the original array, I get this:
So I am really confused as I don't know what I'm missing or where I am going wrong. The reason why I want to run this is so that I can filter the array into a one dimensional array.
Below is the code for the main web page
<?php
//Displays list of companies in 2 columns
$versionAccess = VersionAccess::findAccess($relId);//This gets set earlier in the webpage
$count = count($versionAccess);
var_dump($versionAccess);
foreach ($versionAccess as $va)
{
if ($va->company_access != '0')
{
$versionAcc[] = $va->comapny_id;
}
}
foreach ($company as $compAccess)
{
$compAccessId = $compAccess->company_id;
if (in_array($compAccessId, $versionAcc))
{
$access = 'checked disabled';
}
else { $access = 'disabled'; }
$accessName = 'access'.$compAccessId;
if ($ctr % 2 == 0)
{
echo '<td>'.$compAccess->company_name.':</td>';
echo '<td><label class="switch"><input type="checkbox" name="'.$accessName.'" value="1" '.$access.'><span class="slider round"></span></label></td>';
echo '</tr>';
}
else
{
if ($ctr < $compCount)
{
echo '<tr>';
echo '<td>'.$compAccess->company_name.':</td>';
echo '<td><label class="switch"><input type="checkbox" name="'.$accessName.'" value="1" '.$access.'><span class="slider round"></span></label></td>';
}
else
{
echo '<tr>';
echo '<td>'.$compAccess->company_name.':</td>';
echo '<td><label class="switch"><input type="checkbox" name="'.$accessName.'" value="1" '.$access.'><span class="slider round"></span></label></td>';
echo '</tr>';
}
}
$ctr++;
}
?>
The function that brings the data from the database is:
public static function findAccess($accessId)
//find the version access in database
{
return self::findQuery("SELECT * FROM version_access WHERE version_id = '$accessId'");
}
The findQuery method:
public static function findQuery($sql)
{
global $database;
$resultSet = $database->query($sql);
$objectArray = array();
while ($row = mysqli_fetch_array($resultSet))
{
$objectArray[] = self::instant($row);
}
return $objectArray;
}
I am still relatively new and any help is greatly appreciated.