I have below scenario where, I have one collection "demo" having all data which need to be search,
I have used text search,
{
"_id" : "1",
"type" : "Deal",
"description_title" : "New Deal for test",
"images" : "",
"start_date" : ISODate("2017-07-20T00:00:00.000+0000"),
"end_date" : ISODate("2017-10-30T11:59:00.000+0000"),
"status" : "1"
}
{
"_id" : "2",
"type" : "Event",
"description_title" : "Event1 test",
"images" : "",
"end_date" : ISODate("2017-10-20T00:00:00.000+0000")
"status" : "1"
}
{
"_id" : "3",
"type" : "Text",
"description_title" : "test",
"images" : "",
"status" : "1"
}
{
"_id" : "4",
"type" : "Event",
"description_title" : "Event2 test",
"images" : "",
"end_date" : ISODate("2017-07-20T00:00:00.000+0000")
"status" : "1"
}
In above collection I have stored all data which need to be search by using text search, But when "type" : "Event"/"Deal" then it should only return Active Deals & Events "Current date is less than end_date" need to be searched.
In above collection When I search for "Test", It should return,
{
"_id" : "1",
"type" : "Deal",
"description_title" : "New Deal for test",
"images" : "",
"start_date" : ISODate("2017-07-20T00:00:00.000+0000"),
"end_date" : ISODate("2017-10-30T11:59:00.000+0000"),
"status" : "1"
}
{
"_id" : "2",
"type" : "Event",
"description_title" : "Event1 test",
"images" : "",
"end_date" : ISODate("2017-10-20T00:00:00.000+0000")
"status" : "1"
}
{
"_id" : "3",
"type" : "Text",
"description_title" : "test",
"images" : "",
"status" : "1"
}
I have used below query, but it gives me all result,
db.demo.find({'$text' : {'$search' => 'test'},'$or' : {
{"type" : "Deal","end_date" : {'$gte' : ISODate("2017-09-14T11:59:00.000+0000") }},
{"type" : "Text"},
{"type" : "Event","end_date" : {'$gte' : ISODate("2017-09-14T11:59:00.000+0000") }},
}})
Above query return all records.
Please help me to achieve my result.
Related
I'm using mongoDb in my project, and I have problem using lookup on embedded data.. I searched for my problem and read similar codes.. but they didn't help my problem..
I mean in my embed document there is a variable named user that I want to load its data by lookup..
this is how my documents is:
"_id" : ObjectId("5d0f6a993702da22bc00474d"),
"quotes" : [
{
"amount" : NumberInt(100),
"user" : {
"_id" : ObjectId("5cc69f7f46ab4cedda5c3c12")
},
"details" : "some quote details",
"_id" : ObjectId("5d0f6a993702da22bc00474c"),
"status" : "a"
},
{
"amount" : NumberInt(120),
"user" : {
"_id" : ObjectId("5cc69kij46ab4cedda5c3c12")
},
"details" : "some quote details 2",
"_id" : ObjectId("5d0f6a993702da22bc00484k"),
"status" : "a"
}
],
"status" : "Approved",
"title" : "gardening",
"created_at" : NumberInt(1560841417)
so I want my output be like this:
"_id" : ObjectId("5d0f6a993702da22bc00474d"),
"quotes" : [
{
"amount" : NumberInt(100),
"user" : {
"_id" : ObjectId("5cc69f7f46ab4cedda5c3c12"),
"firstName": "John",
"lastNAme": "Doe",
"phone": 514298742
},
"details" : "some quote details",
"_id" : ObjectId("5d0f6a993702da22bc00474c"),
"status" : "a"
},
{
"amount" : NumberInt(120),
"user" : {
"_id" : ObjectId("5cc69kij46ab4cedda5c3c12")
"firstName": "Jane",
"lastNAme": "Doe",
"phone": 5148547642
},
"details" : "some quote details 2",
"_id" : ObjectId("5d0f6a993702da22bc00484k"),
"status" : "a"
}
],
"status" : "Approved",
"title" : "gardening",
"created_at" : NumberInt(1560841417)
I found the solution.. this worked for me..
.aggregate([
{
{
"$unwind": {
"path": "$quotes",
"preserveNullAndEmptyArrays": true
}
},
{
"$lookup": {
"from": "users",
"localField": "quotes.user._id",
"foreignField": "_id",
"as": "quotes.user",
}
},
{
"$unwind": {
"path": "$quotes.user",
"preserveNullAndEmptyArrays": true
}
},
{
"$group": {
"_id": null,
"quotes": {"$push": "$quotes"},
"status": {"$first": "$status"},
"title": {"$first": "$title"},
"created_at": {"$first": "$created_at"},
}
},
}
])
I posted my answer if anyone have the same issue.
Hey guys Im a student and my question might seem simple but i can't find the right answer anywhere. Please take a look. as you can see $parsed_json works fine with this code $parsed_json = $parsed_json['photos']; how do i add another key of the array there? i tried $parsed_json = $parsed_json[(['photos']['contactInfo'])]; but did now work. Any help will much appreciated. Thank you.
<?php
$json_string = file_get_contents("api/goes/here")
$parsed_json = json_decode($json_string, true);
print_r($parsed_json);
$parsed_json = $parsed_json[(['photos']['contactInfo'])];
foreach($parsed_json as $key => $value)
{
echo $value['typeName'] . '<br>';
echo $value['typeId'] . '<br>';
echo $value['familyName'] . '<br>';
// etc
?>
-------------JSON CONTENT------------------------------
{
"status" : 200,
"requestId" : "0ef05ee4-6bab-4488-a80c-04ce050ca074",
"likelihood" : 0.95,
"photos" : [ {
"type" : "linkedin",
"typeId" : "linkedin",
"typeName" : "LinkedIn",
"url" : "https://d2ojpxxtu63wzl.cloudfront.net/static/651f183b3a1bd463ef5298a2877f2c4f_0c027087db5cd03d244a7dd42e42fc969fa8d636bffd7635b46172c8a597aa73",
"isPrimary" : true
}, {
"type" : "twitter",
"typeId" : "twitter",
"typeName" : "Twitter",
"url" : "https://d2ojpxxtu63wzl.cloudfront.net/static/d0080f4ccd9ea21340b0fd994f82c0e0_2acdc7de41111f7d58e7544ed970b78e72f1739784417c146d5689d96ce79137"
} ],
"contactInfo" : {
"familyName" : "Cassini",
"fullName" : "Flavio Cassini",
"givenName" : "Flavio"
},
"organizations" : [ {
"name" : "DEVTECH .LLC",
"startDate" : "2015-03",
"title" : "President/Owner",
"current" : true
} ],
"demographics" : {
"locationDeduced" : {
"normalizedLocation" : "Boca Raton, United States",
"deducedLocation" : "Boca Raton, Florida, United States",
"city" : {
"name" : "Boca Raton"
},
"state" : {
"deduced" : true,
"name" : "Florida",
"code" : "FL"
},
"country" : {
"name" : "United States",
"code" : "US"
},
"continent" : {
"deduced" : true,
"name" : "North America"
},
"county" : {
"deduced" : true,
"name" : "Palm Beach"
},
"likelihood" : 1.0
},
"gender" : "Male",
"locationGeneral" : "Boca Raton, Florida, United States"
},
"socialProfiles" : [ {
"type" : "klout",
"typeId" : "klout",
"typeName" : "Klout",
"url" : "http://klout.com/DevTechServices",
"username" : "DevTechServices",
"id" : "91760869707035580"
}, {
"followers" : 67,
"following" : 67,
"type" : "linkedin",
"typeId" : "linkedin",
"typeName" : "LinkedIn",
"url" : "https://www.linkedin.com/in/devtechservices",
"username" : "devtechservices",
"id" : "428935547"
}, {
"bio" : "Student at Full Sail University",
"followers" : 5,
"following" : 36,
"type" : "twitter",
"typeId" : "twitter",
"typeName" : "Twitter",
"url" : "https://twitter.com/DevTechServices",
"username" : "DevTechServices",
"id" : "3245620291"
} ],
"digitalFootprint" : {
"scores" : [ {
"provider" : "klout",
"type" : "general",
"value" : 48
} ],
"topics" : [ {
"provider" : "klout",
"value" : "Bitcoin"
}, {
"provider" : "klout",
"value" : "Content Marketing"
}, {
"provider" : "klout",
"value" : "SAAS"
}, {
"provider" : "klout",
"value" : "Software"
}, {
"provider" : "klout",
"value" : "WordPress"
} ]
}
}
The short answer is that if $parsed_json represents an associative array of associative arrays, then it stands to reason that $parsed_json['photos'] is an associative array itself. To access the 'contactInfo' value inside it, you simply use $parsed_json['photos']['contactInfo'].
How to update members age whose name is TEST1 using yii2.?
Used below code to update , but i am specifying the indexes there , i want with out specifying the indexes.
User::updateAll([ '$set'=> ['Addresses.0.members.0.age'=>100] ],['IN','Addresses.members.name',['TEST1'] ]);
{
"_id" : ObjectId("595209b65312f48195fb2e01"),
"username" : "Test name",
"Addresses" : [
{
"address_no" : 1,
"Address" : "Test house",
"City" : "test city",
"State" : "Test state",
"Mobile" : "9999999",
"members" : [
{
"name" : "TEST1",
"age" : 35
},
{
"name" : "TEST2",
"age" : 30
},
]
},
{
"address_no" : 2,
"Address" : "2B, Test place",
"City" : "Test city",
"State" : "Test State",
"Pincode" : "12345",
"Phone" : "1234568789",
"Mobile" : 9999999999
}
],
"Beneficiaries" : [
{
"beneficiary_id" : 1,
"Name" : "Test1",
"Age" : "28",
"Sex" : "F"
}
],
"auth_key" : "esd8d89ds89ds89ds89ds",
}
there is position operator $ to do this kind of job
{
"Addresses.members.name" : "TEST2",
},
{
$set: {
"Addresses.$.members.0.age" : 40
}
}
Here I specified first index as it supports up to one level depth.
New feature might release in future to resolve this issue: https://jira.mongodb.org/browse/SERVER-831
Yii::$app->mongodb->getCollection('user')->update(['_id' => $id, 'members.name' => 'Test1'], ['$set' => [
'members.$.age' => 100,
]]);
when trying to "JOIN" operation with $lookup but results count is ok but "as" document is empty
I have two collections and i need to get user details from subscribercol with user_id in employer_jobscol
subscribercol
{
"_id" : ObjectId("58187e7551d244640626d7e1"),
"type" : "job_seeker",
"firstname" : "vishnu",
"lastname" : "kumar pv",
"email_array" : {
"primary" : "test#test.com",
"secondary" : "test#test.test",
"verified" : false
},
"address_array" : {
"address" : "test address22d",
"streetname" : "test222d",
"pincode" : "test222d",
"city" : "dddd",
"state" : "ALASKA2d",
"country" : "Argentinad"
},
"phone_array" : {
"primary" : "",
"secondary" : "",
"verified" : ""
},
"languages" : [
"english",
"malayalam",
"english2"
]
}
employer_jobscol
{
"_id" : ObjectId("582ada6b51d244073e2a7541"),
"employer_id" : ObjectId("58187e7551d244640626d7e1"),
"job_id" : "testjob16946",
"job_title" : "Test Job 25",
"category" : "IT",
"vacancies" : "5",
"salary" : "200000",
"location" : "Kollam",
"employer_name" : "test test",
"mobile" : "9123456987",
"video" : "",
"image" : "",
"work_place" : "option1",
"email" : "test#test.test",
"skills" : [
"php"
],
"isActive" : true,
"applied_users" : [
{
"user_id" : ObjectId("581b364751d2445c311cf6f1"),
"accepted" : false
},
{
"user_id" : ObjectId("58187e7551d244640626d7e1"),
"accepted" : false
}
]
}
my database query here, (executed with Robomongo )
db.getCollection('employer_jobscol').aggregate([ {
$unwind: "$applied_users"
},
{
$lookup:
{
from: "subscribercol",
localField: "user_id",
foreignField: "_id",
as: "subscribercol_docs"
}
}
])
Result is
{
"_id" : ObjectId("582ada6b51d244073e2a7541"),
"employer_id" : ObjectId("58187e7551d244640626d7e1"),
"job_id" : "testjob16946",
"job_title" : "Test Job 25",
"category" : "IT",
"vacancies" : "5",
"salary" : "200000",
"location" : "Kollam",
"employer_name" : "test test",
"mobile" : "9123456987",
"video" : "",
"image" : "",
"work_place" : "option1",
"email" : "test#test.test",
"skills" : [
"php"
],
"isActive" : true,
"applied_users" : {
"user_id" : ObjectId("58187e7551d244640626d7e1"),
"accepted" : false
},
"subscribercol_docs" : []
}
here subscribercol_docs is empty array i need user info (name, address etc..),
Because there is no user_id field in local document its "applied_users.user_id"
Try this
db.getCollection('employer_jobscol').aggregate([ {
$unwind: "$applied_users"
},
{
$lookup:
{
from: "subscribercol",
localField: "applied_users.user_id", // <-- check here
foreignField: "_id",
as: "subscribercol_docs"
}
}
])
How to search value in multidimensional array,
for example I want to search example keyword in the following data in mongodb
I used to fetch all data from command
>db.info.find()
{
"_id" : ObjectId("4f74737cc3a51043d26f4b90"),
"id" : "12345",
"info" : [
{
"sno" : 1,
"name" : "ABC",
"email" : "abc#example.com"
},
{
"sno" : 2,
"name" : "XYZ",
"email" : "xyz#example.com"
},
{
"sno" : 3,
"name" : "XYZ",
"email" : "xyz#demo.com"
},
{
"sno" : 4,
"name" : "ABC",
"email" : "abc#demo.com"
},
{
"sno" : 5,
"name" : "Rohan",
"email" : "rohan#example.com"
}
]
}
Now, to find data having example I used command
>db.info.find({"info.email":"example"})
and it gives
{
"_id" : ObjectId("4f74737cc3a51043d26f4b90"),
"id" : "12345",
"info" : [
{
"sno" : 1,
"name" : "ABC",
"email" : "abc#example.com"
},
{
"sno" : 2,
"name" : "XYZ",
"email" : "xyz#example.com"
},
{
"sno" : 3,
"name" : "XYZ",
"email" : "xyz#demo.com"
},
{
"sno" : 4,
"name" : "ABC",
"email" : "abc#demo.com"
},
{
"sno" : 5,
"name" : "Rohan",
"email" : "rohan#example.com"
}
]
}
But I want only 3 out of 5 sub rows like
{
"_id" : ObjectId("4f74737cc3a51043d26f4b90"),
"id" : "12345",
"info" : [
{
"sno" : 1,
"name" : "ABC",
"email" : "abc#example.com"
},
{
"sno" : 2,
"name" : "XYZ",
"email" : "xyz#example.com"
},
{
"sno" : 5,
"name" : "Rohan",
"email" : "rohan#example.com"
}
]
}
Rohan, MongoDB always returns the whole document that you are searching on. You can't just make it return the array elements in which your keyword was found. If you want to do that, then you need to make sure all all embedded documents in the "info" field are in their own collection. And that might mean that you need to link them back to the original document in your "info" collection. Perhaps something like:
{
"sno" : 1,
"name" : "ABC",
"email" : "abc#example.com"
"info_id" : "12345",
},
Alternatively, you can of course do post-processing in PHP to obtain only the rows that you want.
Perhaps this is a good idea?
http://php.net/manual/en/class.mongoregex.php
I tried Map Reduce Function and it works on this type of problems the code is something like that:
Write a map function
map=function ()
{
filter = [];
this.info.forEach(function (s) {if (/example/.test(s.email)) {filter.push(s);}});
emit(this._id, {info:filter});
}
Write a reduce function
reduce=function(key, values) { return values;}
MapReduce Function
res=db.info.mapReduce(map,reduce,{out:{inline:1}})
And The Output look likes:
"results" : [
{
"_id" : ObjectId("4f9a2de0ea4a65c3ab85a9d3"),
"value" : {
"info" : [
{
"sno" : 1,
"name" : "ABC",
"email" : "abc#example.com"
},
{
"sno" : 2,
"name" : "XYZ",
"email" : "xyz#example.com"
},
{
"sno" : 5,
"name" : "Rohan",
"email" : "rohan#example.com"
}
]
}
}
],
"timeMillis" : 1,
"counts" : {
"input" : 3,
"emit" : 3,
"reduce" : 0,
"output" : 3
},
"ok" : 1,
Now you can find your search data from
printjson(res.results)
Did you try $ (projection)?
db.info.find({"info.email":"example"}, {"info.email.$":1})
document