I'm trying to replace the first 4 digits of a number with X, for example:
$num= 1234567890
I want the output to appear like this: XXXX567890
I have tried the function:
$new = substr($num, 0, -4) . 'xxx';
but It only removes the last 4 digits so what should I do ?
You can use the same in opposite
$num= 1234567890;
$new = 'xxxx' . substr($num, 4);
echo $new;
second parameter tells about starting point for string and parity(positive or negative) tells about direction. positive number means to right of string and negative number means to left of string.
http://php.net/manual/en/function.substr.php
With substr_replace function:
$num = 1234567890;
print_r(substr_replace($num, 'XXXX', 0, 4)); // XXXX567890
Another solution is to use str_pad which "fills up" the string to 10 elements with "X".
$num= 1234567890;
Echo str_pad(substr($num,4), 10, "X",STR_PAD_LEFT);
https://3v4l.org/tKtB7
Or if the string lenght is not always 10 use:
Echo str_pad(substr($num,4), strlen($num), "X",STR_PAD_LEFT);
I think this one can be helpful for achieving desired output.
Solution 1:
Try this code snippet here
<?php
ini_set('display_errors', 1);
$num= 1234567890;
echo "XXXX".substr($num, 4);//concatenating 4 X and with the substring
Solution 2: Try this code snippet here
<?php
ini_set('display_errors', 1);
$num= 1234567890;
$totalDigits=4;
echo str_repeat("X", $totalDigits).substr($num, $totalDigits);// here we are using str_repeat to repeat a substring no. of times
Output: XXXX567890
If have written a tiny function to do tasks like this.
function hide_details($str, $num = 4, $replace = 'x') {
return str_repeat($replace, $num).substr($str, $num);
}
echo hide_details('1234567890');
Related
How can I get the first and the last digit of a number? For example 2468, I want to get the number 28. I am able to get the ones in the middle (46) but I can't do the same for the first and last digit.
For the digits in the middle I can do it
$substrmid = substr ($sum,1,-1); //my $sum is 2468
echo $substrmid;
Thank you in advance.
You can get first and last character from string as below:-
$sum = (string)2468; // type casting int to string
echo $sum[0]; // 2
echo $sum[strlen($sum)-1]; // 8
OR
$arr = str_split(2468); // convert string to an array
echo reset($arr); // 2
echo end($arr); // 8
Best way is to use substr described by Mark Baker in his comment,
$sum = 2468; // No need of type casting
echo substr($sum, 0, 1); // 2
echo substr($sum, -1); // 8
You can use substr like this:
<?php
$a = 2468;
echo substr($a, 0, 1).substr($a,-1);
You can also use something like this (without casting).
$num = 2468;
$lastDigit = abs($num % 10); // 8
However, this solution doesn't work for decimal numbers, but if you know that you'll be working with nothing else than integers, it'll work.
The abs bit is there to cover the case of negative integers.
$num = (string)123;
$first = reset($num);
$last = end($num);
I have variables of bitcoin values all rounded to 8 decimal places. eg
1.00645600
I need a way in jQuery or php to get the whole number [1], The decimal values [006456], and trailing zeros [00]. I have already tried php substr but it messed up with the results since im dealing with variables.
Simple and general solution in PHP without involving regular expressions (that is an option also):
$number = '1.00645600';
$flooredNumber = floor($number); // 1
$decimalPart = (string) (floatval($number) - $flooredNumber); // 0.006456
$decimals = str_replace('0.', '', $decimalPart); // 006456
$trailingZeros = str_replace(rtrim($number, '0'), '', $number); // 00
substr
Returns the portion of string specified by the start and length parameters.
http://php.net/manual/en/function.substr.php
If the numbers in your string are always in the same position you can use substr() to get the desired values:
$str = '1.00645600';
echo substr($str, 0, 1)."\r\n";
echo substr($str, 2, 2)."\r\n";
echo substr($str, 2, 6)."\r\n";
Output:
1
00
006456
Perhaps, this way?
<?php
$i = '1.00645600';
echo rtrim(rtrim($i, '0'), '.');
?>
This is a tricky one: I want to add +1 to this number: 012345675901 and the expected result is: 012345675902. Instead I get: 2739134 when I do this:
echo (012345675901+1);
When I try:
echo ('012345675901'+1);
I get this: 12345675902 which is pretty close to what I need, but it removes the leading zero.
When I do this:
echo (int) 012345675901;
I get 2739133. I also tried bcadd() without success:
echo bcadd(012345675901, 1);
which resulted in 2739134.
I know I am missing something here. I would really appreciate your help!
UPDATE 1
Answer 1 says that the number is octal:
function is_octal($x) {
return decoct(octdec($x)) == $x;
}
$number = is_octal(012345675901);
echo var_dump($number);
The above returns false. I thought I needed to convert this from octal to a normal string but didn't work. I can't avoid not using the above number - I just need to increment it by one.
EDIT 2
This is the correct code:
$str = '012345675901';
$str1 = ltrim($str, '0'); // to remove the leading zero
$str2 = bcadd($str1, 1); // +1 to your result
$str3 = strlen($str); // get the length of your first number
echo str_pad($str2, $str3, '0', STR_PAD_LEFT); // apply zeros
Thank you everyone for your help! The above code produces: 012345675902 as expected
The leading 0 is treating your number as octal.
The leading 0 you need for output as a string, is a purely a representation.
please see the code for explanation.
$str = "012345675901"; // your number
$str1 = ltrim($str, '0'); // to remove the leading zero
$str2 = bcadd($str1, 1); // +1 to your result
$str3 = strlen($str); // get the length of your first number
echo str_pad($str2, $str3, '0', STR_PAD_LEFT); // apply zeros
What would be an elegant way of doing this?
I have this -> "MC0001" This is the input. It always begins with "MC"
The output I'd be aiming with this input is "MC0002".
So I've created a function that's supposed to return "1" after removing "MC000". I'm going to convert this into an integer later on so I could generate "MC0002" which could go up to "MC9999". To do that, I figured I'd need to loop through the string and count the zeros and so on but I think I'd be making a mess that way.
Anybody has a better idea?
This should do the trick:
<?php
$string = 'MC0001';
// extract the part succeeding 'MC':
$number_part = substr($string, 2);
// count the digits for later:
$number_digits = strlen($number_part);
// turn it into a number:
$number = (int) $number_part;
// make the next sequence:
$next = 'MC' . str_pad($number + 1, $number_digits, '0', STR_PAD_LEFT);
using filter_var might be the best solution.
echo filter_var("MC0001", FILTER_SANITIZE_NUMBER_INT)."\n";
echo filter_var("MC9999", FILTER_SANITIZE_NUMBER_INT);
will give you
0001
9999
These can be cast to int or just used as they are, as PHP will auto-convert anyway if you use them as numbers.
just use ltrim to remove any leading chars: http://php.net/manual/en/function.trim.php
$str = ltrim($str, 'MC0');
$num = intval($str);
<php
// original number to integer
sscanf( $your_string, 'MC%d', $your_number );
// pad increment to string later on
sprintf( 'MC%04u', $your_number + 1 );
Not sure if there is a better way of parsing a string as an integer when there are leading zero's.
I'd suggest doing the following:
1. Loop through the string ( beginning at location 2 since you don't need the MC part )
2. If you find a number thats bigger than 0, stop, get the substring using your current location and the length of the string minus your current location. Cast to integer, return value.
You can remove the "MC" par by doing a substring operating on the string.
$a = "MC0001";
$a = substr($a, 2); //Lengths of "MC"
$number = intval($a); //1
return intval(str_replace($input, 'MC', ''), 10);
It will actually be a decimal but that is not the main point. I will have a set of numbers like:
8976
8765
3454
3453
10198
What I am wanting to do is add a decimal 2 places from the right. So the first would be 89.76 and so forth.
Can't you just multiply each by 0.01?
$formatted = number_format($unformatted_number / 100, 2, '.', '');
2 - decimal places
'.' - decimal separator
'' - thousands separator
docs for the function are here.
try this
$number = 8976;
$number = (float)$number/100;
results:
89.76
You may have to do some checking to see how many digits the number is, i.e 89768 would be devided by 1000 and so on.
Comments are available,
//the string you need to split
$string = "123456";
// read from right 2 character
$rightNums = substr($string, -2, 2);
// maximum 100 character to the left defined now
$otherNums = substr($string, -4, 100);
// pront them just with . between
echo $otherNums.".".$rightNums; ?>
hope it help much.
Try with this
$tmpString = substr("8976", 0, -2);
$finalString = str_replace($tmpString, "." . $tmpString, "8976");
echo $finalString;