Laravel make directory fails with storage_path - php

Question

Am using faker an i would like to generate images and save them but am getting an error
mkdir(): No such file or directory
So i have
$factory->define(App\User::class, function (Faker $faker) {
$filepath = storage_path('images/fakerusr/'); //this fails
if(!File::exists($filepath)){
File::makeDirectory($filepath);
};
return [
'profile_pic' => $faker->image($filepath,400,300)
];
});
BUt when i use
$filepath = public_path('images/fakerusr/'); //this works
But the path saved in the db starts from ./var/www... but i would like the path from images in the public folder.
I have added both read and write permissions to public folder
sudo chmod a+rw -R /var/www.../public
How do i go about this.

Answer 1

Ensure the images and child directory fakerusr already exists. By default the unix command mkdir requires the -p flag to "Create intermediate directories as required" and the PHP function mkdir also requires the 3rd parameter to be true to create nested directories . File::makeDirectory probably works this way too.

Answer 2

$filepath = storage_path('images/fakerusr/'); //this fails
if(!File::exists($filepath)){
File::makeDirectory($filepath, 0755, true, true);
};

Answer 3

you can check using Storage::has
$directory='images/fakerusr';
if (!Storage::has($directory)) {
$resp= Storage::makeDirectory($directory);
dd($resp);
} else{
echo "already exist";
};
Also note that directory will be created inside storage\app\ .And make sure you have 755 permission to these folders
if you want to create directory inside public folder
$directory='images/fakerusr';
if (File::isDirectory($directory)) {
echo "already exist";
} else{
$result = File::makeDirectory($directory, 0775, true);
}

Answer 4

For Check Directory Exists or Not And making the Directory as Public, I am using..
use Illuminate\Http\File;
$path = public_path('upload/imgaes');
if(!File::isDirectory($path)){
File::makeDirectory($path, 0777, true, true);
}
Hope this work