Am trying to figure out how does one make myimage.jpg part of the trail end point of an hyperlink?
So far I have got the image to download but not sure how to make the hyperlink look like:
http://192.168.0.11/myimage.jpg
My code so far:
<?php
$file = "./my_image.jpg";
if (file_exists($file)) {
header('Content-Description: File Transfer');
header('Content-Type: application/octet-stream');
header('Content-Disposition: attachment; filename="'.basename($file).'"');
header('Expires: 0');
header('Cache-Control: must-revalidate');
header('Pragma: public');
header('Content-Length: ' . filesize($file));
readfile($file);
exit;
}
?>
You can use echo to print your $file variable at the end of your link.
Like this,
<a href="//192.168.0.11/<?php echo $file; ?>">
This will create the link look this in HTML,
<a href="//192.168.0.11/myimage.jpg">
Related
I have in my index.php a link like this:
Download
I need that when you click that link the download dialong opens to save the foto with a specific name like myfile123.jpg.
In my download.php I have this:
header('Content-type:image/jpeg');
$handle = fopen($_GET['url'], "rb");
while (!feof($handle)) {
echo fread($handle, 8192);
}
fclose($handle);
And while it retrieves the image, it just opens it in the same tab (instead of forcing the dialog).
Take a look on the PHP readfile example
Example from php.net:
header('Content-Description: File Transfer');
header('Content-Type: application/octet-stream');
header('Content-Disposition: attachment; filename="'.basename($file).'"');
header('Expires: 0');
header('Cache-Control: must-revalidate');
header('Pragma: public');
header('Content-Length: ' . filesize($file));
readfile($file);
You need to add another header, in order to trigger the download, like:
header('Content-Disposition: attachment; filename="image.jpg"');
More info about the Content-Disposition header, here: https://developer.mozilla.org/es/docs/Web/HTTP/Headers/Content-Disposition
I am using the following code, to access a file which exists
$file = 'monkey.gif';
if (file_exists($file)) {
header('Content-Description: File Transfer');
header('Content-Type: application/octet-stream');
header('Content-Disposition: attachment; filename='.basename($file));
header('Expires: 0');
header('Cache-Control: must-revalidate');
header('Pragma: public');
header('Content-Length: ' . filesize($file));
readfile($file);
exit;
}
It downloads fine, but when opening the image viewer is refusing to open stating its not a gif file. Is
I think you should change the Content-Type to 'image/gif'
I found that there was a print elsewhere in the code so when it was forcing the download it was corrupted. Removing the print worked.
I am downloading file with simple code from my server which is like
<a download class="btn btn-warning" target="_blank" href="<?php echo base_url('attachments/' . $row->delivery . '') ?>">Download</a>
There is some security issue in this like if anyone write sitename/attachments/filename the file is automatically download. What I want is it will be like sitename/attachments/filename/ciphertext(embadedtext) so it will hard to break the code. what should I do to implement that in php.
You can put your files out of the server DocumentRoot then use something like this:
<?php
$file = 'monkey.gif';
if (file_exists($file)) {
header('Content-Description: File Transfer');
header('Content-Type: application/octet-stream');
header('Content-Disposition: attachment; filename='.basename($file));
header('Content-Transfer-Encoding: binary');
header('Expires: 0');
header('Cache-Control: must-revalidate, post-check=0, pre-check=0');
header('Pragma: public');
header('Content-Length: ' . filesize($file));
ob_clean();
flush();
readfile($file);
exit;
}
?>
I have the following code for creating thumbnails of the images in the database automatically when the are uploaded.
<?php
include('config.php');
$result = mysql_query("SELECT * FROM photos where caption='cars'");
while($row = mysql_fetch_array($result))
{
echo '<div id="imagelist">';
echo '<p><img src="'.$row['location'].'"></p>';
echo '</div>';
}
?>
Now whenever I click an image in the gallery I want it to open the image in a new tab and give me an option to download, I want the download code which will take in the photo id from the database and then give me the option to download that image only how to do it.
Try this :
$file = your file
header('Content-Description: File Transfer');
header('Content-Type: application/octet-stream');
header('Content-Disposition: attachment; filename='.basename($file));
header('Content-Transfer-Encoding: binary');
header('Expires: 0');
header('Cache-Control: must-revalidate, post-check=0, pre-check=0');
header('Pragma: public');
header('Content-Length: ' . filesize($file));
ob_clean();
flush();
readfile($file);
exit;
mysql_* functions are deprecated in new version of php, So use mysqli_* functions OR PDO
I try to use php to force the image jpg file download, I have implemented eth following code:
html
<a href = "filedownload.php?src=uploads/myimage.jpg&download=true>download this file</a>
download.php
<?php
ob_start();
include_once 'functions.php';
if (isset($_GET['download']) && $_GET['download'] == 'true')
{
$src = sanitizeString($_GET['src']);
header('Content-Description: File Transfer');
header('Content-Type: image/jpeg');
header('Content-Disposition: attachment; filename='.basename($src));
header('Content-Transfer-Encoding: binary');
header('Expires: 0');
header('Cache-Control: public');
header('Pragma: public');
}
?>
Suppose the full path of the image is "www.example.com/smith/topic/uploads/myimage.jpg", I have recieved the right image name and the download window is appeared as well, but the image is corrupt and with 1KB size, any one could tell me why, thanks a lot.
Here you are example how to use readfile function
<?php
$file = 'monkey.gif';
if (file_exists($file)) {
header('Content-Description: File Transfer');
header('Content-Type: application/octet-stream');
header('Content-Disposition: attachment; filename='.basename($file));
header('Content-Transfer-Encoding: binary');
header('Expires: 0');
header('Cache-Control: must-revalidate, post-check=0, pre-check=0');
header('Pragma: public');
header('Content-Length: ' . filesize($file));
ob_clean();
flush();
readfile($file);
exit;
}
?>
You need some code that actually sends over the file. See e.g. readfile or fpassthru
Try to use:
header("Content-Disposition: attachment; filename=\"".basename($fullPath)."\";" );