I'm writing an if statement in which a button needs to show if the cart is empty.
For this button I need to get the form key of the product for the data-url
So something like this:
Order
As mentioned above I need to wrap this button in an if statement, so something like this:
<?php
$_helper = Mage::helper('checkout/cart');
if (1 > $_helper->getItemsCount()){
echo 'Order';
}
else{
'<p>hello</p>';
}
?>
But obviously I can't have php echo within echo. Can anybody point me in the right direction of how to do this?
You don't put PHP inside HTML inside PHP. Since you're already in the context of PHP code, just concatenate the values you want to the output:
echo 'Order';
The resulting output is always just a string. You can simply build that string with whatever values you have.
You can just use string concatenation:
echo '<a href="#" data-url=".../' . Mage::getSingleton(...) . '"' ...
Simply don't open PHP up again. You can terminate the HTML interpretation inside an echo.
Your code should look like this:
<?php
$_helper = Mage::helper('checkout/cart');
if (1 > $_helper->getItemsCount()) {
echo 'Order';
}
else {
'<p>hello</p>';
}
?>
Related
I'm trying to use a PHP variable to add a href value for a link in an echo statement.
Here's a simplified version of the code I want to use. I know that I can't just add the variable into the echo statement, but I can't seem to find an example anywhere that works.
$link_address = '#';
echo 'Link';
Try like
HTML in PHP :
echo "<a href='".$link_address."'>Link</a>";
Or even you can try like
echo "<a href='$link_address'>Link</a>";
Or you can use PHP in HTML like
PHP in HTML :
Link
you can either use
echo 'Link';
or
echo "Link';
if you use double quotes you can insert the variable into the string and it will be parsed.
Basically like this,
<?php
$link = ""; // Link goes here!
print "Link";
?>
as simple as that: echo 'Link';
You can use one and more echo statement inside href
Link
link : "/profile.php?usr=firstname&email=email"
This worked much better in my case.
HTML in PHP: Link
The safest way to generate links in PHP is to use the built-in function http_build_query(). This function is very easy to use and takes an array as an argument.
To create a dynamic link simply echo out the result of http_build_query() like so:
$data = [
'id' => $id,
'name' => $name
];
echo 'Link';
If you want to print in the tabular form with, then you can use this:
echo "<tr> <td><h3> ".$cat['id']."</h3></td><td><h3> ".$cat['title']."<h3></</td><td> <h3>".$cat['desc']."</h3></td><td><h3> ".$cat['process']."%"."<a href='taskUpdate.php' >Update</a>"."</h3></td></tr>" ;
Here's the problem, I am trying to echo a statement or an array after dynamically generated HTML, and unfortunately the thing that i want to echo goes above the HTML, is there any way to echo it after that dynamic HTML or work around?
Code:
Link 1
Link 2
if(isset($_GET["id"]) && $_GET["id"] == "do_something") {
$html = "dynamic html generate";
echo $html;
//after this im using foreach
foreach($array as $item) { echo $item . "<br />"; }
}
As I click one of these two , dynamically generated HTML shows up. Now for example I have an array:
$array = array("error1", "error2");
All the generated PHP goes above the dynamic HTML :/.
How should i fix it so that i can echo all of this array below the dynamic HTML?
Thanks
Use buffering with ob_start
ob_start();
// dynamic html code generate
$dynamic_html = ob_get_clean();
echo $dynamic_html;
// your code
echo $dynamic_html;
Sounds like you missed some closing tags (most likely </table>) in the dynamic html. Thats why the later generated echo gets displayed at the top.
Example (Note the missing closing table):
<?php
echo "<table><tr><td>TableText</td></tr>";
echo "I should be bellow the table, but going to the top.";
?>
will produce:
I should be bellow the table, but going to the top.
TableText
I wrote a php page which has two php tags and one script tag inside it .
<?php
$value = $_GET['hash'];
?>
<script>
function execute(){
<?php
$readfile = file($value);
for ($k=0;$k<=count($readfile)-1;$k++){
$cmd = $readfile[$k];
echo $cmd;}
?>
}
</script>
I want to use $value inside another php tag ( like above it has the file I want to open ), but I am not able to do it.Is the scope of variable limited to one php tag ? if yes how can I solve this problem Please help
Your code works perfectly. The variables in one PHP tag is accessible from all other tags, unless you define them inside a PHP function.
The reason you are not seeing the echo on the screen is because the echo prints to the Javascript function.
If you view the source of the generated page, the file contents will be there.
Try this:
function execute(){
<?php
$readfile = file($value);
for ($k=0;$k<=count($readfile)-1;$k++){
$cmd = $readfile[$k];
?>
alert( <?php echo $cmd; ?> );
<?php
}
?>
}
execute();
if $value is a get then you don't need to access it as a file, it should just be a short string.
just above line 7 (the one with $readfile = file...
type:
echo "alert(The hash value is: ".$value.")";
This will make an alert display (as it is in a script tag)
p.s you should have in your opening tag
I haven't found anytihng in Google or the PHP manual, believe it or not. I would've thought there would be a string operation for something like this, maybe there is and I'm just uber blind today...
I have a php page, and when the button gets clicked, I would like to change a string of text on that page with something else.
So I was wondering if I could set the id="" attrib of the <p> to id="something" and then in my php code do something like this:
<?php
$something = "this will replace existing text in the something paragraph...";
?>
Can somebody please point me in the right direction? As the above did not work.
Thank you :)
UPDATE
I was able to get it working using the following sample:
Place this code above the <html> tag:
<?php
$existing = "default message here";
$something = "message displayed if form filled out.";
$ne = $_REQUEST["name"];
if ($ne == null) {
$output = $existing;
} else {
$output = $something;
}
?>
And place the following where ever your message is to be displayed:
<?php echo $output ?>
As far as I can get from your very fuzzy question, usually you don't need string manipulation if you have source data - you just substitute one data with another, this way:
<?php
$existing = "existing text";
$something = "this will replace existing text in the something paragraph...";
if (empty($_GET['button'])) {
$output = $existing;
} else {
$output = $something;
}
?>
<html>
<and stuff>
<p><?php echo $output ?></p>
</html>
but why not to ask a question bringing a real example of what you need? instead of foggy explanations in terms you aren't good with?
If you want to change the content of the paragraph without reloading the page you will need to use JavaScript. Give the paragraph an id.<p id='something'>Some text here</p> and then use innerHTML to replace it's contents. document.getElementById('something').innerHTML='Some new text'.
If you are reloading the page then you can use PHP. One way would be to put a marker in the HTML and then use str_replace() to insert the new text. eg <p><!-- marker --></p> in the HTML and $html_string = str_replace('<!-- marker -->', 'New Text', $html_string) assuming $html_string contains the HTML to output.
If you are looking for string manipulation and conversion you can simply use the str_replace function in php.
Please check this: str_replace()
If you're using a form (which I'm assuming you do) just check if the variable is set (check the $_POST array) and use a conditional statement. If the condition is false then display the default text, otherwise display something else.
can anybody help me here please?
I am using AJAX for pagination in my application. So I am generating hyperlinks with for loop. as follow:
for($t=1; $t<=$hf; $t++)
{
if($t == $_GET['pageno'])
{
echo $t." ";
}
else
{
echo "<a id ='$t' href='javascript:void(0)' onclick='open_page('ajaxinfo.php','content'); javascript:change('$t');'>$t</a>"." ";
}
}
Above echo statement does not give call to function. But instead of this when i just write html hyperlink it works fine and I get to see page2.html, my HTML code is:
<a id="page2" href="javascript:void(0)" onclick="open_page('ajaxinfo.php','content'); javascript:change('page2');">page2</a>
I don't understand why this is so? But is there any problem in echo's quotes.
Please Help.
that because you have syntax error while building anchors. Try to use double quotes for tag attributes and escape them with backslash.
So, your ECHO should look like this:
echo "<a id =\"{$t}\" href=\"javascript:void(0)\" onclick=\"open_page('ajaxinfo.php','content'); javascript:change('{$t}');\">{$t}</a> ";
You have to have code to add the contents returned by the ajax to the page. I don't see that anywhere.