Match multiple results single line php regex - php

Question

I would like to match multiple results on a single line string but I am only able to get the last iteration on the result I excpected.
For example I have this string : <ul><li>test1</li><li>test2</li>test3</li></ul>
I would like to get :
test1
test2
test3
As result but I only get "test3"
I used this regex <ul>(<li><a.*>(.*)<\/a><\/li>)*<\/ul> on : https://regex101.com/ but I don't know what I did wrong.

Answer 1

Use a parser instead:
<?php
$html = <<<DATA
<ul>
<li>test1</li>
<li>test2</li>
<li>test3</li>
</ul>
DATA;
$dom = new DOMDocument;
$dom->loadHTML($html, LIBXML_HTML_NOIMPLIED | LIBXML_HTML_NODEFDTD);
$xpath = new DomXPath($dom);
$links = $xpath->query("//li/a");
foreach ($links as $link) {
echo $link->textContent;
}
?>
This sets up the DOM and uses an xpath expression to get the element(s).

Answer 2

Try like this:
(?<=(<a href="#">))([\s\S]| |w\[0-9]| )+?(?=(<\/a>))
or
(?<=(">))([\s\S]| |w\[0-9]| )+?(?=(<\/a>))
or
(?<=(<a href="#">))(.)+?(?=(<\/a>))
link with example:
https://regex101.com/r/MHnxxh/1
or
https://regex101.com/r/MHnxxh/2
<?php
$str = '
<ul>
<li>test1</li>
<li>test2</li>
<li>test3</li>
</ul>
';
preg_match_all('/(?<=(#">))([\s\S]| |w\[0-9]| )+?(?=(<\/a>))/', $str, $matches);
// display array if need
echo "<pre>";
print_r($matches);
// display list
foreach ($matches[0] as $key => $value) {
echo $value ."\r\n";
}
?>

Answer 3

preg_match_all("\#\"\>[a-z]\w+\<\/\a\>,
$out, PREG_PATTERN_ORDER)
this the regex pattern....try this
("#\">[a-z]\w+\</\a>)
this will extract only all text strings....

Answer 4

you cane use of preg_replace
$test = '<ul><li>test1</li><li>test2</li>test3</li></ul>';
echo preg_replace('/<[^>]*>/', ' ', $test);