Save data into two tables at same time in laravel - php

Question

I am trying to save datas into two different tables depends on selection(x-editable). Here is my code and Help me by pointing where i am doing mistake.
Result i am looking for: I change payment status pending to paid in TBL:Product, paid values also change 0 to 1 in TBL:Product_payment
TBL:Product
- product_id
- client_id
...
- status {paid/pending}
TBL:Product_payment
- product_id
- payment_id
....
- paid {1/0}
Controller:
public function update()
{
$inputs = Input::all();
if ($row = Product::with('payments')->find($inputs['pk']))
{
$row->$inputs['name'] = $inputs['value'];
if($row['status'] == 'paid') {
$row['paid'] = 1;
}
$row->save();
return $row;
}
Product.php(model)
class Product extends Eloquent
{
protected $primaryKey = 'product_id';
protected $table = 'products';
protected $fillable = array('client_id', 'date', 'amount', 'status', 'notes');
public function payments()
{
return $this->hasMany('ProductPayment');
}
}
ProductPayment.php(model)
class ProductPayment extends Eloquent
{
public $table = 'product_payments';
protected $primaryKey = 'product_payment_id';
protected $fillable = array('product_id', 'client_id', 'payment_method', 'amount_paid', 'paid');
public function product()
{
return $this->belongsTo('Products');
}
public function clients()
{
return $this->belongsTo('Clients');
}
}

Answer 1

Add a model event listener to boot in your AppServiceProvider for whenever an instance of Product is saved.
Product::saved(function ($product) {
$paymentStatus = [
'pending' => 0,
'paid' => 1,
];
if(array_key_exists($product->status, $paymentStatus))
{
ProductPayment::where('product_id', $product->id)
->update(['paid' => $paymentStatus[$product->status]]);
}
});