While fetch row in PHP - php

Question

I have that
<?php
$new=get_records("tbl_item","status=1 AND idshop='{$idshop}' AND special","id DESC", $startRow.",".$pageSize, " ");
$dem=1;
while($row_new=mysql_fetch_assoc($new)){
?>
<div class=""row>
<div class="col-3">
</div>
</div>
<?php } ?>
I want when this code run, it'll display 1 row with 4 col-3 until the end of the loop.
I want output like this
<div class=""row>
<div class="col-3">
</div>
<div class="col-3">
</div>
<div class="col-3">
</div>
<div class="col-3">
</div>
</div>
<div class=""row>
<div class="col-3">
</div>
<div class="col-3">
</div>
<div class="col-3">
</div>
<div class="col-3">
</div>
</div>
Please help me! Thanks all!

Answer 1

This should work:
<?php
$new=get_records("tbl_item","status=1 AND idshop='{$idshop}' AND special","id DESC", $startRow.",".$pageSize, " ");
$i=0;
while($row_new=mysql_fetch_assoc($new)){
if($i % 4 == 0) {
?>
<div class="row">
<?php
}
?>
<div class="col-3">
</div>
<?php
if($i % 4 == 3) {
?>
</div>
<?php
}
?>
<?php
$i++;
}
$i--;
if ($i % 4 != 3) {
?>
</div>
<?php
}
?>
The last if is in case the total number of records weren't a multiple of 4, then we need to close the div tag.
And, not to mention, you should definitely use MySQLi. Why should I use MySQLi?

Answer 2

try this bro:
update, if count rows less then 4:
$new = get_records("tbl_item", "status=1 AND idshop='{$idshop}' AND special", "id DESC", $startRow . "," . $pageSize, " ");
$dem = 1;
$x = 0;
$count = count($new);
while ($row_new = mysql_fetch_assoc($new)) {
$x++;
if ($x==1 || $x % 4 == 1) { ?>
<div class="row">
<?php } ?>
<div class="col-3">
<?= "x: $x" ?>
</div>
<?php if ($x % 4 == 0 || $x == $count) { ?>
</div>
<?php
}
}

Answer 3

Try this:
<?php
$new=get_records("tbl_item","status=1 AND idshop='{$idshop}' AND special","id DESC", $startRow.",".$pageSize, " ");
$dem=1;
while($row_new=mysql_fetch_assoc($new)){
?>
<div class="row">
<?php for($i = 1; $i <= 4; $i++){?>
<div class="col-3">
</div>
<?php } ?>
</div>
<?php } ?>