PHP Find two consecutive numeric entries in array - php

Question

My problem is it just replicates the number twice, though it does add the break when there is a number, but I'm trying to check if there is a number after the number, so it would say line 12 is.....
Thanks for any help
<?PHP
$lines = file_get_contents('http://www.webstitcher.com/test.txt');
$tag = str_split($lines); // puts all lines into a array
foreach ($tag as $num => $letta){
if (is_numeric($letta) == TRUE){
$num2 = $num++;
if (is_numeric($tag[$num2])){ // checks if next line is going to be another digit
$letta .= $tag[$num2];
unset($tag[$num2]); // removes line if it had another digit and adds to ouput
}
echo '<br />' . $letta;
}
else {
echo $letta;
}
}
?>

Answer 1

Try exploding the string using ' ' as the delimiter. This will allow you to keep the numbers whole and will ultimately help cut out a lot of the complexity.
$lines = file_get_contents('http://www.webstitcher.com/test.txt');
$tag = explode(' ', $lines); // puts all words into a array
foreach ($tag as $word){
if (is_numeric($word)) {
// if the word is numeric, simply skip to next line
// if you need to keep the number, add $word to the echo statement
echo '<br />';
}
else {
echo ' '.$word;
}
}
This way you don't have to keep track of the previous element in the array or check for the next element.
Alternatively, you could also use preg_replace which would remove the need for the loop entirely.
$lines = preg_replace('/[0-9]+/', '<br>', $words);