SELECT from MYSQL with INNER JOIN on multiples of the same ID - php

Question

So im just wondering if the next is possible and if so how to approach this.
I created an INNER JOIN query to SELECT multiple ID's from on a table where it is equal to the ID value from another table.
Product table
product_id | cults_id1 | cults_id2 | cults_id3
-----------------------------------------------------
1 | 5 | 4 | 2
2 | 3 | 0 | 0
Cultivar table
cults_id | cults_name |
---------------------------
1 | berries |
2 | fruit |
3 | choc |
4 | wood |
5 | mysql! |
So i created an join where it will fetch all the cults_name based on the product tables cults_id1, cults_id2, cults_id3
Result:
Product_id(1) = mysql! , wood , fruit
Now the problem comes with the next one how can i display the one value that product_id(2) contains.
So it would result in looking like this:
Product_id(1) = mysql! , wood , fruit
Product_id(2) = choc
At this moment product_id(2) wont display in my listing because it has no resemble to the Cultivar table after the first ID, (using this query).
I know normalisation should be considered.
Query
SELECT p.product_image_path, p.product_id, p.brand_name, p.product_name, b.botttle_size, v.vintage,
t.wine_type_blend, p.price, p.quantity, p.time_created, p.reference_number, p.shipping_cost,
c1.cultivar_type as cultivar_type1, c2.cultivar_type as cultivar_type2,
c3.cultivar_type as cultivar_type3, c4.cultivar_type as cultivar_type4
FROM product p
INNER JOIN wine_bottle b ON b.bottle_id = p.bottle_id
INNER JOIN wine_vintage v ON v.vintage_id = p.vintage_id
INNER JOIN wine_type t ON t.type_id = p.type_id
INNER JOIN wine_cultivar c1 ON c1.cultivar_id = p.cultivar_1_id
INNER JOIN wine_cultivar c2 ON c2.cultivar_id = p.cultivar_2_id
INNER JOIN wine_cultivar c3 ON c3.cultivar_id = p.cultivar_3_id
INNER JOIN wine_cultivar c4 ON c4.cultivar_id = p.cultivar_4_id
Now my product listing page has this to display it in listing but i want to display even if cults_id1, cults_id2, cults_id3 has an value of 0.
Product-listing.php
<?php
if($result = mysqli_query($conn, $query)){
if(mysqli_num_rows($result) > 0){
$i = 0;
while($row = mysqli_fetch_array($result)){
$i++;
echo "
<p>Cultivars: <span>" .$row["cultivar_type1"]. "</span>, <span>" .$row["cultivar_type2"]. "</span>, <span>" .$row["cultivar_type3"]. "</span>, <span>" .$row["cultivar_type4"]. "</span></p> ";
}
mysqli_free_result($result);
}
}
Output:
Product_id(1) = mysql! , wood , fruit
Expected:
Product_id(1) = mysql! , wood , fruit
Product_id(2) = choc

Answer 1

So the only thing that i needed to to was to create an LEFT JOIN. Because an LEFT JOIN can accept 0 or an value. And my query worked.
Yes this my mysql DB is not the normalized as would be expected.
Solution:
SELECT p.product_image_path, p.product_id, p.brand_name, p.product_name, b.botttle_size, v.vintage,
t.wine_type_blend, p.price, p.quantity, p.time_created,
p.reference_number, p.shipping_cost,
c1.cultivar_type as cultivar_type1, c2.cultivar_type as cultivar_type2,
c3.cultivar_type as cultivar_type3, c4.cultivar_type as cultivar_type4
FROM product p
INNER JOIN wine_bottle b ON b.bottle_id = p.bottle_id
INNER JOIN wine_vintage v ON v.vintage_id = p.vintage_id
INNER JOIN wine_type t ON t.type_id = p.type_id
LEFT JOIN wine_cultivar c1 ON c1.cultivar_id = p.cultivar_1_id
LEFT JOIN wine_cultivar c2 ON c2.cultivar_id = p.cultivar_2_id
LEFT JOIN wine_cultivar c3 ON c3.cultivar_id = p.cultivar_3_id
LEFT JOIN wine_cultivar c4 ON c4.cultivar_id = p.cultivar_4_id